CBSE Class 5 Mathematics Revision Worksheet Set 26

I Solve the following-:

Question a). Find the area of a park with length 75 m and breadth 60 m.
Answer: Length of the park (\(l\)) = 75 m
Breadth of the park (\(b\)) = 60 m
Area of a rectangle = \(l \times b\)
Area = \(75\text{ m} \times 60\text{ m} = 4500\text{ m}^2\) (or \(4500\text{ sq.m}\))
In simple words: Multiply the length and breadth of the rectangular park to find its total area.

Exam Tip: Always write the correct square units (like \(\text{m}^2\) or \(\text{sq.m}\)) in your final answer.

Question b). What is the tiled area of the floor of a square room with each side 5.2 m?
Answer: Side of the square room = 5.2 m
Area of a square = \(\text{side} \times \text{side}\)
Area = \(5.2\text{ m} \times 5.2\text{ m} = 27.04\text{ m}^2\) (or \(27.04\text{ sq.m}\))
In simple words: Multiply the side length of the square by itself to get the area.

Exam Tip: When multiplying decimals, count the total number of decimal places in both numbers to place the decimal point correctly in the product.

Question c). Find the area covered by a carpet with length 3.5 m and breadth 2 m.
Answer: Length of the carpet (\(l\)) = 3.5 m
Breadth of the carpet (\(b\)) = 2 m
Area of a rectangle = \(l \times b\)
Area = \(3.5\text{ m} \times 2\text{ m} = 7\text{ m}^2\) (or \(7\text{ sq.m}\))
In simple words: Multiply the length by the breadth to get the area covered by the carpet.

Exam Tip: Ensure both dimensions are in the same unit before multiplying.

Question d). Find the area of a sheet with length 2 m 70 cm and breadth 80 cm.
Answer: Length = 2 m 70 cm = \(200\text{ cm} + 70\text{ cm} = 270\text{ cm}\)
Breadth = 80 cm
Area = \(\text{length} \times \text{breadth}\)
Area = \(270\text{ cm} \times 80\text{ cm} = 21600\text{ cm}^2\) (or \(2.16\text{ m}^2\))
In simple words: Convert the length into centimeters first so that both dimensions have the same unit, then multiply.

Exam Tip: Always convert mixed units into a single uniform unit (either all meters or all centimeters) before calculating area.

Question e). Find the cost of painting a wall with length 7 m and breadth 3 m, if the rate is Rs. 200 per square metre.
Answer: Length of the wall (\(l\)) = 7 m
Breadth of the wall (\(b\)) = 3 m
Area of the wall = \(l \times b = 7\text{ m} \times 3\text{ m} = 21\text{ m}^2$
Rate of painting = Rs. 200 per \(\text{m}^2$
Total cost = \(\text{Area} \times \text{Rate} = 21 \times 200 = \text{Rs. } 4200$
In simple words: First find the area of the wall, then multiply it by the cost of painting one square metre.

Exam Tip: For total cost problems, always calculate the total measurement (area, length, or volume) first and then multiply by the given unit rate.

II Find the area of the following-:

Question (a). [Square with side 4.2 m]
Answer: Side of the square = 4.2 m
Area = \(\text{side} \times \text{side}\)
Area = \(4.2\text{ m} \times 4.2\text{ m} = 17.64\text{ m}^2\)
In simple words: Multiply 4.2 by 4.2 to find the area of the square.

Exam Tip: The area of a square is simply the square of its side length.

Question (b). [Rectangle with length 22 m and breadth 12 m]
Answer: Length (\(l\)) = 22 m
Breadth (\(b\)) = 12 m
Area = \(l \times b\)
Area = \(22\text{ m} \times 12\text{ m} = 264\text{ m}^2\)
In simple words: Multiply the given length and breadth values.

Exam Tip: Double-check multiplication involving two-digit numbers to avoid calculation errors.

Question (c). [Compound rectilinear shape with total bottom width 12 cm, left height 10 cm, top horizontal part 7 cm, middle vertical indentation 5 cm, and right side 5 cm + 5 cm]
Answer: Split the compound figure into two simpler rectangles:
Rectangle 1 (Left vertical part):
Length = 10 cm, Breadth = 7 cm
Area 1 = \(10 \times 7 = 70\text{ cm}^2$
Rectangle 2 (Right vertical extension):
Width = Total bottom width (\(12\text{ cm}\)) - Top width (\(7\text{ cm}\)) = 5 cm
Height = 5 cm
Area 2 = \(5 \times 5 = 25\text{ cm}^2$
Total Area = \(\text{Area 1} + \text{Area 2} = 70 + 25 = 95\text{ cm}^2$
In simple words: Break the complex shape into two standard rectangles, find the area of each, and add them together.

Exam Tip: For complex figures, splitting them into non-overlapping standard rectangles or squares is the easiest method.

Question (d). [T-shaped figure with top horizontal bar 15 cm by 4 cm, and vertical stem 5 cm by 8 cm]
Answer: Split the T-shape into two rectangles:
Rectangle 1 (Top horizontal bar):
Length = 15 cm, Breadth = 4 cm
Area 1 = \(15 \times 4 = 60\text{ cm}^2$
Rectangle 2 (Vertical stem):
Length = 5 cm, Breadth = 8 cm
Area 2 = \(5 \times 8 = 40\text{ cm}^2$
Total Area = \(\text{Area 1} + \text{Area 2} = 60 + 40 = 100\text{ cm}^2$
In simple words: Calculate the area of the top horizontal strip and the vertical stem separately, then add both values.

Exam Tip: Clearly mark the dotted dividing line on your diagram to show how you split the shape.

III (a) How many square centimetres (\(\text{sq.cm}\)) make one square metre (\(\text{sq.m}\))?

Question III (a). How many square centimetres (\(\text{sq.cm}\)) make one square metre (\(\text{sq.m}\))?
Answer: \(1\text{ m} = 100\text{ cm}$
\(1\text{ sq.m} = 1\text{ m} \times 1\text{ m} = 100\text{ cm} \times 100\text{ cm} = 10000\text{ sq.cm}$
Therefore, 10000 square centimetres make one square metre.
In simple words: Since 1 metre equals 100 centimetres, multiply 100 by 100 to find how many square centimetres fit in one square metre.

Exam Tip: Remember that when converting units of area, you must square the linear conversion factor (\(100 \times 100\), not just 100).

Question III (b). \(4\text{ sq.m} = \underline{ \quad 40000 \quad } \text{ sq.cm}\)
[ Hint : \(4\text{ sq.m} = 2\text{ m} \times 2\text{ m}\) ]
Answer: \(1\text{ sq.m} = 10000\text{ sq.cm}$
\(4\text{ sq.m} = 4 \times 10000\text{ sq.cm} = 40000\text{ sq.cm}$
In simple words: Multiply 4 by 10000 to convert square metres into square centimetres.

Exam Tip: Always multiply by 10000 when converting from \(\text{m}^2\) to \(\text{cm}^2\).

Question III (c). Find the area of the shaded part -:
[ Hint : Let the area of each square be \(1\text{ sq.unit}\) ]
Answer: Total number of grid squares in the given figure = 12 squares
Number of fully shaded squares = 4 squares
Number of half-shaded squares = 4 squares (which equals \(4 \times \frac{1}{2} = 2\) full squares)
Total shaded area = \(4 + 2 = 6\text{ sq.units}$
In simple words: Count the full shaded squares and combine the half-shaded squares to find the total shaded area.

Exam Tip: Two half-squares count as one complete square unit when calculating area by grid counting.

Please refer to attached file for CBSE Class 5 Maths Revision Worksheets (3)