Official RBSE Solutions for Class 5 Mathematics: Chapter 15 Capacity
Explore reliable textbook solutions for Chapter 15 Capacity tailored for Class 5 learners. Utilizing these Mathematics answers ensures thorough preparation and strengthens foundational knowledge before final RBSE evaluations.
Chapter-wise Solutions for Mathematics: Chapter 15 Capacity
Navigate directly to the solved Mathematics textbook exercises using the digital viewer below. Each solution includes detailed step-by-step explanations, allowing students to instantly cross-check their work and identify areas requiring further revision.
Question 1. How many meters are there in \( 3\frac{1}{2} \) kilometer?
Answer: To find how many meters are in \( 3\frac{1}{2} \) kilometers, we first separate the whole number and the fraction. We know that 1 kilometer is equal to 1000 meters. So, 3 kilometers are \( 3 \times 1000 = 3000 \) meters. The half kilometer is \( \frac{1}{2} \times 1000 = 500 \) meters. Adding these together, \( 3000 + 500 = 3500 \) meters. Therefore, there are 3500 meters in \( 3\frac{1}{2} \) kilometers.
In simple words: To change kilometers to meters, multiply by 1000. So, \( 3\frac{1}{2} \) kilometers is 3500 meters.
🎯 Exam Tip: Always remember that 1 kilometer equals 1000 meters. This conversion factor is key for solving such problems quickly and accurately.
Question 2. Convert 6500 gram into kilograms.
Answer: To convert grams to kilograms, we divide by 1000, because 1 kilogram is equal to 1000 grams. So, 6500 grams can be broken down into 6000 grams and 500 grams. This means we have 6 kilograms and \( \frac{500}{1000} \) of a kilogram. Since \( \frac{500}{1000} \) simplifies to \( \frac{1}{2} \), we have 6 kilograms plus \( \frac{1}{2} \) kilogram. So, 6500 grams is equal to \( 6\frac{1}{2} \) kilograms, which is 6.500 kg.
In simple words: To change grams to kilograms, divide the number of grams by 1000. So, 6500 grams becomes 6.5 kilograms.
🎯 Exam Tip: When converting smaller units to larger units (like grams to kilograms), you always divide. Conversely, when converting larger to smaller, you multiply.
Question 3. Convert 2250 millilitre into litres.
Answer: To convert milliliters to liters, we divide by 1000, because 1 liter is equal to 1000 milliliters. So, 2250 milliliters can be thought of as 2000 milliliters plus 250 milliliters. This means we have 2 liters and \( \frac{250}{1000} \) of a liter. The fraction \( \frac{250}{1000} \) simplifies to \( \frac{1}{4} \). Therefore, 2250 milliliters is equal to \( 2\frac{1}{4} \) liters, which is 2.250 liters. Measuring in liters makes it easier to compare larger quantities of liquids.
In simple words: To change milliliters to liters, divide by 1000. So, 2250 milliliters becomes \( 2\frac{1}{4} \) liters.
🎯 Exam Tip: Remember the basic conversion: 1 liter = 1000 milliliters. Always ensure you are dividing when converting from a smaller unit (ml) to a larger unit (L).
Question 5. Express 75000 gram in kilograms.
Answer: To express grams in kilograms, we use the conversion factor that 1 kilogram is equal to 1000 grams. So, to convert 75000 grams to kilograms, we divide 75000 by 1000. This calculation gives us \( 75000 \div 1000 = 75 \). Therefore, 75000 grams is equal to 75 kilograms. Understanding these conversions helps in daily life, like when buying groceries.
In simple words: To change grams to kilograms, divide the number of grams by 1000. So, 75000 grams is 75 kilograms.
🎯 Exam Tip: When dividing by 1000, you can simply move the decimal point three places to the left, which is a quick mental math trick.
Question 6. How many millilitres are there in two and half litres ?
Answer: First, we write "two and half liters" as a mixed fraction, which is \( 2\frac{1}{2} \) liters. To find the total milliliters, we convert the whole number and the fraction part separately. We know that 1 liter is 1000 milliliters. So, 2 liters are \( 2 \times 1000 = 2000 \) milliliters. The half liter is \( \frac{1}{2} \times 1000 = 500 \) milliliters. Adding these two amounts, \( 2000 + 500 = 2500 \) milliliters. Thus, \( 2\frac{1}{2} \) liters contains 2500 milliliters. This helps understand liquid measurements better.
