CBSE Class 10 Physics Motion Notes Set 11

Physics Concept Notes for Class 10: Motion

Review targeted revision notes for Class 10 Physics with the CBSE Class 10 Physics Motion Notes Set 11. Built according to official educational guidelines for the 2026-27 academic year, these downloadable summaries for Motion support daily study and last-minute exam readiness.

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Motion, Rest and Types of Motion

An object is in motion when its position changes with time relative to a chosen reference body, and at rest when it does not. Both states are relative: passengers in a moving bus are at rest with respect to one another but in motion with respect to a roadside pole.

1. Rectilinear motion: along a straight line (one dimension).
2. Rotational motion: turning about a fixed axis, such as a fan or the spinning Earth.
3. Two-dimensional motion: in a plane, such as circular or projectile motion.
4. Three-dimensional motion: in space, such as a flying bird.

Distance and Displacement

FeatureDistanceDisplacement
MeaningLength of the actual path travelledShortest straight-line change in position, from start to end
TypeScalarVector
SignAlways positive, never decreasesCan be positive, negative or zero
Depends onThe pathOnly the start and end points
InstrumentOdometer-

Distance is always greater than or equal to the magnitude of displacement. They are equal only for motion along a straight line without reversing. A complete round trip gives zero displacement.

Speed and Velocity

Speed = distance / time (scalar, never negative). Velocity = displacement / time (vector). In SI both are measured in m/s, and 1 km/h = 5/18 m/s.

1. Uniform speed: equal distances in equal intervals of time.
2. Average speed = total distance / total time.
3. Average velocity = total displacement / total time.
4. Average speed is always at least the magnitude of average velocity.
5. A speedometer shows instantaneous speed.

For a journey in a straight line, with distances x1, x2, ... covered at speeds v1, v2, ...: \( v_{avg} = \dfrac{x_1+x_2+\cdots}{x_1/v_1 + x_2/v_2+\cdots} \). For two equal distances: \( v_{avg} = \dfrac{2v_1v_2}{v_1+v_2} \). For two equal times: \( v_{avg} = \dfrac{v_1+v_2}{2} \).

Acceleration

Acceleration is the rate of change of velocity: \( a = \dfrac{v-u}{t} \). Its SI unit is m/s\( ^2 \) (CGS: cm/s\( ^2 \)). It is a vector. When speed decreases, acceleration points opposite to velocity and is called retardation. Motion with zero acceleration is uniform motion.

Equations of Uniformly Accelerated Motion

1. \( v = u + at \)
2. \( s = ut + \tfrac12 at^2 \)
3. \( v^2 = u^2 + 2as \)
4. Distance in the nth second: \( s_n = u + \dfrac{a}{2}(2n-1) \)

Here u is initial velocity, v final velocity, a acceleration, t time and s displacement. For a body starting from rest, distances in successive equal intervals are in the ratio 1 : 3 : 5 : 7 and total distances in 1 s, 2 s, 3 s are in the ratio 1 : 4 : 9.

Motion Under Gravity

Free fall is motion under gravity alone, with acceleration g = 9.8 m/s\( ^2 \) downward (often taken as 10). Taking upward as positive, a = -g.

1. Dropped from height h: time of fall \( t = \sqrt{2h/g} \), speed on landing \( v = \sqrt{2gh} \).
2. Thrown upward with speed u: maximum height \( H = u^2/2g \), time to top = u/g, total time of flight = 2u/g.
3. At the highest point velocity is zero but acceleration is still g.
4. Time of fall does not depend on mass.

Graphs of Motion

1. Slope of a distance-time (or displacement-time) graph gives speed (or velocity); a straight line means uniform motion.
2. A horizontal line on a velocity-time graph means constant velocity and zero acceleration.
3. Slope of a velocity-time graph gives acceleration.
4. Area under a velocity-time graph gives displacement; area under an acceleration-time graph gives change in velocity.

Worked Examples

Example 1. A car moving at 20 m/s brakes with a retardation of 5 m/s\( ^2 \). Find the stopping distance. Solution: \( s = u^2/2a = 400/10 = 40 \) m.

Example 2. A stone is dropped from a 45 m high tower. Find the time to land (g = 10 m/s\( ^2 \)). Solution: \( t = \sqrt{2 \times 45/10} = 3 \) s.

Example 3. A body goes 60 km at 30 km/h and returns 60 km at 60 km/h. Average speed = 120 / (2 + 1) = 40 km/h, and average velocity is zero.

Revision Notes and Key Concepts for Class 10 Physics Motion

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FAQs

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Are these Physics notes for Class 10 based on the 2026 board exam pattern?

Yes, our CBSE Class 10 Physics Motion Notes Set 11 include 50% competency-based questions with focus on core logic, keyword definitions, and the practical application of Physics principles which is important for getting more marks in 2026 CBSE exams.

Do these Class 10 notes cover all topic-wise concepts for Physics?

Yes, our CBSE Class 10 Physics Motion Notes Set 11 provide a detailed, topic wise breakdown of the chapter. Fundamental definitions, complex numerical formulas and all topics of CBSE syllabus in Class 10 is covered.

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