CBSE Class 4 Maths Revision Worksheet Set 10

Section A

Q1. Tick the correct option.
a) When 1568 is added to 5861, the digit in the tens place of the sum is
(a) 2
(b) 7
(c) 9
Answer: (b) 7
First, perform the addition: \(5861 + 1568 = 7429\).
Looking at the digits of 7429 from right to left: 9 is in the ones place, 2 is in the tens place, 4 is in the hundreds place, and 7 is in the thousands place.
Therefore, the digit in the tens place is 2... wait, let us re-verify: \(5861 + 1568 = 7429\). The tens digit is 2. Let us check the options again: (a) 2, (b) 7, (c) 9. The correct option is (a) 2.
In simple words: Add the two numbers and check the second digit from the right.

Exam Tip: Always align numbers properly by their place values before adding to avoid careless addition errors.

b) Successor of the largest 5 digit number is
(a) 10001
(b) 100000
(c) 10000
Answer: (b) 100000
The largest 5-digit number is 99,999. The successor is found by adding 1 to the number: \(99999 + 1 = 100000\), which is one lakh (the smallest 6-digit number).
In simple words: The successor is the very next number obtained by adding 1.

Exam Tip: Successor means number + 1; predecessor means number - 1.

c) Smallest 5 digit number using the digits 3, 0, 1, 7 and 5 is
75130
01357
10357
Answer: 10357
To form the smallest 5-digit number using given digits, arrange the non-zero digits in ascending order starting with the smallest non-zero digit as the first digit, place 0 at the second position, and continue with the remaining digits in ascending order: 1, 0, 3, 5, 7 forms 10357.
In simple words: Arrange digits from smallest to largest, but never put 0 at the extreme left.

Exam Tip: A 5-digit number cannot start with 0, so 0 is placed in the second place from the left.

d) 100 lakhs = 1 crore
(a) True
(b) False
Answer: (a) True
In the Indian numbering system, 1 crore equals 100 lakhs (\(1,00,00,000\)).
In simple words: One hundred lakhs make one crore.
Exam Tip: Memorize the Indian place value chart relation: 100 thousands = 1 lakh, 100 lakhs = 1 crore.

e) Digit at the ten crores place in the number 35,67,03,809 is
(a) 3
(b) 5
(c) 8
Answer: (a) 3
Let us write the place values for 35,67,03,809 from right to left:
9 = Ones, 0 = Tens, 8 = Hundreds, 3 = Thousands, 0 = Ten thousands, 6 = Lakhs, 7 = Ten lakhs, 5 = Crores, 3 = Ten crores.
Therefore, the digit at the ten crores place is 3.
In simple words: Count the place values carefully from right to left up to ten crores.

Exam Tip: Use commas according to the Indian system (3,56,70,3809) to easily read large place values.

f) 1 lakh + 2 thousand + 2 ones
(a) 102002
(b) 1002002
(c) 1002020
Answer: (a) 102002
1 lakh = 1,00,000
2 thousand = 2,000
2 ones = 2
Sum = \(100000 + 2000 + 2 = 102002\).
In simple words: Add the expanded place values to get the standard numeral.

Exam Tip: Watch out for missing place values (like hundreds and tens) and fill them with zeros.

Q2. Answer the following
(a) Insert the commas and write the number name according to International Place Value System for 876090900
Answer:
With commas inserted according to the International system: 876,090,900
Number Name: Eight hundred seventy-six million, ninety thousand, nine hundred.
In simple words: Group digits in threes from the right in the International system.

Exam Tip: In the International system, commas are placed after every three digits from the right (thousands, millions, billions).

(b) Expand the following: 9,92,29,390
Answer:
\(9,00,00,000 + 90,00,000 + 2,00,000 + 20,000 + 9,000 + 300 + 90\)
In simple words: Write each digit multiplied by its place value and put a plus sign between them.

Exam Tip: Check that the number of zeros matches the place value for each term.

(c) Short form of 30,00,000 + 400,000 + 4000 + 40
Answer:
\(30,00,000 + 4,00,000 + 4,000 + 40 = 34,04,040\)
In simple words: Combine all the expanded parts into a single standard number.

Exam Tip: Insert zeros for any place values that are skipped in the expansion.

Q3. (a) Arrange in the descending order (Put sign): 3,23,71,195; 3,32,17,195; 3,91,591; 3,32,19,195
Answer:
Descending order means arranging from greatest to smallest.
Comparing the numbers: 3,91,591 has 7 digits (smallest). The others have 8 digits.
Comparing the 8-digit numbers:
- 3,32,19,195
- 3,32,17,195
- 3,23,71,195
Arranged in descending order: \(3,32,19,195 > 3,32,17,195 > 3,23,71,195 > 3,91,591\).
In simple words: Start with the largest number and end with the smallest using the greater-than sign.

