NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller

Get the most accurate NCERT Solutions for Class 4 Mathematics Chapter 6 The Junk Seller here. Updated for the 2025-26 academic session, these solutions are based on the latest NCERT textbooks for Class 4 Mathematics. Our expert-created answers for Class 4 Mathematics are available for free download in PDF format.

Detailed Chapter 6 The Junk Seller NCERT Solutions for Class 4 Mathematics

For Class 4 students, solving NCERT textbook questions is the most effective way to build a strong conceptual foundation. Our Class 4 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 6 The Junk Seller solutions will improve your exam performance.

Class 4 Mathematics Chapter 6 The Junk Seller NCERT Solutions PDF

NCERT Solutions for Class 4 Mathematics Math Magic for Chapter 6 The Junk Seller

Chapter -6

THE JUNK SELLER

1. What about you? Do you also find Maths difficult?

Ans.I do not find Maths difficult.


2. What is the most difficult thing in you Maths book?

Ans.The chapter entitled “The Way the World Looks” is the most difficult thing in Maths book.


3. What do you think is the easiest lesson?

Ans.The lesson “A Trip to Bhopal” is the essential.


4. Find out: how much for a cup of tea?

Ask people and find out the cost of a cup of tea

(a) At a tea stall

Ans. (a)At a tea stall, the cost of a cup is Rs 3.

(b) At a hotel

Ans. (b)At a hotel, the cost of a cup is Rs 10.


5. If a person who runs a tea stalls earns Rs 30 in a day, how much will he earn in 10 days? And in a month? How did you get the answer? Discuss.

Ans.Earning of a tea stall owner per day = Rs 30

Therefore, earning of a tea stall owner in 10 days = Rs (10 30) = Rs 300

And his, earning in a month = Rs (30 30) = Rs 900

I got the answers by multiplication.


6. Find out: What is a loan?

(a) Have you ever heard of someone taking a loan? For what?

Ans. (a)Yes, I have heard of someone taking a loan. It is taken to buy a handcart.

(b) How much loan was taken?

Ans. (b)Rs 300 was taken as loan.

(c) How much money was paid back.

Hariya and Babu went to buy a handcart for Rs 300.

Ans. (c) Hariya:I have taken a loan of Rs 300 from a Bank for six months. I will pay Rs 51 every month to the bank.

Babu:But I have taken a loan of Rs 300 from Chunnilal. After six months, I will pay back Rs 360.

(d) Who has to pay back more- Hariya or Babu?

Ans. (d)In case of Hariya: Money paid back to the bank = Rs. 6 51 = Rs 306

In case of Babu: Money paid back to Chunnilal = Rs 360

Since, Rs 360 is more than Rs 300, therefore, Babu paid back more money.


7. (a) Have 9 rickshaws of my own. I give the rickshaws on rent, each of Rs 20 a day. On Sundays I do not take any money from them? How much does Kiran earn from 9 Rickshaws in a Day?

Ans. (a)For 1 rickshaw she gets Rs 20 per day.

So, for 9 rickshaws she will earn Rs 180.

(b) How did you do it?

Ans. (b)I did it by multiplying 20 and 9 (20 9=180).


8. In a week how much does Kiran earn from one rickshaw?

Ans.Since on Sundays Kiran does not take any money for rickshaw’s rent, therefore, Kiran earns in a week on one rickshaw at the rate of Rs 20 per day = Rs 6 20 = Rs 120.


9. Do it mentally and write the answers:

(a) 2 6= __

Ans. (a)2 6= 12.

(b) 20 6 = __

Ans. (b)20 6 = 120.

(c) 2 60 = __

Ans. (c)2 60 = 120.

(d) 3 42 = __

Ans. (d)3 42 = 126.

(e) 4 80 = __

Ans. (e)4 80 = 320.

(f) 4 81 = __

Ans. (f)4 81 = 324.

(g) 9 25 = __

Ans. (g)9 25 = 225.

(h) 31 9 = __

Ans. (h)31 9 = 279.


10. 4 81 is 4 more than 4 80. Am I right?

Ans.Yes.


11. How much Kiran will pay for 31 kg newspaper?

Ans.Kiran will pay for 31 kg newspaper = Rs (51 30 + 5 1) = Rs 155.


12. 

(a) How much Kiran pay for 42 kg newspaper?

