Read and download the Chapter 10 Profit Loss and Discount PDF from the official ICSE Book for Class 8 Mathematics. Updated for the 2026-27 academic session, you can access the complete Mathematics textbook in PDF format for free.
ICSE Class 8 Mathematics Chapter 10 Profit Loss and Discount Digital Edition
For Class 8 Mathematics, this chapter in ICSE Class 8 Maths Chapter 10 Profit Loss and Discount provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 8 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 10 Profit Loss and Discount ICSE Book Class Class 8 PDF (2026-27)
Chapter 10
Profit, Loss and Discount
10.1 Review
Profit
When the selling price (S.P.) of an article is more than its cost price (C.P.), the article is said to be sold at a profit (gain).
And, Profit = Selling Price - Cost Price
i.e. Profit = S.P. - C.P.
Loss
When the selling price (S.P.) of an article is less than its cost price (C.P.), the article is said to be sold at a loss.
And, Loss = Cost Price - Selling Price
i.e. Loss = C.P. - S.P.
Profit = S.P. - C.P.
(i) S.P. = C.P. + Profit
(ii) C.P. = S.P. - Profit
Loss = C.P. - S.P.
(i) S.P. = C.P. - Loss
(ii) C.P. = S.P. + Loss
Profit and Loss Percentages
Profit (gain)% = \(\frac{\text{Profit}}{\text{C.P.}} \times 100\)% and Loss % = \(\frac{\text{Loss}}{\text{C.P.}} \times 100\)%
Important Note
Profit % and loss % are always calculated on cost price.
Test Yourself
1. If C. P. = ₹ 800 and S. P. = ₹ 600
Loss = ............................. = ........... and loss % = ............................. = ..........
2. If S. P. = ₹ 600 and profit = ₹ 120
C. P. = ............................. = ........... and profit % = ............................. = ..........
3. If S. P. = ₹ 1,250 and loss = ₹ 250
C. P. = ............................. = ........... and loss % = ............................. = ..........
4. S. P. of an article is 80% of its C. P.
If C. P. = ₹ 100, S. P. = ............................. = ..........
Loss = ............................. = ........... and loss % = ............................. = ..........
5. C. P. of an article is 80% of its S. P.
If S. P. = ₹ 100, C. P. = ............................. = ..........
Profit = ............................. = ........... and profit % = ............................. = ..........
Example 1
Articles, bought at 10 for ₹ 8, are sold at 8 for ₹ 10. Find the gain percent.
Also, find the number of articles bought and sold in order to gain ₹ 144.
Solution
Whenever the cost price and the selling price are given for different number of identical articles; first of all, find the C.P. and the S.P. of equal number of articles and then calculate the profit percent or the loss percent, as the case may be.
Also, in order to have a certain gain,
the number of articles bought and sold = \(\frac{\text{Total profit}}{\text{Profit on one article}}\)
Given: C.P. of 10 articles = ₹ 8
C.P. of 1 article = \(\frac{8}{10}\) = ₹ 0.80
Also, given: S.P. of 8 articles = ₹ 10
S.P. of 1 article = \(\frac{10}{8}\) = ₹ 1.25
Profit on 1 article = S.P. - C.P. = ₹ 1.25 - ₹ 0.80 = ₹ 0.45
and, profit % = \(\frac{\text{Profit}}{\text{C.P.}} \times 100\)%
= \(\frac{₹ 0.45}{₹ 0.80} \times 100\)% = 56.25%
(Ans.)
Also, the number of articles bought and sold
= \(\frac{\text{Total profit}}{\text{Profit on one article}}\)
= \(\frac{₹ 144}{₹ 0.45}\) = 320
(Ans.)
Teacher's Note
When buying items in bulk, understanding the profit per unit helps determine how many units to sell to reach a sales target. This is commonly used by retailers planning their inventory.
10.2 Overheads
When an article is purchased at one place and is taken to some other place; an additional money for transportation, labour, packing, etc. is to be spent. This additional money spent is termed as overheads or overhead expenses.
The overheads (if any) incurred is added to the actual cost price to get the total cost price of the article and then the profit or loss is calculated on this total cost price.
Example 2
Raju goes from Agra to Delhi to buy an article, which costs ₹ 6,500 in Delhi. He sells this article in Agra for ₹ 8,000. Find his gain or loss per cent. Consider that he spends ₹ 700 on transportation, food, etc.
