CBSE Class 10 Mathematics Time, Speed and Distance MCQs Set 26

Practice MCQs for Class 10 Mathematics Time, Speed and Distance

Access targeted multiple-choice questions for Time, Speed and Distance designed to align with the latest CBSE academic syllabus for Class 10 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Multiple Choice Questions

Question 1: Ravi rows a distance of 1 km down the stream in 10 minutes and takes 30 minutes to cover the same distance up stream. The speed of the stream is
(a) 5 km per hour
(b) 3 km per hour
(c) 2 km per hour
(d) 4 km per hour
Show Answer & Explanation

Answer: (c) 2 km per hour

Explanation:
1. Downstream speed = 1 km/(1/6 hr) = 6 km/hr and upstream speed = 1 km/(1/2 hr) = 2 km/hr
2. Speed of stream = (6 − 2)/2 = 2 km/hr.

Teacher's Note:
1. Downstream speed = b + s and upstream speed = b − s.
2. Speed in still water = half the sum of the two speeds.

Question 2: It takes an hour for a saree to dry in the sun. 25 such sarees will dry in
(a) 50 hrs
(b) 20 hrs
(c) 1 hr
(d) 625 hrs
Show Answer & Explanation

Answer: (c) 1 hr

Explanation:
1. The sarees dry at the same time, spread out in the sun
2. So 25 sarees also take 1 hr.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 3: A car is 25 km ahead of a scooter. The car is travelling at 40 km/hr and the scooter at 50 km/hr. The scooter will overtake the car after
(a) 1 1/2 hrs
(b) 2 1/2 hrs
(c) 3 1/2 hrs
(d) 3 hrs
Show Answer & Explanation

Answer: (b) 2 1/2 hrs

Explanation:
1. Relative speed = 50 − 40 = 10 km/hr
2. Time = 25/10 = 2 1/2 hrs.

Teacher's Note:
1. Use relative speed: add the speeds for opposite directions and subtract for the same direction.
2. Time = distance/relative speed.

Question 4: Javed walks at the rate of 3 km/hr for 2 hours and then at the rate of 2 km/hr for 3 hours. His average speed is ... km/hr.
(a) 4
(b) 2.4
(c) 2.5
(d) 5
Show Answer & Explanation

Answer: (b) 2.4

Explanation:
1. Total distance = 6 + 6 = 12 km in 5 hours
2. Average speed = 12/5 = 2.4 km/hr.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 5: A train takes 40 minutes for a journey if it runs at 0.05 km/sec. The rate at which the train must run to reduce the time to 28 minutes will be nearly
(a) 257 km/hr
(b) 212 km/hr
(c) 188 km/hr
(d) 88 km/hr
Show Answer & Explanation

Answer: (a) 257 km/hr

Explanation:
1. Speed = 0.05 × 3600 = 180 km/hr, so distance = 180 × 40/60 = 120 km
2. New speed = 120/(28/60) = 257 km/hr.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 6: A man takes 6 hours 15 minutes to walk a certain distance and ride back. He could walk both ways in 7 hours 45 minutes. He can ride both ways in
(a) 4 hrs 30 min
(b) 6 hrs 30 min
(c) 4 hrs 45 min
(d) None of the above
Show Answer & Explanation

Answer: (c) 4 hrs 45 min

Explanation:
1. Walk + ride = 6.25 hrs, so 2 × walk + 2 × ride = 12.5
2. Walk both ways = 7.75 hrs, so ride both ways = 12.5 − 7.75 = 4.75 hrs = 4 hrs 45 min.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 7: The speed of a boat in still water is 12 km/h. If it takes 1 hour to go upstream 6 km, in what time will it return the same distance downstream?
(a) 20 min
(b) 30 min
(c) 5 min
(d) 10 min
Show Answer & Explanation

Answer: (a) 20 min

Explanation:
1. Upstream speed = 6 km/h, so the stream = 12 − 6 = 6 km/h
2. Downstream speed = 18 km/h, so time = 6/18 hr = 20 min.

Teacher's Note:
1. Downstream speed = b + s and upstream speed = b − s.
2. Speed in still water = half the sum of the two speeds.