Exam Tip: Count the number of digits first; numbers with fewer digits are smaller.

(b) Numeral for Seventy Six Lakhs Seventy Nine Thousand and Seventy.
Answer:
Seventy Six Lakhs = 76,00,000
Seventy Nine Thousand = 79,000
Seventy = 70
Numeral = 76,79,070
In simple words: Translate the number names into digits according to Indian periods and add them up.

Exam Tip: Ensure hundreds place has a zero since no hundreds were mentioned.

Section B

Q4. Fill in the blanks.

(a) \(909 \div 0 =\) _____
Answer: Not defined (or Division by zero is not possible)
In simple words: You cannot divide any number by zero.

Exam Tip: Remember that division by zero is undefined in mathematics.

(b) \(40 \times 500 =\) _____
Answer: 20000
Multiply non-zero digits: \(4 \times 5 = 20\), then append three zeros: 20,000.
In simple words: Multiply the base numbers and attach all the zeros from both factors.

Exam Tip: Count the total number of zeros at the end of the factors and place them in the product.

(c) \(89079 \div 1000\), Q = _____, R = _____
Answer: Q = 89, R = 79
Dividing by 1000 shifts the decimal point three places to the left. The quotient is the thousands part (89) and the remainder is the last three digits (79).
In simple words: When dividing by 1000, the last three digits form the remainder and the rest form the quotient.

Exam Tip: For powers of 10 like 10, 100, 1000, use the shortcut rule for quotient and remainder.

(d) \(11623 + 3261 = 3261 +\) _____
Answer: 11623
By the commutative property of addition (\(a + b = b + a\)), the missing number is 11,623.
In simple words: Changing the order of addends does not change the sum.

(e) 10 more than 68990 is _____
Answer: 69000
\(68990 + 10 = 69000\).
In simple words: Add 10 to the given number.
Exam Tip: The phrase "more than" always indicates addition.

(f) _____ - 0 = 9078
Answer: 9078
Subtracting 0 from any number leaves the number unchanged, so the missing number is 9078.
In simple words: Any number minus zero equals itself.

Exam Tip: Use the inverse operation if needed: \(9078 + 0 = 9078\).

Q5. (a) Arrange and add 96234, 89275 and 1098
Answer:
Arrange numbers vertically by place value:
9 6 2 3 4
+ 8 9 2 7 5
+ 1 0 9 8
------------
Step 1: Ones place: \(4 + 5 + 8 = 17\) (write 7, carry 1)
Step 2: Tens place: \(3 + 7 + 9 + 1 (\text{carry}) = 20\) (write 0, carry 2)
Step 3: Hundreds place: \(2 + 2 + 0 + 2 (\text{carry}) = 6\) (write 6)
Step 4: Thousands place: \(6 + 9 + 1 = 16\) (write 6, carry 1)
Step 5: Ten thousands place: \(9 + 8 + 0 + 1 (\text{carry}) = 18\) (write 18)
Sum = 1,86,607
In simple words: Line up the digits by place value from right to left and add column by column with carrying.

Exam Tip: Keep columns straight so you do not add digits from different place values.

(b) Subtract 30,929 from 49000
Answer:
4 9 0 0 0
- 3 0 9 2 9
------------
Borrowing across zeros:
\(49000 - 30929 = 18071\).
In simple words: Borrow carefully from neighboring columns when subtracting from numbers with trailing zeros.

Exam Tip: Double check subtraction by adding the difference to the smaller number to see if you get the greater number.

(c) Find the product 60938 and 867
Answer:
Multiply 60,938 by each digit of 867 (7, 6, and 8):
- \(60938 \times 7 = 426566\)
- \(60938 \times 60 = 3656280\)
- \(60938 \times 800 = 48750400\)
Sum = \(426566 + 3656280 + 48750400 = 52833246\)
In simple words: Multiply the multi-digit number by each digit of the multiplier starting from the ones place and add the partial products.

(d) Find the Quotient and Remainder: \(90039 \div 45\)
Answer:
Perform long division of 90,039 by 45:
- \(45 \times 2 = 90\) (subtract from 90, bring down 0)
- Bring down 3 (45 cannot divide 3, write 0 in quotient, bring down 9)
- Number becomes 39 (45 cannot divide 39, write 0 in quotient, remainder is 39)
Quotient = 2000, Remainder = 39. (Check: \(45 \times 2000 + 39 = 90000 + 39 = 90039\)).
In simple words: Divide step-by-step, placing zeros in the quotient when a digit is too small to divide.

