Get the most accurate MSBSHSE Solutions for Class 7 Maths Chapter 2 Set 9 Multiplication and Division of Integers here. Updated for the 2026-27 academic session, these solutions are based on the latest MSBSHSE textbooks for Class 7 Maths. Our expert-created answers for Class 7 Maths are available for free download in PDF format.
Detailed Chapter 2 Set 9 Multiplication and Division of Integers MSBSHSE Solutions for Class 7 Maths
For Class 7 students, solving MSBSHSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 7 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 2 Set 9 Multiplication and Division of Integers solutions will improve your exam performance.
Class 7 Maths Chapter 2 Set 9 Multiplication and Division of Integers MSBSHSE Solutions PDF
Question 1. Solve
(i) (-96) ÷ 16
(ii) 98 ÷ (-28)
(iii) (-51) ÷ 68
(iv) 38 ÷ (-57)
(v) (-85) ÷ 20
(vi) (-150) ÷ (-25)
(vii) 100 ÷ 60
(viii) 9 ÷ (-54)
(ix) 78 ÷ 65
(x) (-5) ÷ (-315)
Answer:
Solution:
i. (-96) ÷ 16
\( \frac{-96}{16} = \frac{(-1)\times96}{16} \)
\( = (-1) \times (6) = -6 \)
ii. 98 ÷ (-28)
\( \frac{98}{-28} = \frac{98}{(-1)(28)} \)
\( = \frac{7}{(-1)\times(2)} = \frac{-7}{2} \)
iii. (-51) ÷ 68
\( \frac{-51}{68} = \frac{(-1)\times(51)}{68} \)
\( = \frac{(-1)\times(3)}{4} = \frac{-3}{4} \)
iv. 38 ÷ (-57)
\( \frac{38}{-57} = \frac{38}{(-1)\times(57)} \)
\( = \frac{2}{(-1)\times(3)} = \frac{-2}{3} \)
v. (-85) ÷ 20
\( \frac{-85}{20} = \frac{(-1)\times(85)}{20} \)
\( = \frac{(-1)\times17}{4} = \frac{-17}{4} \)
vi. (-150) ÷ (-25)
\( \frac{-150}{-25} = \frac{(-1)\times150}{(-1)\times25} \)
\( = 6 \)
vii. 100 ÷ 60
\( \frac{100}{60} = \frac{5}{3} \)
viii. 9 ÷ (-54)
\( \frac{9}{-54} = \frac{9}{(-1)\times54} = \frac{-1}{6} \)
ix. 78 ÷ 65
\( \frac{78}{65} = \frac{6}{5} \)
x. (-5) ÷ (-315)
\( \frac{-5}{-315} = \frac{(-1)\times5}{(-1)\times315} = \frac{1}{63} \)
In simple words: Division of integers follows rules of signs: negative divided by positive is negative, positive divided by negative is negative, and negative divided by negative is positive. Simplify fractions to their lowest terms.
🎯 Exam Tip: Pay close attention to the signs of the numbers and simplify fractions to their simplest form to score maximum marks.
Question 2. Write three divisions of integers such that the fractional form of each will be \( \frac{24}{5} \).
Answer:
Solution:
1. \( \frac{24}{5} = \frac{24\times1}{5\times1} = 24 \div 5 \)
2. \( \frac{24}{5} = \frac{24\times2}{5\times2} = \frac{48}{10} = 48 \div 10 \)
3. \( \frac{24}{5} = \frac{24\times(-10)}{5\times(-10)} = \frac{-240}{-50} = (-240) \div (-50) \)
In simple words: To find equivalent fractional forms for a given fraction, multiply both the numerator and the denominator by the same non-zero integer. This also applies to expressing them as divisions of integers.
🎯 Exam Tip: Remember that multiplying the numerator and denominator by the same number (positive or negative) does not change the value of the fraction, allowing you to create various equivalent division expressions.
Question 3. Write three divisions of integers such that the fractional form of each will be \( \frac{-5}{7} \).
Answer:
Solution:
1. \( \frac{-5}{7} = \frac{-5\times2}{7\times2} = \frac{-10}{14} = (-10) \div 14 \)
2. \( \frac{-5}{7} = \frac{-5\times(-5)}{7\times(-5)} = \frac{25}{-35} = 25 \div (-35) \)
3. \( \frac{-5}{7} = \frac{-5\times7}{7\times7} = \frac{-35}{49} = (-35) \div 49 \)
In simple words: Similar to positive fractions, multiplying both the numerator and denominator of a negative fraction by the same non-zero integer generates equivalent fractions and corresponding division expressions.
🎯 Exam Tip: Be careful with signs when multiplying by negative integers; for example, a negative numerator multiplied by a negative number becomes positive.
Question 4. The fish in the pond below, carry some numbers. (Choose any 4 pairs and carry out four multiplications with those numbers. Now, choose four other pairs and carry out divisions with these numbers.
Examples:
i. (-13) × (-15) = 195
ii. (-24) ÷ 9 = \( \frac{-24}{9} = \frac{-8}{3} \)
ℹ️ चित्र व्याख्या (Diagram Explanation): एक तालाब में विभिन्न मछलियाँ हैं जिन पर अलग-अलग पूर्णांक संख्याएँ लिखी हुई हैं, जैसे -13, +41, -15, -8, 24, +9, -27, +12, 37, -28, -18, +13। छात्रों को इन संख्याओं के जोड़ों का उपयोग करके गुणा और भाग के उदाहरण हल करने हैं।
Answer:
Solution:
1. (-13) × 9 = -117
2. 12 x 13 = 156
3. 9 × (-37) = -333
4. (-15) × (-8) = 120
5. (-28) ÷ 12 = \( \frac{-28}{12} = \frac{(-1)\times(28)}{12} = \frac{-7}{3} \)
6. 12 ÷ 9 = \( \frac{12}{9} = \frac{4}{3} \)
7. 9 ÷ (-24) = \( \frac{9}{-24} = \frac{9}{(-1)\times24} = \frac{-3}{8} \)
8. (-18) ÷ (-27) = \( \frac{-18}{-27} = \frac{(-1)\times18}{(-1)\times27} = \frac{2}{3} \)
In simple words: This problem requires selecting pairs of integers from the diagram and performing both multiplication and division operations, remembering the rules for signs in integer arithmetic.
🎯 Exam Tip: Carefully select distinct pairs for multiplication and division. Show all steps for simplification, especially for division of negative numbers, to ensure accuracy.
MSBSHSE Solutions Class 7 Maths Chapter 2 Set 9 Multiplication and Division of Integers
Students can now access the MSBSHSE Solutions for Chapter 2 Set 9 Multiplication and Division of Integers prepared by teachers on our website. These solutions cover all questions in exercise in your Class 7 Maths textbook. Each answer is updated based on the current academic session as per the latest MSBSHSE syllabus.
Detailed Explanations for Chapter 2 Set 9 Multiplication and Division of Integers
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 7 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 7 students who want to understand both theoretical and practical questions. By studying these MSBSHSE Questions and Answers your basic concepts will improve a lot.
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Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 7 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 2 Set 9 Multiplication and Division of Integers to get a complete preparation experience.
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The complete and updated Maharashtra Board Class 7 Chapter 2 Set 9 Multiplication and Division of Integers Solutions is available for free on StudiesToday.com. These solutions for Class 7 Maths are as per latest MSBSHSE curriculum.
Yes, our experts have revised the Maharashtra Board Class 7 Chapter 2 Set 9 Multiplication and Division of Integers Solutions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
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