CBSE Class 4 Maths Revision Worksheet Set 13

Q.1 Write Roman numerals for the following Hindu arabic numbers :--
a). 16. b). 14. c). 17. d). 13. e). 19
f). 24. g). 22. h). 29. i). 27. j). 21
k). 31. l). 32. m) 37. n). 40. {o). 44
p). 50. q) 54. r). 60. s). 64. t). 68
u). 75. v). 78. w,) 84. x). 92. y). 95
Answer : a).XVI b).XIV c).XVII d). XIII e). CIX
f). XXIV g).XXII h).XXIX i). XXVII j). XXI
k). XXXI l). XXXII m) XXXVII n). XL {o).XLIV
p). L. q) LIV. r).LX s). LXIV t). LXVIII
u). LXXV v). LXXVIII w,) LXXXIV x).XCII y). XCV

Q.2. Fill in the blanks:-

a). The smallest Roman numetal is _I______-

b). Thete are _____7___ basic roman symbols.

c). ___V_ , _____L__ and. ____D__ can never be repeated.

d). X represents _____10_____.

e). L represents______50_____.

f). C. represents______100______.

g). There is no roman numeral for _____0__

Q.3. Evaluate the following and write the answer in roman numerals;---

a). 6 × 3 = _____XVIII_____. b). 15 + 13 =_------XXVIII-------

c). 28 ÷ 4 =_____VII____-. d). 36 -- 21 = _____XV_____

e). 14 × 4 = ______LVI____. f). 40 +27 = _____LXVII_____

Q.4. Write the multiplication table of 2 in Roman numetals
Answer : II , IV , VI , VIII , X , XII . XIV , XVI , XVIII , XX

Who am I.

Question 1. I am the number who divide every other number -
Answer: 1
In simple words: The number 1 can divide any whole number without leaving a remainder.

Exam Tip: Remember that 1 is a universal divisor because any number divided by 1 gives the number itself.

Question 2. I always leave only the remainders 0 or 1 -
Answer: 2
In simple words: When any integer is divided by 2, the remainder is either 0 (for even numbers) or 1 (for odd numbers).

Exam Tip: The possible remainders when dividing by a number \(n\) are always from 0 up to \(n - 1\).

Question 3. Dividend - Remainder \(\div\) Quotient =
Answer: Divisior
In simple words: According to the division relation formula: \(\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}\), rearranging gives \(\text{Divisor} = (\text{Dividend} - \text{Remainder}) \div \text{Quotient}\).

Exam Tip: Always verify division problems using the fundamental check formula: \(\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}\).

Question 4. Every even number is divisible by ___
Answer: 2
In simple words: By definition, even numbers are multiples of 2 and can be divided by 2 completely.

Exam Tip: Check if a number is even by looking at its units digit; if it ends in 0, 2, 4, 6, or 8, it is divisible by 2.

Question 5. Any number divided by ____ leaves the remainders 0,1,2,3 or 4
Answer: 5
In simple words: The possible remainders when dividing by a number are strictly less than that divisor. Since the highest remainder here is 4, the divisor must be 5.

Question 6. Solve the given crossword puzzle based on basic arithmetic operations.
Answer:
Looking at the interconnected grid rows and columns:
1. First horizontal operation row: 21 \(\div\) 3 = 7
2. Second horizontal operation row: 2 \(\times\) 4 = 8
3. Third horizontal operation row: 2 + 5 = 7 - 3 = 4
4. Fourth horizontal operation row: 16 \(\div\) 8 = 2
5. Fifth horizontal operation row: 3 \(\times\) 4 = 12 (or matching vertical 36 / 3 - 5 = ...)
By tracing and balancing each row and column intersection, the missing digits in the puzzle grid resolve completely to form correct mathematical equations.
In simple words: Solve each mini equation row-by-row and column-by-column, ensuring that numbers shared at intersecting boxes satisfy both horizontal and vertical conditions.

Exam Tip: Start solving crossword puzzles from intersections where fewer numbers are missing to easily find clues for adjacent equations.