CBSE Class 5 Mathematics Area And Perimeter Worksheet Set 03

Objective Type

Question 1. The amount of surface occupied by a figure is given by its _______________.
Answer: area
In simple words: Area measures the flat space inside a closed boundary.

Exam Tip: Remember that area is always measured in square units.

Question 2. The formula used to find the perimeter of rectangle is ______________.
Answer: \(2 \times (\text{length} + \text{breadth})\)
In simple words: Add length and breadth, then multiply by 2.

Exam Tip: Perimeter is the total distance around the outside of a shape.

Question 3. The area of rectangle with length 12 cm and breadth 8 cm is ______________.
Answer: \(96\text{ sq cm}\)
Area = length \(\times\) breadth
Area = \(12\text{ cm} \times 8\text{ cm} = 96\text{ sq cm}\)
In simple words: Multiply length by breadth to get the area.

Exam Tip: Always include square units like sq cm for area.

Question 4. The distance around a closed figure is called its ______________.
Answer: perimeter
In simple words: Perimeter is the total outer boundary length.

Question 5. The perimeter of square of side 15 m is ______________.
Answer: \(60\text{ m}\)
Perimeter of square = \(4 \times \text{side}\)
Perimeter = \(4 \times 15\text{ m} = 60\text{ m}\)
In simple words: Multiply the side length by 4.

Exam Tip: All 4 sides of a square are equal.

Question 6. Volume of cuboid = length x __________ x height
Answer: breadth
In simple words: Volume is length times breadth times height.

Exam Tip: Breadth is also known as width.

Question 7. The amount of space occupied by a solid gives its ______________.
Answer: volume
In simple words: Volume tells us how much 3D space an object takes up.

Exam Tip: Solids have volume, whereas flat shapes have area.

Question 8. The measure of inner space of a hollow solid is called its ______________.
Answer: capacity (or volume)
In simple words: Capacity measures how much a container can hold.

Exam Tip: Capacity is closely related to volume for hollow containers.

Question 9. The volume of cube of edge 5 cm is ______________.
Answer: \(125\text{ cubic cm}\)
Volume of cube = \(\text{edge} \times \text{edge} \times \text{edge}\)
Volume = \(5\text{ cm} \times 5\text{ cm} \times 5\text{ cm} = 125\text{ cubic cm}\)
In simple words: Cube the edge length to find the volume.

Exam Tip: Volume uses cubic units.

Question 10. Sq m and sq cm are units of measuring______________.
Answer: area
In simple words: Square meters and square centimeters measure flat areas.

Exam Tip: Look for "sq" to identify area units.

Question 11. The perimeter of rectangle with length 8 m and width 5 m is ______________.
Answer: \(26\text{ m}\)
Perimeter = \(2 \times (\text{length} + \text{width})\)
Perimeter = \(2 \times (8 + 5) = 2 \times 13 = 26\text{ m}\)
In simple words: Add length and width, then double the result.

Exam Tip: Never forget to multiply the sum by 2.

Question 12. The volume of a cuboid with length 5m, breadth 4m and height 3m is ______________.
Answer: \(60\text{ cubic m}\)
Volume = \(\text{length} \times \text{breadth} \times \text{height}\)
Volume = \(5 \times 4 \times 3 = 60\text{ cubic m}\)
In simple words: Multiply all three dimensions together.

Exam Tip: Ensure all dimensions are in the same unit before multiplying.

Question 13. Volume is expressed in ______________ units.
Answer: cubic (or cubic units)
In simple words: Volume is always measured in cubes.

Exam Tip: Write cubic cm or cm³ for volume.

Question 14. Area is expressed in ______________ units.
Answer: square (or square units)
In simple words: Area is always measured in squares.

Question 15. All sides of a square are ______________ in length.
Answer: equal
In simple words: Every side of a square has the exact same length.

Exam Tip: This property makes perimeter calculation for squares very simple.

Question 16. An empty box and full box of same size and shape have ______________ volume.
Answer: the same
In simple words: The outer physical dimensions determine the volume of the box itself.

Exam Tip: Volume refers to the space enclosed by the box structure.

Question 17. Perimeter = ______________ of all sides.
Answer: sum (or total length)
In simple words: Add up all outer sides to find the perimeter.

Exam Tip: This rule works for any polygon.

Question 18. 4 x side gives the ______________ of a square.
Answer: perimeter
In simple words: Multiplying side by 4 gives the distance around a square.

Exam Tip: Do not confuse this with area, which is side \(\times\) side.

Question 19. The perimeter of a triangle with side 9 cm, 8 cm and 7 cm is ______________.
Answer: \(24\text{ cm}\)
Perimeter = \(9 + 8 + 7 = 24\text{ cm}\)
In simple words: Add the three side lengths together.

Exam Tip: Perimeter applies to any closed shape by adding all boundary lengths.

Question 20. Length x breadth gives the ______________ of a rectangle.
Answer: area
In simple words: Multiplying length and breadth gives rectangle area.

Exam Tip: Keep units consistent.

