RBSE Solutions Class 5 Maths Chapter 10 Currency More Ques

Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Additional Questions

Multiple Choice Questions

 

Question 1. If the rate of potato is 12 Rs. per kg. then cost of 15 kg potato is-
(a) 150 Rupees
(b) 180 Rupees
(c) 170 Rupees
(d) 190 Rupees
Answer: (b) 180 Rupees
In simple words: To find the total cost, you multiply the price of one kilogram by the total number of kilograms bought. This gives you the full amount to pay.

🎯 Exam Tip: Remember to always multiply the per-unit price by the quantity to find the total cost.

 

Question 2. If the rate of tomato is 10 Rs. per kg. then what amount to be paid to vegetable seller on buying 10 kg. tomato:
(a) 250 Rupees
(b) 35 Rupees
(c) 200 Rupees
(d) 300 Rupees
Answer: (a) 250 Rupees
In simple words: To calculate the total amount, you always multiply the price per unit by the quantity purchased. This simple multiplication gives you the final payment.

🎯 Exam Tip: Read the question carefully to identify the rate and the quantity needed for the calculation.

 

Question 3. A vegetable trader bought coriander at rate of 28 Rs. per kg. How much amount he paid for 5 kg coriander ?
(a) 33 Rupees
(b) 150 Rupees
(c) 160 Rupees
(d) 140 Rupees
Answer: (d) 140 Rupees
In simple words: Just multiply the cost of one kilogram of coriander by the total kilograms the trader bought. This will give you the total money paid.

🎯 Exam Tip: This type of problem is a direct application of multiplication for finding total cost, so clearly identify the rate and quantity.

 

Question 4. A trader bought 15 kg. cauliflower at the rate of 18 Rs. per kg. How much he paid-
(a) 240 Rupees
(b) 252 Rupees
(c) 270 Rupees
(d) 260 Rupees
Answer: (c) 270 Rupees
In simple words: To find the total payment, multiply the rate of cauliflower per kilogram by the total kilograms the trader bought.

🎯 Exam Tip: Always set up your multiplication problem clearly: (quantity) x (rate per unit) = total cost.

 

Question 5. How much amount did trader paid when he bought 7 kg. Taro (Arabi) at the rate of 36 Rs. per kg.
(a) 240 Rupees
(b) 252 Rupees
(c) 250 Rupees
(d) 260 Rupees
Answer: (b) 252 Rupees
In simple words: Multiply the price of one kg of Taro by the quantity bought to get the total amount paid. It's a simple multiplication problem.

🎯 Exam Tip: Pay attention to the units (kg, per kg) to ensure you are multiplying the correct values.

 

Question 6. To find price of item we perform ....... between quantity and rate.
(a) Addition
(b) Subtraction
(c) Multiplication
(d) Division
Answer: (c) Multiplication
In simple words: To figure out the total cost of an item, you multiply how many you bought (quantity) by the price of each one (rate).

🎯 Exam Tip: This is a basic principle in calculating total cost in money problems. Remember that 'per' often indicates multiplication or division.

 

Question 7. Price of 3 kg. of rice at the rate of 45 Rs. per kg. is-
(a) 135 Rupees
(b) 50 Rupees
(c) 15 Rupees
(d) 1350 Rupees
Answer: (a) 135 Rupees
In simple words: To find the total price, multiply the price of one kilogram of rice by the total kilograms bought.

🎯 Exam Tip: Double-check your multiplication to avoid simple arithmetic errors that can lead to wrong answers.

 

Question 8. Total price of the item listed in a bill is find out by-
(a) Adding
(b) Subtracting
(c) Multiplying
(d) Dividing
Answer: (a) Adding
In simple words: When you have a list of items and their individual costs on a bill, you add all those costs together to get the final total amount.

🎯 Exam Tip: Understand that a "total" for multiple items almost always means addition, while "total cost of *one type* of item" often means multiplication.

