NCERT Solutions for Class 5 Mathematics: Chapter 12 Weight
Review structured textbook solutions for Class 5 Mathematics Chapter 12 Weight. Built according to RBSE guidelines for the 2026-27 academic year, these downloadable answers support daily revision and problem-solving accuracy.
Practice Class 5 Mathematics Solutions: Chapter 12 Weight
Access the complete solution PDF for Class 5 Mathematics below. Regular practice with these targeted textbook answers builds familiarity with standard question patterns and helps secure higher marks in final school evaluations.
Question 1. Reena bought 1 kg. 400 gm of tomato, 750 gram of chili, 2 kg 600 gm of potato and keeps them in the bag. What is the total weight of her bag?
Answer:
Weight of tomato \( = 1 \text{ kg. } 400 \text{ gram} \)
Weight of chili \( = 0 \text{ kg. } 750 \text{ gram} \)
Weight of potato \( = +2 \text{ kg. } 600 \text{ gram} \)
Total weight \( = 4 \text{ kg. } 750 \text{ gram} \)
Therefore, the total weight of Reena's bag is 4 kg 750 gram. When combining different items, their individual weights are added together to find the total.
In simple words: Reena bought tomato, chili, and potato. We add all their weights to find out the total weight of her bag, which is 4 kg and 750 grams.
🎯 Exam Tip: Remember to align the kilograms and grams correctly when adding weights to avoid mistakes. Convert all units to grams or kilograms before adding if they are mixed.
Question 2. Manoj bought 10 kg bag of sugar from the market. While returning home due to a hole in the bag some sugar is scattered out through the hole and 8 kg 750 gm sugar remained. Find out the weight of scattered quantity of sugar.
Answer:
Total weight of sugar \( = 10 \text{ kg. } 000 \text{ gram} \)
Weight remain after sugar scattered \( = - 8 \text{ kg. } 750 \text{ gram} \)
Sugar scattered on the way \( = 1 \text{ kg. } 250 \text{ gram} \)
Therefore, 1 kg, 250 gm sugar scattered on the way. To find the amount of scattered sugar, subtract the remaining sugar from the initial total.
In simple words: Manoj had 10 kg of sugar. Some fell out, and 8 kg 750 grams were left. To find how much fell, we subtract the left sugar from the total. This means 1 kg 250 grams of sugar scattered.
🎯 Exam Tip: When subtracting weights, ensure to borrow from kilograms to grams if needed, treating 1 kg as 1000 grams. Always double-check your subtraction.
Question 3. Sheela is having a packet of 5 kg. 470 gram and a box of 3 kg. 690 gram. Weight of the packet is now much more than that of the box?
Answer:
Weight of packet \( = 5 \text{ kg } 470 \text{ gram} \)
Weight of box \( = 3 \text{ kg } 690 \text{ gram} \)
Difference in weight \( = 1 \text{ kg } 780 \text{ gram} \)
To find out how much more the packet weighs, we subtract the weight of the box from the weight of the packet. This difference helps us compare the two weights directly.
In simple words: Sheela's packet weighs 5 kg 470 gram and her box weighs 3 kg 690 gram. We subtract the box's weight from the packet's weight to see how much heavier the packet is, which is 1 kg 780 gram.
🎯 Exam Tip: When comparing two weights to find the difference, always subtract the smaller weight from the larger one. Be careful with borrowing when grams are less than the grams being subtracted.
Question 4. A shopkeeper sells 250 gm packet of spices by grinding them from 6 kg of spices. Find out the number of these formed packets. If 4 packets of 250 gm. are prepared from 1 kg of spices.
Answer:
Total quantity of spices \( = 6 \text{ kg} \)
Quantity of spices in one packet \( = 250 \text{ gm} \)
We know that 1 kg \( = 1000 \text{ gm} \).
So, 6 kg \( = 6 \times 1000 \text{ gm} = 6000 \text{ gm} \).
Number of packets \( = \frac{6000 \text{ gm}}{250 \text{ gm/packet}} = 24 \text{ packets} \).
Therefore, 24 packets of 250 gram weight can be formed from 6 kg spices. This calculation helps the shopkeeper know how many smaller units they can make from a larger quantity.
