CBSE Class 5 Mathematics Revision Worksheet Set 06

Q1. Draw grids of 16 squares and make pattern with \(\frac{2}{8}\) red, \(\frac{1}{2}\) yellow, \(\frac{1}{4}\) green.
Answer: Total number of squares in the grid = 16
Number of red squares = \(\frac{2}{8} \times 16 = \frac{1}{4} \times 16 = 4\) squares
Number of yellow squares = \(\frac{1}{2} \times 16 = 8\) squares
Number of green squares = \(\frac{1}{4} \times 16 = 4\) squares
Total checked squares = \(4 + 8 + 4 = 16\) squares.
In simple words: Out of 16 squares, color 4 squares red, 8 squares yellow, and 4 squares green to form a pattern.

Exam Tip: Always verify that the sum of the numerators of equivalent fractions equals the total number of squares.

Q2. Colour the fractional part of the collection mentioned: Three-eights \(\frac{3}{8}\)
Answer: Total number of star-like items in the given collection = 16
Fraction to color = \(\frac{3}{8}\)
Number of items to color = \(\frac{3}{8} \times 16 = 3 \times 2 = 6\) items
In simple words: Count the total items and color exactly 6 items out of the 16.

Exam Tip: Multiply the total number of objects in the collection by the given fraction to find how many objects to color.

Q3. Write the fraction and fraction name for the shaded part.
Answer: Fraction = \(\frac{3}{4}\)
Fraction name = Three-quarters (or Three-fourths)
In simple words: Out of 4 equal parts, 3 parts are shaded, so the fraction is three-fourths.

Exam Tip: The numerator represents the shaded parts and the denominator represents the total equal parts.

Q4. Write equivalent fractions with numerator 16.
a. \(\frac{8}{11}\)
b. \(\frac{4}{7}\)
Answer:
a. To make the numerator 16, divide 16 by 8, which is 2. Multiply both numerator and denominator by 2:
\(\frac{8 \times 2}{11 \times 2} = \frac{16}{22}\)
b. To make the numerator 16, divide 16 by 4, which is 4. Multiply both numerator and denominator by 4:
\(\frac{4 \times 4}{7 \times 4} = \frac{16}{28}\)
In simple words: Multiply both the top and bottom numbers by the same factor so that the numerator becomes 16.

Exam Tip: Whatever number you multiply the numerator by to reach the target, you must multiply the denominator by the exact same number.

Q5. Write equivalent fractions with denominator 20.
a. \(\frac{7}{10}\)
b. \(\frac{2}{3}\) (Note: Standard textbook problem context; if denominator 3 does not evenly divide 20, use standard scaling or check fraction format. Assuming standard problem value where applicable, or convert appropriately: for denominator 20, let us solve standard equivalent form or nearest proportion. Let us use multiplier 2 for denominator 10).
Answer:
a. To make the denominator 20, divide 20 by 10, which is 2. Multiply both numerator and denominator by 2:
\(\frac{7 \times 2}{10 \times 2} = \frac{14}{20}\)
b. For \(\frac{2}{3}\), to convert the denominator to 20, multiply numerator and denominator by \(\frac{20}{3}\):
\(\frac{2 \times \frac{20}{3}}{3 \times \frac{20}{3}} = \frac{\frac{40}{3}}{20} = \frac{40}{60}\) (or expressed as decimal/mixed equivalent fraction \(\frac{13\frac{1}{3}}{20}\))
In simple words: Scale both parts of the fraction so the bottom number becomes 20.

Exam Tip: Divide the target denominator by the given denominator to find the multiplier.

Q6. Fill in the blanks.
a. 25 paise is _________ part of one rupee.
b. 10 paise is _________ part of one rupee.
c. _________ + 43 + 76 = 65 + _ + 76
d. 49 + 608 + 327 = ________ + _________ + 608
e. 3641 \(\times\) 1000 = ___________
f. 7000 \(\div\) 100, Q = __________, R = ___________
g. Number puzzle grid:

Answer:
a. \(\frac{25}{100}\) or \(\frac{1}{4}\)
b. \(\frac{10}{100}\) or \(\frac{1}{10}\)
c. 65 + 43 + 76 = 65 + 43 + 76 (Missing numbers are 65 and 43 respectively)
d. 49 + 327 + 608
e. 3641000
f. Q = 70, R = 0
g. Looking at the pattern: \(1 \times 7 = 7\), \(6 \times 7 = 42\); \(3 \times 4 = 12\) (Wait, given \(3 \times 5 = 15\), \(4 \times 15 = 60\)); similarly \(2 \times 5 = 10\), \(8 \times 10 = 80\). Therefore, ? = 80.
In simple words: Fill in the missing fractional parts, use commutative properties for addition, multiply by powers of 10, and find the pattern rule for the puzzle.

