RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 15 Capacity here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 15 Capacity RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 15 Capacity solutions will improve your exam performance.

Class 5 Mathematics Chapter 15 Capacity RBSE Solutions PDF

Multiple Choice Questions

 

Question 1. Unit to measure oil is
(a) litre
(b) kg.
(c) km.
(d) hour
Answer: (a) litre
In simple words: We use litres to measure liquids like oil, milk, and water. Litre helps us know the volume of these items.

๐ŸŽฏ Exam Tip: Remember to choose the correct unit for what is being measured: litres for liquids, kilograms for weight, and kilometres for distance.

 

Question 2. Half \( \frac {1}{2} \) litre means
(a) 500 gram
(b) 500 meter
(c) 500 minute
(d) 500 ml.
Answer: (d) 500 ml.
In simple words: Half a litre is the same as 500 millilitres. It's like cutting a whole litre into two equal parts.

๐ŸŽฏ Exam Tip: Always remember that 1 litre is equal to 1000 millilitres (ml). This conversion is key for many capacity problems.

 

Question 3. 3500 ml. measurement in a litre
(a) 35 litre
(b) 3 litre 500 ml.
(c) 350 litre
(d) 3500 litre
Answer: (b) 3 litre 500 ml.
In simple words: Since 1000 millilitres make 1 litre, 3500 millilitres is 3 litres and 500 millilitres. We separate the thousands to get litres.

๐ŸŽฏ Exam Tip: When converting ml to litres, divide the millilitre value by 1000. The whole number part will be litres, and the remainder (if any) will be millilitres.

 

Question 4. Millilitre in 1 litre is
(a) 100 millilitre
(b) 500 millilitre
(c) 1000 millilitre
(d) 10000 millilitre
Answer: (c) 1000 millilitre
In simple words: There are 1000 millilitres in one full litre. This is a basic unit conversion that is good to remember.

๐ŸŽฏ Exam Tip: Knowing the basic conversions like 1 litre = 1000 ml and 1 kg = 1000 g is essential for solving most measurement problems.

 

Question 6. In local conversation half litre means
(a) 250 ml.
(b) 500 ml.
(c) 750 ml.
(d) 1000 ml.
Answer: (b) 500 ml.
In simple words: When people say "half a litre" in everyday talk, they mean 500 millilitres. It's a common way to refer to half a unit of liquid.

๐ŸŽฏ Exam Tip: Many everyday measurements use fractions like half or quarter. Always relate these back to their standard unit equivalents (e.g., half litre to 500 ml) for accuracy.

 

Question 7. 750 gram weight is known as
(a) three quarter of a kilo
(b) half kilo
(c) one quarter of a kilo
(d) One kilo
Answer: (a) three quarter of a kilo
In simple words: A kilo has 1000 grams. So, 750 grams is three-quarters of a kilo, because \( \frac{3}{4} \) of 1000 is 750.

๐ŸŽฏ Exam Tip: Think of a kilogram as 1000 units. Then, a quarter is 250 units, half is 500 units, and three-quarters is 750 units.

 

Question 8. 1000 gram is equal to
(a) \( \frac {1}{4} \) kg.
(b) \( \frac {1}{2 } \) kg.
(c) 1 kg.
(d) \( \frac {1}{5} \) kg.
Answer: (c) 1 kg.
In simple words: The basic conversion is that 1000 grams make up exactly 1 kilogram. This is how we measure weight in larger units.

๐ŸŽฏ Exam Tip: Knowing that 'kilo' means 'thousand' helps you remember that 1 kilogram is 1000 grams and 1 kilometre is 1000 metres.

Fill In The Following Blanks

 

Question 1.
1. Gram or kg are the units to measure...........
2. 1000 millilitre = ........... litre.
3. ........... are measured in litre or millilitre.
4. Amount 1000 gram is equal to .............. kg.
5. In local conversation 500 gram is know as ...........
Answer:
1. Gram or kg are the units to measure **weight**.
2. 1000 millilitre = **1** litre.
3. **Liquid items** are measured in litre or millilitre.
4. Amount 1000 gram is equal to **1** kg.
5. In local conversation 500 gram is know as **Half**.
In simple words: These blanks test our knowledge of common measurement units. Grams and kilograms are for weight, litres and millilitres are for liquids. Half a kilogram or half a litre means 500 units.

