NCERT Solutions for Class 7 Maths: Chapter 02 Set 8 Multiplication and Division of Integers
Access comprehensive textbook solutions for Chapter 02 Set 8 Multiplication and Division of Integers using the official curriculum guides for Class 7 Maths. Designed to align with the 2026-27 MSBSHSE standards, these detailed answers help students reinforce core academic concepts.
Practice Class 7 Maths Solutions: Chapter 02 Set 8 Multiplication and Division of Integers
Access the complete solution PDF for Class 7 Maths below. Regular practice with these targeted textbook answers builds familiarity with standard question patterns and helps secure higher marks in final school evaluations.
Question 1. Multiply:
1. (-5) × (-7)
2. (-9) × (6)
3. (9) × (-4)
4. (8) × (-7)
5. (-124) × (-1)
6. (-12) × (-7)
7. (-63) × (-7)
8. (-7) × (15)
Answer:
1. 35
2. -54
3. -36
4. -56
5. 124
6. 84
7. 441
8. -105
In simple words: When multiplying integers, if the signs are the same (both positive or both negative), the product is positive. If the signs are different (one positive and one negative), the product is negative.
🎯 Exam Tip: Pay close attention to the signs of the integers. A common mistake is to forget the rule for multiplying two negative numbers, which results in a positive product.
Maharashtra Board Class 7 Maths Chapter 2 Multiplication And Division Of Integers Practice Set 8 Intext Questions And Activities
Question 1. In the previous class, we have learnt to add and subtract integers. Using those methods, fill in the blanks below. (Textbook pg. no. 11)
1. 5 + 7 =
2. 10 + (-5) =
3. -4 + 3 =
4. (-7) + (-2) =
5. (+8) – (+ 3) =
6. (+8) - (-3) =
Answer:
1. 12
2. 5
3. -1
4. -9
5. 5
6. 11
In simple words: To add integers, combine their values considering their signs. To subtract an integer, add its opposite. Remember that subtracting a negative number is the same as adding a positive number.
🎯 Exam Tip: Be careful with subtraction, especially when dealing with double negatives (e.g., subtracting a negative number). This is a frequent area for errors.
Question 2. Write a number in each bracket to obtain the answer '3' in each operation. (Textbook pg. no. 11)
ℹ️ चित्र व्याख्या (Diagram Explanation): यह चित्र एक केंद्रीय संख्या '3' से संबंधित विभिन्न गणितीय संक्रियाओं को दर्शाता है। प्रत्येक ऑपरेशन में एक प्रारंभिक संख्या और एक ऑपरेटर (+ या -) होता है, जिसके बाद एक खाली कोष्ठक होता है, जिसे इस तरह भरना है कि परिणाम हमेशा '3' आए।
Answer:
4 - (1) = 3
(-6) + (9) = 3
7 + (-4) = 3
(-5) - (-8) = 3
9 - (6) = 3
-8 + (11) = 3
In simple words: For each equation, we need to find the missing number in the bracket that makes the operation's result equal to 3. This involves using inverse operations or simple arithmetic to solve for the unknown.
🎯 Exam Tip: Practice working with inverse operations to quickly find missing numbers in equations. Be mindful of positive and negative signs when performing addition and subtraction.
Question 3. Multiply the given integers and complete the table given below. (Textbook pg. no. 12)
| (-5) × (-3) = 15 | (-6) × (-3) = | (-7) × (-3) = |
| (-5) × (-2) = 10 | (-6) × (-2) = | (-7) × (-2) = |
| (-5) × (-1) = 5 | (-6) × (-1) = | (-7) × (-1) = |
| (-5) x 0 = 0 | (-6) × 0 = | (-7) × 0 = |
| (-5) x 1 = -5 | (-6) x 1 = | (-7) x 1 = |
| (-5) x 2 = -10 | (-6) x 2 = | (-7) x 2 = |
| (-5) x 3 = -15 | (-6) x 3 = | (-7) x 3 = |
| (-5) x 4 = -20 | (-6) x 4 = | (-7) x 4 = |
Answer:
| (-6) × (-3) = | 18 | (-7) × (-3) = | 21 |
| (-6) × (-2) = | 12 | (-7) × (-2) = | 14 |
| (-6) × (-1) = | 6 | (-7) × (-1) = | 7 |
| (-6) × 0 = | 0 | (-7) × 0 = | 0 |
| (-6) x 1 = | -6 | (-7) x 1 = | -7 |
| (-6) x 2 = | -12 | (-7) x 2 = | -14 |
| (-6) x 3 = | -18 | (-7) x 3 = | -21 |
| (-6) x 4 = | -24 | (-7) x 4 = | -28 |
In simple words: This table demonstrates the multiplication of negative integers with other integers. The key rule is that multiplying two numbers with the same sign (both negative or both positive) results in a positive product, while multiplying numbers with different signs (one negative, one positive) results in a negative product. Multiplication by zero always results in zero.
🎯 Exam Tip: Understanding the rules for multiplying positive and negative integers is crucial. Pay close attention to the signs in each multiplication problem to avoid common errors.
Maths Class 7 Curriculum Solutions: Chapter 02 Set 8 Multiplication and Division of Integers
Accessing Chapter 02 Set 8 Multiplication and Division of Integers Solutions
Review comprehensive exercise answers for Class 7 Maths Chapter 02 Set 8 Multiplication and Division of Integers. Fully updated to match current MSBSHSE syllabus guidelines, these textbook solutions help students verify their work and maintain accurate study notes.
Concept-Driven Answers for Class 7 Maths
Each solution includes detailed reasoning to foster genuine comprehension of Chapter 02 Set 8 Multiplication and Division of Integers concepts. Reviewing these step-by-step breakdowns allows learners to master both analytical and descriptive questions expected in school evaluations.
Maximizing Study Efficiency
Consistent practice with these solution guides cultivates faster problem-solving habits and clearer logical structuring. For a complete preparation experience, pair these textbook answers with our dedicated revision notes and sample papers for Class 7 Maths.
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The complete and updated Maharashtra Board Class 7 Chapter 2 Set 8 Multiplication and Division of Integers Solutions is available for free on StudiesToday.com. These solutions for Class 7 Maths are as per latest MSBSHSE curriculum.
Yes, our experts have revised the Maharashtra Board Class 7 Chapter 2 Set 8 Multiplication and Division of Integers Solutions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
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