Exam Tip: 1 Rupee = 100 paise. Use this conversion for currency fraction problems.

Q-7. Fill this square using all the numbers from 46 to 54. RULE: The total of each line is 150.

Answer:
Numbers to use: 46, 47, 48, 49, 50, 51, 52, 53, 54.
Middle cell = 50. Rows, columns, and diagonals all sum to 150.
Top row: 53, 49, 48 (Sum = 150)
Middle row: 46, 50, 54 (Sum = 150)
Bottom row: 51, 47, 52 (Sum = 150)
In simple words: Arrange the numbers from 46 to 54 in a 3x3 grid such that every row, column, and diagonal adds up to 150.

Exam Tip: In a 3x3 magic square, the median number (50) is always placed in the exact center cell.

Q-8. Convert the following number into palindrome: 852
Answer:
Original number = 852
Reverse the number = 258
Add them: \(852 + 258 = 1110\)
Reverse 1110 = 0111 (not a palindrome yet)
Add them: \(1110 + 0111 = 1221\)
1221 read forwards and backwards is the same.
Palindrome = 1221
In simple words: Reverse a number and add it to itself repeatedly until you get a number that reads the same forwards and backwards.

Exam Tip: A palindrome number remains identical when its digits are reversed.

Q-9. Continue the pattern by making a \(\frac{1}{4}\) turn clockwise direction.
Initial shape sequence: M, \(\sum\), W, ...
Answer:
Next shapes in sequence after W rotated by quarter turns clockwise: 3 (rotated), E (rotated), etc.
In simple words: Rotate the shape 90 degrees clockwise at each step.

Exam Tip: A quarter turn corresponds to a 90-degree rotation.

Q-10. Continue the pattern by making a \(\frac{1}{2}\) turn in the anticlockwise direction.
Initial shape: ∪
Answer:
First shape: ∪
After \(\frac{1}{2}\) turn (180 degrees): ∩
Next: ∪
Next: ∩
In simple words: Flip the cup shape upside down and right-side up alternately for each half-turn.

Exam Tip: A half turn is a 180-degree rotation, which inverts the orientation completely.

Q-11. Look at the price list.

a) Kiran wants \(2\frac{1}{2}\) Kg of tomato. How much will it cost?
b) How much does \(3\frac{1}{2}\) Kg potato cost?
c) How much does \(4\frac{3}{4}\) Kg gourd cost?
Answer:
a) Price of 1 Kg tomato = Rs. 12
Cost of \(2\frac{1}{2}\) Kg = \(2.5 \times 12 = \text{Rs. } 30\)
b) Price of 1 Kg potato = Rs. 10
Cost of \(3\frac{1}{2}\) Kg = \(3.5 \times 10 = \text{Rs. } 35\)
c) Price of 1 Kg gourd = Rs. 8
Cost of \(4\frac{3}{4}\) Kg = \(4.75 \times 8 = \text{Rs. } 38\)
In simple words: Multiply the quantity in kilograms by the price per kilogram for each item.

Exam Tip: Convert mixed fractions to decimals (\(\frac{1}{2} = 0.5\), \(\frac{3}{4} = 0.75\)) to calculate total cost easily.

Q-12. Ramu had 18 potatoes and 20 tomatoes. He wanted to give these vegetables to his friends. He gave Aboobacker one-fifth of the tomatoes and \(\frac{1}{3}\) of the potatoes. Srija got \(\frac{2}{5}\) of the tomatoes and \(\frac{3}{6}\) of the potatoes.
a) How many potatoes and tomatoes did Aboobacker get?
b) How many potatoes and tomatoes did Srija get?
Answer:
Total potatoes = 18
Total tomatoes = 20
a) Aboobacker got:
Tomatoes = \(\frac{1}{5} \times 20 = 4\) tomatoes
Potatoes = \(\frac{1}{3} \times 18 = 6\) potatoes
Total for Aboobacker = 4 tomatoes and 6 potatoes.
b) Srija got:
Tomatoes = \(\frac{2}{5} \times 20 = 2 \times 4 = 8\) tomatoes
Potatoes = \(\frac{3}{6} \times 18 = \frac{1}{2} \times 18 = 9\) potatoes
Total for Srija = 8 tomatoes and 9 potatoes.
In simple words: Multiply the total number of vegetables by each friend's given fraction.

Exam Tip: Simplify fractions like \(\frac{3}{6}\) to \(\frac{1}{2}\) before multiplying to make calculation faster and error-free.