Question 8: Two persons 27 km apart, starting at the same time, are together in 9 hrs if they walk in the same direction, but if they walk in opposite directions, they meet in 3 hrs. What are their rates of walking (in km/h)?
(a) 5, 2
(b) 4, 3
(c) 6, 3
(d) 8, 7
Show Answer & Explanation

Answer: (c) 6, 3

Explanation:
1. x − y = 27/9 = 3 and x + y = 27/3 = 9
2. x = 6 and y = 3.

Teacher's Note:
1. Use relative speed: add the speeds for opposite directions and subtract for the same direction.
2. Time = distance/relative speed.

Question 9: A train starts from station X at the rate of 60 km/h and reaches station Y in 45 minutes. If the speed is reduced by 6 km/h, how much more time will the train take to return from station Y to station X?
(a) 5 min
(b) 7 1/2 min
(c) 6 min
(d) 4 min
Show Answer & Explanation

Answer: (a) 5 min

Explanation:
1. Distance = 60 × 3/4 = 45 km
2. New speed = 54 km/h, so time = 45/54 hr = 50 min
3. Extra time = 5 min.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 10: In a 500 m race, the ratio of the speeds of two runners Vinay and Shyam is 3 : 4. Vinay has a start of 140 m. By how many metres does the faster runner win the race?
(a) 15 m
(b) 20 m
(c) 25 m
(d) 30 m
Show Answer & Explanation

Answer: (b) 20 m

Explanation:
1. Vinay runs 500 − 140 = 360 m while Shyam runs 500 m
2. In the time Vinay covers 360 m, Shyam covers 360 × 4/3 = 480 m
3. Shyam wins by 500 − 480 = 20 m.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 11: Salil walks a certain distance at 2.5 km/h for 2 hours and then runs 10 km at a certain speed for 3 hours. Salil's average speed for the whole journey is
(a) 2 km/h
(b) 3 km/h
(c) 5 km/h
(d) 6 km/h
Show Answer & Explanation

Answer: (b) 3 km/h

Explanation:
1. Distance = 5 + 10 = 15 km in 5 hours
2. Average speed = 3 km/h.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 12: A policeman travelling at 75 km/h chases a thief 1500 m away from him and travelling at 60 km/h. What is the time taken by the policeman to catch the thief?
(a) 6 min
(b) 16 min
(c) 12 min
(d) 8 min
Show Answer & Explanation

Answer: (a) 6 min

Explanation:
1. Relative speed = 15 km/h and the gap = 1.5 km
2. Time = 1.5/15 hr = 6 min.

Teacher's Note:
1. Use relative speed: add the speeds for opposite directions and subtract for the same direction.
2. Time = distance/relative speed.

Question 13: The ratio of the speeds of Amar and Akbar is 8 : 5. If Akbar takes 15 minutes more than Amar to cover a certain distance, find the time taken by Akbar to cover the same distance.
(a) 25 minutes
(b) 15 minutes
(c) 20 minutes
(d) 40 minutes
Show Answer & Explanation

Answer: (d) 40 minutes

Explanation:
1. Time is inversely proportional to speed, so Amar : Akbar = 5 : 8
2. 3 parts = 15 min, so 1 part = 5 min and Akbar takes 8 × 5 = 40 min.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 14: Two persons A and B move towards each other from P and Q respectively. They meet 50 km away from Q. If the ratio of the speeds of A and B is 4 : 1, find the distance between P and Q.
(a) 200 km
(b) 175 km
(c) 125 km
(d) 250 km
Show Answer & Explanation

Answer: (d) 250 km

Explanation:
1. Distances covered are in the ratio of speeds, 4 : 1
2. B covers 50 km = 1 part, so the total distance = 5 × 50 = 250 km.

Teacher's Note:
1. Use relative speed: add the speeds for opposite directions and subtract for the same direction.
2. Time = distance/relative speed.

Question 15: A person takes 1 h more than his friend to reach a party. The distance travelled by the person is 20 km more than that of his friend. The speed of the person is 16 km/h while that of his friend is 15 km/h. Find the distance travelled by his friend.
(a) 60 km
(b) 40 km
(c) 80 km
(d) 30 km
Show Answer & Explanation

Answer: (a) 60 km

Explanation:
1. Let the friend's distance be d: (d + 20)/16 = d/15 + 1
2. 15d + 300 = 16d + 240, so d = 60 km.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 16: The average of the speed of the boat upstream and the speed of the boat downstream is equal to the
(a) speed of the boat in still water
(b) speed of the stream
(c) speed of the boat upstream
(d) speed of the boat downstream
Show Answer & Explanation

Answer: (a) speed of the boat in still water

Explanation:
1. Average = ((b + s) + (b − s))/2 = b, the speed in still water.