 

Question 9. If the rate of oil is 72 Rs. 50 paise per kg. then cost of 1/2 kg oil is-
(a) 752 Rs. 50 paise
(b) 652 Rs. 50 paise
(c) 36 Rs. 25 paise
Answer: (c) 36 Rs. 25 paise
In simple words: To find the cost of half a kilogram, divide the price of a full kilogram by two. This gives you the cost for the smaller quantity.

🎯 Exam Tip: When dealing with fractions of kilograms (like 1/2 kg), convert the fraction to a decimal (0.5 kg) for easier multiplication with the per-kilogram rate.

 

Question 10. In the following fill in the blanks-
1. 100 paisa = ....... Rupee
2. More than one items purchased then ....... all the list price in bill.
3. 225 Rs. x 3 = ....... Rs.
4. 108 Rs. ÷ 9 = ....... Rs.
5. The shopkeeper calculates the price of the goods on the purchase of each- item and gives a slip called .......
Answer:
1. 100 paisa = 1 Rupee
2. More than one items purchased then **add** all the list price in bill.
3. 225 Rs. x 3 = **675** Rs.
4. 108 Rs. ÷ 9 = **12** Rs.
5. The shopkeeper calculates the price of the goods on the purchase of each- item and gives a slip called **Invoice or Bill**.
In simple words: This question tests your basic knowledge about currency conversions, how prices are added on a bill, simple multiplication, and simple division. It also asks about the document a shopkeeper provides.

🎯 Exam Tip: Pay close attention to standard financial terms like "Invoice" or "Bill" and basic arithmetic operations (addition, multiplication, division) when solving such fill-in-the-blanks questions.

Very Short Answer Type Questions

 

Question 1. If the price of 1 kg. ghee is 380 Rs. and the price of 1 kg. oil is 95 Rs. then price of how much kg oil is equal to price of 1 kg ghee ?
Answer: To find how many kilograms of oil are equal to 1 kg of ghee, we need to divide the price of 1 kg of ghee by the price of 1 kg of oil.
Price of 1 kg ghee = 380 Rs.
Price of 1 kg oil = 95 Rs.
Kilograms of oil equal to 1 kg ghee \( = \frac{380}{95} \)
\( = 4 \) kg.
So, the price of 4 kg of oil is equal to the price of 1 kg of ghee.
In simple words: We divide the cost of ghee by the cost of oil to find out how many times more expensive ghee is, which tells us how many kg of oil are worth 1 kg of ghee.

🎯 Exam Tip: When comparing values and finding equivalence, division is the correct operation to use. Ensure your division is accurate.

 

Question 2. In the rate list of shop, price of 1 kg. Tuar dal is 70 Rs. and Price of 1 kg. ghee is 380 Rs. then find out one buying 10 kg. tuar dal or 2 kg. ghee, you will have to pay more money.
Answer: First, we calculate the cost for buying 10 kg of Tuar dal.
Price of 1 kg Tuar dal = 70 Rs.
Cost of 10 kg Tuar dal \( = 70 \times 10 = 700 \) Rs.
Next, we calculate the cost for buying 2 kg of ghee.
Price of 1 kg ghee = 380 Rs.
Cost of 2 kg ghee \( = 380 \times 2 = 760 \) Rs.
Comparing the two costs, 760 Rs. (for ghee) is more than 700 Rs. (for dal).
Therefore, you will have to pay more money for ghee.
In simple words: We calculate the total cost for the dal and the total cost for the ghee. Then we look at which total is bigger to see which one costs more.

🎯 Exam Tip: Break down comparison problems into separate calculations for each item, then clearly state which one is higher or lower based on the question.

 

Question 3. Sheela puts a dupatta shop in the hot market. This time she took 32 dupatta with her. The price of one was 60 Rs. Her 8 dupatta Solution. d out. Find out how many rupees she got?
Answer: We need to calculate the amount Sheela received from selling 8 dupattas.
Price of one dupatta = 60 Rs.
Number of dupattas sold = 8
Amount received from selling 8 dupattas \( = 60 \times 8 = 480 \) Rs.
So, Sheela got 480 Rupees.
In simple words: To find out how much money Sheela earned, we multiply the price of one dupatta by the number of dupattas she sold.