Exam Tip: Always verify division using the relation: \(\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}\).

Q6. (a) The difference of two numbers is 42321. If the greater number is 934567, find the smaller number.
Answer:
Greater number = 9,34,567
Difference = 42,321
Smaller number = Greater number - Difference
9 3 4 5 6 7
- 0 4 2 3 2 1
-------------
8 9 2 2 4 6
Smaller number = 8,92,246.
In simple words: Subtract the difference from the greater number to find the smaller number.

Exam Tip: In subtraction word problems involving difference, subtract the difference from the given greater number to find the unknown smaller number.

(b) What number is 3527 more than 89235?
Answer:
Number = \(89235 + 3527\)
8 9 2 3 5
+ 0 3 5 2 7
------------
9 2 7 6 2
The required number is 92,762.
In simple words: Add the given amount to the base number.

Exam Tip: The phrase "more than" always means addition.

Q7. Solve the following (write statement)

(a) The sales turnover of a company in 2010 was 8962574. In the year 2011 the sale was 9867123. In which year the sale was more and by how much.
Answer:
Sales in 2011 = 9,867,123
Sales in 2010 = 8,962,574
Comparing the two values, \(9,867,123 > 8,962,574\).
Therefore, the sale was more in the year 2011.
To find by how much, subtract the sales of 2010 from the sales of 2011:
9 8 6 7 1 2 3
- 8 9 6 2 5 7 4
---------------
0 9 0 4 5 4 9
Difference = 9,04,549.
The sale was more in 2011 by 9,04,549.
In simple words: Compare the numbers to find which is larger, then subtract to find the difference.

Exam Tip: Statement problems require clear concluding sentences stating both answers clearly.

(b) Badminton Tournament were played over 39 days. If 8999 people came each day, how many people came for the tournament?
Answer:
Number of days = 39
Number of people who came each day = 8,999
Total people = \(8999 \times 39\)
Calculate \(8999 \times 39\):
\(8999 \times (40 - 1) = (8999 \times 40) - (8999 \times 1) = 359960 - 8999 = 350,961\).
Total people who came for the tournament = 3,50,961.
In simple words: Multiply the daily attendance by the total number of days.

Exam Tip: Use distributive multiplication shortcuts (like multiplying by 40 and subtracting 1) to save time and reduce calculation errors.

(c) There were 93510 sheep. How many enclosures will be required if 15 sheep are kept in one enclosure?
Answer:
Total number of sheep = 93,510
Sheep in one enclosure = 15
Number of enclosures required = \(93510 \div 15\)
Perform long division: \(93510 \div 15 = 6234\).
Total enclosures required = 6,234.
In simple words: Divide the total number of sheep by the capacity of one enclosure.

Exam Tip: Division problems dealing with grouping or packing always require dividing the total quantity by the group size.

Q8. The rent of a house for 1 year is Rs. 48120. Find the rent of the house for 9 months?
Answer:
Rent for 1 year (12 months) = Rs. 48,120
Rent for 1 month = \(48120 \div 12 = \text{Rs. } 4010\)
Rent for 9 months = \(4010 \times 9 = \text{Rs. } 36,090\).
In simple words: First find the rent for 1 month by dividing by 12, then multiply by 9.

Exam Tip: Unitary method problems always require finding the value of a single unit first.

Section C

Q9. Tick the correct option.
(a) The number which is divisible by 4 is
(a) 2782
(b) 2000
(c) 1093
Answer: (b) 2000
A number is divisible by 4 if the number formed by its last two digits is divisible by 4. For 2000, the last two digits are 00, which is divisible by 4.
In simple words: Check if the last two digits form a number divisible by 4.

Exam Tip: Divisibility rule for 4: last two digits must be divisible by 4.

(b) 12th Multiple of 12 is
(a) 24
(b) 144
(c) 120
Answer: (b) 144
The 12th multiple of 12 is calculated as \(12 \times 12 = 144\).
In simple words: Multiply 12 by 12.

Exam Tip: Learn your multiplication tables up to 20 to answer directly.

(c) The next odd number after 47999 is
(a) 47991
(b) 479001
(c) 48001
Answer: (c) 48001
The number 47,999 is an odd number. The very next odd number is obtained by adding 2: \(47999 + 2 = 48001\).
In simple words: Add 2 to an odd number to get the next odd number.

Exam Tip: Adding 1 to an odd number gives an even number; adding 2 gives the next consecutive odd number.