Teacher's Note:
1. Downstream speed = b + s and upstream speed = b − s.
2. Speed in still water = half the sum of the two speeds.

Question 17: A man can row 20 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the speed of the stream.
(a) 8 kmph
(b) 10 kmph
(c) 12 kmph
(d) 15 kmph
Show Answer & Explanation

Answer: (b) 10 kmph

Explanation:
1. 20 + s = 3(20 − s)
2. 4s = 40, so s = 10 kmph.

Teacher's Note:
1. Downstream speed = b + s and upstream speed = b − s.
2. Speed in still water = half the sum of the two speeds.

Question 18: Two trains are travelling in opposite directions with speeds 25 m/sec and 30 m/sec respectively. If the length of one train is 300 m and that of the other train is 250 m, find the time taken by the trains to cross each other.
(a) 8 sec.
(b) 10 sec.
(c) 12 sec.
(d) 14 sec.
Show Answer & Explanation

Answer: (b) 10 sec.

Explanation:
1. Relative speed = 55 m/s and the total length = 550 m
2. Time = 10 sec.

Teacher's Note:
1. Convert all speeds to the same units; 1 km/h = 5/18 m/s.
2. When two trains cross, add their lengths for the distance to be covered.

Question 19: Ashok ran around a square plot ABCD once in the following manner. He ran the distances AB and BC at 4 kmph and 6 kmph respectively. He ran the distances CD and DA at 4 kmph and 6 kmph respectively. His average speed from A to C was 4.8 kmph. Find his average speed for running around the square plot once (in kmph).
(a) 3.6
(b) 4
(c) 4.8
(d) 5.4
Show Answer & Explanation

Answer: (c) 4.8

Explanation:
1. For a side a: time = a/4 + a/6 = 5a/12 for two sides
2. Average speed over any two consecutive sides = 2a/(5a/12) = 4.8 kmph
3. The same holds for the other two sides, so the speed around the plot is 4.8 kmph.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 20: In a 100 m race, A beats B by 20 m or 5 seconds. Find the speed of A.
(a) 2 m/sec
(b) 4 m/sec
(c) 5 m/sec
(d) 8 m/sec
Show Answer & Explanation

Answer: (c) 5 m/sec

Explanation:
1. B covers the last 20 m in 5 s, so B's speed = 4 m/s
2. When A runs 100 m, B runs 80 m, so A's speed = 4 × 100/80 = 5 m/s.

Teacher's Note:
1. Use distance = speed × time carefully with consistent units.
2. Average speed = total distance/total time, not the average of the speeds.

Question 21: Ravi travels at the speed of 20 kmph and after 5 hours, Pradeep starts from the same point and travels in the direction as Ravi at 25 kmph. What distance does Pradeep travel before he catches up with Ravi?
(a) 200 km
(b) 300 km
(c) 500 km
(d) 150 km
Show Answer & Explanation

Answer: (c) 500 km

Explanation:
1. Lead = 5 × 20 = 100 km and relative speed = 5 km/h, so time = 20 hrs
2. Distance = 25 × 20 = 500 km.

Teacher's Note:
1. Use relative speed: add the speeds for opposite directions and subtract for the same direction.
2. Time = distance/relative speed.

Question 22: A boat covers a round trip in a river in a certain time. If its speed in still water is doubled and the speed of the stream tripled, it would take the same time for the round trip. Find the ratio of the speed of boat in still water to the speed of the stream.
(a) 3√2 : √3
(b) 2√2 : √3
(c) 4√2 : √7
(d) √7 : √2
Show Answer & Explanation

Answer: (d) √7 : √2

Explanation:
1. Time = 2bd/(b² − s²); with 2b and 3s: 4bd/(4b² − 9s²)
2. Equal times: 2(4b² − 9s²) = 4(b² − s²), so 4b² = 14s²
3. b²/s² = 7/2, so b : s = √7 : √2.

Teacher's Note:
1. Downstream speed = b + s and upstream speed = b − s.
2. Speed in still water = half the sum of the two speeds.

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FAQs

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