🎯 Exam Tip: Ignore extra information that is not needed for the calculation, such as the total number of dupattas she started with, if it's not relevant to the question asked.

 

Question 4. Add 9 Rs. 50 paise and 12 Rs. 75 paise.
Answer: We add the rupees and paise separately, then convert excess paise to rupees.
Rs. Paise 9 50 + 12 75 ----- 21 125
We know that 100 paise = 1 Rupee.
So, 125 paise = 1 Rupee and 25 paise.
We add this 1 Rupee to the total rupees.
\( 21 \text{ Rs.} + 1 \text{ Rs.} = 22 \text{ Rs.} \)
The remaining paise are 25.
Therefore, 9 Rs. 50 paise + 12 Rs. 75 paise = 22 Rs. 25 paise.
In simple words: First, add the rupees together and the paise together. If the paise sum is 100 or more, convert 100 paise into 1 rupee and add it to the rupees total.

🎯 Exam Tip: Always remember that 100 paise makes 1 Rupee. When adding paise, carry over any amount over 99 to the rupees column.

 

Question 5. Subtract 9 Rs. 50 paise from 12 Rs. 40 paise.
Answer: We subtract the paise and rupees separately, borrowing from rupees if needed.
To subtract 50 paise from 40 paise, we need to borrow 1 Rupee (100 paise) from 12 Rs.
So, 12 Rs. 40 paise becomes 11 Rs. (100 + 40) paise = 11 Rs. 140 paise.
Now, subtract the paise:
140 paise - 50 paise = 90 paise.
Subtract the rupees:
11 Rs. - 9 Rs. = 2 Rs.
Therefore, 12 Rs. 40 paise - 9 Rs. 50 paise = 2 Rs. 90 paise.
In simple words: When subtracting money, if you can't subtract the paise directly, borrow 1 rupee from the rupees side and add 100 paise to the paise side. Then subtract normally.

🎯 Exam Tip: Be careful with borrowing in money subtractions. One Rupee borrowed converts into 100 paise, not 10, when moving between columns.

 

Question 6. Solve : 7 Rs. 25 paise x 5.
Answer: We multiply the rupees and paise separately by 5.
Multiply paise: \( 25 \text{ paise} \times 5 = 125 \text{ paise} \).
Convert 125 paise to rupees: 125 paise = 1 Rupee and 25 paise.
Multiply rupees: \( 7 \text{ Rs.} \times 5 = 35 \text{ Rs.} \).
Add the converted rupee from the paise to the total rupees:
\( 35 \text{ Rs.} + 1 \text{ Rs.} = 36 \text{ Rs.} \).
The remaining paise are 25.
Therefore, 7 Rs. 25 paise x 5 = 36 Rs. 25 paise.
In simple words: Multiply the rupees part by the number, and then multiply the paise part by the number. If the paise go over 100, convert them into rupees and add to the rupee total.

🎯 Exam Tip: In multiplication of currency, always convert the paise part to rupees if it exceeds 99 paise *after* multiplication, and add the converted rupees to the rupee total.

 

Question 7. Solve : 47 Rs. 32 paise ÷ 7
Answer: We perform division by dividing the rupees first, then converting the remainder into paise to continue the division.
Divide Rupees:
\( 47 \text{ Rs.} \div 7 \)
\( 7 \times 6 = 42 \). So, 6 Rs. is the quotient for rupees.
Remainder \( = 47 - 42 = 5 \) Rs.
Convert the remainder 5 Rs. to paise: \( 5 \text{ Rs.} = 5 \times 100 = 500 \text{ paise} \).
Add this to the original paise: \( 500 \text{ paise} + 32 \text{ paise} = 532 \text{ paise} \).
Divide paise:
\( 532 \text{ paise} \div 7 \)
\( 53 \div 7 = 7 \) with remainder \( 4 \).
Bring down \( 2 \), making it \( 42 \).
\( 42 \div 7 = 6 \).
So, 76 paise is the quotient for paise.
Therefore, 47 Rs. 32 paise ÷ 7 = 6 Rs. 76 paise.
In simple words: Divide the rupees part first. Any leftover rupees are changed into paise and added to the original paise. Then, divide the total paise.