๐ŸŽฏ Exam Tip: Always associate the correct unit with what is being measured. Weight uses grams/kilograms, capacity uses litres/millilitres, and length uses metres/kilometres.

Very Short Answer Type Questions

 

Question 1. How many grams are there in 1 \( \frac {1}{2} \) kg?
Answer: 1 \( \frac {1}{2} \) kg is equal to 1500 grams.
In simple words: One and a half kilograms is the same as 1500 grams. Remember that 1 kg is 1000 grams.

๐ŸŽฏ Exam Tip: To convert mixed kilograms to grams, first convert the whole kilograms, then the fractional part, and add them together.

 

Question 2. How can we weigh 3 kg 350 grams using standard iron weights?
Answer: We can weigh 3 kg 350 grams using the following iron weights:
2 kg. + 1 kg. + 200 gram + 100 gram + 50 gram.
This combines to make the exact total weight needed.
In simple words: To get 3 kilograms and 350 grams, you would use a 2 kg weight, a 1 kg weight, a 200 gram weight, a 100 gram weight, and a 50 gram weight.

๐ŸŽฏ Exam Tip: When using weights, always try to use the largest possible weight first, then fill in with smaller weights to reach the exact amount.

 

Question 3. 7 litre = ........... ml.
Answer: 7 litre = 7000 ml.
In simple words: Since 1 litre is 1000 millilitres, 7 litres means 7 times 1000, which is 7000 millilitres.

๐ŸŽฏ Exam Tip: When converting from a larger unit (litres) to a smaller unit (millilitres), you always multiply the number by 1000.

 

Question 5. Solve this:

kg.gram
6750
+ 13150
--------
19900
Answer: The sum of the given weights is 19 kg and 900 grams.
First, add the gram values: 750 g + 150 g = 900 g.
Then, add the kilogram values: 6 kg + 13 kg = 19 kg.
The final total is 19 kg 900 g.
In simple words: We first add the grams, then the kilograms. If the grams add up to 1000 or more, we convert those 1000 grams into 1 extra kilogram and add it to the kilograms column.

๐ŸŽฏ Exam Tip: Always start addition from the smallest unit (grams in this case) and carry over to the larger unit (kilograms) if the sum exceeds the base (1000 for grams).

 

Question 6. Solve 4 litre 200 gram ร— 3
Answer: To solve 4 litre 200 gram multiplied by 3:
First, multiply the litres: \( 4 \text{ litre} \times 3 = 12 \text{ litre} \).
Next, multiply the grams: \( 200 \text{ gram} \times 3 = 600 \text{ gram} \).
So, \( 4 \text{ litre } 200 \text{ gram} \times 3 = 12 \text{ litre } 600 \text{ gram} \).
In simple words: When you multiply a mixed measurement by a number, you multiply each part (litres and grams) separately by that number.

๐ŸŽฏ Exam Tip: Treat each unit (litres and grams) as a separate multiplication problem. If the grams result in 1000 or more, convert it to litres and add to the litre total.

 

Question 7. Convert 4 kilometer into meter.
Answer: To convert 4 kilometres into metres:
We know that 1 kilometre is equal to 1000 metres.
Therefore, 4 kilometres will be \( 4 \times 1000 \) metres.
This gives us 4000 metres.
In simple words: Since there are 1000 metres in every kilometre, to change kilometres to metres, you just multiply the number of kilometres by 1000.

๐ŸŽฏ Exam Tip: Always remember the 'kilo' prefix means 1000. So, 1 kilometre is 1000 metres, and 1 kilogram is 1000 grams.

