CBSE Class 10 Mathematics Percentage MCQs Set 22

Practice MCQs for Class 10 Mathematics Percentage

Access targeted multiple-choice questions for Percentage designed to align with the latest CBSE academic syllabus for Class 10 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Multiple Choice Questions

Question 1: A salesman is allowed 5 1/2% discount on the total sales made by him plus a bonus of 1/2% on the sales over Rs. 10,000. If his total earnings are Rs. 1990, then his total sales (in Rs.) were
(a) 30,000
(b) 32,000
(c) 34,000
(d) 35,000
Show Answer & Explanation

Answer: (c) 34,000

Explanation:
1. 0.055S + 0.005(S − 10000) = 1990
2. 0.06S − 50 = 1990, so S = 34000.

Teacher's Note:
1. Write the commission and the bonus separately.
2. The bonus applies only to the amount above Rs. 10,000.

Question 2: What percent decrease in salaries would exactly cancel out the 20 percent increase?
(a) 16 2/3
(b) 18
(c) 20
(d) 33 1/3
Show Answer & Explanation

Answer: (a) 16 2/3

Explanation:
1. Salary 100 becomes 120
2. Decrease needed = 20/120 × 100 = 16 2/3%.

Teacher's Note:
1. The decrease is calculated on the increased salary.
2. The fall is smaller than the rise.

Question 3: If inflation increases at a rate of 8% p.a., what will a Rs. 20 article cost at the end of two years?
(a) Between Rs. 20 and Rs. 21
(b) Between Rs. 21 and Rs. 22
(c) Between Rs. 22 and Rs. 23
(d) Between Rs. 23 and Rs. 24
Show Answer & Explanation

Answer: (d) Between Rs. 23 and Rs. 24

Explanation:
1. Cost = 20 × 1.08² = 20 × 1.1664 = Rs. 23.328
2. This lies between Rs. 23 and Rs. 24.

Teacher's Note:
1. Compound the 8% increase for two years.
2. Do not add the rates.

Question 4: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was
(a) Rs. 10,000
(b) Rs. 11,372
(c) Rs. 12,000
(d) Rs. 12,500
Show Answer & Explanation

Answer: (c) Rs. 12,000

Explanation:
1. P × 0.9³ = 8748, so P × 0.729 = 8748
2. P = 12000.

Teacher's Note:
1. Depreciation multiplies the value by 0.9 each year.
2. Divide to find the original price.

Question 5: The present population of a country is estimated to be 10 crores and is expected to increase to 13.31 crores during the next three years. The uniform rate of growth is
(a) 8%
(b) 10%
(c) 12.7%
(d) 15%
Show Answer & Explanation

Answer: (b) 10%

Explanation:
1. (1 + r)³ = 13.31/10 = 1.331 = 1.1³
2. So r = 10%.

Teacher's Note:
1. Recognise 1.331 as 1.1 cubed.
2. Use compound growth.

Question 6: Two numbers are less than a third number by 30% and 37% respectively. How much percent is the second number less than the first?
(a) 3%
(b) 4%
(c) 7%
(d) 10%
Show Answer & Explanation

Answer: (d) 10%

Explanation:
1. First = 0.70C and second = 0.63C
2. Required = (0.70 − 0.63)/0.70 × 100 = 10%.

Teacher's Note:
1. Express both numbers in terms of the third.
2. The base for the comparison is the first number.

Question 7: Two candidates contested for a post in an election. 70 votes were declared as invalid. The victorious candidate secured 55% votes and won the election by 90 votes. The total number of votes polled is
(a) 475
(b) 565
(c) 970
(d) 1070
Show Answer & Explanation

Answer: (c) 970

Explanation:
1. Valid votes: 55% − 45% = 10% = 90, so valid votes = 900
2. Total polled = 900 + 70 = 970.

Teacher's Note:
1. The winning margin is the difference of the two percentages.
2. Add the invalid votes at the end.

Question 8: In an examination, 450 candidates were boys and 550 were girls. If 32% of the boys and 38% of the girls passed the examination, the percentage of failed candidates is
(a) 35.3%
(b) 62%
(c) 64.7%
(d) 68%
Show Answer & Explanation

Answer: (c) 64.7%

Explanation:
1. Passed = 0.32 × 450 + 0.38 × 550 = 144 + 209 = 353
2. Failed = 1000 − 353 = 647, i.e. 64.7%.

Teacher's Note:
1. Count the passes separately for boys and girls.
2. Failures = total − passes.

Question 9: If 18% of x is the same as 90% of y, then 60% of x is the same as
(a) 120% of y
(b) 20% of y
(c) 30% of y
(d) None of the above
Show Answer & Explanation

Answer: (d) None of the above

Explanation:
1. 0.18x = 0.9y, so x = 5y
2. 60% of x = 3y = 300% of y, which is not listed.