🎯 Exam Tip: The key to dividing currency is knowing how to handle the remainder of the rupees. Always convert it to paise and combine with existing paise before continuing division.

Short Answer Type and Essay Type Questions

 

Question 1. Ram went to market with 537 rupees 60 paise to buy vegetable. He bought potato for 158 rupees 80 paise and tomato for 246 rupees and 90 paise. How much money is left with him?
Answer: First, we calculate Ram's total expenditure.
Cost of potato = 158 Rs. 80 paise
Cost of tomato = 246 Rs. 90 paise
Add the paise: \( 80 + 90 = 170 \) paise.
Convert 170 paise to rupees: 1 Rupee 70 paise.
Add the rupees: \( 158 + 246 = 404 \) Rs.
Add the carried-over rupee: \( 404 + 1 = 405 \) Rs.
So, total expenditure = 405 Rs. 70 paise.
Next, we calculate the remaining money.
Total money Ram had = 537 Rs. 60 paise
Total expenditure = 405 Rs. 70 paise
To subtract 70 paise from 60 paise, we borrow 1 Rupee (100 paise) from 537 Rs.
So, 537 Rs. 60 paise becomes 536 Rs. 160 paise.
Subtract paise: \( 160 - 70 = 90 \) paise.
Subtract rupees: \( 536 - 405 = 131 \) Rs.
Therefore, remaining money with Ram = 131 Rs. 90 paise.
In simple words: Add up all the money spent on vegetables first. Then, subtract this total from the money Ram started with to find how much money is still left.

🎯 Exam Tip: When adding or subtracting sums involving rupees and paise, always handle the paise conversion to rupees (and vice versa for borrowing) carefully to avoid errors.

 

Question 2. Price of a table is 826 rupees 40 paise and price of a chair is 545 rupees 70 paise. Find out the total price of 5 tables and 6 chairs.
Answer: First, we calculate the total price of 5 tables.
Price of 1 table = 826 Rs. 40 paise
Price of 5 tables \( = 826.40 \times 5 \)
\( = 4132.00 \) Rs. or 4132 Rs. 00 paise.
Next, we calculate the total price of 6 chairs.
Price of 1 chair = 545 Rs. 70 paise
Price of 6 chairs \( = 545.70 \times 6 \)
\( = 3274.20 \) Rs. or 3274 Rs. 20 paise.
Finally, we add the total price of tables and chairs.
Total price of tables = 4132 Rs. 00 paise
Total price of chairs = 3274 Rs. 20 paise
Add the paise: \( 00 + 20 = 20 \) paise.
Add the rupees: \( 4132 + 3274 = 7406 \) Rs.
Therefore, the total price of 5 tables and 6 chairs = 7406 Rs. 20 paise.
In simple words: First, find the cost of all tables together by multiplying. Then, find the cost of all chairs together by multiplying. Finally, add these two total costs to get the grand total.

🎯 Exam Tip: This problem involves multiple steps: multiplication for each item type and then addition for the final total. Perform each step clearly and keep track of paise conversions.