Ans. (a)Kiran will pay Rs (42 5) = Rs 210.

(b) Also find the costs of:

(i) 22 kg of plastic

Ans. (b) (i)Cost of 22 kg of plastic = Rs (22 10) = Rs 220.

(ii) 23 kg of wastepaper

Ans. (b) (ii)Cost of 23 kg of newspaper = Rs (23 4) = Rs 92.

(iii) 12 kg of iron.

Ans. (b) (iii)Cost of 12 kg of iron = Rs (12 12) = Rs 144.


13. Can you do this without writing? Guess the total money Kiran will pay to the junk collectors. Will it be: More than 600? Less than 600?

Ans.Less than 600.


14. Kiran bought 1 kg of plastic for Rs 10, but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg plastic?

Ans.Earning on selling 1 kg of plastic = Selling price – Cost price = Rs 12 – Rs 10 = Rs 2

So, earning on selling 63 kg of plastic = Rs 2 Rs 63

60 3
60 2 3 2
120 6

On adding the numbers in the last row = 120 + 6 = 126.

So, for 63 kg of plastic, Kiran earns = Rs 126.


15. How much money will Dinu pay for 32 kg iron?

Ans.The rate of 1 kg of iron is Rs 14. So, the cost for 32kg of iron is Rs 14 32.

We write as:

30 2
10 30 10 2 10
300 20
4 30 4 2 4
120 8

So, for 32 kg iron, Dinu will pay Rs 448.


16. Kiran buys 1 kg iron for Rs 12, but sells it for Rs 14. How much does she earn when she sells 32 kg iron?

Ans.Earning of selling 1 kg iron = Selling price -Cost price = Rs 14 – Rs 12 = Rs 2

So, earning on selling 32 kg of iron = Rs 2 32 of iron = Rs 2 32

We write as:

30 2
30 2 2 2
60 4

So, Kiran earns Rs 64 on the sale of 32 kg iron.


17. I bought 1 kg newspaper for Rs 5, but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper?

Ans.Rs 152.


18. How much money will Dinue pay for 4 kg brass? Guess the answer first.

Ans.The rate of 1 kg brass is Rs 170. So, the cost of 4 kg brass is Rs 170 4. We guess the answer to lie between Rs 600 and Rs 800.

We write as:

 

4

100 70
100 4 70 4
400 280

So, for 4 kg brass Dinu will pay Kiran Rs 680.


19. First guess the answer then calculate:

(a) 37 18

Ans. (a)On guessing 37 18 may be = 740.

We write as:

30 7
10 30 10 7 10
300 70
8 30 8 7 8
240 56

Adding the numbers = 300 + 240 + 70 + 56 = 666

So, 37 18 = 666.

(b) 45 24

Ans. (b)On guessing 45 24 = 1080

We write as:

40 7
20 40 20 5 20
800 100
4 40 4 5 4
160 20

Adding the numbers = 800 + 160 + 100 + 20 = 1080

So, 45 24 = 1080

(c) 69 52

Ans. (c)On guessing 69 52 = 3588

We write as:

60 9
50 60 50 9 50
3000 450
2 60 2 9 2
120 18

Adding the numbers = 3000 + 120 + 450 + 18 = 3588

So, 69 52 = 3588.

(d) 77 55

Ans. (d)On guessing 77 55 = 4235

We write as:

70 7
50 70 50 7 50
3500 350
5 70 5 7 5
350 35

Adding the numbers = 3500 + 350 + 350 + 35 = 4235

So, 77 55 = 4235.

(e) 142 5

Ans. (e)On guessing 142 5 = 710

We write as:

100 40 2
5 100 5 40 5 2 5
500 200 10

Adding the numbers = 500 + 200 + 10 = 710

So, 142 5= 710.

(f) 382 3

Ans. (f)On guessing 382 3 =1146

We write as:

300 80 2
3 300 3 80 3 2 3
900 240 6

Adding the numbers = 900 + 240 + 6 = 1146

So, 382 3 = 1146

(g) 2 175

Ans. (g)On guessing 2 175 = 350

We write as:

100 70 5
2 100 2 70 2 5 2
200 140 10

Adding the numbers = 200 + 140 + 10 = 350

So, 2 175 = 350.

(h)4 206

Ans. (h)On guessing 4 206 = 824

We write as:

     200 0 6
4 200 4 0 4 6 4
800 0 24

Adding the numbers = 800 + 0 + 24 = 824

So, 4 206 = 824.

