CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08

Practice MCQs for Class 8 Mathematics Algebraic Expressions and Factorisation

Review structured MCQ sets for Class 8 Mathematics Algebraic Expressions and Factorisation. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Access Algebraic Expressions and Factorisation Questions and Solutions

View or download the dedicated Algebraic Expressions and Factorisation MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: Subtract \( \left(-2y^2+\frac{1}{2}y-3\right) \) from \( 7y^2-2y+10 \).
(a) \( 9 y^{2} + \frac{5 y}{2} + 13 \)
(b) \( 9 y^{2} - \frac{5 y}{2} + 26 \)
(c) \( 9 y^{2} - \frac{5 y}{2} + 13 \)
(d) \( - 9 y^{2} - \frac{5 y}{2} + 13 \)
Show Answer & Explanation

Answer: (c) \( 9 y^{2} - \frac{5 y}{2} + 13 \)

Explanation:
1. Required = (7y^2 - 2y + 10) - (-2y^2 + y/2 - 3).
2. = 7y^2 + 2y^2 - 2y - y/2 + 10 + 3 = 9y^2 - (5/2)y + 13.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 2: Add: \( 2,\ \frac{2y}{3}-\frac{5y^2}{3}+\frac{5y^3}{2},\ -\frac{4}{3}+\frac{2y^2}{3}-\frac{y}{2},\ \frac{5y^3}{3}+3y^2+3y+\frac{6}{5} \).
(a) \( \frac{25 y^{3}}{6} + 2 y^{2} - \frac{19 y}{6} + \frac{28}{15} \)
(b) \( - \frac{25 y^{3}}{6} + 2 y^{2} + \frac{19 y}{6} + \frac{28}{15} \)
(c) \( \frac{25 y^{3}}{6} + 2 y^{2} + \frac{19 y}{6} + \frac{28}{15} \)
(d) \( \frac{25 y^{3}}{6} + 2 y^{2} + \frac{19 y}{6} + \frac{56}{15} \)
Show Answer & Explanation

Answer: (c) \( \frac{25 y^{3}}{6} + 2 y^{2} + \frac{19 y}{6} + \frac{28}{15} \)

Explanation:
1. Constants: 2 - 4/3 + 6/5 = 28/15. y: 2/3 - 1/2 + 3 = 19/6.
2. y^2: -5/3 + 2/3 + 3 = 2. y^3: 5/2 + 5/3 = 25/6.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 3: Subtract \( \frac{3}{2}x^2y+\frac{4}{5}y-\frac{1}{3}x^2yz \) from \( \frac{12}{5}x^2yz-\frac{3}{5}xyz+\frac{2}{3}x^2y \).
(a) \( \frac{41 x^{2} y z}{15} - \frac{5 x^{2} y}{6} + \frac{3 x y z}{5} - \frac{4 y}{5} \)
(b) \( \frac{41 x^{2} y z}{15} - \frac{5 x^{2} y}{6} - \frac{3 x y z}{5} - \frac{8 y}{5} \)
(c) \( \frac{41 x^{2} y z}{15} - \frac{5 x^{2} y}{6} - \frac{3 x y z}{5} - \frac{4 y}{5} \)
(d) \( - \frac{41 x^{2} y z}{15} - \frac{5 x^{2} y}{6} - \frac{3 x y z}{5} - \frac{4 y}{5} \)
Show Answer & Explanation

Answer: (c) \( \frac{41 x^{2} y z}{15} - \frac{5 x^{2} y}{6} - \frac{3 x y z}{5} - \frac{4 y}{5} \)

Explanation:
1. Subtract term by term: x^2yz: 12/5 + 1/3 = 41/15; x^2y: 2/3 - 3/2 = -5/6.
2. Remaining terms: -3/5 xyz and -4/5 y.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 4: A rectangular box has length m^2 n, breadth n^2 p and height p^2 m. Its volume is:
(a) \( m^3n^3p^3 \)
(b) \( m^3n^2p^3 \)
(c) \( m^2n^2p^2 \)
(d) \( m^4n^3p^3 \)
Show Answer & Explanation

Answer: (a) \( m^3n^3p^3 \)