In simple words: A shopkeeper has 6 kg of spices and makes packets that weigh 250 gm each. Since 1 kg makes 4 packets, 6 kg will make 6 times 4 packets, which is 24 packets in total.
🎯 Exam Tip: Always make sure that all units are the same (either all kilograms or all grams) before performing calculations like division. It helps in getting the correct number of packets.
Question 5. If 150 gm of wheat and 100 gm. of rice per child is required for the mid day meal then how much wheat and rice is needed for 60 children?
Answer:
Amount of wheat per child \( = 150 \text{ gram} \)
Amount of rice per child \( = 100 \text{ gram} \)
Number of children \( = 60 \)
Amount of wheat needed for 60 children \( = 150 \text{ gram} \times 60 = 9000 \text{ gram} \)
Convert grams to kilograms: \( 9000 \text{ gram} = \frac { 9000 }{ 1000 } \text{ kg} = 9 \text{ kg} \).
Amount of rice needed for 60 children \( = 100 \text{ gram} \times 60 = 6000 \text{ gram} \)
Convert grams to kilograms: \( 6000 \text{ gram} = \frac { 6000 }{ 1000 } \text{ kg} = 6 \text{ kg} \).
Therefore, 9 kg wheat and 6 kg rice are required for 60 students. By multiplying the requirement per child by the total number of children, we can find the total amount needed.
In simple words: Each child needs 150 gm of wheat and 100 gm of rice. For 60 children, we multiply these amounts by 60. This means 9 kg of wheat and 6 kg of rice are needed.
🎯 Exam Tip: Remember to convert grams to kilograms at the end if the question implies a larger quantity, as 1000 grams makes 1 kilogram. This makes the answer easier to understand.
Question 6. Savita bought 2 kg of cabbage, 4 kg of cucumber, 3 kg 700 gm of yam and 2 kg 900 gm of other vegetables from market. Find out the total weight of her bag.
Answer:
Weight of cabbage \( = 2 \text{ kg. } 000 \text{ gram} \)
Weight of cucumber \( = 4 \text{ kg. } 000 \text{ gram} \)
Weight of yam \( = 3 \text{ kg. } 700 \text{ gram} \)
Weight of other vegetables \( = + 2 \text{ kg. } 900 \text{ gram} \)
Total weight of bag \( = 12 \text{ kg. } 600 \text{ gram} \)
Therefore, the total weight of Savita's bag is 12 kg 600 gm. Adding all the individual weights together helps determine the total load carried.
In simple words: Savita bought many vegetables. We add up the weight of the cabbage, cucumber, yam, and other vegetables. This gives a total weight of 12 kg and 600 grams for her bag.
🎯 Exam Tip: Always align kilograms and grams in separate columns when adding to prevent errors. Remember that 1000 grams equals 1 kilogram, so carry over grams if they exceed 999.
Question 8. Find out
(i) \( 3 \frac {1}{2 } \) kg. = ....... gram
(ii) \( 3 \frac {2}{5} \) kg. = ....... gram
(iii) \( 4 \frac {3}{4} \) kg. = ....... gram
(iv) \( 2 \frac {1}{5} \) kg. = ....... gram
Answer:
(i) To convert \( 3 \frac { 1 }{ 2 } \) kg to grams:
\( 3 \frac { 1 }{ 2 } \text{ kg} = 3 \text{ kg} + \frac { 1 }{ 2 } \text{ kg} \)
We know that 1 kg \( = 1000 \text{ gram} \).
