CBSE Class 4 Maths Tables And Shares Worksheet Set 03

Competency : Ability to Compute

Question 1. Write these in repeated addition form
a) \(10 \times 1 =\)
Answer: \(1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 10\)
In simple words: Multiplication is repeated addition of the same number. Adding 1 ten times gives 10.

Exam Tip: The first number tells how many times the second number is added.

Question 1. (Continued)
b) \(3 \times 2 =\)
Answer: \(2 + 2 + 2 = 6\)
In simple words: Add 2 three times to get 6.

Exam Tip: Remember \(3 \times 2\) means 3 groups of 2.

Question 1. (Continued)
c) \(6 \times 5 =\)
Answer: \(5 + 5 + 5 + 5 + 5 + 5 = 30\)
In simple words: Add 5 six times to get 30.

Question 1. (Continued)
d) \(2 \times 3 =\)
Answer: \(3 + 3 = 6\)
In simple words: Add 3 two times to get 6.

Exam Tip: Pay close attention to the order of numbers when converting to repeated addition.

Question 3. Find the product of
a) \(2 \times 5 =\)
Answer: 10
In simple words: Multiply 2 by 5 to get 10.

Exam Tip: Basic multiplication fact from the table of 2 or 5.

Question 3. (Continued)
b) \(12 \times 0 =\)
Answer: 0
In simple words: Any number multiplied by 0 is always 0.

Exam Tip: Zero property of multiplication states that \(a \times 0 = 0\).

Question 3. (Continued)
c) \(7 \times 8 =\)
Answer: 56
In simple words: 7 times 8 equals 56.

Exam Tip: Memorize multiplication tables up to 20 for faster computation.

Question 3. (Continued)
d) \(18 \times 50 =\)
Answer: 900
Calculation:
\(18 \times 5 = 90\)
\(18 \times 50 = 900\)
In simple words: Multiply 18 by 5 and attach a zero at the end.

Exam Tip: When multiplying by multiples of 10, multiply the non-zero digits first and append the total number of zeros.

Question 3. (Continued)
e) \(17 \times 1 =\)
Answer: 17
In simple words: Any number multiplied by 1 remains the same number.

Exam Tip: This is known as the multiplicative identity property.

Question 3. (Continued)
f) \(90 \times 10 =\)
Answer: 900
In simple words: Multiply 9 by 1 and put two zeros at the end.

Exam Tip: Multiplying by 10 adds one zero; multiplying by 100 adds two zeros.

Question 4. Find the product of
a) \(65 \times 35\)
Answer: 2275
Calculation steps:
\(65 \times 5 = 325\)
\(65 \times 30 = 1950\)
\(325 + 1950 = 2275\)
In simple words: Multiply 65 by 5, then multiply 65 by 30, and add both results together.

Exam Tip: Align your partial products carefully by place value columns when doing column multiplication.

Question 4. (Continued)
b) \(102 \times 84\)
Answer: 8568
Calculation steps:
\(102 \times 4 = 408\)
\(102 \times 80 = 8160\)
\(408 + 8160 = 8568\)
In simple words: Multiply 102 by 4 and by 80, then add the two products.

Exam Tip: Alternatively, use distributive property: \((100 + 2) \times 84 = 8400 + 168 = 8568\).

Competency : Problem Solving Ability

a) Meera plants 50saplings in 10 rows. How many saplings are there in each row?

b) You have to distribute 96 oranges equally in 3 baskets. How many oranges will there be in each basket?

c) Frame your question:
A) There are 10 packets of sugar. Arun paid 100 rupees for all the packets.

Question:
d) Try solve these:

(Division is repeated subtraction)

1) Raju collects 112 sea shells to make necklaces for his sisters. He requires 28 ses shells to make a necklace. How many necklaces did he make?

2) Gangu made sweets for Diwali. He had 80 laddoos. He packs 4 laddoos in each small packet.
a) How many packets did he make? ------------
b) If he packs, 20 laddoos in bigger packets how many packets does he get?

Competency : Ability to Compute

1. Divide

a) 28 / 4 =

b) 14/ 2 =

c) 36/ 9 =

d) 25 /5 =

e) 100/ 10 =

f) 27/3 =

g) 44/4=

h) 54/6 =

i) 64/ 8 =

2.Anu wants change for Rs.100
How many notes will she get if she wants change?

a) All 50 rupee notes? ___________

b) All 10 rupee notes ? ______________

c) All 20 rupee notes? _______________

d) All 5 rupee notes ? _________________

3) Divide and find the quotient:

a) 65 / 5 =

b) 108/9 =

c) 428 / 2