Explanation:
1. Multiply: m^2 n x n^2 p x p^2 m = m^(2+1) n^(1+2) p^(1+2).
2. = m^3 n^3 p^3.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 5: A rectangular box has length 2q, breadth 4q^2 and height 8q^3. Its volume is:
(a) \( 16q^6 \)
(b) \( 14q^6 \)
(c) \( 64q^6 \)
(d) \( 64q^5 \)
Show Answer & Explanation

Answer: (c) \( 64q^6 \)

Explanation:
1. 2 x 4 x 8 = 64 and q x q^2 x q^3 = q^6.
2. Volume = 64q^6.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 6: Find the product \( (-2x^2)(7a^2x^7)(6a^5x^5) \).
(a) \( - 84 a^{7} x^{14} \)
(b) \( - 168 a^{7} x^{14} \)
(c) \( - 42 a^{7} x^{14} \)
(d) \( 84 a^{7} x^{14} \)
Show Answer & Explanation

Answer: (a) \( - 84 a^{7} x^{14} \)

Explanation:
1. Coefficients: -2 x 7 x 6 = -84.
2. Powers: x^(2+7+5) = x^14 and a^(2+5) = a^7.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 7: Find the product \( (4s^2t)(3s^3t^3)(2st^4)(-2) \).
(a) \( - 24 s^{6} t^{8} \)
(b) \( 48 s^{6} t^{8} \)
(c) \( - 48 s^{6} t^{8} \)
(d) \( - 96 s^{6} t^{8} \)
Show Answer & Explanation

Answer: (c) \( - 48 s^{6} t^{8} \)

Explanation:
1. Coefficients: 4 x 3 x 2 x (-2) = -48.
2. Powers: s^(2+3+1) = s^6 and t^(1+3+4) = t^8.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 8: Multiply \( -\frac{4}{3}xy^3 \) by \( \frac{6}{7}x^2y \).
(a) \( \frac{8 x^{3} y^{4}}{7} \)
(b) \( - \frac{8 x^{3} y^{4}}{7} \)
(c) \( - \frac{4 x^{3} y^{4}}{7} \)
(d) \( - \frac{16 x^{3} y^{4}}{7} \)
Show Answer & Explanation

Answer: (b) \( - \frac{8 x^{3} y^{4}}{7} \)

Explanation:
1. Coefficients: -4/3 x 6/7 = -8/7.
2. Powers: x^3 and y^4.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 9: Find the product of \( -5x^2y,\ -\frac{2}{3}xy^2z,\ \frac{8}{15}xyz^2,\ -\frac{1}{4} \).
(a) \( \frac{4 x^{4} y^{4} z^{3}}{9} \)
(b) \( - \frac{4 x^{4} y^{4} z^{3}}{9} \)
(c) \( - \frac{8 x^{4} y^{4} z^{3}}{9} \)
(d) \( - \frac{2 x^{4} y^{4} z^{3}}{9} \)
Show Answer & Explanation

Answer: (b) \( - \frac{4 x^{4} y^{4} z^{3}}{9} \)

Explanation:
1. Coefficients: (-5)(-2/3)(8/15)(-1/4) = -4/9.
2. Powers: x^4 y^4 z^4.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 10: Find the product of \( \frac{7}{2}s^2t \) and \( (s+t) \).
(a) \( 7 s^{3} t + \frac{7 s^{2} t^{2}}{2} \)
(b) \( - \frac{7 s^{3} t}{2} - \frac{7 s^{2} t^{2}}{2} \)
(c) \( \frac{7 s^{3} t}{2} - \frac{7 s^{2} t^{2}}{2} \)
(d) \( \frac{7 s^{3} t}{2} + \frac{7 s^{2} t^{2}}{2} \)
Show Answer & Explanation

Answer: (d) \( \frac{7 s^{3} t}{2} + \frac{7 s^{2} t^{2}}{2} \)

Explanation:
1. Distribute: (7/2)s^2t x s + (7/2)s^2t x t.
2. = (7/2)s^3t + (7/2)s^2t^2.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 11: Find the product \( 100x\times(0.01x^4-0.01x^2) \).
(a) \( - x^{5} + x^{3} \)
(b) \( 2 x^{5} - x^{3} \)
(c) \( x^{5} + x^{3} \)
(d) \( x^{5} - x^{3} \)
Show Answer & Explanation