Teacher's Note:
1. Find x in terms of y.
2. Then evaluate 60% of x.

Question 10: In an examination, a candidate must secure 45% marks to pass. Ashok secures 325 marks but he fails by 35 marks. What were the maximum marks for the examination?
(a) 1800
(b) 900
(c) 800
(d) 750
Show Answer & Explanation

Answer: (c) 800

Explanation:
1. Pass marks = 325 + 35 = 360
2. 45% of the maximum = 360, so maximum = 800.

Teacher's Note:
1. Failing by 35 means 35 marks short of the pass mark.
2. Divide by 0.45.

Question 11: Two numbers are 40% and 20% less than a third number. What percentage does the first number form of the second?
(a) 60%
(b) 150%
(c) 75%
(d) 200%
Show Answer & Explanation

Answer: (c) 75%

Explanation:
1. First = 0.6C and second = 0.8C
2. First/second = 0.6/0.8 = 75%.

Teacher's Note:
1. Express both in terms of the third number.
2. Divide the first by the second.

Question 12: If x increases to y, the percentage increase is
(a) (x − y)/100
(b) (y − x)/100
(c) ((y − x)/y) × 100
(d) ((y − x)/x) × 100
Show Answer & Explanation

Answer: (d) ((y − x)/x) × 100

Explanation:
1. Increase = y − x, original value = x
2. Percentage increase = (y − x)/x × 100.

Teacher's Note:
1. The base is always the original value.
2. Compare with percentage decrease.

Question 13: To reduce a given number by 12 1/2 percent, we should multiply it by
(a) 1/8
(b) 12.5
(c) 7/8
(d) 2/25
Show Answer & Explanation

Answer: (c) 7/8

Explanation:
1. 12 1/2% = 1/8
2. New number = N − N/8 = 7N/8, so multiply by 7/8.

Teacher's Note:
1. Convert the percentage to a fraction.
2. Subtract it from 1.

Question 14: The price of a machine bought for Rs. 32000 falls by 5 percent every year. At the end of 2 years, it is worth
(a) Rs. 28800
(b) Rs. 29200
(c) Rs. 28880
(d) Rs. 28240
Show Answer & Explanation

Answer: (c) Rs. 28880

Explanation:
1. Value = 32000 × 0.95² = 32000 × 0.9025
2. = Rs. 28880.

Teacher's Note:
1. Apply the 5% depreciation twice.
2. Use compound depreciation, not simple.

Question 15: The population of a village at the beginning of a year was 10000. During that year it increased by 5 percent and during the next year decreased by 5 percent. At the end of the second year, the population of the village was
(a) 9975
(b) 10500
(c) 10525
(d) 10075
Show Answer & Explanation

Answer: (a) 9975

Explanation:
1. After year 1: 10000 × 1.05 = 10500
2. After year 2: 10500 × 0.95 = 9975.

Teacher's Note:
1. The 5% fall applies to the new, larger population.
2. So the net change is a small decrease.

Question 16: If x% of 910 = 81.9, the value of x is
(a) 0.9
(b) 9
(c) 90
(d) None of these
Show Answer & Explanation

Answer: (b) 9

Explanation:
1. x/100 × 910 = 81.9
2. x = 8190/910 = 9.

Teacher's Note:
1. Isolate x.
2. Divide 81.9 by 9.1.

Question 17: 37.5% of 648 is the same as
(a) 3.75% of 64.8
(b) 75% of 1296
(c) 3.75% of 6480
(d) 3/32 of 162
Show Answer & Explanation

Answer: (c) 3.75% of 6480

Explanation:
1. 37.5% of 648 = 243
2. 3.75% of 6480 = 243, while the other options give 2.43, 972 and 15.19.

Teacher's Note:
1. Evaluate the given quantity first.
2. Check each option.

Question 18: The value of a machine depreciates from Rs. 32768 to Rs. 21952 in three years. What is the rate percentage of depreciation?
(a) 11%
(b) 12.5%
(c) 33%
(d) 12.25%
Show Answer & Explanation

Answer: (b) 12.5%

Explanation:
1. 21952/32768 = (28/32)³ = (7/8)³
2. So (1 − r) = 7/8 and r = 12.5%.

Teacher's Note:
1. Factorise the numbers as perfect cubes.
2. Use P(1 − r)³ = final value.

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Percentage Objective Questions & Solutions for Class 10 Mathematics

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FAQs

Where can I access latest CBSE Class 10 Mathematics Percentage MCQs Set 22?

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