CBSE Class 4 Maths Subtraction Worksheet Set 01

Mental Ability

Question 1. Choose the correct option :
1. The product of one hundred and fifty
(a) 500
(b) 5000
(c) 1500
2. The number left after division is called
(a) Quotient
(b) sum
(c) remainder
3. Two numbers multiplied in any order give the same
(a) Product
(b) quotient
(c) difference
4. When any number is divided by zero the answer is
(a) Zero
(b) infinity
(c) same
5. When one is subtracted from a no. we get the ________ number
(a) Previous
(b) odd
(c) next
Answer:
1. (b) 5000
2. (c) remainder
3. (a) Product
4. (b) infinity
5. (a) Previous
In simple words: Multiplying 100 by 50 gives 5000. The leftover part in division is the remainder. Changing the order in multiplication gives the same result. Subtracting 1 gives the number that comes just before.

Exam Tip: Learn basic math terms like product, quotient, and remainder by heart so you can solve objective questions quickly.

Question 2. Put the correct sign >, <, =
1. 4455 - 1 _____ 4458
2. 1325 x 1 _____ 1300 + 25
3. 496 ÷ 4 _____ 100 ÷ 2
4. 3299 - 1 _____ 500 x 2
5. 1091 - 1000 _____ 13 x 7
Answer:
1. \( 4455 - 1 = 4454 \), and \( 4454 < 4458 \). So, the sign is <.
2. \( 1325 \times 1 = 1325 \), and \( 1300 + 25 = 1325 \). So, the sign is =.
3. \( 496 \div 4 = 124 \), and \( 100 \div 2 = 50 \). Since \( 124 > 50 \), the sign is >.
4. \( 3299 - 1 = 3298 \), and \( 500 \times 2 = 1000 \). Since \( 3298 > 1000 \), the sign is >.
5. \( 1091 - 1000 = 91 \), and \( 13 \times 7 = 91 \). So, the sign is =.
In simple words: Work out the values on both sides first. Then choose the correct sign to show which side is bigger or if they match.

Exam Tip: Never guess the sign by looking at the numbers; always solve both sides on rough paper before writing your answer.

Question 3. Match the following :
1. Bigger no. in subtraction    quotient
2. The no. which divides    multiplicand
3. The no. to be multiplied    dividend
4. Answer of division    minuend
Answer:
1. Bigger no. in subtraction - minuend
2. The no. which divides - dividend
3. The no. to be multiplied - multiplicand
4. Answer of division - quotient
In simple words: The minuend is the larger number you subtract from. The multiplicand is the number you multiply. The quotient is the answer you get after dividing.

Exam Tip: Remember the roles in arithmetic operations: minuend comes first in subtraction, and quotient is always the final result of division.

Question 4. Solve mentally :
1. 9999 - 100 =
2. _____ - 1 = 4815
3. 2000 x 10 x 5 =
4. 1080 ÷ 12 =
5. _____ + 6 = 71
6. 14 x 0 x 68 =
7. 32 x 1000 =
Answer:
1. \( 9999 - 100 = 9899 \)
2. \( 4816 - 1 = 4815 \)
3. \( 2000 \times 10 \times 5 = 20000 \times 5 = 100000 \)
4. \( 1080 \div 12 = 90 \)
5. \( 65 + 6 = 71 \) (since \( 71 - 6 = 65 \))
6. \( 14 \times 0 \times 68 = 0 \)
7. \( 32 \times 1000 = 32000 \)
In simple words: Multiplying any group of numbers by zero makes the final answer zero. When you multiply by 1000, simply write three zeros at the end.

Exam Tip: Look out for zero in a multiplication chain - no matter how large the other numbers are, the product is always zero.

Concept

Question 1. Fill in the blanks :
1. When we divide any no. by 1 , the quotient is the ________ itself.
2. The answer of multiplication is called _________.
3. Dividend = Divisor x ________ + _________
4. The remainder is always less than the _________.
5. If we subtract a no. from its ________ we get 1 as the answer.
Answer:
1. number
2. product
3. Quotient, Remainder
4. divisor
5. successor
In simple words: Any number divided by 1 stays the same. The answer to a multiplication problem is the product. The remainder must always be smaller than the divisor.

Exam Tip: Memorize the division relation formula: \( \text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder} \). It is very common in fill-in-the-blank questions.

Question 2. Divide and check your answer :
4988 ÷ 9
Answer:
Dividing 4988 by 9:
- \( 49 \div 9 = 5 \) with a remainder of 4.
- Bring down 8 to make 48; \( 48 \div 9 = 5 \) with a remainder of 3.
- Bring down 8 to make 38; \( 38 \div 9 = 4 \) with a remainder of 2.

So, Quotient = 554 and Remainder = 2.

Check:
\( \text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder} \)
\( = (9 \times 554) + 2 \)
\( = 4986 + 2 \)
\( = 4988 \)
Since the calculated value matches the dividend, the answer is correct.
In simple words: Divide step by step to find the quotient and remainder. Multiply the quotient by the divisor and add the remainder to check if you get the original number back.

Exam Tip: Always show both the long division steps and the check formula clearly to get full marks.

