CBSE Class 8 Mathematics Ratio and Proportion MCQs Set 47

Mathematics Objective Questions and Answers: Ratio and Proportion

Access targeted multiple-choice questions for Ratio and Proportion designed to align with the latest CBSE academic syllabus for Class 8 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Multiple Choice Questions

Question 1: Find the mean proportional between 3 and 75.
(a) 14
(b) 20
(c) 15
(d) 16
Show Answer & Explanation

Answer: (c) 15

Explanation:
1. √(3 × 75) = √225 = 15.

Teacher's Note:
1. Mean proportional = √(product).
2. 15² = 225.

Question 2: A bus covers 102 km on 6.8 litres of petrol. How far will it travel on 24.2 litres?
(a) 326 km
(b) 320 km
(c) 336 km
(d) 363 km
Show Answer & Explanation

Answer: (d) 363 km

Explanation:
1. Distance per litre = 102 / 6.8 = 15 km.
2. Distance = 15 × 24.2 = 363 km.

Teacher's Note:
1. Distance and petrol are in direct proportion.
2. Unit method is the quickest.

Question 3: 55 cows graze a field in 16 days. How many cows will graze the same field in 10 days?
(a) 88 cows
(b) 35 cows
(c) 80 cows
(d) 77 cows
Show Answer & Explanation

Answer: (a) 88 cows

Explanation:
1. Cows and days are inversely proportional: 55 × 16 = x × 10.
2. x = 880 / 10 = 88.

Teacher's Note:
1. Fewer days need more cows (inverse variation).
2. Product of cows and days is constant.

Question 4: A person has money to buy 25 cycles worth Rs. 500 each. How many cycles can he buy if each cycle costs Rs. 125 more?
(a) 22
(b) 15
(c) 30
(d) 20
Show Answer & Explanation

Answer: (d) 20

Explanation:
1. Money = 25 × 500 = Rs. 12500.
2. New price = Rs. 625, so cycles = 12500 / 625 = 20.

Teacher's Note:
1. Total money is fixed; number and price are inversely proportional.
2. 25 × 500 = x × 625.

Question 5: An amount of Rs. 975 is distributed among A, B and C in the ratio 3 : 4 : 8. If C gives Rs. 517 of his share to D, how much is left with C?
(a) Rs. 15
(b) Rs. 3
(c) Rs. 8
(d) Rs. 520
Show Answer & Explanation

Answer: (b) Rs. 3

Explanation:
1. Sum of ratio terms = 15 and one part = 975 / 15 = Rs. 65.
2. C's share = 8 × 65 = Rs. 520.
3. Left with C = 520 − 517 = Rs. 3.

Teacher's Note:
1. Find one part, then C's share.
2. Subtract what C gave away.

Question 6: An amount of Rs. 950 is divided among A, B and C in the ratio 5 : 11 : 3. The difference between the shares of B and A divided by 150 is
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation

Answer: (b) 2

Explanation:
1. One part = 950 / 19 = Rs. 50.
2. B − A = (11 − 5) × 50 = Rs. 300.
3. 300 / 150 = 2.

Teacher's Note:
1. Sum of ratio terms is 19.
2. Difference of shares = difference of ratio terms × one part.

Question 7: The contents of two vessels containing water and milk in the ratios 2 : 3 and 4 : 5 are mixed in the ratio 1 : 2. The resulting mixture has water and milk in the ratio
(a) 77 : 58
(b) 4 : 5
(c) 58 : 77
(d) 2 : 3
Show Answer & Explanation

Answer: (c) 58 : 77

Explanation:
1. Fraction of water in vessel 1 = 2/5 and in vessel 2 = 4/9.
2. Water in mixture = (1 × 2/5 + 2 × 4/9) / 3 = (18 + 40) / 135 = 58 / 135.
3. Milk = 77 / 135, so ratio = 58 : 77.

Teacher's Note:
1. Convert each ratio to the fraction of water, then take a weighted average.
2. Water + milk fractions must sum to 1.

Question 8: The contents of two vessels containing water and milk in the ratios 3 : 4 and 5 : 4 are mixed in the ratio 1 : 4. The resulting mixture has water and milk in the ratio
(a) 148 : 167
(b) 5 : 4
(c) 3 : 4
(d) 167 : 148
Show Answer & Explanation

Answer: (d) 167 : 148

Explanation:
1. Water fractions: 3/7 and 5/9.
2. Water in mixture = (1 × 3/7 + 4 × 5/9) / 5 = (27 + 140) / 315 = 167 / 315.
3. Milk = 148 / 315, so the ratio is 167 : 148.

Teacher's Note:
1. Use a weighted average of the water fractions.
2. Mixing ratio is by volume.

Question 9: The contents of two vessels containing water and milk in the ratios 2 : 5 and 4 : 7 are mixed in the ratio 1 : 3. The resulting mixture has water and milk in the ratio
(a) 2 : 5
(b) 53 : 101
(c) 4 : 7
(d) 101 : 53
Show Answer & Explanation

Answer: (b) 53 : 101

Explanation:
1. Water fractions: 2/7 and 4/11.
2. Water = (1 × 2/7 + 3 × 4/11) / 4 = (22 + 84) / 308 = 53 / 154.
3. Milk = 101 / 154, so the ratio is 53 : 101.

