RBSE Solutions Class 5 Maths Chapter 10 Currency Exercise 10.1

Get the most accurate RBSE Solutions for Class 5 Mathematics Chapter 10 Currency here. Updated for the 2026-27 academic session, these solutions are based on the latest RBSE textbooks for Class 5 Mathematics. Our expert-created answers for Class 5 Mathematics are available for free download in PDF format.

Detailed Chapter 10 Currency RBSE Solutions for Class 5 Mathematics

For Class 5 students, solving RBSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 10 Currency solutions will improve your exam performance.

Class 5 Mathematics Chapter 10 Currency RBSE Solutions PDF

Question 1. A farmer sells wheat for 2058 rupees and 25 paise and corn for 1154 rupees 50 paise, for how much money he has sold total grain?
Answer: To find the total amount of money the farmer earned, we need to add the money received from selling wheat and corn. We sum up the rupees and paise separately. This helps to keep the calculation clear and avoid mistakes.

 Rs.Paise
Wheat sold205825
Corn sold115450
Total grains sold321275

Therefore, the farmer has sold total grain for Rs. 3212 and 75 paise.
In simple words: The farmer added the money he got from selling wheat and corn. He sold all the grain for a total of Rs. 3212 and 75 paise.
🎯 Exam Tip: When adding amounts with rupees and paise, always add paise first. If the sum of paise is 100 or more, convert 100 paise into 1 rupee and add it to the rupees column.

 

Question 2. A shopkeeper went to market with 8575 rupees and 75 paise. Out of these he paid 5052 rupees 25 paise for clothes and 2070 rupees 25 paise for grocery. Now how much money is left with the shopkeeper?
Answer: First, we need to calculate the total amount of money the shopkeeper spent. This involves adding the cost of clothes and groceries. After finding the total expense, we subtract it from the initial amount of money the shopkeeper had to find out how much is left. This is a common way to manage money.

 Rs.Paise
Cloth bought505225
Grocery bought207025
Total items bought712250
 Rs.Paise
Total Rs. he has857575
Items bought-712250
Money left with him145325

Therefore, Rs. 1453 and 25 paise are left with him.
In simple words: The shopkeeper spent Rs. 7122 and 50 paise in total. From his starting money of Rs. 8575 and 75 paise, he had Rs. 1453 and 25 paise remaining.
🎯 Exam Tip: When subtracting amounts, always start with the paise column. If the paise to be subtracted is more than the available paise, borrow 1 rupee (which is 100 paise) from the rupees column and then perform the subtraction.

 

Question 3. Solve-
(i) 525 Rs. 25 Paise x 13
(ii) 507 Rs. 75 Paise x 16
(iii) 899 Rs. 50 Paise x 17
Answer: We need to multiply the given rupee and paise amounts by the specified numbers. Remember to multiply paise separately, then convert any extra 100 paise into rupees and add it to the rupee total. This ensures correct currency conversion.
(i) 525 Rs. 25 Paise x 13

 Rs.Paise
 52525
\( \times \) 13  
 157575
 525 x25 x
 6825325
+ 3 (325 Paise = 3 Rs. 25 Paise)
Total682825

Therefore, 6828 Rupees 25 Paise.
(ii) 507 Rs. 75 Paise x 16

 Rs.Paise
 50775
\( \times \) 16  
 3042450
 507 x75 x
 81121200
+ 12 (1200 Paise = 12 Rs.)
Total812400

Therefore, 8124 Rs.
(iii) 899 Rs. 50 Paise x 17

 Rs.Paise
 89950
\( \times \) 17  
 6293350
 899 x50 x
 15283850
+ 8 (850 Paise = 8 Rs. 50 Paise)
Total1529150

Therefore, 15291 Rupees 50 Paise.
In simple words: To multiply money, you first multiply the paise by the number. If the paise go over 100, convert them into rupees and add them to the rupee amount, then multiply the rupees and add any extra rupees from the paise.
🎯 Exam Tip: Always keep the rupee and paise calculations separate until the end. Convert excess paise into rupees (100 paise = 1 rupee) only after completing the multiplication in the paise column.

 

Question 4. 13 women of Gorela village got 35755 rupees 20 paise for buying sewing machine under Pradhanmantri Swarojgar Yojna. How much money each woman would have received ?
Answer: To find out how much money each woman received, we need to divide the total amount of money by the number of women. This process helps distribute the total sum equally among them, like sharing a pizza into equal slices. We divide the rupees first, then any remaining amount is converted to paise and divided.

