RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 12 Weight here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 12 Weight RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 12 Weight solutions will improve your exam performance.

Class 5 Mathematics Chapter 12 Weight RBSE Solutions PDF

Weight In Text Exercise

Page No. 62

 

Question 1. Convert 4 kilogram into gram.
Answer: We know that 1 kilogram is equal to 1000 grams. To convert 4 kilograms into grams, we need to multiply 4 by 1000.
\( 4 \text{ Kilogram} = 4 \times 1000 \text{ gram} \)
\( = 4000 \text{ gram} \)
So, 4 kilograms is 4000 grams.
In simple words: To change kilograms to grams, just multiply the number of kilograms by 1000.

🎯 Exam Tip: Remember the basic conversion: 1 kg = 1000 g. This fundamental relationship is key to solving all such conversion problems.

 

Page No. 63

 

Question 1. Convert 3000 gram into kilogram.
Answer: We know that 1000 grams make 1 kilogram. To convert grams into kilograms, we need to divide the number of grams by 1000.
\( 3000 \text{ gram} = \frac{3000}{1000} \text{ kilogram} \)
\( = 3 \text{ kilogram} \)
Thus, 3000 grams is equal to 3 kilograms.
In simple words: To change grams to kilograms, divide the number of grams by 1000.

🎯 Exam Tip: Always divide by 1000 when converting from a smaller unit (gram) to a larger unit (kilogram).

 

Question 2. Fill in the blanks
1. (i) 200 gram = ...... kilogram
(ii) 400 gram = ...... kilogram
(iii) 1250 gram = ...... kilogram
2. Convert \( 1\frac {1}{4} \) kilogram into grams
3. Convert \( 1\frac {3}{4} \) kilogram into grams
Answer:
1. (i) To convert 200 grams to kilograms, divide by 1000:
\( 200 \text{ gram} = \frac{200}{1000} \text{ kilogram} = \frac{2}{10} \text{ kg} = \frac{1}{5} \text{ kilogram} \)
(ii) To convert 400 grams to kilograms, divide by 1000:
\( 400 \text{ gram} = \frac{400}{1000} \text{ kilogram} = \frac{4}{10} \text{ kg} = \frac{2}{5} \text{ kilogram} \)
(iii) To convert 1250 grams to kilograms, divide by 1000:
\( 1250 \text{ gram} = \frac{1250}{1000} \text{ kilogram} = \frac{125}{100} \text{ kg} = \frac{5}{4} \text{ kilogram} = 1\frac{1}{4} \text{ kilogram} \)
2. To convert \( 1\frac{1}{4} \) kilograms to grams, first split the whole and fractional parts:
\( 1\frac {1}{4} \text{ kilogram} = 1 \text{ kilogram} + \frac {1}{4} \text{ kilogram} \)
Now, convert each part to grams (1 kg = 1000 g):
\( = 1000 \text{ gram} + \frac {1}{4} \times 1000 \text{ gram} \)
\( = 1000 \text{ gram} + 250 \text{ gram} \)
\( = 1250 \text{ gram} \)
3. To convert \( 1\frac{3}{4} \) kilograms to grams, first split the whole and fractional parts:
\( 1\frac {3}{4} \text{ kg.} = 1 \text{ kg} + \frac {3}{4} \text{ kg} \)
Now, convert each part to grams:
\( = 1000 \text{ gram} + \frac {3}{4} \times 1000 \text{ gram} \)
\( = 1000 \text{ gram} + 3 \times 250 \text{ gram} \)
\( = 1000 \text{ gram} + 750 \text{ gram} \)
\( = 1750 \text{ gram} \)
In simple words: When changing grams to kilograms, you divide by 1000. When changing kilograms to grams, you multiply by 1000. For mixed numbers, convert the whole part and the fraction part separately and then add them.

🎯 Exam Tip: Always simplify fractions to their lowest terms (e.g., \( \frac{2}{10} \) to \( \frac{1}{5} \)) for a complete answer.