Teacher's Note:
1. Weighted average again.
2. Check that 53 + 101 = 154.

Question 10: In 50 girls' hostel there is food for 40 days. If 30 more girls join, how long will the provisions last?
(a) 25 days
(b) 15 days
(c) 10 days
(d) 20 days
Show Answer & Explanation

Answer: (a) 25 days

Explanation:
1. Girls × days = constant: 50 × 40 = 80 × x.
2. x = 2000 / 80 = 25.

Teacher's Note:
1. More girls means fewer days (inverse proportion).
2. Total girl-days of food = 2000.

Question 11: A work force of 420 men with a contractor can finish a piece of work in 9 months. How many men must he employ to finish the job in 7 months?
(a) 600
(b) 360
(c) 480
(d) 540
Show Answer & Explanation

Answer: (d) 540

Explanation:
1. Men × months = constant: 420 × 9 = x × 7.
2. x = 3780 / 7 = 540.

Teacher's Note:
1. Less time needs more men.
2. 540 − 420 = 120 extra men.

Question 12: The cost of 32 packets of sugar, each weighing 900 g, is Rs. 84. What is the cost of 27 packets, each weighing 1 kg?
(a) Rs. 70.75
(b) Rs. 78.75
(c) Rs. 80.75
(d) Rs. 76.75
Show Answer & Explanation

Answer: (b) Rs. 78.75

Explanation:
1. Total weight = 32 × 0.9 = 28.8 kg costs Rs. 84, so Rs. 84 / 28.8 per kg.
2. 27 kg costs 84 × 27 / 28.8 = Rs. 78.75.

Teacher's Note:
1. Cost is proportional to total weight.
2. Convert grams to kilograms.

Question 13: If the cost of transporting 160 kg of goods for 125 km is Rs. 60, what will be the cost of transporting 200 kg of goods for 400 km?
(a) Rs. 140
(b) Rs. 440
(c) Rs. 340
(d) Rs. 240
Show Answer & Explanation

Answer: (d) Rs. 240

Explanation:
1. Cost is proportional to weight × distance.
2. Cost = 60 × (200 / 160) × (400 / 125) = 60 × 1.25 × 3.2 = Rs. 240.

Teacher's Note:
1. Two direct proportions multiply.
2. Weight factor 1.25 and distance factor 3.2.

Question 14: The cost of 16 bags of washing powder, each weighing 1.5 kg, is Rs. 672. Find the cost of 18 bags, each weighing 2 kg.
(a) Rs. 1008
(b) Rs. 1004
(c) Rs. 1006
(d) Rs. 1000
Show Answer & Explanation

Answer: (a) Rs. 1008

Explanation:
1. Weight 1 = 24 kg for Rs. 672, so Rs. 28 per kg.
2. Weight 2 = 36 kg, so the cost = 36 × 28 = Rs. 1008.

Teacher's Note:
1. Find the price per kilogram.
2. Total weight = bags × weight per bag.

Question 15: Two numbers are in the ratio 5 : 6. What should be added to each to make the ratio 6 : 7?
(a) 5
(b) 3
(c) 1
(d) 2
Show Answer & Explanation

Answer: (c) 1

Explanation:
1. (5 + x) / (6 + x) = 6 / 7.
2. 35 + 7x = 36 + 6x, so x = 1.

Teacher's Note:
1. Cross-multiply.
2. Check: 6 : 7.

Question 16: In what ratio must a grocer mix two types of tea costing Rs. 35 and Rs. 28 per kg to get a mixture worth Rs. 33 per kg?
(a) 1 : 3
(b) 2 : 5
(c) 3 : 2
(d) 5 : 2
Show Answer & Explanation

Answer: (d) 5 : 2

Explanation:
1. Use alligation: dearer : cheaper = (33 − 28) : (35 − 33) = 5 : 2.

Teacher's Note:
1. Quantities are in the inverse ratio of the differences from the mean price.
2. Check: (5 × 35 + 2 × 28) / 7 = 33.

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Practice MCQs for Class 8 Mathematics Ratio and Proportion

About Ratio and Proportion MCQs for Class 8 Mathematics

Test your conceptual understanding of Ratio and Proportion with these targeted multiple-choice questions. Designed in alignment with the latest CBSE curriculum for Class 8 Mathematics, these problem sets build accuracy and prepare students for objective exams.

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FAQs

Where can I access latest CBSE Class 8 Mathematics Ratio and Proportion MCQs Set 47?

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Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Class 8 material?

Yes, our CBSE Class 8 Mathematics Ratio and Proportion MCQs Set 47 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

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By solving our CBSE Class 8 Mathematics Ratio and Proportion MCQs Set 47, Class 8 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

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Yes, Mathematics MCQs for Class 8 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

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