Chemistry Objective Questions and Answers: Carbon and its Compounds
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Multiple Choice Questions
(a) carboxylic acid
(b) aldehyde
(c) ketone
(d) alcohol
Show Answer & Explanation
Answer: (c) ketone
Explanation:
1. The suffix –one denotes a ketone, with the carbonyl group C=O between two carbon atoms.
2. Butanone is CH3COCH2CH3.
Teacher's Note:
1. –al is an aldehyde, –ol an alcohol and –oic acid a carboxylic acid.
2. Propanone (acetone) is the first ketone.
(a) methene
(b) ethene
(c) propene
(d) butene
Show Answer & Explanation
Answer: (b) ethene
Explanation:
1. An alkene needs a C=C double bond, so at least two carbon atoms are needed.
2. The first member is ethene, C2H4.
Teacher's Note:
1. Methene does not exist.
2. General formula of alkenes: CnH2n.
(a) alcohols
(b) simple esters of methanol
(c) carboxylic acids
(d) glycerides (fats and oils)
Show Answer & Explanation
Answer: (d) glycerides (fats and oils)
Explanation:
1. Fats and oils are glycerides, esters of glycerol with long-chain fatty acids.
2. Boiling them with NaOH gives soap (sodium salt of a fatty acid) and glycerol.
Teacher's Note:
1. This reaction is alkaline hydrolysis of esters.
2. Glycerol is the by-product.
Assertion (A): Methane, ethane and propane form a homologous series.
Reason (R): They are all hydrocarbons.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. The three compounds form a homologous series because they have the same functional group, similar properties and successive members differ by a CH2 unit, so A is true.
2. They are all hydrocarbons, so R is true, but being hydrocarbons alone does not make them a homologous series.
Teacher's Note:
1. Members of a homologous series differ by CH2 (14 mass units).
2. Ethane and ethene are hydrocarbons but are not in the same series.
(a) pure acetic acid which freezes into ice-like crystals at about 17 °C
(b) a 5–8% solution of acetic acid in water
(c) a mixture of acetic acid and alcohol
(d) frozen vinegar
Show Answer & Explanation
Answer: (a) pure acetic acid which freezes into ice-like crystals at about 17 °C
Explanation:
1. Pure (100%) ethanoic acid freezes at about 16.6 °C into ice-like crystals, so it is called glacial acetic acid.
2. Vinegar is the 5–8% solution.
Teacher's Note:
1. Glacial means ice-like.
2. It is a corrosive liquid.
(a) only ketones
(b) only aldehydes
(c) only esters
(d) aldehydes, ketones and esters, all of these
Show Answer & Explanation
Answer: (d) aldehydes, ketones and esters, all of these
Explanation:
1. The carbonyl group is present in aldehydes (–CHO), ketones (>C=O) and esters (–COO–).
2. So all of them contain it.
Teacher's Note:
1. Carboxylic acids also contain C=O.
2. Alcohols do not.
(a) CnH2n and CnH2n+1
(b) CnH2n and CnH2n+2
(c) CnH2n–1 and CnH2n
(d) CnH2n+1 and CnH2n+2
Show Answer & Explanation
Answer: (a) CnH2n and CnH2n+1
Explanation:
1. An alkene has formula CnH2n.
2. An alkyl group is an alkane minus one hydrogen, CnH2n+1.
Teacher's Note:
1. Methyl is CH3, ethyl is C2H5.
2. Alkane is CnH2n+2.
(a) (i) and (ii)
(b) (i) and (iii)
(c) (ii) and (iv)
(d) (iii) and (iv)
Show Answer & Explanation
Answer: (a) (i) and (ii)
Explanation:
1. In diamond each carbon is bonded to four others in a rigid three-dimensional network, so it is the hardest substance and bends light strongly.
2. It has no free electrons so it does not conduct electricity, and it does not mark paper.
Teacher's Note:
1. Graphite conducts and marks paper.
2. Diamond is used in cutting tools.
(a) it has a pi-bond that can break to add H and OH
(b) it has only sigma bonds
(c) it has an ionic bond
(d) it is a metal
Show Answer & Explanation
Answer: (a) it has a pi-bond that can break to add H and OH
Explanation:
1. The pi-bond is weaker and more reactive than a sigma bond and breaks easily.
2. The two carbons then bond to H and OH, giving ethanol.
Teacher's Note:
1. Unsaturated compounds give addition reactions.
2. Alkanes do not add water.
(a) always explosive
(b) endothermic
(c) neither exothermic nor endothermic
(d) exothermic, releasing heat and light
Show Answer & Explanation
Answer: (d) exothermic, releasing heat and light
Explanation:
1. Burning of carbon compounds in oxygen gives CO2 and water along with heat and light.
2. They are therefore exothermic, which is why carbon compounds are used as fuels.
Teacher's Note:
1. CH4 + 2O2 → CO2 + 2H2O + heat.
2. Incomplete combustion gives soot and CO.
(a) glycerol
(b) carbon dioxide
(c) ethanol
(d) hydrogen
Show Answer & Explanation
Answer: (a) glycerol
Explanation:
1. Fat + NaOH → soap + glycerol.
2. Glycerol is the alcohol part of the fat.
Teacher's Note:
1. This is an alkaline hydrolysis of an ester.
2. Glycerol is valuable in cosmetics.
(a) sodium hydroxide and ethane
(b) no reaction
(c) sodium ethoxide and hydrogen gas
(d) sodium oxide and ethene
Show Answer & Explanation
Answer: (c) sodium ethoxide and hydrogen gas
Explanation:
1. 2CH3CH2OH + 2Na → 2CH3CH2ONa + H2.
