Maharashtra Board Class 6 Maths Chapter 12 Percentage Set 30 Solutions

Percentage Class 6 Maths Chapter 12 Practice Set 30 Solutions Maharashtra Board

Std 6 Maths Practice Set 26 Solutions Answers

Question 1. Shabana scored 736 marks out of 800 in her exams. What was the percentage she scored?
Answer: Solution:
Total marks of the examination = 800
Marks scored by Shabana = 736
Suppose Shabana scored A% marks.
\( \implies \frac{A}{100} = \frac{736}{800} \)
\( \implies \frac{A}{100} \times 100 = \frac{736}{800} \times 100 \) ....(Multiplying both sides by 100)
\( \implies A = \frac{736 \times 100}{800} \)
\( \implies A = 92\% \)
\( \implies \) Shabana scored 92% marks.
In simple words: To find the percentage, divide the marks scored by the total marks and multiply by 100. This calculation shows Shabana achieved 92% in her exams.

🎯 Exam Tip: Ensure that all steps of the percentage calculation are clearly shown to avoid errors in competitive examinations.

Question 2. There are 500 students in the school in Dahihanda village. If 350 of them can swim, what percent of them can swim and what percent cannot?
Answer: Solution:
Total number of students in the school = 500
Number of students who can swim = 350
Suppose A% students can swim.
\( \implies \frac{A}{100} = \frac{350}{500} \)
\( \implies \frac{A}{100} \times 100 = \frac{350}{500} \times 100 \) ....(Multiplying both sides by 100)
\( \implies A = \frac{350 \times 100}{500} \)
\( \implies A = 70\% \)
Percentage of students who cannot swim = 100% - Percentage of students who can swim.
= 100% - 70% = 30%
\( \implies \) 70% of the students can swim and 30% cannot swim.
In simple words: Calculate the percentage of students who can swim by dividing their number by the total and multiplying by 100. Then, subtract this percentage from 100% to find the percentage of students who cannot swim.

🎯 Exam Tip: Remember to address both parts of the question – percentage of students who can swim and those who cannot – for full marks.

Question 3. If Prakash sowed jowar on 75% of the 19500 sq. m. of his land, on how many sq. m. did he actually plant jowar?
Answer: Solution:
Total area of the land = 19500 sq. m.
Percentage of area in which Prakash sowed jowar = 75%
Suppose Prakash planted jowar in A sq. m.
\( \implies \frac{A}{19500} = \frac{75}{100} \)
\( \implies \frac{A}{19500} \times 19500 = \frac{75}{100} \times 19500 \) ....(Multiplying both sides by 19500)
\( \implies A = \frac{75 \times 19500}{100} \)
\( \implies A = 14,625 \) sq. m.
\( \implies \) Prakash planted jowar in 14,625 sq.m.
In simple words: To find the actual area, multiply the total land area by the given percentage (75%) expressed as a decimal or fraction.

🎯 Exam Tip: Convert percentages to fractions or decimals correctly before performing multiplication to avoid calculation errors.

Question 4. Soham received 40 messages on his birthday. Of these, 90% were birthday greetings. How many other messages did he get besides the greetings?
Answer: Solution:
Total messages received by Soham on his birthday = 40
Percentage of messages received for birthday greetings = 90%
Suppose Soham got A number of birthday greetings.
\( \implies \frac{A}{40} = \frac{90}{100} \)
\( \implies \frac{A}{40} \times 40 = \frac{90}{100} \times 40 \) ....(Multiplying both sides by 40)
\( \implies A = \frac{90 \times 40}{100} \)
\( \implies A = 36 \)
Number of messages received other than birthday greetings
= total messages received - total number of birthday greetings
= 40 - 36 = 4
\( \implies \) The number of messages received other than birthday greetings is 4.
In simple words: First, calculate 90% of the total messages to find the number of birthday greetings. Then, subtract this number from the total messages to find the count of other messages.

🎯 Exam Tip: Pay attention to the phrasing of the question; often, you'll need to calculate a percentage and then use that result for a second step (subtraction, in this case).

Question 5. Of the 5675 people in a village 5448 are literate. What is the percentage of literacy in the village?
Answer: Solution:
Number of people in the village = 5675
Number of people who are literate = 5448
Suppose the percentage of literacy in the village is A%.
\( \implies \frac{A}{100} = \frac{5448}{5675} \)
\( \implies \frac{A}{100} \times 100 = \frac{5448}{5675} \times 100 \) ....(Multiplying both sides by 100)
\( \implies A = \frac{5448 \times 100}{5675} \)
\( \implies A = 96\% \)
\( \implies \) The percentage of literacy in the village is 96%.
In simple words: To find the percentage of literacy, divide the number of literate people by the total number of people in the village and then multiply the result by 100.

🎯 Exam Tip: Ensure precise calculations, especially when dealing with large numbers, to derive the correct percentage.

Question 6. In the elections, 1080 of the 1200 women in Jambhulgaon cast their vote, while 1360 of the 1700 in Wadgaon cast theirs. In which village did a greater proportion of women cast their votes?
Answer: Solution:
Total number of women in Jambhulgaon = 1200
Number of women in Jambhulgaon who voted = 1080
Suppose A% women cast their vote in Jambhulgaon village.
\( \implies \frac{A}{100} = \frac{1080}{1200} \)
\( \implies \frac{A}{100} \times 100 = \frac{1080}{1200} \times 100 \)
(Multiplying both sides by 100)
\( \implies A = \frac{1080 \times 100}{1200} \)
\( \implies A = 90\% \)
In Jambhulgaon, the percentage of women who voted in the elections was 90%.
Total number of women in Wadgaon = 1700
Number of women in Wadgaon who voted = 1360
Suppose B% women cast their vote in Wadgaon.
\( \implies \frac{B}{100} = \frac{1360}{1700} \)
\( \implies \frac{B}{100} \times 100 = \frac{1360}{1700} \times 100 \)
(Multiplying both sides by 100)
\( \implies B = \frac{1360 \times 100}{1700} \)
\( \implies B = 80\% \)
In Wadgaon, the percentage of women who voted in the elections was 80%.
\( \implies \) A greater proportion of women cast their votes in Jambhulgaon.
In simple words: Calculate the voting percentage for each village by dividing the number of voters by the total population and multiplying by 100. Then, compare the two percentages to determine which village had a higher proportion of women voters.

🎯 Exam Tip: Always compare the calculated percentages directly to determine the greater proportion, ensuring both calculations are distinct and clear.

Maharashtra Board Class 6 Maths Chapter 12 Percentage Practice Set 30 Intext Questions And Activities

Question 1. There are 9 squares in the figure alongside. The letters ABCDEFGHI are written in squares. Give each of the letters a unique number from 1 to 9 so that every letter has a different number.
Besides, A + B + C = C + D + E = E+F+ G = G + H + I should also be true.
(Textbook pg. no. 64)
ℹ️ चित्र व्याख्या (Diagram Explanation): A 3x3 grid-like structure is shown where letters A, B, C are in the first row, D is in the middle of the second row, E, F, G are in the third row, H is in the middle of the fourth row, and I is in the middle of the fifth row. Students need to assign unique numbers from 1 to 9 to these letters such that the sums A+B+C, C+D+E, E+F+G, and G+H+I are all equal.
Answer: Solution:

🎯 Exam Tip: For such puzzles, a systematic approach of trial and error while keeping the unique number and sum conditions in mind is key. Start with common numbers and try to build the sums.

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