Answer: (d) \( x^{5} - x^{3} \)

Explanation:
1. 100 x 0.01 = 1.
2. Product = x^5 - x^3.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 12: Find the product \( 121.5ab\times\left(ac+\frac{b}{10}\right) \).
(a) \( - \frac{243 a^{2} b c}{2} + \frac{243 a b^{2}}{20} \)
(b) \( - \frac{243 a^{2} b c}{2} - \frac{243 a b^{2}}{20} \)
(c) \( \frac{243 a^{2} b c}{2} + \frac{243 a b^{2}}{20} \)
(d) \( \frac{243 a^{2} b c}{2} + \frac{243 a b^{2}}{10} \)
Show Answer & Explanation

Answer: (c) \( \frac{243 a^{2} b c}{2} + \frac{243 a b^{2}}{20} \)

Explanation:
1. 121.5ab x ac = 121.5a^2bc.
2. 121.5ab x b/10 = 12.15ab^2.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 13: Add \( 5m(3-m) \) and \( 6m^2-13m \).
(a) \( 2 m^{2} + 2 m \)
(b) \( m^{2} - 2 m \)
(c) \( - m^{2} - 2 m \)
(d) \( m^{2} + 2 m \)
Show Answer & Explanation

Answer: (d) \( m^{2} + 2 m \)

Explanation:
1. 5m(3 - m) = 15m - 5m^2.
2. Sum = 15m - 5m^2 + 6m^2 - 13m = m^2 + 2m.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 14: Add \( 4y(3y^2+5y-7) \) and \( 2(y^3-4y^2+5) \).
(a) \( 14 y^{3} + 12 y^{2} - 28 y + 20 \)
(b) \( 14 y^{3} + 12 y^{2} - 28 y + 10 \)
(c) \( 14 y^{3} - 12 y^{2} - 28 y + 10 \)
(d) \( - 14 y^{3} + 12 y^{2} - 28 y + 10 \)
Show Answer & Explanation

Answer: (b) \( 14 y^{3} + 12 y^{2} - 28 y + 10 \)

Explanation:
1. 4y(3y^2 + 5y - 7) = 12y^3 + 20y^2 - 28y.
2. 2(y^3 - 4y^2 + 5) = 2y^3 - 8y^2 + 10.
3. Sum = 14y^3 + 12y^2 - 28y + 10.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 15: Subtract \( 3a(a+b+c)-2b(a+b+c) \) from \( 4c(-a+b+c) \).
(a) \( - 3 a^{2} + a b - 7 a c + 2 b^{2} + 6 b c + 4 c^{2} \)
(b) \( - 6 a^{2} - a b - 7 a c + 2 b^{2} + 6 b c + 4 c^{2} \)
(c) \( - 3 a^{2} - a b - 7 a c + 2 b^{2} - 6 b c + 4 c^{2} \)
(d) \( - 3 a^{2} - a b - 7 a c + 2 b^{2} + 6 b c + 4 c^{2} \)
Show Answer & Explanation

Answer: (d) \( - 3 a^{2} - a b - 7 a c + 2 b^{2} + 6 b c + 4 c^{2} \)

Explanation:
1. 4c(-a + b + c) = -4ac + 4bc + 4c^2.
2. 3a(a + b + c) - 2b(a + b + c) = 3a^2 + ab + 3ac - 2b^2 - 2bc.
3. Difference = -7ac + 6bc + 4c^2 - 3a^2 - ab + 2b^2.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 16: Multiply \( \left(\frac{1}{5}x-\frac{1}{4}y\right) \) and \( (5x^2-4y^2) \).
(a) \( x^{3} + \frac{5 x^{2} y}{4} - \frac{4 x y^{2}}{5} + y^{3} \)
(b) \( x^{3} - \frac{5 x^{2} y}{4} + \frac{4 x y^{2}}{5} + y^{3} \)
(c) \( 2 x^{3} - \frac{5 x^{2} y}{4} - \frac{4 x y^{2}}{5} + y^{3} \)
(d) \( x^{3} - \frac{5 x^{2} y}{4} - \frac{4 x y^{2}}{5} + y^{3} \)
Show Answer & Explanation