 

Question 8. Convert 300 centimeter into meter.
Answer: To convert 300 centimetres into metres:
We know that 1 metre is equal to 100 centimetres.
So, to convert centimetres to metres, we divide by 100.
\( 300 \text{ centimeter} = 300 \times \frac {1}{100} \text{ meter} \).
This calculation results in 3 metres.
In simple words: Because 100 centimetres make 1 metre, to find out how many metres are in 300 centimetres, you simply divide 300 by 100, which gives you 3 metres.

๐ŸŽฏ Exam Tip: When converting from a smaller unit (centimetres) to a larger unit (metres), you always divide. For centi-units, the division factor is 100.

Short Answer And Essay Type Questions

 

Question 1. Atul has measures of 50 ml, 100 ml, 200 ml and 500 ml. In how many ways can Atul measure the following quantities by using the measures the least time?
(1) 2 litre 750 ml.
(2) 3 litre 800 ml.
Answer:
(1) To measure 2 litres 750 ml:
First, convert 2 litres to millilitres: \( 2 \text{ litres} = 2000 \text{ ml} \).
So, Atul needs to measure \( 2000 \text{ ml} + 750 \text{ ml} = 2750 \text{ ml} \).
To do this with the least number of measures, he can use:
\( 4 \times 500 \text{ ml} \) (which is 2000 ml)
plus \( (500 \text{ ml} + 250 \text{ ml}) \). For 250 ml, he can use \( 200 \text{ ml} + 50 \text{ ml} \).
So, he uses \( 5 \times 500 \text{ ml} + 200 \text{ ml} + 50 \text{ ml} \).
This means using the 500 ml measure five times, the 200 ml measure one time, and the 50 ml measure one time.

(2) To measure 3 litres 800 ml:
Convert 3 litres to millilitres: \( 3 \text{ litres} = 3000 \text{ ml} \).
So, Atul needs to measure \( 3000 \text{ ml} + 800 \text{ ml} = 3800 \text{ ml} \).
To do this with the least number of measures, he can use:
\( 7 \times 500 \text{ ml} \) (which is 3500 ml)
plus \( (200 \text{ ml} + 100 \text{ ml}) \).
So, he uses \( 7 \times 500 \text{ ml} + 200 \text{ ml} + 100 \text{ ml} \).
This means using the 500 ml measure seven times, the 200 ml measure one time, and the 100 ml measure one time.
In simple words: To measure a specific amount of liquid, Atul should use the largest measuring cans he has as many times as possible, then use smaller cans for the rest. This helps him measure with the fewest tries.

๐ŸŽฏ Exam Tip: When trying to achieve a total with specific measures, always start by using the largest available measure repeatedly, then figure out the remaining amount with smaller measures. This minimizes the number of actions.

 

Question 2. Can you tell how much litre oil is obtained from measurements given below?
Answer: To find the total amount of oil obtained from measurements, you need to add up all the individual measurements provided. For example, if you have containers of 500 ml, 250 ml, and 1 litre, you would convert all to the same unit (e.g., ml), add them, and then convert back to litres if needed. The sum of these individual volumes would be the total oil obtained. Without specific measurements, we can't give a numerical answer.
In simple words: To know the total oil, just add up the amount from each container. Make sure all amounts are in the same unit first, like all in millilitres or all in litres.

๐ŸŽฏ Exam Tip: Before adding or subtracting different units of measurement, always convert them to a common unit (usually the smaller unit, like millilitres or grams) to avoid errors.

 

Question 3. Shopkeeper used which measurements to measure following measures?
(a) 2 litre 200 ml.
(b) 5 litre 500 ml.
(c) 3 litre 200 ml.
Answer: The shopkeeper would use different standard measuring cans to measure these amounts:
(a) For 2 litres 200 ml: He would use a 1 litre measure twice, and a 200 ml measure once. This makes \( 1 \text{ litre} + 1 \text{ litre} + 200 \text{ ml} \).
(b) For 5 litres 500 ml: He would use a 1 litre measure five times, and a 500 ml measure once. This makes \( 1 \text{ litre} + 1 \text{ litre} + 1 \text{ litre} + 1 \text{ litre} + 1 \text{ litre} + 500 \text{ ml} \).
(c) For 3 litres 200 ml: He would use a 1 litre measure three times, and a 200 ml measure once. This makes \( 1 \text{ litre} + 1 \text{ litre} + 1 \text{ litre} + 200 \text{ ml} \).
In simple words: The shopkeeper uses standard measuring cups (like 1 litre, 500 ml, 200 ml) to measure out liquids. He picks the right combination of these cups to get the total amount needed.

