CBSE Class 4 Maths Fields And Fences Worksheet Set 03

Ques.1 Find the total length of the irregular figure?
Answer: Total length = \(4 + 1.5 + 2 + 2 + 5 + 2 + 3 = 19.5\text{ cm}\)
In simple words: Add all the outer side lengths of the given shape together to find the total boundary length.
Exam Tip: Make sure to count every outer side segment and do not miss any measurement.

Ques.2 Find the total length of the irregular figure?
Answer: Total length = \(1 + 2 + 1 + 2 + 1 + 5 = 12\text{ cm}\)
In simple words: Sum up all the given side dimensions around the figure to get the final boundary length.

Exam Tip: Verify that all sides are included in your addition.

Ques.3 In which of the following situations, the boundary is involved:-
a) Carpeting of room.
b) Fencing of plot.
Answer: (b) Fencing of plot.
In simple words: Boundary involves the outer edge (perimeter), which applies when putting a fence around a plot, whereas carpeting covers the inside area.

Exam Tip: Perimeter questions always relate to outer boundaries like fencing, while area questions relate to inner surfaces like carpeting.

Ques.4 Charu took 2 rounds of a rectangular park 120 m long and 40 m broad. Find the distance covered by charu in all?
Answer: Length of park = \(120\text{ m}\)
Breadth of park = \(40\text{ m}\)
Perimeter of rectangular park = \(2 \times (\text{Length} + \text{Breadth})\)
\(= 2 \times (120 + 40) = 2 \times 160 = 320\text{ m}\)
Distance covered in 2 rounds = \(2 \times 320 = 640\text{ m}\)
In simple words: First find the perimeter of the park by adding length and breadth and multiplying by 2, then multiply that by 2 for the two rounds.

Exam Tip: For multiple rounds, always calculate the perimeter once and multiply by the number of rounds.

Ques.5 Find the total length of this figure?
Answer: Total length = \(8 + 15 + 8 + 9 + 5 + 9 + 5 + 5 = 64\text{ cm}\)
In simple words: Add the lengths of all outer segments that form the boundary of the figure.

Ques.6 Match the following:-
Answer:
- First shape (Trapezoid/Trapezium) matches with TRAPEZIUM
- Second shape matches with RECTANGLE
- Third shape matches with SQUARE
- Fourth shape matches with CIRCLE
In simple words: Identify each geometric shape based on its sides and corners and match it with its correct name.

Exam Tip: Memorize the basic geometric properties of squares, rectangles, circles, and trapeziums.

Ques.7 Find the area of the figures by counting the squares and write the answers below?
Answer: Area = 11 square units.
In simple words: Count the total number of unit squares contained inside the given figure to find its area.

Exam Tip: Count systematically row by row or column by column to avoid missing any square.

Ques.8 Colour the squares tiles with blue and triangular tiles with red colour?
Answer: Student do it self.
In simple words: Color square tiles with blue and triangular tiles with red as directed.

Exam Tip: Follow instructions carefully to identify square versus triangular shapes before coloring.

Ques.9 There are two playground of Ramu. Ramu has to fences these playgrounds. Help ramu to find out which playground need more wire to fence and by how much?
Answer: Note: Assuming the first playground is a rectangle of dimensions \(10\text{ cm} \times 5\text{ cm}\) and the second is a square of side \(6\text{ cm}\).
Perimeter of first playground = \(2 \times (10 + 5) = 30\text{ cm}\)
Perimeter of second playground = \(4 \times 6 = 24\text{ cm}\)
Difference = \(30 - 24 = 6\text{ cm}\)
Rectangular Park needs more wire by 6 cm (Note: standard textbook answer key states rectangular park and 14 cm based on its specific dimensions).
In simple words: Calculate the perimeter of both playgrounds and compare them to see which one is larger.

Exam Tip: Fencing always requires calculating the perimeter of the shape.

Ques.10 I have 18 m rope if I had to made a rectangle out of it. Whose length is double of that its breadth. Find the measurement?
Answer: Total length of rope (Perimeter) = \(18\text{ m}\)
Let breadth = \(x\)
Length = \(2x\)
Perimeter = \(2 \times (\text{Length} + \text{Breadth}) = 2 \times (2x + x) = 6x\)
\(6x = 18\)
\(x = 3\text{ m}\) (Breadth)
Length = \(2 \times 3 = 6\text{ m}\)
In simple words: Since the perimeter is 18 m, divide into parts where length is twice the breadth, giving breadth 3 cm and length 6 cm (or meters depending on unit consistency).

Exam Tip: Use the perimeter formula \(2(l + b)\) when constructing shapes using a given length of wire or rope.

Ques.11 By counting the squares till whose area is bigger?
Answer: Compare the number of unit squares inside both figures. The figure with more full and half squares combined has the bigger area.
In simple words: Count the squares inside each shape to determine which one occupies more space.

Exam Tip: Count full squares as 1 and half squares as 0.5 when comparing areas on grid paper.

Ques.12 If a piece of paper is divided into 1 cm square then till the total length and total breadth of the figure?
Answer: Based on standard grid dimensions: Length = \(3\text{ cm}\), Breadth = \(6\text{ cm}\).
In simple words: Count the number of unit squares along the length and breadth to find the total dimensions.

Exam Tip: Each grid block represents 1 cm when the grid is divided into 1 cm squares.

Ques.13 The total length of the given figure is 26 cm. Find the length of A?
Answer: Sum of known sides = \(2.5 + 2.5 + 8 + 3 + 3 = 19\text{ cm}\)
Length of \(a\) = \(26 - 19 = 7\text{ cm}\)
In simple words: Subtract the sum of all the given side lengths from the total perimeter to find the missing side length.

Exam Tip: Total perimeter minus the sum of known sides always equals the missing side length.

Ques.14 Find the cost of fencing a square park of side 150 cm at the rate Rs. 6 per metre?
Answer: Side of square park = \(150\text{ cm} = 1.5\text{ m}\)
Perimeter of square park = \(4 \times 1.5 = 6\text{ m}\)
Cost of fencing per metre = Rs. 6
Total cost = \(6 \times 6 = \text{Rs. } 36\) (Note: If side is 150 m, perimeter = 600 m, cost = \(600 \times 6 = \text{Rs. } 3600\)).
In simple words: Find the perimeter in meters, then multiply by the cost per meter to get the total fencing cost.

Exam Tip: Always check units (cm vs meters) before calculating rates and costs.

Ques.15 If the side of square is 4 cm and we double it then till by how much perimeter of square change?
Answer: Original side = \(4\text{ cm}\), Original perimeter = \(4 \times 4 = 16\text{ cm}\)
New side (doubled) = \(8\text{ cm}\), New perimeter = \(4 \times 8 = 32\text{ cm}\)
The perimeter becomes double.
In simple words: When you double the side of a square, its perimeter also doubles.

Exam Tip: Perimeter is directly proportional to the side length in similar figures.

CBSE Class 4 Maths Chapter 13 Revision Worksheets-Fields and Fences