2. Hydrogen is evolved, and the product is sodium ethoxide.
Teacher's Note:
1. The reaction shows the weakly acidic hydrogen of alcohol.
2. Sodium reacts more slowly than with water.
(a) 2, 3 and 5
(b) 3, 4 and 5
(c) 1, 2 and 3
(d) 2, 3 and 4
Show Answer & Explanation
Answer: (a) 2, 3 and 5
Explanation:
1. Butane has two isomers (n-butane, isobutane).
2. Pentane has three and hexane has five.
Teacher's Note:
1. The number of isomers increases rapidly with carbon number.
2. C7H16 has nine.
(a) water only
(b) hydrochloric acid
(c) sodium chloride only
(d) sodium hydroxide solution (caustic soda)
Show Answer & Explanation
Answer: (d) sodium hydroxide solution (caustic soda)
Explanation:
1. The process is saponification: fat + NaOH → soap + glycerol.
2. Common salt is added later to precipitate (salt out) the soap.
Teacher's Note:
1. The soap floats as a curd.
2. Potassium hydroxide gives soft soap.
(a) carbon is removed
(b) nitrogen is added
(c) oxygen is added (or hydrogen is removed)
(d) hydrogen is added
Show Answer & Explanation
Answer: (c) oxygen is added (or hydrogen is removed)
Explanation:
1. CH3CH2OH + 2[O] → CH3COOH + H2O.
2. Gain of oxygen means oxidation, and the oxidising agent here is alkaline KMnO4 or acidified K2Cr2O7.
Teacher's Note:
1. Oxidising agents give oxygen to other substances.
2. Reverse: reduction.
(a) detergents form no scum with hard water, whereas a soap does
(b) detergents are acidic
(c) detergents react with sodium
(d) detergents are very expensive
Show Answer & Explanation
Answer: (a) detergents form no scum with hard water, whereas a soap does
Explanation:
1. Detergents lather even in hard water as their Ca and Mg salts are soluble.
2. So no scum is formed to show the hardness; soap is used for the test.
Teacher's Note:
1. Hardness is due to dissolved Ca2+ and Mg2+ salts.
2. Scum is calcium or magnesium soap.
(a) It turns blue litmus red and liberates CO2 with NaHCO3
(b) It is a neutral compound
(c) It has a higher pH than ethanol
(d) It does not react with sodium
Show Answer & Explanation
Answer: (a) It turns blue litmus red and liberates CO2 with NaHCO3
Explanation:
1. Ethanoic acid is a weak acid: it turns blue litmus red and reacts with NaHCO3 to give CO2.
2. Ethanol does not change litmus and does not liberate CO2.
Teacher's Note:
1. Both react with sodium to give hydrogen.
2. Ethanoic acid freezes at 16.6 °C and ethanol at –114 °C.
(a) C5H8 and C7H12
(b) C4H6 and C6H10
(c) C3H4 and C5H8
(d) C2H2 and C4H6
Show Answer & Explanation
Answer: (b) C4H6 and C6H10
Explanation:
1. The series starts with ethyne, C2H2 (n = 2), then C3H4, C4H6, C5H8, C6H10.
2. The third member is C4H6 and the fifth is C6H10.
Teacher's Note:
1. Alkynes: CnH2n–2.
2. Count members starting from n = 2.
(a) pentane and hexane only
(b) pentane, 2,2-dimethylbutane and 3-methylbutane
(c) pentene only
(d) pentane, 2-methylbutane and 2,2-dimethylpropane
Show Answer & Explanation
Answer: (d) pentane, 2-methylbutane and 2,2-dimethylpropane
Explanation:
1. The three isomers of C5H12 are n-pentane, 2-methylbutane (isopentane) and 2,2-dimethylpropane (neopentane).
2. The other names are not valid.
Teacher's Note:
1. All isomers have the same formula and molar mass.
2. Branching lowers the boiling point.
(a) detergents are cheaper than water
(b) detergents are made from fats
(c) detergents lather in hard water and do not form scum
(d) detergents are biodegradable in every case
Show Answer & Explanation
Answer: (c) detergents lather in hard water and do not form scum
Explanation:
1. Detergents work even with hard water since their calcium and magnesium salts are soluble.
2. Soaps form insoluble scum with hard water, reducing cleaning.
Teacher's Note:
1. Detergents are made from petroleum chemicals.
2. Biodegradability depends on the structure.
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Carbon and its Compounds Objective Questions & Solutions for Class 10 Chemistry
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FAQs
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