\( = 3 \times 1000 \text{ gram} + \frac { 1 }{ 2 } \times 1000 \text{ gram} \)
\( = 3000 \text{ gram} + 500 \text{ gram} \)
\( = 3500 \text{ gram} \)
(ii) To convert \( 3 \frac { 2 }{ 5 } \) kg to grams:
\( 3 \frac { 2 }{ 5 } \text{ kg} = 3 \text{ kg} + \frac { 2 }{ 5 } \text{ kg} \)
\( = 3 \times 1000 \text{ gram} + \frac { 2 }{ 5 } \times 1000 \text{ gram} \)
\( = 3000 \text{ gram} + 2 \times 200 \text{ gram} \)
\( = 3000 \text{ gram} + 400 \text{ gram} \)
\( = 3400 \text{ gram} \)
(iii) To convert \( 4 \frac { 3 }{ 4 } \) kg to grams:
\( 4 \frac { 3 }{ 4 } \text{ kg} = 4 \text{ kg} + \frac { 3 }{ 4 } \text{ kg} \)
\( = 4 \times 1000 \text{ gram} + \frac { 3 }{ 4 } \times 1000 \text{ gram} \)
\( = 4000 \text{ gram} + 3 \times 250 \text{ gram} \)
\( = 4000 \text{ gram} + 750 \text{ gram} \)
\( = 4750 \text{ gram} \)
(iv) To convert \( 2 \frac { 1 }{ 5 } \) kg to grams:
\( 2 \frac { 1 }{ 5 } \text{ kg} = 2 \text{ kg} + \frac { 1 }{ 5 } \text{ kg} \)
\( = 2 \times 1000 \text{ gram} + \frac { 1 }{ 5 } \times 1000 \text{ gram} \)
\( = 2000 \text{ gram} + 200 \text{ gram} \)
\( = 2200 \text{ gram} \)
In simple words: To change kilograms (kg) into grams, remember that 1 kg is 1000 grams. So, multiply the whole number part by 1000, and for the fraction part, multiply the fraction by 1000 grams and then add the two results together.
🎯 Exam Tip: Always remember the conversion factor: 1 kilogram = 1000 grams. This is key for solving all such problems accurately. Simplify fractions before multiplying for easier calculations.
Question 9. Find out
(i) 1500 gram = ....... kg.
(ii) 2250 gram = ....... kg.
(iii) 100 gram = ....... kg.
(iv) 4750 gram = ....... kg.
Answer:
(i) To convert 1500 gram to kg:
\( 1500 \text{ gram} = 1000 \text{ gram} + 500 \text{ gram} \)
\( = \frac { 1000 }{ 1000 } \text{ kg} + \frac { 500 }{ 1000 } \text{ kg} \)
\( = 1 \text{ kg} + \frac { 1 }{ 2 } \text{ kg} \)
\( = 1\frac { 1 }{ 2 } \text{ kg} \)
(ii) To convert 2250 gram to kg:
\( 2250 \text{ gram} = 2000 \text{ gram} + 250 \text{ gram} \)
\( = \frac { 2000 }{ 1000 } \text{ kg} + \frac { 250 }{ 1000 } \text{ kg} \)
\( = 2 \text{ kg} + \frac { 1 }{ 4 } \text{ kg} \)
\( = 2\frac { 1 }{ 4 } \text{ kg} \)
(iii) To convert 100 gram to kg:
\( 100 \text{ gram} = \frac { 100 }{ 1000 } \text{ kg} \)
\( = \frac { 1 }{ 10 } \text{ kg} \)
(iv) To convert 4750 gram to kg:
\( 4750 \text{ gram} = 4000 \text{ gram} + 750 \text{ gram} \)
\( = \frac { 4000 }{ 1000 } \text{ kg} + \frac { 750 }{ 1000 } \text{ kg} \)
\( = 4 \text{ kg} + \frac { 3 }{ 4 } \text{ kg} \)
\( = 4\frac { 3 }{ 4 } \text{ kg} \)
In simple words: To change grams into kilograms, you need to divide the number of grams by 1000. This is because 1000 grams make up 1 kilogram. You can write the answer as a whole number with a fraction or a decimal.
🎯 Exam Tip: Remember that when converting grams to kilograms, you are moving from a smaller unit to a larger one, so division by 1000 is necessary. Always simplify the fraction part if possible.
Free study material for Mathematics
RBSE Solutions for Class 5 Mathematics Chapter 12 Weight
Accessing Chapter 12 Weight Solutions
Access structured RBSE textbook solutions for Chapter 12 Weight. Designed in alignment with the latest academic curriculum for Class 5 Mathematics, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
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Beyond providing final answers, these guides offer step-by-step breakdowns for complex queries in the Class 5 Mathematics module. This approach helps students balance theoretical depth with practical problem-solving skills required for RBSE exams.
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The complete and updated RBSE Solutions Class 5 Maths Chapter 12 Weight Exercise 12.1 is available for free on StudiesToday.com. These solutions for Class 5 Mathematics are as per latest RBSE curriculum.
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