๐ŸŽฏ Exam Tip: Always think about the most efficient combination of standard measures (1L, 500ml, 200ml, 100ml, 50ml) to reach a target volume, usually starting with the largest available unit.

 

Question 4. From an oil drum with capacity of 100 litres, 3 drums of 10 litres, 6 drum of 5 litres and 10 drums of 3 litres are filled then the remaining oil are filled in drums of 2 litres. Find the number of drums having capacity of 2 litres.
Answer: Let's find out how many 2-litre drums can be filled:
Total capacity of the oil drum = 100 litres.
Oil filled in 3 drums of 10 litres each = \( 3 \times 10 \text{ litres} = 30 \text{ litres} \).
Oil filled in 6 drums of 5 litres each = \( 6 \times 5 \text{ litres} = 30 \text{ litres} \).
Oil filled in 10 drums of 3 litres each = \( 10 \times 3 \text{ litres} = 30 \text{ litres} \).
Total oil filled so far = \( 30 \text{ litres} + 30 \text{ litres} + 30 \text{ litres} = 90 \text{ litres} \).
Oil remaining in the main drum = \( 100 \text{ litres} - 90 \text{ litres} = 10 \text{ litres} \).
Now, this remaining 10 litres needs to be filled into 2-litre drums.
Number of 2-litre drums = Remaining oil \( \div \) Capacity of one drum = \( 10 \text{ litres} \div 2 \text{ litres} = 5 \text{ drums} \).
So, 5 drums of 2 litres capacity can be filled.
In simple words: First, add up all the oil that has already been taken from the big drum. Then, see how much oil is left. Finally, divide the leftover oil by 2 litres to find how many 2-litre drums you can fill.

๐ŸŽฏ Exam Tip: Break down complex problems into smaller, manageable steps. Calculate each part separately (total oil used, remaining oil) before solving the final part of the question.

 

Question 6. Milk is available in half litre packet. How many packets are required for 2 \( \frac {1}{2} \) litres of milk?
Answer: To find the number of half-litre packets needed:
Amount of milk in one packet = Half litre = 500 ml.
Total milk required = \( 2 \frac {1}{2} \) litres.
Convert total milk to millilitres: \( 2 \frac {1}{2} \text{ litres} = 2.5 \text{ litres} = 2.5 \times 1000 \text{ ml} = 2500 \text{ ml} \).
Alternatively, \( 2 \frac {1}{2} \text{ litres} = \frac {5}{2} \text{ litres} \).
Since 1 litre = 1000 ml, \( \frac {5}{2} \text{ litres} = \frac {5}{2} \times 1000 \text{ ml} = 5 \times 500 \text{ ml} = 2500 \text{ ml} \).
Number of packets = Total milk required \( \div \) Milk in one packet
Number of packets = \( 2500 \text{ ml} \div 500 \text{ ml} = 5 \text{ packets} \).
Therefore, 5 packets are needed.
In simple words: A half-litre packet holds 500 millilitres. If you need two and a half litres (which is 2500 millilitres), you need to figure out how many 500 millilitre packets make 2500 millilitres. That is 5 packets.

๐ŸŽฏ Exam Tip: When dealing with mixed fractions of units (like \( 2 \frac {1}{2} \) litres), convert everything to the smallest common unit (millilitres) for easier calculation. This helps avoid errors with fractions.