 

Question. 880 - 88 is equal to
(a) 968
(b) 802
(c) 792
(d) 6

Answer : C

Question. What number comes in the box?
650 - ................. tens = 450

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-6

(a) 2
(b) 10
(c) 20
(d) 200

Answer : C

Question. 200 + 30 + 1 + 60 + 4 + 3 + 400 is equal to
(a) 2300
(b) 1490
(c) 1274
(d) 698

Answer : D

Question. In which of the following divisions will the answer be a 2-digit number?
(a) 400   divide by 2
(b) 408 divide by 4
(c) 428  divide by 4
(d) 426 divide by 6

Answer : D

Question. If each jar has 10 marbles, in all how many marbles are there in the box below?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-5

(a) 328
(b) 211
(c) 53
(d) 31

Answer : D

Question. Which of these is a 2-rupee coin?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-4

b

Question. If I add 60 to 325 and then subtract 40, the answer I get will be equal to
(a) 325 + 20
(b) 325 + 100
(c) 325 - 20
(d) 325 - 100

Answer : A

Question. 500 - 46 gives the same answer as 400 +?
(a) 46
(b) 54
(c) 64
(d) 146

Answer : B

Question. Each big box shown below contains 100 apples and each small box contains 10 apples. In all, how many apples are there in the boxes?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-3

(a) 500
(b) 230
(c) 320
(d) 50

Answer : B

Question. Which symbol should go into the empty box to make this number sentence true?
75 + 9 .......... 19 + 65

(a) =
(b) >
(c) <
(d) none of these

Answer : A

Question. Ritu wants to buy this teddy for her sister. On counting the coins in her piggy bank, she finds that she has 84 one-rupee coins and 80 fifty-paise coins only. How much MORE money will she need to buy it?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-2

(a) Rs.11
(b) Rs.51
(c) Rs.87
(d) Rs.93

Answer : B

Question. 23 + 300 = 180 + 23 +............ Which of the following is a correct way of finding the number that goes into the empty box above?
(a) subtract 23 from 180
(b) subtract 180 from 300
(c) subtract 180 from 300
(d) subtract 23 from 300

Answer : B

Question. Anu's doctor has told her to take one tablet like this every morning, noon and night for a week. How many tablets will Anu need for the whole week?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller-1

(a) 3 + 7
(b) 7 + 3
(c) 7 * 3
(d) 7 * 30

Answer : A

Question. Look at this poster from an ice cream shop Abdul bought one ice cream from the shop and paid with a 20-rupee note. If the shopkeeper returned Rs. 2 to him, which ice cream did Abdul buy?

""NCERT-Solutions-Class-4-Mathematics-Chapter-6-The-Junk-Seller

(a) King Cone
(b) Ice Lolly
(c) Double Decker
(d) Sundae

Answer : A

Question. 100 – X  > 40 Which of the following could be the number in X?
(a) 76
(b) 60
(c) 85
(d) 47

Answer : D

NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller

Students can now access the NCERT Solutions for Chapter 6 The Junk Seller prepared by teachers on our website. These solutions cover all questions in exercise in your Class 4 Mathematics textbook. Each answer is updated based on the current academic session as per the latest NCERT syllabus.

Detailed Explanations for Chapter 6 The Junk Seller

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 4 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 4 students who want to understand both theoretical and practical questions. By studying these NCERT Questions and Answers your basic concepts will improve a lot.

Benefits of using Mathematics Class 4 Solved Papers

Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 4 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 6 The Junk Seller to get a complete preparation experience.

Where can I find the latest [current-page:node:field_title] for the 2025-26 session?

The complete and updated is available for free on StudiesToday.com. These solutions for Class 4 Mathematics are as per latest NCERT curriculum.

Are the Mathematics NCERT solutions for Class 4 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

How do these Class 4 NCERT solutions help in scoring 90% plus marks?

Toppers recommend using NCERT language because NCERT marking schemes are strictly based on textbook definitions. Our will help students to get full marks in the theory paper.

Do you offer [current-page:node:field_title] in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 4 Mathematics. You can access in both English and Hindi medium.

Is it possible to download the Mathematics NCERT solutions for Class 4 as a PDF?

Yes, you can download the entire in printable PDF format for offline study on any device.