 

Page No. 64

 

Question 1. Find weight of following with the help of these weighting units?
Answer: We can find the required weights by combining the given standard weighing units like 5 kg, 2 kg, 1 kg, 500 gram, 200 gram, 100 gram, and 50 gram. This helps in accurate measurements.

WeightTypes of iron weighing units
3 kg. 600 gram2 kg. + 1 kg. + 500 gram + 100 gram
4 kg. 750 gram2 kg. + 2 kg. + 500 gram + 200 gram + 50 gram
2 kg. 800 gram2 kg. + 500 gram + 200 gram + 100 gram
7 kg. 450 gram5 kg. + 2 kg. + 200 gram + 200 gram + 50 gram


In simple words: To make a certain weight, you combine different standard weight pieces together until they add up to the total you need.
🎯 Exam Tip: When combining weights, start with the largest units first (e.g., kilograms before grams) to simplify the process and ensure you use the minimum number of weights.

 

Question 2. Ramesh has one 5 kg and one 500 gm. of iron weight unit. He wants to weight out 4 kg and 500 gm of sugar. Look at the balance carefully and discuss, what would be the amount of sugar in the bag, is it 4 kg and 500 gram?
Answer: Ramesh has a 5 kg weight and a 500 gm weight. He wants to measure 4 kg 500 gm of sugar. If he places the 5 kg weight on one side of the balance, and places the sugar bag along with the 500 gm weight on the other side, the balance would be equal. This method is called subtraction weighing.
The weight of the sugar in the bag would be the total weight on one side (5 kg) minus the weight added to the sugar side (500 gm).
So, weight of sugar \( = 5 \text{ kg} - 500 \text{ gm} \)
\( = 5000 \text{ gm} - 500 \text{ gm} \)
\( = 4500 \text{ gm} \)
\( = 4 \text{ kg } 500 \text{ gm} \)
Yes, the amount of sugar in the bag would be 4 kg 500 gram. This method is efficient for measuring specific quantities.
In simple words: Ramesh used a 5 kg weight and put 500 gm with the sugar on the other side. So, the sugar in the bag actually weighed 4 kg 500 gm, because 5 kg minus 500 gm equals 4 kg 500 gm.

🎯 Exam Tip: When using a balance, you can weigh items by placing known weights on one side and the item on the other, or by using a combination of weights to find the difference, which is called subtraction weighing.

 

Page No. 65

Try It

 

Question 1. Weigh out 300 gm with the help of 500 gm and 200 gm iron weight units.
Answer: To weigh out 300 gm using 500 gm and 200 gm iron weight units on a balance scale, you can use the subtraction method. This technique helps achieve precise measurements using available weights.
1. Place the 500 gm weight on one pan of the balance scale.
2. Place the 200 gm weight on the other pan of the balance scale.
3. Add the substance (e.g., sand, sugar) to the pan that has the 200 gm weight until both pans are perfectly balanced.
The weight of the substance will be the difference between the weights on the two pans: \( 500 \text{ gm} - 200 \text{ gm} = 300 \text{ gm} \).
In simple words: To get 300 grams, put the 500 gram weight on one side of the scale. On the other side, put the 200 gram weight, and then add your item until the scale is even. Your item will be 300 grams (500 minus 200).

🎯 Exam Tip: When using a balance, always ensure the scale is level before adding weights or items to get an accurate reading.

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 12 Weight

Students can now access the RBSE Solutions for Chapter 12 Weight prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 12 Weight

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.

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Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 12 Weight to get a complete preparation experience.

FAQs

Where can I find the latest RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques for the 2026-27 session?

The complete and updated RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.

Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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Toppers recommend using RBSE language because RBSE marking schemes are strictly based on textbook definitions. Our RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Mathematics. You can access RBSE Solutions Class 5 Maths Chapter 12 Weight More Ques in both English and Hindi medium.

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