CBSE Class 11 Chemistry VBQs Chemical Bonding And Molecular Structure

Question. In which of the following pairs both the species have sp3 hybridization?
(a) SiF₄, BeH₂
(b) NF₃, H₂O
(c) NF₃, BF₃
(d) H₂S, BF₃
Answer. B

Question. Which one of the following pairs is isostructural (i.e., having the same shape and hybridization)?
(a) [BCl₃ and BrCl₃]
(b) [NH₃ and NO₃^–]
(c) [NF₃ and BF₃]
(d) [BF₄^– and NH₄⁺]
Answer. D

Question. Which of the two ions from the list given below that have the geometry that is explained by the same hybridization of orbitals, NO₂^–, NO₃^–, NH₂^–, NH₄⁺,SCN^– ?
(a) NO₂ ^– and NO₃^–
(b) NH₄⁺ and NO₃^–
(c) SCN^– and NH₂^–
(d) NO₂^– and NH₂^–
Answer. A

Question. In which of the following pairs of molecules/ions,the central atoms have sp2 hybridisation?
(a) NO₂^– and NH₃
(b) BF₃ and NO₂^–
(c) NH₂^– and H₂O
(d) BF₃ and NH₂^–
Answer. B

Question. In which one of the following species the central atom has the type of hybridization which is not the same as that present in the other three?
(a) SF₄
(b) I₃^–
(c) SbCl₅ ^2–
(d) PCl₅ 
Answer. C

Question. In which of the following molecules the central atom does not have sp³ hybridization?
(a) CH₄
(b) SF₄
(c) BF₄^–
(d) NH₄
Answer. B

Question. Some of the properties of the two species, NO₃^– and H₃O⁺ are described below. Which one of them is correct?
(a) Dissimilar in hybridization for the central atom with different structures.
(b) Isostructural with same hybridization for the central atom.
(c) Isostructural with different hybridization for the central atom.
(d) Similar in hybridization for the central atom with different structures. 
Answer. A

Question. In which of the following molecules/ions BF₃, NO₂^–,NH₂^– and H₂O, the central atom is sp2 hybridised?
(a) NH₂^– and H₂O
(b) NO₂^– and H₂O
(c) BF3 and NO₂^–
(d) NO₂^– and NH₂^–
Answer. C

Question. In which of the following pairs, the two species are isostructural?
(a) SO₃^2– and NO₃^–
(b) BF₃ and NF₃
(c) BrO₃^– and XeO₃
(d) SF₄ and XeF₄ 
Answer. C

Question. Which of the following species has a linear shape?
(a) O₃
(b) NO₂^–
(c) SO₂
(d) NO₂⁺
Answer. D

Question. The correct order regarding the electronegativity of hybrid orbitals of carbon is
(a) sp < sp² < sp³
(b) sp > sp² < sp³
(c) sp > sp² > sp³
(d) sp < sp² > sp³
Answer. C

Question. Among the following, the pair in which the two species are not isostructural is
(a) SiF₄ and SF₄
(b) IO₃^– and XeO₃
(c) BH₄^– and NH₄⁺
(d) PF₆^– and SF₆. 
Answer. A

Question. Which of the following has pp – dp bonding?
(a) NO₃^–
(b) SO₃^2–
(c) BO₃^3–
(d) CO₃^2–
Answer. B

Question. Which of the following two are isostructural?
(a) XeF₂, IF₂^–
(b) NH₃, BF₃
(c) CO₃^2–, SO₃^2–
(d) PCl₅, ICl₅
Answer. A

Question. The bond length between hybridised carbon atom and other carbon atom is minimum in
(a) propene
(b) propyne
(c) propane
(d) butane. 
Answer. B

Question. Which of the following has sp²-hybridisation?
(a) BeCl₂
(b) C₂H₂
(c) C₂H₆
(d) C₂H₄ 
Answer. D

Question. When the hybridization state of carbon atom changes from sp³ to sp² and finally to sp, the angle between the hybridized orbitals
(a) decreases gradually
(b) decreases considerably
(c) is not affected
(d) increases progressively. 
Answer. D

Question. Which one of the following has the shortest carbon carbon bond length?
(a) Benzene
(b) Ethene
(c) Ethyne
(d) Ethane 
Answer. C

Question. Which structure is linear?
(a) SO₂
(b) CO₂
(c) CO₃^2–
(d) SO₄^2– 
Answer. B

Question. A sp³ hybrid orbital contains
(a) 1/4 s-character
(b) 1/2 s-character
(c) 1/3 s-character
(d) 2/3 s-character.
Answer. A

Question. The complex ion [Co(NH₃)₆]³⁺ is formed by sp³d² hybridisation. Hence the ion should possess
(a) octahedral geometry
(b) tetrahedral geometry
(c) square planar geometry
(d) tetragonal geometry. 
Answer. A