 Rs.Paise
13 )3575520
 -26 
 97 
 -91 
 65 
 -65 
 52 
 -52 
 00 

Each woman received 2750 Rs. 40 Paise.
In simple words: The total money was divided equally among 13 women. Each woman received Rs. 2750 and 40 paise.
🎯 Exam Tip: When dividing money, divide the rupees first. Any remainder in rupees should be converted to paise (multiply by 100) and then added to the existing paise before continuing the division.

 

Question 5. Sujal bought 5 kg. of rice at the rate of 45 rupees 50 paise per kg and 3 kg of sugar at the rate of 28 rupees 60 paise per kg. Now he was left with 245 rupees 60 paise. Find out the total money he had in the begining ?
Answer: To find the total money Sujal had initially, we must first calculate the total cost of the rice and sugar he bought. Then, we add this total cost to the money he had left. This will give us the starting amount, as if we are reversing the spending. It's like adding up all the parts to find the whole.
Cost of 1 kg rice = 45 Rs. 50 paise
Cost of 5 kg rice = 45 Rs. 50 paise \( \times \) 5 = 227 Rs. 50 paise
Cost of 1 kg sugar = 28 Rs. 60 paise
Cost of 3 kg sugar = 28 Rs. 60 paise \( \times \) 3 = 85 Rs. 80 paise
Total cost of items = 227 Rs. 50 paise + 85 Rs. 80 paise = 313 Rs. 30 paise
Money left with Sujal = 245 Rs. 60 paise
Total money he had = Total cost of items + Money left
Total money he had = 313 Rs. 30 paise + 245 Rs. 60 paise = 558 Rs. 90 paise
Therefore, Sujal went to market with 558 Rupees 90 Paise.
In simple words: Sujal spent Rs. 227 and 50 paise on rice and Rs. 85 and 80 paise on sugar. He had Rs. 245 and 60 paise left. So, he started with Rs. 558 and 90 paise.

🎯 Exam Tip: Always break down complex word problems into smaller, manageable steps. Calculate the cost of each item bought first, then find the total spending, and finally, add it to the remaining money to get the initial amount.

 

Question 6. Price of a shirt is 326 rupees 50 paise and price of a pant is 780 rupees 60 paise, find out the total of 3 shirts and 5 pants.
Answer: To find the total cost, we first calculate the cost of 3 shirts by multiplying the price of one shirt by 3. Then, we calculate the cost of 5 pants by multiplying the price of one pant by 5. Finally, we add these two total costs together to get the grand total. This method helps calculate the cost of multiple identical items before summing them up.
Cost of one shirt = 326 Rs. 50 paise
Cost of 3 shirts = 326 Rs. 50 paise \( \times \) 3 = 979 Rs. 50 paise
Cost of one pant = 780 Rs. 60 paise
Cost of 5 pants = 780 Rs. 60 paise \( \times \) 5 = 3903 Rs. 00 paise
Total Price = Cost of 3 shirts + Cost of 5 pants
Total Price = 979 Rs. 50 paise + 3903 Rs. 00 paise = 4882 Rs. 50 paise
Therefore, the total price of 3 shirts and 5 pants = 4882 rupees 50 paise.
In simple words: First, find the cost of 3 shirts (Rs. 979.50) and 5 pants (Rs. 3903.00). Then, add these two amounts together to get the total cost, which is Rs. 4882 and 50 paise.

🎯 Exam Tip: Make sure to correctly multiply each item's price by its quantity before adding the sub-totals. This prevents common errors in calculation.

 

Question 7. A fruit seller went to market with 35916 rupees, from this he has paid 12763 rupees 30 paise for apple, 13243 rupees 30 paise for grapes and 947 rupees 25 paise for banana. Now how much money is left with him ?
Answer: To find the money left with the fruit seller, we first need to sum up all the amounts he paid for apples, grapes, and bananas. This gives us his total spending. Then, we subtract this total spending from the initial amount of money he had. This calculation helps determine the remaining balance after purchases.
Total money fruit seller had = 35916 Rs. 00 paise
Money spent on apples = 12763 Rs. 30 paise
Money spent on grapes = 13243 Rs. 30 paise
Money spent on bananas = 947 Rs. 25 paise
Total money spent = 12763 Rs. 30 paise + 13243 Rs. 30 paise + 947 Rs. 25 paise
Total money spent = 26953 Rs. 85 paise
Money left = Total money had - Total money spent
Money left = 35916 Rs. 00 paise - 26953 Rs. 85 paise

 Rs.Paise
Total money fruit seller had3591600
Money spent in buying fruits-2695385
Money left896215

Therefore, money left with fruit seller is 8962 rupees 15 paise.
In simple words: The fruit seller spent a total of Rs. 26953 and 85 paise on fruits. Since he started with Rs. 35916, he now has Rs. 8962 and 15 paise left.
🎯 Exam Tip: Always make sure to sum up all expenditures accurately before performing the final subtraction. Pay close attention to borrowing from rupees to paise if needed during subtraction.