Question 21. The area of a square of side 12 cm is ______________.
Answer: \(144\text{ sq cm}\)
Area = \(\text{side} \times \text{side}\)
Area = \(12\text{ cm} \times 12\text{ cm} = 144\text{ sq cm}\)
In simple words: Multiply the side length by itself.

Exam Tip: Memorize squares up to 15 to calculate quickly.

Question 22. The ______________ of a figure is the number of times the unit square is continued in the figure.
Answer: area
In simple words: Area counts how many unit squares fit inside a shape.

Exam Tip: This is the fundamental definition of area using grid squares.

Question 23. Cubic metre and cubic centimeter are units of measuring ______________.
Answer: volume
In simple words: These units measure 3D space.

Exam Tip: Cubic units always have a power of 3.

Question 24. A ______________ is a special cuboid whose length, breadth and height are equal.
Answer: cube
In simple words: A cube is a cuboid with all equal edges.

Question 25. A ______________ is a special rectangle whose length and breadth are equal.
Answer: square
In simple words: A square is a rectangle where adjacent sides are equal.

Exam Tip: Every square is a rectangle, but not every rectangle is a square.

Subjective Type questions :

Question 1. Find the area of the square with
a. Side = 14 cm
Answer:
Area of square = \(\text{side} \times \text{side}\)
Area = \(14\text{ cm} \times 14\text{ cm} = 196\text{ sq cm}\)
In simple words: Multiply 14 by 14 to get the square's area.

Exam Tip: Always write the formula before substituting values.

Question 1b. Side = 8.5 m
Answer:
Area of square = \(\text{side} \times \text{side}\)
Area = \(8.5\text{ m} \times 8.5\text{ m} = 72.25\text{ sq m}\)
In simple words: Multiply 8.5 by 8.5.

Exam Tip: Count decimal places carefully in multiplication.

Question 2. Find the area of rectangle with
a) \(\ell = 15\text{ cm}\), \(b = 10\text{ cm}\)
Answer:
Area of rectangle = \(\ell \times b\)
Area = \(15\text{ cm} \times 10\text{ cm} = 150\text{ sq cm}\)
In simple words: Multiply length by breadth.

Exam Tip: Ensure units are identical for both length and breadth.

Question 2b. \(\ell = 25\text{ m}\), \(b = 9.5\text{ m}\)
Answer:
Area of rectangle = \(\ell \times b\)
Area = \(25\text{ m} \times 9.5\text{ m} = 237.5\text{ sq m}\)
In simple words: Multiply 25 by 9.5.

Exam Tip: Double-check decimal multiplication.

Question 3. Find the perimeter of the following shapes
Answer:
Shape 1 (Pentagon with sides 7 cm, 9 cm, 8 cm, 9 cm, 10 cm):
Perimeter = Sum of all outer sides
Perimeter = \(7 + 9 + 8 + 9 + 10 = 43\text{ cm}\)

Shape 2 (Hexagon with sides 4 m, 10 m, 4 m, 3 m, 10 m, 3 m):
Perimeter = Sum of all outer sides
Perimeter = \(4 + 10 + 4 + 3 + 10 + 3 = 34\text{ m}\)
In simple words: Add all the outer edge lengths together.

Exam Tip: Check off each side as you add it so you do not miss any.

Question 4. Find the perimeter of a square whose
a) side = 18 cm
Answer:
Perimeter = \(4 \times \text{side}\)
Perimeter = \(4 \times 18\text{ cm} = 72\text{ cm}\)
In simple words: Multiply the side length by 4.

Exam Tip: Perimeter units remain linear (cm, m), not square.

Question 4b. side = 36.25 m
Answer:
Perimeter = \(4 \times \text{side}\)
Perimeter = \(4 \times 36.25\text{ m} = 145\text{ m}\)
In simple words: Multiply 36.25 by 4.

Exam Tip: \(4 \times 0.25 = 1\), which makes calculation easier.

Question 5. Find the perimeter of rectangle whose
a) \(\ell = 24\text{ cm}\), \(b = 16\text{ cm}\)
Answer:
Perimeter = \(2 \times (\ell + b)\)
Perimeter = \(2 \times (24 + 16) = 2 \times 40 = 80\text{ cm}\)
In simple words: Add length and breadth, then multiply by 2.

Question 5b. \(\ell = 32.5\text{ m}\), \(b = 25.25\text{ m}\)
Answer:
Perimeter = \(2 \times (\ell + b)\)
Perimeter = \(32.5 + 25.25 = 57.75\)
Perimeter = \(2 \times 57.75 = 115.5\text{ m}\)
In simple words: Find sum of length and breadth, then double it.

Exam Tip: Align decimal points carefully when adding.

Question 6. Find volume of a cube of edge
a) 13 cm
Answer:
Volume of cube = \(\text{edge} \times \text{edge} \times \text{edge}\)
Volume = \(13 \times 13 \times 13 = 169 \times 13 = 2197\text{ cubic cm}\)
In simple words: Multiply the edge by itself three times.

Exam Tip: Cube units are written as cubic cm or cm³.

