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ICSE Class 8 Mathematics Chapter 9 Percent and Percentage Digital Edition
For Class 8 Mathematics, this chapter in ICSE Class 8 Maths Chapter 09 Percent and Percentage provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 8 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 9 Percent and Percentage ICSE Book Class Class 8 PDF (2026-27)
Chapter 9
Percent And Percentage
Review
| 1. Percent | Percent means 'for every hundred'. The word percent is abbreviated as p.c.; and is denoted by the symbol %. |
|---|---|
| 2. Percentage | A fraction, whose denominator is 100 is called a percentage and the numerator of such fraction is called the rate percent. \[\frac{8}{100} = 8 \text{ percent i.e. } 8 \text{ out of } 100.\] Percent and percentage are used in the same sense. |
| 3. | To express a given number as percent, multiply by 100 and in the same step attach the percentage sign (%). \[\therefore \frac{3}{5} = \frac{3}{5} \times 100\% = 60\%; \quad 0.45 = 0.45 \times 100\% = 45\% \text{ and so on.}\] |
| 4. | To express a given percent into a fraction, divide by 100 and in the same step remove the sign of percentage. \[45\% = \frac{45}{100} = \frac{9}{20} \text{ (as a vulgar fraction) or } 45\% = \frac{45}{100} = 0.45 \text{ (as a decimal fraction)}\] |
| 5. | x as the percent of y = \[\frac{x}{y} \times 100\%\] and x% of y = \[\frac{x}{100} \times y\] (i) 5 as the percent of 20 = \[\frac{5}{20} \times 100\% = 25\%\] and (ii) 5% of 20 = \[\frac{5}{100} \times 20 = 1\] |
| 6. | (i) Increase % = \[\frac{\text{Increase in quantity}}{\text{Original quantity}} \times 100\%\] (ii) Decrease % = \[\frac{\text{Decrease in quantity}}{\text{Original quantity}} \times 100\%\] |
Test Yourself
1. \[\frac{7}{10} = \frac{7}{10} \times \ldots\ldots \% = \ldots\ldots \%\]
2. \[0.087 = 0.087 \times \ldots\ldots \% = \ldots\ldots \%\]
3. 37.5% as a vulgar fraction = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\]
4. 5.6% as a decimal fraction = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\]
5. 32 as the percent of 40 = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\] = \[\ldots\ldots\]
6. 12.5% of 80 m = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\] = \[\ldots\ldots\]
7. A number is changed from 60 to 75
Increase in number = \[\ldots\ldots\] - \[\ldots\ldots\] = \[\ldots\ldots\] and increase % = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\] = \[\ldots\ldots\]
8. A number is changed from 75 to 60
Decrease in number = \[\ldots\ldots\] - \[\ldots\ldots\] = \[\ldots\ldots\] and decrease % = \[\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\] = \[\ldots\ldots\]
Teacher's Note
Percentages help us understand real-world comparisons, like calculating discounts while shopping or tracking grades in school. When a shirt costs 1000 rupees and gets a 20% discount, you save 200 rupees - a practical use of percentage calculations in daily life.
Example 1
(i) Find, 36 is what percent of 144.
(ii) 80 is 32% of a certain number, find the number.
(iii) Evaluate : 16% of 150 - 25% of 84 + 8% of 550.
Solution
(i) Direct method :
The required percent = \[\frac{36}{144} \times 100\% = 25\%\]
Alternative method :
Let x% of 144 = 36 \[\Rightarrow \frac{x}{100} \times 144 = 36 \Rightarrow x = \frac{36 \times 100}{144} = 25\]
Therefore, the required percent = 25%
(ii) Given : 32% of a certain number = 80
\[\Rightarrow \frac{32}{100} \times \text{The number} = 80 \Rightarrow \text{The required number} = 80 \times \frac{100}{32} = 250\]
Alternative method :
Let the required number be x
\[\therefore 32\% \text{ of } x = 80 \Rightarrow \frac{32}{100} \times x = 80 \text{ i.e. } x = 80 \times \frac{100}{32} = 250\]
Therefore, the required number = 250
(iii) 16% of 150 - 25% of 84 + 8% of 550
\[= \frac{16}{100} \times 150 - \frac{25}{100} \times 84 + \frac{8}{100} \times 550 = 24 - 21 + 44 = 47\]
Teacher's Note
These methods show that percentages connect to fractions and decimals, helping us solve problems about parts of wholes. In a test where you score 36 out of 144 total marks, finding the percentage tells you exactly how well you performed.
Example 2
A man spends 65% of his salary and saves 525 rupees per month. Find his monthly salary.
Solution
Since, the man spends 65% of his salary
\[\therefore\] He saves (100 - 65)% = 35% of his salary
Given : 35% of his monthly salary = 525 rupees
\[\Rightarrow \frac{35}{100} \times \text{his monthly salary} = 525\]
\[\therefore \text{His monthly salary} = 525 \times \frac{100}{35} = 1,500\]
Alternative method :
Let the man's monthly salary be 100 rupees
\[\therefore \text{He spends} = 65\% \text{ of } 100 = \frac{65}{100} \times 100 = 65\]
and, saves = 100 - 65 = 35 rupees
Applying Unitary method :
When the man saves = 35 rupees, his monthly salary = 100 rupees
\[\Rightarrow \text{When the man saves} = 1 \text{ rupee, his monthly salary} = \frac{100}{35}\]
And, when the man saves = 525 rupees, his monthly salary = \[\frac{100}{35} \times 525 = 1,500\]
Therefore, man's monthly salary = 1,500 rupees
Teacher's Note
Understanding salary percentages helps in budgeting real income. If you earn 1,500 rupees monthly and save 35%, you automatically know you spend 65% or about 975 rupees on expenses.
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ICSE Book Class 8 Mathematics Chapter 9 Percent and Percentage
Download the official ICSE Textbook for Class 8 Mathematics Chapter 9 Percent and Percentage, updated for the latest academic session. These e-books are the main textbook used by major education boards across India. All teachers and subject experts recommend the Chapter 9 Percent and Percentage NCERT e-textbook because exam papers for Class 8 are strictly based on the syllabus specified in these books. You can download the complete chapter in PDF format from here.
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