Download CBSE MCQs for Class 8 Mathematics: Linear Equations in Two Variables
Access targeted multiple-choice questions for Linear Equations in Two Variables designed to align with the latest CBSE academic syllabus for Class 8 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: Linear Equations in Two Variables
View or download the dedicated Linear Equations in Two Variables MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.
Multiple Choice Questions
(a) x = −2y
(b) x = 4y
(c) x = 2y
(d) x = 3y
Show Answer & Explanation
Answer: (c) x = 2y
Explanation:
1. Notebook cost = 2 × pen cost, so x = 2y.
Teacher's Note:
1. Translate the words directly into an equation.
2. Check with y = 5, x = 10.
(a) y = 5x + 8
(b) y = 5x − 3
(c) y = 8x + 5
(d) y = 5x + 3
Show Answer & Explanation
Answer: (d) y = 5x + 3
Explanation:
1. Fare = 8 + 5(x − 1) = 5x + 3.
2. Check: x = 1 gives y = 8.
Teacher's Note:
1. Charge the first km separately, then (x − 1) km at Rs. 5.
2. Test with x = 1 and x = 2 (fare 13).
(a) x − y = 100
(b) x + y = 50
(c) x + y = 100
(d) xy = 100
Show Answer & Explanation
Answer: (c) x + y = 100
Explanation:
1. Total contribution = x + y = 100.
Teacher's Note:
1. Sum of the two contributions is the total.
2. The equation has infinitely many solutions.
(a) 70 and 50
(b) 60 and 40
(c) 50 and 70
(d) 80 and 60
Show Answer & Explanation
Answer: (a) 70 and 50
Explanation:
1. Let A have a and B have b: a + 10 = 2(b − 10) and b + 10 = a − 10.
2. From the second, a = b + 20. Then b + 30 = 2b − 20, so b = 50 and a = 70.
Teacher's Note:
1. Form two equations and substitute.
2. Check: 80 = 2 × 40 and 60 = 60.
(a) 20 coins of 20 paise and 30 coins of 25 paise
(b) 15 coins of 20 paise and 35 coins of 25 paise
(c) 25 coins of 20 paise and 25 coins of 25 paise
(d) 30 coins of 20 paise and 20 coins of 25 paise
Show Answer & Explanation
Answer: (c) 25 coins of 20 paise and 25 coins of 25 paise
Explanation:
1. Let there be x coins of 20 paise: 0.20x + 0.25(50 − x) = 11.25.
2. 12.5 − 0.05x = 11.25, so x = 25 and there are 25 coins of 25 paise.
Teacher's Note:
1. Value of coins = number × denomination.
2. Check: 5 + 6.25 = 11.25.
(a) 65
(b) 83
(c) 47
(d) 74
Show Answer & Explanation
Answer: (d) 74
Explanation:
1. Let the digits be a (tens) and b: 11(a + b) = 121, so a + b = 11, and a − b = 3.
2. a = 7 and b = 4, so the number is 74.
Teacher's Note:
1. Number + its reverse = 11 × (sum of digits).
2. Check: 74 + 47 = 121.
(a) 3/7
(b) 4/9
(c) 5/8
(d) 4/7
Show Answer & Explanation
Answer: (d) 4/7
Explanation:
1. Let the fraction be n/d: n + d = 2d − 3, so n = d − 3.
2. n − 1 = (d − 1) / 2 gives 2d − 8 = d − 1, so d = 7 and n = 4.
Teacher's Note:
1. Form two linear equations in n and d.
2. Check: 4 + 7 = 11 = 14 − 3 and 3 / 6 = 1/2.
(a) Father 34 years, son 12 years
(b) Father 40 years, son 14 years
(c) Father 44 years, son 15 years
(d) Father 36 years, son 13 years
Show Answer & Explanation
Answer: (a) Father 34 years, son 12 years
Explanation:
1. f − 10 = 12(s − 10) and f + 10 = 2(s + 10).
2. Subtract: from the second f = 2s + 10, so 2s + 10 − 10 = 12s − 120, giving s = 12 and f = 34.
Teacher's Note:
1. Write both conditions as equations.
2. Check: 24 = 12 × 2 and 44 = 2 × 22.
(a) 13x − 4x = 6
(b) 260x − 8y = 100
(c) 260x − 8y = 12
(d) 13x − 4y = 60
Show Answer & Explanation
Answer: (d) 13x − 4y = 60
Explanation:
1. 2.60x − 0.80y = 12.
2. Multiply by 5: 13x − 4y = 60.
Teacher's Note:
1. Keep rupees and paise in the same unit.
2. Multiplying by 5 clears the decimals.
(a) x = 2, y = 0
(b) x = 15, y = 6
(c) x = 7, y = 2
(d) x = 12, y = 4
Show Answer & Explanation
Answer: (b) x = 15, y = 6
Explanation:
1. (2, 0): 4 − 0 = 4. (7, 2): 14 − 10 = 4. (12, 4): 24 − 20 = 4.
2. (15, 6): 30 − 30 = 0, not 4.
Teacher's Note:
1. Substitute each pair.
2. The pair that gives a different value is not a solution.
(a) 110
(b) 135
(c) 120
(d) 45
Show Answer & Explanation
Answer: (c) 120
Explanation:
1. Sum of parts = 11, so one part = 15.
2. Numbers: 45 and 120.
Teacher's Note:
1. Divide the sum in the given ratio.
2. Larger number = 8 × 15.
(a) Rs. 900
(b) Rs. 600
(c) Rs. 750
(d) Rs. 1050
Show Answer & Explanation
Answer: (c) Rs. 750
Explanation:
1. 4T + 3C = 2250 and 3T + 4C = 1950.
2. Subtracting: T − C = 300; adding: 7(T + C) = 4200, so T + C = 600.
3. T = 450, C = 150. So 2C + T = 300 + 450 = 750.
Teacher's Note:
1. Adding and subtracting the equations is faster than substitution.
2. Check: 1800 + 450 = 2250.
(a) 24 and 11
(b) 22 and 13
(c) 23 and 12
(d) 25 and 10
Show Answer & Explanation
Answer: (a) 24 and 11
Explanation:
1. Larger = (35 + 13) / 2 = 24 and smaller = (35 − 13) / 2 = 11.
Teacher's Note:
1. Sum and difference give both numbers.
2. Check: 24 + 11 = 35.
(a) 39
(b) 84
(c) 48
(d) 57
Show Answer & Explanation
Answer: (c) 48
Explanation:
1. 11(a + b) = 132, so a + b = 12.
2. Number + 12 = 5 × 12 = 60, so the number is 48 (digits 4 and 8, sum 12).
Teacher's Note:
1. Use number + reverse = 11 × digit sum.
2. Check: 48 + 84 = 132.
Free study material for Mathematics
Linear Equations in Two Variables Objective Questions & Solutions for Class 8 Mathematics
Download Multiple Choice Questions: Linear Equations in Two Variables (Class 8 Mathematics)
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Concept Clarification for Linear Equations in Two Variables
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FAQs
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