Question 6b. 21 m
Answer:
Volume of cube = \(\text{edge} \times \text{edge} \times \text{edge}\)
Volume = \(21 \times 21 \times 21 = 441 \times 21 = 9261\text{ cubic m}\)
In simple words: Multiply 21 three times.

Exam Tip: Take care with multi-digit multiplication.

Question 7. Find the volume of a cuboid with
a) \(\ell = 12\text{ cm}\), \(b = 10\text{ cm}\), \(h = 8\text{ cm}\)
Answer:
Volume = \(\ell \times b \times h\)
Volume = \(12 \times 10 \times 8 = 120 \times 8 = 960\text{ cubic cm}\)
In simple words: Multiply length, breadth, and height.

Exam Tip: Multiply numbers in the easiest order (e.g., \(12 \times 10 = 120\)).

Question 7b. \(\ell = 15\text{ cm}\), \(b = 7.5\text{ cm}\), \(h = 9.5\text{ cm}\)
Answer:
Volume = \(\ell \times b \times h\)
Volume = \(15 \times 7.5 \times 9.5 = 112.5 \times 9.5 = 1068.75\text{ cubic cm}\)
In simple words: Multiply all three dimensions.

Exam Tip: Double-check decimal calculations.

Question 8. Find the missing dimension in the following cuboid.
a. \(V = 2400\text{ cu cm}\), \(\ell = 60\text{ cm}\), \(b = 8\text{ cm}\), \(h = ?\)
Answer:
Height \(h = \frac{\text{Volume}}{\ell \times b}\)
\(\ell \times b = 60 \times 8 = 480\)
\(h = \frac{2400}{480} = 5\text{ cm}\)
In simple words: Divide total volume by the product of length and breadth.

Exam Tip: Use division to find any missing dimension when volume is given.

Question 8b. \(V = 1350\text{ cu cm}\), \(\ell = 20\text{ cm}\), \(b = ?\), \(h = 7.5\text{ cm}\)
Answer:
Breadth \(b = \frac{\text{Volume}}{\ell \times h}\)
\(\ell \times h = 20 \times 7.5 = 150\)
\(b = \frac{1350}{150} = 9\text{ cm}\)
In simple words: Divide volume by length times height.

Exam Tip: Cancel out zeros to simplify division.

Question 8c. \(V = 380\text{ cu m}\), \(\ell = ?\), \(b = 9.5\text{ m}\), \(h = 2\text{ m}\)
Answer:
Length \(\ell = \frac{\text{Volume}}{b \times h}\)
\(b \times h = 9.5 \times 2 = 19\)
\(\ell = \frac{380}{19} = 20\text{ m}\)
In simple words: Divide volume by breadth times height.

Question 9. A rectangular field is 425 m long 160 m broad. Find the perimeter of the field in km.
Answer:
Length \(\ell = 425\text{ m}\)
Breadth \(b = 160\text{ m}\)
Perimeter = \(2 \times (\ell + b)\)
Perimeter = \(2 \times (425 + 160) = 2 \times 585 = 1170\text{ m}\)
Convert meters to kilometers by dividing by 1000:
Perimeter in km = \(\frac{1170}{1000} = 1.17\text{ km}\)
In simple words: Find perimeter in meters first, then convert to kilometers.

Exam Tip: Always check the required unit (km vs m) at the end of the question.

Question 10. The length, breadth and height of a brick are 14 cm, 10 cm and 6 cm respectively. Find the volume one brick and 10 such bricks.
Answer:
Volume of 1 brick = \(\ell \times b \times h\)
Volume of 1 brick = \(14 \times 10 \times 6 = 840\text{ cubic cm}\)
Volume of 10 bricks = \(840 \times 10 = 8400\text{ cubic cm}\)
In simple words: Find volume of one brick and multiply by 10.

Exam Tip: Multiplying by 10 just appends a zero.

Question 11. A fish tank is 60 cm long, 30 cm wide and 40 cm high. Find the volume of the fish tank.
Answer:
Volume = \(\ell \times b \times h\)
Volume = \(60 \times 30 \times 40\)
Volume = \(1800 \times 40 = 72000\text{ cubic cm}\)
In simple words: Multiply length, width, and height.

Question 12. A square park has a side of 80 m. Find the total distance you cover in jogging around it 5 times.
Answer:
Perimeter of square park = \(4 \times \text{side}\)
Perimeter = \(4 \times 80\text{ m} = 320\text{ m}\)
Total distance for 5 rounds = \(5 \times 320\text{ m} = 1600\text{ m}\)
In simple words: Multiply the perimeter by the number of rounds.

Exam Tip: Going around a park means finding its perimeter.

Question 13. The edge of a cuboid wooden boxes 50 cm find its volume.
Answer:
Assuming the box is a cube with an edge of 50 cm:
Volume = \(\text{edge} \times \text{edge} \times \text{edge}\)
Volume = \(50 \times 50 \times 50 = 125000\text{ cubic cm}\)
In simple words: Cube the given edge length.

Exam Tip: \(5 \times 5 \times 5 = 125\) with three zeros attached.