CBSE Class 8 Mathematics Simple Interest MCQs Set 24

Mathematics Objective Questions and Answers: Simple Interest

Review structured MCQ sets for Class 8 Mathematics Simple Interest. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Download Simple Interest MCQs with Answers

View or download the dedicated Simple Interest MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: A firm pays 18% per annum. The amount received after 6 years on Rs. 10,000 deposited now and Rs. 5000 deposited three years from now is
(a) Rs. 28,500
(b) Rs. 25,800
(c) Rs. 20,800
(d) Rs. 30,400
Show Answer & Explanation

Answer: (a) Rs. 28,500

Explanation:
1. Rs. 10,000 for 6 years: SI = 10000 × 18 × 6/100 = 10,800, amount 20,800
2. Rs. 5000 for 3 years: SI = 2700, amount 7700
3. Total = 20,800 + 7,700 = Rs. 28,500.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 2: A sum was borrowed at 8% per annum and Rs. 138.75 interest was paid after 3 years 1 month. The sum borrowed was
(a) Rs. 450
(b) Rs. 600
(c) Rs. 625
(d) Rs. 562.50
Show Answer & Explanation

Answer: (d) Rs. 562.50

Explanation:
1. T = 37/12 years
2. P = 138.75 × 100/(8 × 37/12)
3. = 13875 × 12/296 = Rs. 562.50.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 3: In what time will a sum of money at \( 13\frac{1}{3}\% \) simple interest triple itself?
(a) 7.5 years
(b) 15 years
(c) 20 years
(d) 10 years
Show Answer & Explanation

Answer: (b) 15 years

Explanation:
1. Interest earned = 2P
2. 2P = P × (40/3) × T/100
3. T = 200 × 3/40 = 15 years.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 4: Find the simple interest when P = Rs. 600, R = 2% per annum and T = 20 months.
(a) Rs. 12
(b) Rs. 24
(c) Rs. 20
(d) Rs. 240
Show Answer & Explanation

Answer: (c) Rs. 20

Explanation:
1. T = 20/12 = 5/3 years
2. SI = 600 × 2 × (5/3)/100 = Rs. 20.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 5: Find the principal when SI = Rs. 72, R = 3% per annum and T = 3 months.
(a) Rs. 2400
(b) Rs. 7200
(c) Rs. 960
(d) Rs. 9600
Show Answer & Explanation

Answer: (d) Rs. 9600

Explanation:
1. T = 1/4 year
2. P = 72 × 100/(3 × 1/4)
3. = 7200 × 4/3 = Rs. 9600.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 6: Find the time when P = Rs. 640, R = 12.5% per annum and SI = Rs. 40.
(a) 1 year
(b) 6 months
(c) 3 months
(d) 9 months
Show Answer & Explanation

Answer: (b) 6 months

Explanation:
1. T = 40 × 100/(640 × 12.5)
2. = 4000/8000 = 1/2 year = 6 months.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 7: Neeraj borrowed money at \( 10\frac{1}{2}\% \) per annum and paid Rs. 1863.75 interest for \( 2\frac{1}{2} \) years. The sum borrowed was
(a) Rs. 6000
(b) Rs. 7500
(c) Rs. 7100
(d) Rs. 5900
Show Answer & Explanation

Answer: (c) Rs. 7100

Explanation:
1. P = 1863.75 × 100/(10.5 × 2.5)
2. = 186375/26.25 = Rs. 7100.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Question 8: What rate gives Rs. 280 interest on Rs. 56,000 in 2 years?
(a) 2.5%
(b) 0.25%
(c) 0.5%
(d) 0.025%
Show Answer & Explanation

Answer: (b) 0.25%

Explanation:
1. R = 280 × 100/(56000 × 2)
2. = 28000/112000 = 0.25%.

Teacher's Note:
1. Simple interest = P × R × T / 100, with T in years. Convert months into years by dividing by 12 before substituting.

Practice MCQs for Class 8 Mathematics Simple Interest

Class 8 Mathematics Simple Interest Objective Test Questions

Explore reliable practice questions for Simple Interest tailored for Class 8 Mathematics learners. Use these multiple-choice formats to evaluate preparedness and strengthen problem-solving skills.

NCERT-Aligned Objective Questions and Solutions

Built using the official NCERT book for Class 8, these Mathematics objective sets provide reliable academic guidance. Pair your practice with our recommended NCERT solutions to master optimal problem-solving approaches.

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FAQs

Where can I access latest CBSE Class 8 Mathematics Simple Interest MCQs Set 24?

You can get most exhaustive CBSE Class 8 Mathematics Simple Interest MCQs Set 24 for free on StudiesToday.com. These MCQs for Class 8 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Class 8 material?

Yes, our CBSE Class 8 Mathematics Simple Interest MCQs Set 24 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in Class 8 exams?

By solving our CBSE Class 8 Mathematics Simple Interest MCQs Set 24, Class 8 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for CBSE Class 8 Mathematics Simple Interest MCQs Set 24?

Yes, Mathematics MCQs for Class 8 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

Can I practice these Mathematics Class 8 MCQs online?

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