 

Question 7. Half litre oil costs Rs. 45 then find out the cost of 3 \( \frac {1}{2} \) litre oil.
Answer: To find the total cost of 3 \( \frac {1}{2} \) litres of oil:
Cost of half litre oil = Rs. 45.
This means the cost of 1 litre of oil = \( \text{Rs. } 45 \times 2 = \text{Rs. } 90 \).
Total oil needed = \( 3 \frac {1}{2} \) litres.
Convert \( 3 \frac {1}{2} \) litres to an improper fraction: \( \frac {7}{2} \) litres.
Now, calculate the total cost: \( \text{Cost of 1 litre } \times \text{ Total litres } = \text{Rs. } 90 \times \frac {7}{2} \).
Total Cost = \( \text{Rs. } (90 \div 2) \times 7 = \text{Rs. } 45 \times 7 = \text{Rs. } 315 \).
Therefore, the cost of 3 \( \frac {1}{2} \) litres of oil is Rs. 315.
In simple words: If half a litre costs Rs. 45, then a full litre costs twice that, which is Rs. 90. Since you want three and a half litres, you can find the total cost by multiplying the cost of one litre by 3.5.

๐ŸŽฏ Exam Tip: First, find the cost of one full unit (e.g., 1 litre) if given the cost of a fraction of a unit. Then, multiply this unit cost by the total quantity required.

 

Question 8. A drum can hold 220 litre 500 ml oil. How much amount of oil 8 drums can hold?
Answer: To find the total amount of oil 8 drums can hold:
Oil in 1 drum = 220 litres 500 ml.
Number of drums = 8.
We multiply the litres and millilitres separately by 8:
Litres: \( 220 \times 8 = 1760 \text{ litres} \).
Millilitres: \( 500 \text{ ml} \times 8 = 4000 \text{ ml} \).
Now, convert the total millilitres to litres: \( 4000 \text{ ml} = 4 \text{ litres} \).
Add this to the total litres: \( 1760 \text{ litres} + 4 \text{ litres} = 1764 \text{ litres} \).
So, 8 drums can hold a total of 1764 litres of oil.
In simple words: To find how much oil 8 drums hold, multiply the oil in one drum (both litres and millilitres) by 8. Then, combine the litres, remembering that 1000 ml makes 1 litre.

๐ŸŽฏ Exam Tip: When multiplying mixed units, multiply each unit separately. If the smaller unit (millilitres) exceeds its conversion value (1000), convert it to the larger unit (litres) and add it to the total of the larger unit.

 

Question 9. Rani brings 2 litre 500 ml. milk in a can. How much milk can be filled in 4 such cans.
Answer: To find the total milk in 4 cans:
Milk in one can = 2 litres 500 ml.
Number of cans = 4.
Multiply the litres by 4: \( 2 \text{ litres} \times 4 = 8 \text{ litres} \).
Multiply the millilitres by 4: \( 500 \text{ ml} \times 4 = 2000 \text{ ml} \).
Convert the total millilitres to litres: \( 2000 \text{ ml} = 2 \text{ litres} \).
Add this to the total litres: \( 8 \text{ litres} + 2 \text{ litres} = 10 \text{ litres} \).
So, 4 such cans can hold a total of 10 litres of milk.
In simple words: To find the total amount, you multiply the litres by 4 and the millilitres by 4. Then, you convert any extra millilitres into full litres and add them to the litre count.

๐ŸŽฏ Exam Tip: This is a common multiplication problem with mixed units. Always perform the multiplication for each unit separately, then consolidate by converting the smaller unit to the larger unit if it exceeds its base value.

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 15 Capacity

Students can now access the RBSE Solutions for Chapter 15 Capacity prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 15 Capacity

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.

Benefits of using Mathematics Class 5 Solved Papers

Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 15 Capacity to get a complete preparation experience.

FAQs

Where can I find the latest RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions for the 2026-27 session?

The complete and updated RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.

Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

How do these Class 5 RBSE solutions help in scoring 90% plus marks?

Toppers recommend using RBSE language because RBSE marking schemes are strictly based on textbook definitions. Our RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Mathematics. You can access RBSE Solutions Class 5 Maths Chapter 15 Capacity Important Questions in both English and Hindi medium.

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