RBSE Solutions Class 5 Maths Chapter 12 Weight Exercise 12.1

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 12 Weight here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 12 Weight RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 12 Weight solutions will improve your exam performance.

Class 5 Mathematics Chapter 12 Weight RBSE Solutions PDF

 

Question 1. Reena bought 1 kg. 400 gm of tomato, 750 gram of chili, 2 kg 600 gm of potato and keeps them in the bag. What is the total weight of her bag?
Answer:
Weight of tomato \( = 1 \text{ kg. } 400 \text{ gram} \)
Weight of chili \( = 0 \text{ kg. } 750 \text{ gram} \)
Weight of potato \( = +2 \text{ kg. } 600 \text{ gram} \)
Total weight \( = 4 \text{ kg. } 750 \text{ gram} \)
Therefore, the total weight of Reena's bag is 4 kg 750 gram. When combining different items, their individual weights are added together to find the total.
In simple words: Reena bought tomato, chili, and potato. We add all their weights to find out the total weight of her bag, which is 4 kg and 750 grams.

🎯 Exam Tip: Remember to align the kilograms and grams correctly when adding weights to avoid mistakes. Convert all units to grams or kilograms before adding if they are mixed.

 

Question 2. Manoj bought 10 kg bag of sugar from the market. While returning home due to a hole in the bag some sugar is scattered out through the hole and 8 kg 750 gm sugar remained. Find out the weight of scattered quantity of sugar.
Answer:
Total weight of sugar \( = 10 \text{ kg. } 000 \text{ gram} \)
Weight remain after sugar scattered \( = - 8 \text{ kg. } 750 \text{ gram} \)
Sugar scattered on the way \( = 1 \text{ kg. } 250 \text{ gram} \)
Therefore, 1 kg, 250 gm sugar scattered on the way. To find the amount of scattered sugar, subtract the remaining sugar from the initial total.
In simple words: Manoj had 10 kg of sugar. Some fell out, and 8 kg 750 grams were left. To find how much fell, we subtract the left sugar from the total. This means 1 kg 250 grams of sugar scattered.

🎯 Exam Tip: When subtracting weights, ensure to borrow from kilograms to grams if needed, treating 1 kg as 1000 grams. Always double-check your subtraction.

 

Question 3. Sheela is having a packet of 5 kg. 470 gram and a box of 3 kg. 690 gram. Weight of the packet is now much more than that of the box?
Answer:
Weight of packet \( = 5 \text{ kg } 470 \text{ gram} \)
Weight of box \( = 3 \text{ kg } 690 \text{ gram} \)
Difference in weight \( = 1 \text{ kg } 780 \text{ gram} \)
To find out how much more the packet weighs, we subtract the weight of the box from the weight of the packet. This difference helps us compare the two weights directly.
In simple words: Sheela's packet weighs 5 kg 470 gram and her box weighs 3 kg 690 gram. We subtract the box's weight from the packet's weight to see how much heavier the packet is, which is 1 kg 780 gram.

🎯 Exam Tip: When comparing two weights to find the difference, always subtract the smaller weight from the larger one. Be careful with borrowing when grams are less than the grams being subtracted.

 

Question 4. A shopkeeper sells 250 gm packet of spices by grinding them from 6 kg of spices. Find out the number of these formed packets. If 4 packets of 250 gm. are prepared from 1 kg of spices.
Answer:
Total quantity of spices \( = 6 \text{ kg} \)
Quantity of spices in one packet \( = 250 \text{ gm} \)
We know that 1 kg \( = 1000 \text{ gm} \).
So, 6 kg \( = 6 \times 1000 \text{ gm} = 6000 \text{ gm} \).
Number of packets \( = \frac{6000 \text{ gm}}{250 \text{ gm/packet}} = 24 \text{ packets} \).
Therefore, 24 packets of 250 gram weight can be formed from 6 kg spices. This calculation helps the shopkeeper know how many smaller units they can make from a larger quantity.
In simple words: A shopkeeper has 6 kg of spices and makes packets that weigh 250 gm each. Since 1 kg makes 4 packets, 6 kg will make 6 times 4 packets, which is 24 packets in total.

