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ICSE Class 8 Mathematics Chapter 8 Speed Distance and Time Digital Edition
For Class 8 Mathematics, this chapter in ICSE Class 8 Maths Chapter 08 Speed Distance and Time provides a detailed overview of important concepts. We highly recommend using this text alongside the ICSE Solutions for Class 8 Mathematics to learn the exercise questions provided at the end of the chapter.
Chapter 8 Speed Distance and Time ICSE Book Class Class 8 PDF (2026-27)
Chapter 8
Speed, Distance And Time
8.1 Review
1. Speed
The distance covered by an object, in unit time, is called its speed.
e.g., If the speed of a car is 65 km/hr this means, the car covers a distance of 65 kilometre in one hour.
Conversely, if an object covers a distance of 20 cm in one second, its speed = 20 cm/sec.
Speed = \(\frac{\text{Distance}}{\text{Time}}\)
2. From the formula, Speed = Distance/Time we can deduce:
(i) Distance = Speed \(\times\) Time and (ii) Time = \(\frac{\text{Distance}}{\text{Speed}}\)
3. Units
Relations between the units of distance covered, speed and time are:
| Speed | Distance | Time |
|---|---|---|
| (i) km/hr | km (kilometre) | hr (hour) |
| (ii) m/min | m (metre) | min (minute) |
| (iii) m/sec | m (metre) | sec (second) |
| (iv) cm/sec | cm (centimetre) | sec (second) and so on. |
8.2 An Important Result
Since, 1 km/hr = \(\frac{1000 \text{ m}}{1 \text{ hr}} = \frac{1000 \text{ m}}{60 \times 60 \text{ sec}} = \frac{5}{18}\) m/s
Therefore, to convert speed from km/hr to m/s; multiply by \(\frac{5}{18}\).
Conversely, to convert speed from m/s to km/hr, multiply by \(\frac{18}{5}\).
Example 1
An aeroplane flies 450 km in 20 minutes. Find:
(i) its speed in km/hr.
(ii) time taken by it to cover 1800 km.
(iii) distance covered by it in 0.6 hours.
Solution
(i) Since, distance = 450 km and time = 20 min = \(\frac{20}{60}\) hr = \(\frac{1}{3}\) hr
Speed = \(\frac{\text{Distance}}{\text{Time}} = \frac{450 \text{ km}}{\frac{1}{3} \text{ hr}} = 1350\) km/hr
(ii) Time taken to cover 1800 km
= \(\frac{\text{Distance}}{\text{Speed}} = \frac{1800}{1350}\) hr = \(\frac{4}{3}\) hr = 1 hr 20 minutes
(iii) Distance covered in 0.6 hours = Speed \(\times\) Time = 1350 km/hr \(\times\) 0.6 hr = 810 km
Teacher's Note
Understanding speed helps us plan our travel time for daily activities - whether catching a bus to school or planning a road trip with family.
1. Uniform speed
If an object covers equal distances in equal intervals of time, its speed is said to be uniform.
2. Variable speed
When the speed of a body is not uniform, it is variable.
i.e. if an object covers unequal distances in equal intervals of time, its speed is variable.
Unless mentioned, the speed is always taken as uniform.
3. Average speed
Usually, a moving object (car, motor-cycle, etc.) does not cover its entire distance with the same (uniform) speed. Sometimes it increases its speed, sometimes it reduces its speed and sometimes it stops also.
Under such circumstances, the total distance covered by the moving object divided by the time, taken by it to cover this distance, gives the average speed of the object.
Average speed = \(\frac{\text{Total distance travelled}}{\text{Total time taken}}\)
Example 2
A man covers a distance of 60 km at a speed of 40 km/hr and another distance of 50 km at a speed of 30 km/hr. Calculate his average speed for the whole journey.
Solution
(i) Time taken to cover 60 km = \(\frac{60}{40}\) hrs = \(\frac{3}{2}\) hrs
and, time taken to cover 50 km = \(\frac{50}{30}\) hrs = \(\frac{5}{3}\) hrs
Total distance travelled = 60 km + 50 km = 110 km
and, total time taken = \(\frac{3}{2}\) hrs + \(\frac{5}{3}\) hrs = \(\frac{9 + 10}{6}\) hrs = \(\frac{19}{6}\) hrs
Average speed = \(\frac{\text{Total distance travelled}}{\text{Total time taken}}\)
= \(\frac{110 \text{ km}}{\frac{19}{6} \text{ hrs}} = \frac{110 \times 6}{19}\) km/hr = \(34\frac{14}{19}\) km/hr
Example 3
A distance of 450 km is covered in \(6\frac{1}{2}\) hrs. If the first two-thirds of the distance is covered at the speed of 75 km/hr, at what speed the remaining distance is covered?
Solution
Since, two-thirds of the whole distance = \(\frac{2}{3} \times 450\) km = 300 km
And, the speed with which this distance is covered = 75 km/hr
Therefore, the time taken to cover this distance = \(\frac{\text{Distance}}{\text{Speed}} = \frac{300}{75}\) hrs = 4 hrs
For the remaining distance:
Distance to be covered = (450 - 300) km = 150 km
and, time taken = \((6\frac{1}{2} - 4)\) hrs = \(2\frac{1}{2}\) hrs = \(\frac{5}{2}\) hrs
Speed = \(\frac{150 \text{ km}}{\frac{5}{2} \text{ hrs}} = 60\) km/hr
Teacher's Note
Real-world journeys rarely maintain one speed - calculating average speed helps us understand how traffic delays and different road conditions affect our total travel time in daily commutes.
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ICSE Book Class 8 Mathematics Chapter 8 Speed Distance and Time
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