(d) 51 is a Prime number
(a) True
(b) False
Answer: (b) False
51 is divisible by 1, 3, 17, and 51 (\(3 \times 17 = 51\)). Since it has factors other than 1 and itself, it is a composite number, not a prime number.
In simple words: 51 can be divided by 3 and 17, so it is composite.

(e) Smallest multiple of 375 is
(a) \(375 \times 9\)
(b) 1
(c) 100
Answer: (a) \(375 \times 9\) (Note: The smallest multiple of any number is the number itself, which corresponds to multiplying by 1, but matching standard options usually points to multiplying by 1 or the number itself. If strictly interpreting standard math: the smallest multiple of a number is the number multiplied by 1. Here option (a) \(375 \times 9\) is listed, but let us check typical question banks where the smallest multiple is the number multiplied by 1. Since 1 is option (b), wait: 1 is a factor, not a multiple. The smallest multiple of 375 is 375 itself, i.e. \(375 \times 1\). Let us select the most appropriate conceptual answer: the smallest multiple of a number is the number itself.)
In simple words: The smallest multiple of a number is the number multiplied by 1.
Exam Tip: Every number is a multiple of itself (number × 1).

(f) Smallest 3 digit even number
(a) 102
(b) 101
(c) 100
Answer: (c) 100
The smallest 3-digit number is 100, and since its last digit is 0, it is an even number.
In simple words: 100 is the first 3-digit number and it ends in 0, so it is even.

(g) Largest factor of a number is number itself
(a) True
(b) False
Answer: (a) True
Every number is the largest factor of itself.
In simple words: A number cannot have a factor larger than itself.
Exam Tip: Remember: Factors are less than or equal to the number; multiples are greater than or equal to the number.

(h) A no. is divisible by 6 if it is
(a) divided by 3
(b) divided by 2
(c) divisible by both 2 and 3
Answer: (c) divisible by both 2 and 3
Since \(6 = 2 \times 3\), a number is divisible by 6 if it is divisible by both 2 and 3.
In simple words: A number is divisible by 6 if it passes tests for both 2 and 3.

Exam Tip: Check the evenness (for 2) and sum of digits (for 3) simultaneously.

Q10. (a) Find the Prime Factorization of 180
Answer:
Divide 180 by the smallest prime numbers successively:
- \(180 \div 2 = 90\)
- \(90 \div 2 = 45\)
- \(45 \div 3 = 15\)
- \(15 \div 3 = 5\)
- \(5 \div 5 = 1\)
Prime factorization = \(2 \times 2 \times 3 \times 3 \times 5\) (or \(2^2 \times 3^2 \times 5\)).
In simple words: Keep dividing by prime numbers until you reach 1.

Exam Tip: Always start dividing by the smallest prime factor (2) and proceed upwards.

(b) Draw the factor tree for 100
Answer:
Factor tree steps:
1. 100 splits into \(2 \times 50\)
2. 50 splits into \(2 \times 25\)
3. 25 splits into \(5 \times 5\)
Prime factorization: \(2 \times 2 \times 5 \times 5\).
In simple words: Branch out numbers into pairs of factors until all end branches are prime numbers.

Exam Tip: Circle prime numbers at the end of each branch so you do not break them down further.

Q11. Give reasons.

(a) Is 51 a Prime number?
Answer:
No, 51 is not a prime number because it has factors other than 1 and itself. Specifically, \(3 \times 17 = 51\), so its factors are 1, 3, 17, and 51. Since it has more than two factors, it is a composite number.
In simple words: Prime numbers have only two factors (1 and the number itself), but 51 has four factors.

(b) Is 7028 divisible by 4?
Answer:
Yes, 7028 is divisible by 4 because the number formed by its last two digits is 28, and 28 is divisible by 4 (\(28 \div 4 = 7\)).
In simple words: Look at the last two digits (28); since 28 is divisible by 4, the whole number is divisible by 4.

Exam Tip: Applying divisibility rules saves time compared to doing long division.

Q12. (a) List all the composite number between 83 and 89?
Answer:
The numbers between 83 and 89 are: 84, 85, 86, 87, 88.
Checking each number:
- 84 is composite (divisible by 2, 3, 4, etc.)
- 85 is composite (divisible by 5 and 17)
- 86 is composite (divisible by 2 and 43)
- 87 is composite (divisible by 3 and 29, since \(8 + 7 = 15\))
- 88 is composite (divisible by 2, 4, 8, etc.)
All numbers between 83 and 89 (84, 85, 86, 87, 88) are composite numbers.
In simple words: Check every integer between 83 and 89; none of them are prime.

Exam Tip: Consecutive integers do not have to be all prime; check divisibility by small primes (2, 3, 5, 7).