Solution
Given: Actual price paid for the article = ₹ 6,500
and, overhead expenses = ₹ 700
Total cost price = ₹ 6,500 + ₹ 700 = ₹ 7,200
Since, selling price = ₹ 8,000
Gain = ₹ 8,000 - ₹ 7,200
[Gain = S.P. - C.P.]
= ₹ 800
and, gain % = \(\frac{₹ 800}{₹ 7,200} \times 100\)% = \(11\frac{1}{9}\)%
(Ans.)
Teacher's Note
When starting a business, entrepreneurs must account for all expenses including transportation and labor. These overhead costs significantly affect the actual profit margin.
Example 3
A man sold his bicycle for ₹ 810; losing one-ninth of its selling price. Find:
(i) the loss
(ii) the cost price of the bicycle
(iii) the loss as percent.
Solution
(i) Since, S. P. = ₹ 810;
loss = \(\frac{1}{9} \times ₹ 810\) = ₹ 90
(Ans.)
(ii) C.P. = S.P. + loss = ₹ 810 + ₹ 90 = ₹ 900
(Ans.)
(iii) Loss % = \(\frac{\text{Loss}}{\text{C.P.}} \times 100\)%
= \(\frac{₹ 90}{₹ 900} \times 100\)% = 10%
(Ans.)
Example 4
The selling price of a table is \(\frac{27}{25}\) times its cost price. Find the loss or the profit as percent.
Solution
Let the cost price of the table = ₹ 100
Its selling price = \(\frac{27}{25} \times ₹ 100\) = ₹ 108
Profit = S.P. - C.P. = ₹ 108 - ₹ 100 = ₹ 8
Profit % = \(\frac{\text{Profit}}{\text{C.P.}} \times 100\)% = \(\frac{₹ 8}{₹ 100} \times 100\)% = 8%
(Ans.)
Algebraic Method
Let the C.P. = ₹ x
S.P. = \(\frac{27}{25}x\)
Profit = S.P. - C.P. = \(\frac{27}{25}x - ₹ x\) = \(\frac{27 - 25}{25}x\) = \(\frac{2}{25}x\)
And, profit % = \(\frac{\frac{2}{25}x}{₹ x} \times 100\)%
= \(\frac{2}{25} \times 100\)% = 8%
(Ans.)
Teacher's Note
Understanding ratios and percentages helps in comparing prices between different vendors or analyzing profit margins across different products.
This is a preview of the first 3 pages. To get the complete book, click below.
Free study material for Mathematics
ICSE Book Class 8 Mathematics Chapter 10 Profit Loss and Discount
Download the official ICSE Textbook for Class 8 Mathematics Chapter 10 Profit Loss and Discount, updated for the latest academic session. These e-books are the main textbook used by major education boards across India. All teachers and subject experts recommend the Chapter 10 Profit Loss and Discount NCERT e-textbook because exam papers for Class 8 are strictly based on the syllabus specified in these books. You can download the complete chapter in PDF format from here.
Download Mathematics Class 8 NCERT eBooks in English
We have provided the complete collection of ICSE books in English Medium for all subjects in Class 8. These digital textbooks are very important for students who have English as their medium of studying. Each chapter, including Chapter 10 Profit Loss and Discount, contains detailed explanations and a detailed list of questions at the end of the chapter. Simply click the links above to get your free Mathematics textbook PDF and start studying today.
Benefits of using ICSE Class 8 Textbooks
The Class 8 Mathematics Chapter 10 Profit Loss and Discount book is designed to provide a strong conceptual understanding. Students should also access NCERT Solutions and revision notes on studiestoday.com to enhance their learning experience.
FAQs
You can download the latest, teacher-verified PDF for ICSE Class 8 Maths Chapter 10 Profit Loss and Discount for free on StudiesToday.com. These digital editions are updated as per 2026-27 session and are optimized for mobile reading.
Yes, our collection of Class 8 Mathematics NCERT books follow the 2026 rationalization guidelines. All deleted chapters have been removed and has latest content for you to study.
Downloading chapter-wise PDFs for Class 8 Mathematics allows for faster access, saves storage space, and makes it easier to focus in 2026 on specific topics during revision.
NCERT books are the main source for ICSE exams. By reading ICSE Class 8 Maths Chapter 10 Profit Loss and Discount line-by-line and practicing its questions, students build strong understanding to get full marks in Mathematics.