 

Question 3. If 14 packets of the pen is priced at 986 rupees 22 paise then, find out the price of a packet.
Answer: To find the price of one packet, we divide the total price by the number of packets.
Total price of 14 packets = 986 Rs. 22 paise
Number of packets = 14
Divide Rupees:
\( 986 \text{ Rs.} \div 14 \)
\( 14 \times 70 = 980 \). So, 70 Rs. is the quotient for rupees.
Remainder \( = 986 - 980 = 6 \) Rs.
Convert the remainder 6 Rs. to paise: \( 6 \text{ Rs.} = 6 \times 100 = 600 \text{ paise} \).
Add this to the original paise: \( 600 \text{ paise} + 22 \text{ paise} = 622 \text{ paise} \).
Divide paise:
\( 622 \text{ paise} \div 14 \)
\( 14 \times 44 = 616 \). So, 44 paise is the quotient for paise.
Remainder \( = 622 - 616 = 6 \) paise.
This remainder 6 paise can be ignored for practical purposes, or carried further into fractions of a paise, but typically we stop at paise.
Therefore, the price of one packet of pen = 70 Rs. 44 paise.
In simple words: Divide the total cost by the number of packets. Remember to convert any leftover rupees into paise before continuing to divide the paise.

🎯 Exam Tip: Long division with currency requires careful handling of the rupee remainder, converting it to paise before proceeding with the division of paise. Ensure all steps are shown clearly.

 

Question 4. Rupchand resident of Puskar bought following items from Rajasthan Stationers Krishan Ganj, Ajmer-
(1) 18 Practice notebook, at the rate of 4 rupees 75 paise per notebook.
(2) 1 geometry box, at the rate of 32 rupees.
(3) 10 pencils, at the rate of 1 rupee 25 paise per pencil.
(4) 5 pen, at the rate of 18 rupees per pen.
(5) 1 liter gum, at the rate of 90 rupees 25 paise.
(6) 12 register, at the rate of 30 rupees per register.
(7) 5 diary.
Prepare a bill of the above purchased items.
Answer:

In words - Nine hundred seventy rupees and twenty five paise only.
1. E & OE.
2. Goods once sold will not be taken back or exchanged.
In simple words: To make a bill, list each item with its quantity and rate, then calculate the amount for each. Finally, sum all the individual amounts to get the total bill.

🎯 Exam Tip: When preparing a bill, ensure all calculations for individual items are accurate, and the final total reflects the sum of all item amounts. Include standard bill disclaimers.

 

Question 5. Smt. Kanta Wairagi went to Bharat general store, Dailwas of her locality to purchase things of need. Where she bought 5 kg. rice at the rate of 65 Rs./Kg. 4 liter oil at the rate of 80 Rs./Liter, 500 gram tea at the rate of 240 Rs./Kg., 6 kg. sugar at the rate of 28 Rs./kg. and 500 gram turmeric at the rate of 140 Rs./kg. Prepare a bill made by shopkeeper.
Answer:

In simple words: To create a bill, list each item, its quantity, and its price per unit. Multiply these to get the amount for each item. Then, add all the individual amounts to find the grand total.

🎯 Exam Tip: Pay attention to unit consistency; for example, if the rate is per kg but quantity is in grams (like 500 gram), convert the quantity to kg (0.5 kg) before multiplication.

 

Question 6. Ganesh purchased the following items from "Swadeshi General Store” Bharatpur.
(1) 3 kg rice at the rate of Rs. 40 and 25 paise per kg.
(2) 2 litres of oil at the rate of Rs. 75 and 60 paise per kg.
(3) 4 kg of sugar at the rate of Rs. 41 per kg.
(4) 2 colour boxes at the rate of Rs. 9 per color box.
Find the total expenditure made by Ganesh by making the bill.
Answer:

In words - Four hundred fifty-three rupees and ninety-five paise only.
1. E & OE.
2. Goods once sold will not be taken back or exchanged.
In simple words: For each item, multiply its quantity by its rate to find the individual amount. Then, sum all these individual amounts to calculate Ganesh's total expenditure on the bill.

🎯 Exam Tip: When calculating bills, carefully convert paise to decimal rupees (e.g., 40 Rs. 25 paise = 40.25 Rs.) before multiplying, then convert back for the final total if needed.