Question 3. Solve the following :
a) 625 x 130
b) 34210 x 12
Answer:
a) \( 625 \times 130 \)
First, multiply 625 by 13:
\( 625 \times 3 = 1875 \)
\( 625 \times 10 = 6250 \)
\( 1875 + 6250 = 8125 \)
Now, multiply by 10:
\( 8125 \times 10 = 81250 \)
So, \( 625 \times 130 = 81250 \).

b) \( 34210 \times 12 \)
Multiply step by step:
\( 34210 \times 2 = 68420 \)
\( 34210 \times 10 = 342100 \)
Add both values:
\( 68420 + 342100 = 410520 \)
So, \( 34210 \times 12 = 410520 \).
In simple words: Break the multiplier into simpler parts, multiply each part, and add the products together.

Exam Tip: Be careful with digit alignment when adding partial products in two-digit multiplication.

Question 4. Subtract 254806 from 523145
Answer:
Arrange the numbers in columns according to their place values:
\[ \begin{array}{r@{\quad}l} 523145 \\ -\, 254806 \\ \hline 268339 \end{array} \]
Step-by-step subtraction:
- Ones place: Borrow 1 from tens; \( 15 - 6 = 9 \).
- Tens place: \( 3 - 0 = 3 \).
- Hundreds place: Borrow 1 from thousands; \( 11 - 8 = 3 \).
- Thousands place: Borrow 1 from ten-thousands; \( 12 - 4 = 8 \).
- Ten-thousands place: Borrow 1 from lakhs; \( 11 - 5 = 6 \).
- Lakhs place: \( 4 - 2 = 2 \).

The final difference is 268339.
In simple words: Line up the numbers by their place values and borrow from the next column whenever the top digit is smaller than the bottom digit.

Exam Tip: Cross out borrowed numbers cleanly and write the new reduced digits above them to avoid subtraction mistakes.

Problem Solving

Question 1. Find the difference between the place values of 4 in 54218 and 67401.
Answer:
In the number 54218, the digit 4 is at the thousands place.
So, its place value is \( 4 \times 1000 = 4000 \).

In the number 67401, the digit 4 is at the hundreds place.
So, its place value is \( 4 \times 100 = 400 \).

Now, find the difference:
\( \text{Difference} = 4000 - 400 = 3600 \).

Thus, the difference between the place values is 3600.
In simple words: Find the place value of 4 in each number first. Then take away the smaller value from the larger value.

Exam Tip: Do not confuse place value with face value; place value depends on the position of the digit in the number.

Question 2. If 6098 people travel by air from Delhi every day , how many people travelled in the month of January ?
Answer:
Number of people travelling each day = 6098
Number of days in January = 31

Total number of people who travelled in January:
\( = 6098 \times 31 \)

Working out the multiplication:
\( 6098 \times 1 = 6098 \)
\( 6098 \times 30 = 182940 \)
\( 6098 + 182940 = 189038 \)

Therefore, 189038 people travelled in January.
In simple words: January has 31 days. Multiply the number of travellers in one day by 31 to find the total for the whole month.

Exam Tip: Always state the exact number of days in the given month clearly as your first step.

Question 3. 5475 posters of the President were displayed in 25 villages. How many Posters were displayed in 1 village ?
Answer:
Total number of posters = 5475
Total number of villages = 25

Number of posters displayed in 1 village:
\( = 5475 \div 25 \)

Performing long division:
- \( 54 \div 25 = 2 \) with a remainder of 4.
- Bring down 7 to make 47; \( 47 \div 25 = 1 \) with a remainder of 22.
- Bring down 5 to make 225; \( 225 \div 25 = 9 \) with a remainder of 0.

\( 5475 \div 25 = 219 \)

Therefore, 219 posters were displayed in 1 village.
In simple words: Share the total number of posters equally among all 25 villages by dividing 5475 by 25.

Exam Tip: When a word problem gives a total for many items and asks for one item, use division.

Question 4. The population of a town was 76,419. The number of males were 41,210 and the number of females were 22, 679. Find the number of children in the town.
Answer:
Total population of the town = 76419
Number of males = 41210
Number of females = 22679

Total number of adults (males + females):
\( = 41210 + 22679 = 63889 \)

Now, subtract the number of adults from the total population to find the number of children:
\( \text{Number of children} = 76419 - 63889 \)
\[ \begin{array}{r@{\quad}l} 76419 \\ -\, 63889 \\ \hline 12530 \end{array} \]

Therefore, there were 12530 children in the town.
In simple words: Add the number of men and women together. Then subtract that sum from the total town population to find how many children there are.

Exam Tip: For multi-step word problems, write a separate statement for each step so the examiner can award step marks even if a minor addition error occurs.

Q1) Solve :-

a) 10088—9999

b) 3185 + 4815 – 5348

c) 40001 – 18993

d) 79123 – 18775

e) 43hundreds from 7 thousands

Q2) fill in the boxes :-

a) Th   H   T   O
       __  2   0   5
    - 3  __ __ __
___________________
       5   3   3   2

b) 8    __   8   3    8
     __ __  __  __  __

Q3) Put > , < , or =

a) 1091 – 1000 _____ 90+1

b) 5968 – 200 _____ 4000 + 1625

c) 736 + 100 _____ 936

Q4) Write the number which is

a) 9 less than greatest 5 digit number

b) 840 less than 400568

Q5) What must be added to 850050 to get the greatest 5 digit number

Q6) The population of a town is 128600 . If there are 64300 males . Find the number of females in town

Q7) The sum of two number is 7030 . If one number is 6693.Find the other number