🎯 Exam Tip: Always make sure that all units are the same (either all kilograms or all grams) before performing calculations like division. It helps in getting the correct number of packets.

 

Question 5. If 150 gm of wheat and 100 gm. of rice per child is required for the mid day meal then how much wheat and rice is needed for 60 children?
Answer:
Amount of wheat per child \( = 150 \text{ gram} \)
Amount of rice per child \( = 100 \text{ gram} \)
Number of children \( = 60 \)
Amount of wheat needed for 60 children \( = 150 \text{ gram} \times 60 = 9000 \text{ gram} \)
Convert grams to kilograms: \( 9000 \text{ gram} = \frac { 9000 }{ 1000 } \text{ kg} = 9 \text{ kg} \).
Amount of rice needed for 60 children \( = 100 \text{ gram} \times 60 = 6000 \text{ gram} \)
Convert grams to kilograms: \( 6000 \text{ gram} = \frac { 6000 }{ 1000 } \text{ kg} = 6 \text{ kg} \).
Therefore, 9 kg wheat and 6 kg rice are required for 60 students. By multiplying the requirement per child by the total number of children, we can find the total amount needed.
In simple words: Each child needs 150 gm of wheat and 100 gm of rice. For 60 children, we multiply these amounts by 60. This means 9 kg of wheat and 6 kg of rice are needed.

🎯 Exam Tip: Remember to convert grams to kilograms at the end if the question implies a larger quantity, as 1000 grams makes 1 kilogram. This makes the answer easier to understand.

 

Question 6. Savita bought 2 kg of cabbage, 4 kg of cucumber, 3 kg 700 gm of yam and 2 kg 900 gm of other vegetables from market. Find out the total weight of her bag.
Answer:
Weight of cabbage \( = 2 \text{ kg. } 000 \text{ gram} \)
Weight of cucumber \( = 4 \text{ kg. } 000 \text{ gram} \)
Weight of yam \( = 3 \text{ kg. } 700 \text{ gram} \)
Weight of other vegetables \( = + 2 \text{ kg. } 900 \text{ gram} \)
Total weight of bag \( = 12 \text{ kg. } 600 \text{ gram} \)
Therefore, the total weight of Savita's bag is 12 kg 600 gm. Adding all the individual weights together helps determine the total load carried.
In simple words: Savita bought many vegetables. We add up the weight of the cabbage, cucumber, yam, and other vegetables. This gives a total weight of 12 kg and 600 grams for her bag.

🎯 Exam Tip: Always align kilograms and grams in separate columns when adding to prevent errors. Remember that 1000 grams equals 1 kilogram, so carry over grams if they exceed 999.

 

Question 8. Find out
(i) \( 3 \frac {1}{2 } \) kg. = ....... gram
(ii) \( 3 \frac {2}{5} \) kg. = ....... gram
(iii) \( 4 \frac {3}{4} \) kg. = ....... gram
(iv) \( 2 \frac {1}{5} \) kg. = ....... gram
Answer:
(i) To convert \( 3 \frac { 1 }{ 2 } \) kg to grams:
\( 3 \frac { 1 }{ 2 } \text{ kg} = 3 \text{ kg} + \frac { 1 }{ 2 } \text{ kg} \)
We know that 1 kg \( = 1000 \text{ gram} \).
\( = 3 \times 1000 \text{ gram} + \frac { 1 }{ 2 } \times 1000 \text{ gram} \)
\( = 3000 \text{ gram} + 500 \text{ gram} \)
\( = 3500 \text{ gram} \)
(ii) To convert \( 3 \frac { 2 }{ 5 } \) kg to grams:
\( 3 \frac { 2 }{ 5 } \text{ kg} = 3 \text{ kg} + \frac { 2 }{ 5 } \text{ kg} \)
\( = 3 \times 1000 \text{ gram} + \frac { 2 }{ 5 } \times 1000 \text{ gram} \)
\( = 3000 \text{ gram} + 2 \times 200 \text{ gram} \)
\( = 3000 \text{ gram} + 400 \text{ gram} \)
\( = 3400 \text{ gram} \)
(iii) To convert \( 4 \frac { 3 }{ 4 } \) kg to grams:
\( 4 \frac { 3 }{ 4 } \text{ kg} = 4 \text{ kg} + \frac { 3 }{ 4 } \text{ kg} \)
\( = 4 \times 1000 \text{ gram} + \frac { 3 }{ 4 } \times 1000 \text{ gram} \)
\( = 4000 \text{ gram} + 3 \times 250 \text{ gram} \)
\( = 4000 \text{ gram} + 750 \text{ gram} \)
\( = 4750 \text{ gram} \)
(iv) To convert \( 2 \frac { 1 }{ 5 } \) kg to grams:
\( 2 \frac { 1 }{ 5 } \text{ kg} = 2 \text{ kg} + \frac { 1 }{ 5 } \text{ kg} \)
\( = 2 \times 1000 \text{ gram} + \frac { 1 }{ 5 } \times 1000 \text{ gram} \)
\( = 2000 \text{ gram} + 200 \text{ gram} \)
\( = 2200 \text{ gram} \)
In simple words: To change kilograms (kg) into grams, remember that 1 kg is 1000 grams. So, multiply the whole number part by 1000, and for the fraction part, multiply the fraction by 1000 grams and then add the two results together.