Answer: (d) \( x^{3} - \frac{5 x^{2} y}{4} - \frac{4 x y^{2}}{5} + y^{3} \)

Explanation:
1. Multiply each term of the first bracket by each term of the second.
2. = x^3 - (4/5)xy^2 - (5/4)x^2y + y^3.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 17: Multiply \( (3x^2+y^2) \) by \( (x^2+2y^2) \).
(a) \( 3 x^{4} + 7 x^{2} y^{2} + 2 y^{4} \)
(b) \( 3 x^{4} + 7 x^{2} y^{2} + 4 y^{4} \)
(c) \( - 3 x^{4} + 7 x^{2} y^{2} + 2 y^{4} \)
(d) \( 3 x^{4} - 7 x^{2} y^{2} + 2 y^{4} \)
Show Answer & Explanation

Answer: (a) \( 3 x^{4} + 7 x^{2} y^{2} + 2 y^{4} \)

Explanation:
1. = 3x^4 + 6x^2y^2 + x^2y^2 + 2y^4.
2. = 3x^4 + 7x^2y^2 + 2y^4.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 18: Find the product of \( \left(y+\frac{2}{7}y^2\right) \) and \( (7y-y^2) \).
(a) \( - \frac{2 y^{4}}{7} + 2 y^{3} + 7 y^{2} \)
(b) \( \frac{2 y^{4}}{7} + y^{3} + 7 y^{2} \)
(c) \( - \frac{2 y^{4}}{7} + y^{3} - 7 y^{2} \)
(d) \( - \frac{2 y^{4}}{7} + y^{3} + 7 y^{2} \)
Show Answer & Explanation

Answer: (d) \( - \frac{2 y^{4}}{7} + y^{3} + 7 y^{2} \)

Explanation:
1. = 7y^2 - y^3 + 2y^3 - (2/7)y^4.
2. = 7y^2 + y^3 - (2/7)y^4.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Question 19: Simplify \( \frac{1}{3}(6x^2+15y^2)(6x^2-15y^2) \).
(a) \( - 12 x^{4} - 75 y^{4} \)
(b) \( 12 x^{4} - 75 y^{4} \)
(c) \( - 12 x^{4} + 75 y^{4} \)
(d) \( 12 x^{4} - 150 y^{4} \)
Show Answer & Explanation

Answer: (b) \( 12 x^{4} - 75 y^{4} \)

Explanation:
1. (a + b)(a - b) = a^2 - b^2 gives 36x^4 - 225y^4.
2. Multiply by 1/3: 12x^4 - 75y^4.

Teacher's Note:
1. Multiply or add term by term, then combine like terms.
2. Check with a simple value of the variables when in doubt.

Algebraic Expressions and Factorisation Objective Questions & Solutions for Class 8 Mathematics

Class 8 Mathematics Algebraic Expressions and Factorisation Objective Test Questions

Review structured objective questions for Class 8 Mathematics Algebraic Expressions and Factorisation. Built according to official CBSE guidelines, these MCQ sets support daily revision and core concept reinforcement.

NCERT-Aligned Objective Questions and Solutions

Cross-reference your completed choices with comprehensive NCERT solutions for Class 8 Mathematics to ensure absolute clarity across all sub-topics in this chapter.

Next Steps in Your Exam Preparation

Explore our broader library of printable assignments, chapter notes, and mock tests designed to support continuous revision and secure higher marks in CBSE assessments.

FAQs

Where can I access latest CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08?

You can get most exhaustive CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08 for free on StudiesToday.com. These MCQs for Class 8 Mathematics are updated for the 2026-27 academic session as per CBSE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Class 8 material?

Yes, our CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in Class 8 exams?

By solving our CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08, Class 8 students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08?

Yes, Mathematics MCQs for Class 8 have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused CBSE exams.

Can I practice these Mathematics Class 8 MCQs online?

Yes, you can also access online interactive tests for CBSE Class 8 Mathematics Algebraic Expressions and Factorisation MCQs Set 08 on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.