In simple words: Two and a half liters means 2.5 liters. Since 1 liter is 1000 milliliters, 2.5 liters is 2500 milliliters.
🎯 Exam Tip: When converting from a larger unit (liters) to a smaller unit (milliliters), remember to multiply by the conversion factor, which is 1000.
Question 7. How many grams are there in one and half kilograms.
Answer: First, we write "one and half kilograms" as a mixed fraction, which is \( 1\frac{1}{2} \) kilograms. To find the total grams, we convert the whole number and the fraction part separately. We know that 1 kilogram is 1000 grams. So, 1 kilogram is \( 1 \times 1000 = 1000 \) grams. The half kilogram is \( \frac{1}{2} \times 1000 = 500 \) grams. Adding these two amounts, \( 1000 + 500 = 1500 \) grams. So, \( 1\frac{1}{2} \) kilograms contains 1500 grams. Knowing this helps when cooking or weighing items.
In simple words: One and a half kilograms means 1.5 kilograms. Since 1 kilogram is 1000 grams, 1.5 kilograms is 1500 grams.
🎯 Exam Tip: Always break down mixed unit problems into whole and fractional parts. Convert each part to the desired unit and then add them together.
Question 9. How many drums of capacity 20 litre each can be filled from fully filled water tank of capacity 5000 litre.
Answer: To find out how many drums can be filled, we need to divide the total capacity of the water tank by the capacity of one drum. The water tank has a capacity of 5000 liters, and each drum has a capacity of 20 liters. So, we calculate \( 5000 \div 20 \).
\( 5000 \div 20 = 250 \).
Therefore, 250 drums, each holding 20 liters, can be filled from a water tank with a capacity of 5000 liters. This is a common way to measure and distribute liquids.
In simple words: Divide the total water in the tank (5000 liters) by how much one drum holds (20 liters). You can fill 250 drums.
🎯 Exam Tip: When determining how many smaller containers can be filled from a larger one, always perform a division operation: Total Quantity / Quantity per Container.
Question 10. An oil container contains 15 litre of oil. For 3750 litre of oil how many containers are required?
Answer: To find the number of containers required for 3750 liters of oil, when each container holds 15 liters, we need to divide the total amount of oil by the capacity of a single container. So, we calculate \( 3750 \div 15 \).
\( 3750 \div 15 = 250 \).
Therefore, 250 containers, each with a capacity of 15 liters, are required to hold 3750 liters of oil. This calculation is similar to how warehouses manage inventory.
In simple words: Divide the total oil (3750 liters) by the amount each container holds (15 liters). You will need 250 containers.
🎯 Exam Tip: Make sure to set up the division correctly (total quantity divided by unit quantity). Double-checking your division calculation can prevent errors.
Question 11. A container contains 13 kg 500 gm. of oil. What is the total amount of oil in such 48 containers ?
Answer: First, convert the amount of oil in one container to a single unit, either all grams or all kilograms in decimal form. 13 kg 500 gm is equal to \( 13 \text{ kg} + 0.5 \text{ kg} = 13.5 \text{ kg} \). Now, to find the total amount of oil in 48 containers, we multiply the amount in one container by 48. So, \( 13.5 \text{ kg} \times 48 = 648 \text{ kg} \). Therefore, 648 kg of oil can be filled in 48 containers. This process is similar to calculating the total weight of many identical items.
In simple words: One container has 13.5 kilograms of oil. To find out how much oil is in 48 containers, multiply 13.5 kilograms by 48. The total oil will be 648 kilograms.
🎯 Exam Tip: When dealing with mixed units (kg and gm), always convert them to a single unit before performing multiplication or division to avoid errors.
Free study material for Mathematics
Mathematics Class 5 Curriculum Solutions: Chapter 15 Capacity
Accessing Chapter 15 Capacity Solutions
Access structured RBSE textbook solutions for Chapter 15 Capacity. Designed in alignment with the latest academic curriculum for Class 5 Mathematics, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
Concept-Driven Answers for Class 5 Mathematics
Each solution includes detailed reasoning to foster genuine comprehension of Chapter 15 Capacity concepts. Reviewing these step-by-step breakdowns allows learners to master both analytical and descriptive questions expected in school evaluations.
Maximizing Study Efficiency
Frequent review of these structured answers builds strong analytical capabilities and response efficiency. Maximize your academic readiness by combining these textbook solutions with our curated study materials and mock evaluations for Class 5 Mathematics.
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The complete and updated RBSE Solutions Class 5 Maths Chapter 15 Capacity Exercise 15.2 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.
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