🎯 Exam Tip: Always remember the conversion factor: 1 kilogram = 1000 grams. This is key for solving all such problems accurately. Simplify fractions before multiplying for easier calculations.

 

Question 9. Find out
(i) 1500 gram = ....... kg.
(ii) 2250 gram = ....... kg.
(iii) 100 gram = ....... kg.
(iv) 4750 gram = ....... kg.
Answer:
(i) To convert 1500 gram to kg:
\( 1500 \text{ gram} = 1000 \text{ gram} + 500 \text{ gram} \)
\( = \frac { 1000 }{ 1000 } \text{ kg} + \frac { 500 }{ 1000 } \text{ kg} \)
\( = 1 \text{ kg} + \frac { 1 }{ 2 } \text{ kg} \)
\( = 1\frac { 1 }{ 2 } \text{ kg} \)
(ii) To convert 2250 gram to kg:
\( 2250 \text{ gram} = 2000 \text{ gram} + 250 \text{ gram} \)
\( = \frac { 2000 }{ 1000 } \text{ kg} + \frac { 250 }{ 1000 } \text{ kg} \)
\( = 2 \text{ kg} + \frac { 1 }{ 4 } \text{ kg} \)
\( = 2\frac { 1 }{ 4 } \text{ kg} \)
(iii) To convert 100 gram to kg:
\( 100 \text{ gram} = \frac { 100 }{ 1000 } \text{ kg} \)
\( = \frac { 1 }{ 10 } \text{ kg} \)
(iv) To convert 4750 gram to kg:
\( 4750 \text{ gram} = 4000 \text{ gram} + 750 \text{ gram} \)
\( = \frac { 4000 }{ 1000 } \text{ kg} + \frac { 750 }{ 1000 } \text{ kg} \)
\( = 4 \text{ kg} + \frac { 3 }{ 4 } \text{ kg} \)
\( = 4\frac { 3 }{ 4 } \text{ kg} \)
In simple words: To change grams into kilograms, you need to divide the number of grams by 1000. This is because 1000 grams make up 1 kilogram. You can write the answer as a whole number with a fraction or a decimal.

🎯 Exam Tip: Remember that when converting grams to kilograms, you are moving from a smaller unit to a larger one, so division by 1000 is necessary. Always simplify the fraction part if possible.

Free study material for Mathematics

RBSE Solutions Class 5 Mathematics Chapter 12 Weight

Students can now access the RBSE Solutions for Chapter 12 Weight prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 12 Weight

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these RBSE Questions and Answers your basic concepts will improve a lot.

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Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 12 Weight to get a complete preparation experience.

FAQs

Where can I find the latest RBSE Solutions Class 5 Maths Chapter 12 Weight Exercise 12.1 for the 2026-27 session?

The complete and updated RBSE Solutions Class 5 Maths Chapter 12 Weight Exercise 12.1 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.

Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 12 Weight Exercise 12.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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