 

Question 8. Mira has 20974 rupees 80 paise, of these she had spend 10544 rupees 40 paise and remaining amount, she equally divides between her son and daughter. How many rupees each will get?
Answer: First, we need to calculate how much money Mira has left after her spending. This is done by subtracting the spent amount from her initial total. Then, the remaining money is divided equally between her son and daughter, which means we divide it by two. This ensures both children receive the same share, which is a fair way to distribute funds.
Total money Mira has = 20974 Rs. 80 paise
Money Mira spent = 10544 Rs. 40 paise
Money left with her = Total money - Money spent
Money left with her = 20974 Rs. 80 paise - 10544 Rs. 40 paise = 10430 Rs. 40 paise
She wants to divide the remaining amount equally between her son and daughter, so we divide the money by 2.

 Rs.Paise
 521520
2 )1043040
 -10 
 4 
 -4 
 03 
 -2 
 10 
 -10 
 04 
 -4 
 00 

Therefore each son and daughter will get 5215 Rs. 20 paise.
In simple words: Mira had Rs. 10430 and 40 paise left after spending. She divided this money between her two children, so each child received Rs. 5215 and 20 paise.
🎯 Exam Tip: When dividing money, first calculate the remaining amount accurately. Remember to convert any leftover rupees into paise before continuing the division for precise results.

 

Question 9. Price of a cycle is 1075 rupees 50 paise. What will be the price of such 52 cycles ?
Answer: To find the total price of 52 cycles, we need to multiply the price of one cycle by the number of cycles. This is a direct multiplication problem, and it helps us calculate the cost of buying many similar items. We multiply the paise part first, then the rupees, handling any conversions as needed.
Price of one cycle = 1075 Rs. 50 paise
Number of cycles = 52
Price of 52 cycles = 1075 Rs. 50 paise \( \times \) 52

 Rs.Paise
 107550
\( \times \) 52  
 2151100
 53775 x250 x
 559262600
+ 26 (2600 Paise = 26 Rs.)
Total5595200

Therefore, the price of 52 cycles will be Rs. 55952.
In simple words: One cycle costs Rs. 1075 and 50 paise. To find the cost of 52 cycles, we multiply this amount by 52, which gives us a total of Rs. 55952.
🎯 Exam Tip: When multiplying money, first multiply the paise by the given number. Convert any amount over 100 paise into rupees and carry it over to the rupee column before multiplying the rupee amount.

 

Question 10. Add 25081 rupees 75 paise, 70860 rupees 60 paise and 9876 rupees 42 paise.
Answer: To add these amounts, we line up the rupees and paise in their respective columns and add them. Start by adding the paise column first. If the sum of the paise is 100 or more, convert 100 paise to 1 rupee and carry it over to the rupees column before summing the rupees. This method is standard for adding currency.

 Rs.Paise
  (1)
 2508175
 7086060
+987642
Total10581877

The total sum is 105818 rupees 77 paise.
In simple words: We added three different amounts of money. The total came out to be Rs. 105818 and 77 paise.
🎯 Exam Tip: When adding multiple currency amounts, ensure vertical alignment of rupees and paise. Always start adding from the paise column, carrying over any excess (100 paise = 1 rupee) to the rupee column.

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RBSE Solutions Class 5 Mathematics Chapter 10 Currency

Students can now access the RBSE Solutions for Chapter 10 Currency prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Mathematics textbook. Each answer is updated based on the current academic session as per the latest RBSE syllabus.

Detailed Explanations for Chapter 10 Currency

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Where can I find the latest RBSE Solutions Class 5 Maths Chapter 10 Currency Exercise 10.1 for the 2026-27 session?

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Are the Mathematics RBSE solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the RBSE Solutions Class 5 Maths Chapter 10 Currency Exercise 10.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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