CBSE Class 4 Maths Budget Planning Worksheet

ACTIVITY 1

Question 1. Make a budget for 3 days and follow the steps given below. I. Day 1- List out the items bought and the money spent on them. Find the total money spent on that day. II. Follow the same step for the next 2 days. Add the total amount spent on day 1, 2 and 3. From the list prepared, find out the amount spent unnecessarily (which could have been avoided and saved). Now subtract the amount spent unnecessarily from the total amount. The amount saved is Rs. ___________.
Answer: Day 1 Expenses:
- Vegetables: Rs. 150
- Fruits: Rs. 250
- Milk: Rs. 60
- Groceries: Rs. 300
- Total for Day 1 = 150 + 250 + 60 + 300 = Rs. 760

Day 2 Expenses:
- Vegetables: Rs. 120
- Milk: Rs. 60
- Bakery items: Rs. 150
- Snacks/Chips: Rs. 100
- Total for Day 2 = 120 + 60 + 150 + 100 = Rs. 430

Day 3 Expenses:
- Vegetables: Rs. 130
- Fruits: Rs. 200
- Milk: Rs. 60
- Groceries: Rs. 250
- Total for Day 3 = 130 + 200 + 60 + 250 = Rs. 640

Total amount spent on Day 1, 2, and 3 = 760 + 430 + 640 = Rs. 1830
Amount spent unnecessarily (Chips and extra snacks) = Rs. 100
Amount saved = Total amount - Unnecessary expenses = 1830 - 100 = Rs. 1730
In simple words: Create a 3-day shopping budget, calculate the daily and total expenses, identify wasteful spending, and find the net savings.

Exam Tip: Always double-check your addition column-wise to avoid calculation errors in real-life financial budgets.

ACTIVITY 2

Question 2. Plan a budget for your birthday party from the amount left in Activity 1. Do both the activities on A4 size sheets. Hints are given below: Birthday Party Expenses - Cake, Decoration, Eatables (Rs. 600), Return gifts, Prizes, Cool drinks. Total spent = ?
Answer: Available Budget from Activity 1 = Rs. 1730
Birthday Party Expense Breakdown:
- Cake: Rs. 450
- Decoration: Rs. 200
- Eatables: Rs. 600
- Return gifts: Rs. 250
- Prizes: Rs. 100
- Cool drinks: Rs. 130
Total spent = 450 + 200 + 600 + 250 + 100 + 130 = Rs. 1730
In simple words: Allocate your remaining savings from Activity 1 across different birthday party items so that total expenses do not exceed the budget.

Exam Tip: Ensure that the sum of all individual party expenses equals the exact remaining amount from the previous activity.

NUMERATION

Question 1. Reena has 5 bricks with digits written on them: 7, 3, 9, 5, 2. In which way should she arrange the bricks in order to obtain the largest and the smallest numbers using each brick only once? Largest number: _________ Smallest number: _________
Answer: To form the largest number, arrange the given digits in descending order: 9, 7, 5, 3, 2.
Largest number = 97,532
To form the smallest number, arrange the given digits in ascending order: 2, 3, 5, 7, 9.
Smallest number = 23,579
In simple words: Put digits from biggest to smallest for the largest number, and from smallest to biggest for the smallest number.

Exam Tip: Never start the smallest number with 0 if 0 is present, but here all digits are non-zero so direct ascending order works perfectly.

Question 2. Rohit has 4 televisions with the following numbers written on them: 2,43,968, 2,41,724, 25,390, 23,984. In which way should he arrange the televisions in order to obtain the ascending and descending order? Ascending order: _________ Descending order: _________
Answer: Ascending order (smallest to largest): 23,984, 25,390, 2,41,724, 2,43,968
Descending order (largest to smallest): 2,43,968, 2,41,724, 25,390, 23,984
In simple words: Ascending means going up in value, and descending means going down in value.

Exam Tip: Compare the number of digits first; numbers with fewer digits are always smaller.

Question 3. Write the following numbers in expanded form. i) 2,34,698 ii) 7,12,034
Answer: i) 2,34,698 = \(2,00,000 + 30,000 + 4,000 + 600 + 90 + 8\)
ii) 7,12,034 = \(7,00,000 + 10,000 + 2,000 + 30 + 4\)
In simple words: Break down each digit according to its place value and add them together.