(b) Find all the factors of 60?
Answer:
Factors of 60 are numbers that divide 60 completely without leaving a remainder:
\(1 \times 60 = 60\)
\(2 \times 30 = 60\)
\(3 \times 20 = 60\)
\(4 \times 15 = 60\)
\(5 \times 12 = 60\)
\(6 \times 10 = 60\)
List of all factors: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
In simple words: Find all pairs of numbers that multiply to give 60.

Exam Tip: Write factors in pairs to ensure you do not miss any.

(c) Find the next 4 multiples of 25?
Answer:
The multiples of 25 are obtained by multiplying 25 by consecutive counting numbers starting from 1 (or starting after the given sequence if specified, but usually the first 4 multiples are):
\(25 \times 1 = 25\)
\(25 \times 2 = 50\)
\(25 \times 3 = 75\)
\(25 \times 4 = 100\)
The next 4 multiples are 25, 50, 75, 100.
In simple words: Skip count by 25 four times.

Exam Tip: Multiples are infinite; list them in order by multiplying by 1, 2, 3, 4, etc.

Section D

Q13. (a) Construct and name a line segment measuring 7.5 cm
Answer:
Steps of construction:
1. Mark a point A on a sheet of paper.
2. Place the zero mark of a ruler at point A.
3. Mark a point B at the 7.5 cm mark on the ruler.
4. Join points A and B using a sharp pencil.
5. Name the line segment AB of length 7.5 cm.
In simple words: Use a ruler and pencil to draw a straight path of exactly 7.5 cm between two endpoints.

Exam Tip: Always label the endpoints and write the exact measurement along the line segment.

(b) Count and name the line segments in the given figure.
Answer:
Based on the geometric outline provided in the diagram (with vertices A, B, C, D, E, F, G, H, I):
Line segments include: AB, BC, CD, DE, EF, FG, GH, HI, HA, AI, IF, FC.
Total line segments = 12 distinct segments.
In simple words: Count every straight line piece connecting two letters in the figure.
Exam Tip: Go systematically around the outer boundary and then through the inner lines so you do not count any segment twice.

Q14. Fill in the blanks.

(a) Simplest Polygon is _____
Answer: Triangle
In simple words: A triangle is a polygon with the minimum number of sides (3 sides).
Exam Tip: A polygon must have at least 3 straight sides.

(b) _____ radii can be made in a circle.
Answer: Infinite (or Countless / Many)
In simple words: You can draw an endless number of radii from the center to the circumference.

(c) If diameter is 44 cm then radius is _____ cm.
Answer: 22
Radius = \(\text{Diameter} \div 2 = 44 \div 2 = 22\text{ cm}\).
In simple words: Radius is always half of the diameter.
Exam Tip: Formula: \(r = \frac{d}{2}\) and \(d = 2r\).

(d) Diameter = _____ x radius
Answer: 2
In simple words: Diameter is twice the length of the radius.
Exam Tip: Memorize the fundamental circle relations before exams.

(e) _____ can be extended from one side.
Answer: Ray
In simple words: A ray has one fixed endpoint and extends endlessly in one direction.
Exam Tip: Line = extends both sides; Line segment = fixed length; Ray = extends one side.

(f) _____ is the shortest distance between two points.
Answer: Line segment
In simple words: The straight line path joining two points is the shortest distance.
Exam Tip: This is a standard geometric definition of a line segment.

Q15. Answer in Roman Numerals
(a) Symbol for 99 _____
Answer: XCIX
99 is broken down as \(90 + 9\). 90 is XC and 9 is IX. Combined: XCIX.
In simple words: 90 is XC and 9 is IX, so 99 is XCIX.
Exam Tip: Use subtraction rules in Roman numerals (e.g., C minus X = 90).

(b) Predecessor of 40 _____
Answer: XXXIX
Predecessor of 40 is \(40 - 1 = 39\). In Roman numerals, 39 is XXXIX.
In simple words: Find the number before 40, which is 39, and write it in Roman numerals.

(c) Sum of XIV and XI _____
Answer: XXV
XIV = 14
XI = 11
Sum = \(14 + 11 = 25\). In Roman numerals, 25 is XXV.
In simple words: Convert Roman numerals to numbers, add them, and convert back.
Exam Tip: Convert to Hindu-Arabic numerals for calculation, then convert the final result back to Roman numerals.

(d) Product of IX and VI _____
Answer:  LIV
IX = 9
VI = 6
Product = \(9 \times 6 = 54\). In Roman numerals, 54 is LIV (50 + 4).
In simple words: Multiply 9 by 6 to get 54, then write it in Roman numerals as LIV.
Exam Tip: L represents 50 and IV represents 4, making LIV equal to 54.