Question. Which of the following molecules does not have a linear arrangement of atoms?
(a) H₂S
(b) C₂H₂
(c) BeH₂
(d) CO₂ 
Answer. A

Question. In which one of the following molecules the central atom can be said to adopt sp² hybridization?
(a) BeF₂
(b) BF₃
(c) C₂H₂
(d) NH₃ 
Answer. B

Question. Equilateral shape has
(a) sp hybridisation
(b) sp² hybridisation
(c) sp³ hybridisation
(d) dsp³ hybridisation.
Answer. B

Question. Consider the following species : CN⁺, CN^–, NO and CN. Which one of these will have the highest bond order?
(a) NO
(b) CN^–
(c) CN⁺
(d) CN 
Answer. B

Question. Which one of the following pairs of species have the same bond order?
(a) O₂, NO⁺
(b) CN^–, CO
(c) N₂, O₂^–
(d) CO, NO
Answer. B

Question. Which of the following is paramagnetic?
(a) CN^–
(b) NO⁺
(c) CO
(d) O₂ ^– 
Answer. D

Question. The pair of species that has the same bond order in the following is
(a) CO, NO⁺
(b) NO^–, CN^–
(c) O₂, N₂
(d) O₂, B₂
Answer. A

Question. In which of the following ionization processes the bond energy increases and the magnetic behaviour changes from paramagnetic to diamagnetic?
(a) O₂ → O₂⁺
(b) C₂ → C₂⁺
(c) NO → NO⁺
(d) N₂ → N₂⁺
Answer. C

Question. The pair of species with the same bond order is
(a) O₂^2–, B₂
(b) O₂^+, NO₊
(c) NO, CO
(d) N2, O₂
Answer. A

Question. During change of O₂ to O₂^– ion, the electron adds on which one of the following orbitals?
(a) p* orbital
(b) p orbital
(c) s* orbital
(d) s orbital
Answer. A

Question. Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them.
(a) NO < O₂– < C₂^2– < He₂⁺
(b) O₂^– < NO < C₂^2– < He₂⁺
(c) C₂^2– < He₂⁺ < O₂^– < NO
(d) He₂⁺ < O₂^– < NO < C₂^2– 
Answer. D

Question. Which of the following is isoelectronic?
(a) CO₂, NO₂
(b) NO₂^–, CO₂
(c) CN^–, CO
(d) SO₂, CO₂ 
Answer. C

Question. Which species does not exhibit paramagnetism?
(a) N₂⁺
(b) O₂^–
(c) CO
(d) NO 
Answer. C

Question. The number of anti-bonding electron pairs in O₂^2– molecular ion on the basis of molecular orbital theory is (Atomic number of O is 8.)
(a) 3
(b) 2
(c) 5
(d) 4 
Answer. D

Question. Which of the following species is paramagnetic?
(a) CO
(b) CN^–
(c) O₂^2–
(d) NO
Answer. D 

Question. Ice floats on water. Rishabh asked his teacher, why ice is lighter than water? The teacher explained the phenomenon to Rishabh and He got satisfied.

(i) What would be the answer of the teacher?

(ii) What is the hydrogen bond or hydrogen bonding?

(iii) What values are displayed by Rishabh?

Question. Two students Saloni and Aditi were discussing about the allotropes of carbon. Saloni asked Aditi, why one allotrope of carbon is very hard use to make jewellery meanwhile Aditi told Saloni that other allotrope of carbon is a good conductor and used to make pencils.

(i) Name the above two allotropes of carbon.

(ii) Why one allotrope is conductor and other is not?

(iii) What are allotropes?

(iv)  What values are associated with these allotropes?

Question. The Chemistry teacher was explaining the properties of two hydrides of Sulphur and Oxygen: H₂S and H₂O. H₂S and H₂O are having same hybridization states but different bond angles. H₂S have indefinite volume while H₂O has definite volume. H₂S cannot be placed in an open container but H₂O can be placed due to their different physical states.

(i) Write the hybridization states of central atom in H₂S and H₂O.

(ii) What are the physical states of H₂S and H₂O?

(iii) Write bond angle of H₂O.

(iv) Why H₂S and H₂O have different bond angles?

(v) Draw the Lewis structures of both the hydrides.

Question.​​​​ Rishabh and Sejal were discussing the difference between NF₃ and NH₃ and both got confused. Rishabh and Sejal asked their subject teacher, why NF₃ and NH₃ have different dipole moment while both are having same hybridization states and same number of lone pair of electrons.

Please click the link below to download CBSE Class 11 Chemistry VBQs Chemical Bonding And Molecular Structure.