Exam Tip: Zero in any place value position can be skipped or written as 0 in the expanded form.

Question 4. Write the place value of the given digits. i) 2 in 4,56,102 ii) 5 in 7,86,506
Answer: i) Place value of 2 in 4,56,102 is 2 (ones place, \(2 \times 1 = 2\))
ii) Place value of 5 in 7,86,506 is 500 (hundreds place, \(5 \times 100 = 500\))
In simple words: Multiply the digit by its position value (ones, tens, hundreds, etc.).

Exam Tip: Place value depends on the exact position of the digit in the number.

Question 5. Solve the following and write the answers in Roman numerals. a) XX - VII = b) XLVIII - XLIII = c) XVIII - IV = d) XXXI + XXVII = e) VIII + XXVI = f) XXII + XII + VII =
Answer: a) XX - VII = 20 - 7 = 13 = XIII
b) XLVIII - XLIII = 48 - 43 = 5 = V
c) XVIII - IV = 18 - 4 = 14 = XIV
d) XXXI + XXVII = 31 + 27 = 58 = LVIII
e) VIII + XXVI = 8 + 26 = 34 = XXXIV
f) XXII + XII + VII = 22 + 12 + 7 = 41 = XLI
In simple words: Convert Roman numerals to numbers, perform addition or subtraction, and convert the result back to Roman numerals.

Answer: i) 30000
ii) 70
iii) 8000
iv) 80
v) 4
In simple words: Find the missing place value by subtracting the sum of the given numbers from the total sum.

Exam Tip: Match each place value term on the left with the corresponding digit in the right-side total.

Question 7. Compare using <, >, or =:
864447 ____ 864031
689254 ____ 688999
23192 ____ 232782
814421 ____ 814914
Answer: 864447 > 864031
689254 > 688999
23192 < 232782
814421 < 814914
In simple words: Compare digits from left to right to determine which number is greater or smaller.

Exam Tip: Always compare the highest place value digit first.

Question 8. Write the range of numbers which can be rounded off to the nearest 1,000.
i) 2,469 is between 2,000 and 3,000 and is rounded to 2,000.
ii) 4,760 is between ___________ and ___________ and is rounded to ____________.
iii) 6,099 is between ___________ and ___________ and is rounded to ____________.
iv) 2,967 is between ___________ and ___________ and is rounded to ____________.
Answer: ii) 4,760 is between 4,000 and 5,000 and is rounded to 5,000.
iii) 6,099 is between 6,000 and 7,000 and is rounded to 6,000.
iv) 2,967 is between 2,000 and 3,000 and is rounded to 3,000.
In simple words: Check the digit in the hundreds place; if it is 5 or more, round up to the next thousand, otherwise round down.

Exam Tip: The midpoint for rounding to the nearest 1,000 is 500.

PROPERTIES OF ADDITION

Question 9. Solve the missing blanks based on the properties of addition:
- Identity Property:
i) \(35678 + 0 = 35678\)
ii) \(987607 + 987607 = 987607\) (Filling: 0)

- Successor Property (Adding 1):
i) \(56748 + 1 = 56749\)
ii) \(1 + 12983 = 12984\)

- Commutative Property:
i) \(23761 + 47604 = 47604 + 23761 = 71365\)
ii) \(67531 + 4768 + 97522 = 97522 + 67531 + 4768\)

- Associative Property:
i) \(13498 + (67854 + 4789) = 67854 + (13498 + 4789)\)
ii) \((45098 + 6573) + 38790 = 45098 + (38790 + 6573)\)
Answer: - Identity Property blanks: i) 35678, ii) 0
- Successor Property blanks: i) 56749, ii) 12983
- Commutative Property blanks: i) 23761, 71365; ii) 67531, 67531
- Associative Property blanks: i) 13498; ii) 38790, 38790
In simple words: Use addition rules such as adding zero, changing order, or regrouping numbers.

Exam Tip: Memorize the names and rules of addition properties: Commutative, Associative, and Identity.