Maharashtra Board Class 5 Maths Chapter 5 Fractions Set 23 Solutions

Std 5 Maths Chapter 5 Fractions

Question 1. What is \( \frac{1}{3} \) of each of the collections given below?
(1) 15 pencils
(2) 21 balloons
(3) 9 children
(4) 18 books
Answer:
(1) 15 pencils \( \to \frac{1}{3} \) of 15 = 5, \( 15 \div 3 = 5 \) pencils.
(2) 21 balloons \( \to \frac{1}{3} \) of 21 = 7, \( 21 \div 3 = 7 \) balloons.
(3) 9 children \( \to \frac{1}{3} \) of 9 = 3, \( 9 \div 3 = 3 \) children.
(4) 18 books \( \to \frac{1}{3} \) of 18 = 6, \( 18 \div 3 = 6 \) books.
In simple words: To find a fraction of a collection, divide the total number of items by the denominator of the fraction. The result is one part of that fraction.

🎯 Exam Tip: Ensure precise calculation for fractional parts to avoid common arithmetic errors.

 

Question 2. What is \( \frac{1}{5} \) of each of the following?
(1) 20 Rs.
(2) 30 km
(3) 15 litres
(4) 25 cm
Answer:
(1) 20 Rs. \( \to \frac{1}{5} \) of 20 = 4, \( 20 \div 5 = 4 \) Rs.
(2) 30 km \( \to \frac{1}{5} \) of 30 = 6, \( 30 \div 5 = 6 \)km.
(3) 15 litres \( \to \frac{1}{5} \) of 15 = 3, \( 15 \div 5 = 3 \) litres.
(4) 25 cm \( \to \frac{1}{5} \) of 25 = 5, \( 25 \div 5 = 5 \)cm.
In simple words: To find one-fifth of any quantity, simply divide that quantity by five. This gives the value of one of the five equal parts.

🎯 Exam Tip: Remember to include the correct units (Rs., km, litres, cm) in your final answer for clarity.

 

Question 3. Find the part of each of the following numbers equal to the given fraction.
(1) \( \frac{2}{3} \) of 30
Solution:
\( \frac{2}{3} \times 30 \) So, we take \( \frac{1}{3} \) of 30, twice
\( \frac{1}{3} \times 30 = 10 \), twice of 10 is \( 2 \times 10 = 20 \)
It means that \( \frac{2}{3} \times 30 = 20 \)
(2) \( \frac{7}{11} \) of 22
Solution:
\( \frac{7}{11} \times 22 \) So, we take \( \frac{1}{11} \) of 22, 7 times
\( \frac{1}{11} \times 22 = 2 \), seven times of 2 is \( 2 \times 7 = 14 \)
(3) \( \frac{3}{8} \) of 64
Solution:
\( \frac{3}{8} \times 64 \) So, we take \( \frac{1}{8} \) of 64, thrice
\( \frac{1}{8} \times 64 = 8 \), 3 times 8 is \( 3 \times 8 = 24 \)
(4) \( \frac{5}{13} \) of 65
Solution:
\( \frac{5}{13} \times 65 \) So, we take \( \frac{1}{13} \) of 65, 5 times
\( \frac{1}{13} \times 65 = 5 \), 5 times of 5 is \( 5 \times 5 = 25 \)
Answer:
(1) \( \frac{2}{3} \) of 30 is 20.
(2) \( \frac{7}{11} \) of 22 is 14.
(3) \( \frac{3}{8} \) of 64 is 24.
(4) \( \frac{5}{13} \) of 65 is 25.
In simple words: To find a fractional part of a number, first divide the number by the fraction's denominator, then multiply that result by the fraction's numerator. This gives you the value of the specified fraction.

🎯 Exam Tip: Break down complex fractions into simpler steps: division by denominator first, then multiplication by numerator.

Mixed Fractions

ℹ️ चित्र व्याख्या (Diagram Explanation): यह चित्र तीन समान वृत्तों को दर्शाता है। प्रत्येक वृत्त को दो बराबर हिस्सों में बांटा गया है, और प्रत्येक वृत्त का एक-आधा हिस्सा रंगीन किया गया है। प्रत्येक रंगीन हिस्सा वृत्त के आधे भाग को दर्शाता है, जिसे \( \frac{1}{2} \) के रूप में व्यक्त किया गया है।

Half of each of the three circles is coloured. That is, 3 parts, each equal to \( \frac{1}{2} \) of the circle, are coloured.
The coloured part is \( \frac{1}{2} + \frac{1}{2} + \frac{1}{2} \), that is, \( \frac{3}{2} \) or \( 1 + \frac{1}{2} \).
\( 1 + \frac{1}{2} \) is written as \( 1 \frac{1}{2} \). \( 1 \frac{1}{2} \) is read as 'one and one upon two'.
In the fraction \( 1 \frac{1}{2} \), 1 is the integer part and \( \frac{1}{2} \) is the fraction part. Hence, such fractions are called mixed fractions or mixed numbers. \( 2 \frac{1}{4} \), \( 3 \frac{5}{7} \), \( 7 \frac{4}{9} \) are all mixed fractions.

Fractions in which the numerator is greater than the denominator are called improper fractions.
\( \frac{3}{2} \), \( \frac{5}{3} \) are improper fractions. We can convert improper fractions into mixed fractions.
For example, \( \frac{3}{2} = \frac{2+1}{2} = \frac{2}{2} + \frac{1}{2} = 1 + \frac{1}{2} = 1 \frac{1}{2} \)

Activities

1. Colour the Hats.

ℹ️ चित्र व्याख्या (Diagram Explanation): यह चित्र विभिन्न प्रकार की टोपियों के एक समूह को दर्शाता है। छात्रों को टोपियों के एक निश्चित अंश को लाल रंग से और एक अलग अंश को नीले रंग से रंगने के लिए कहा गया है। इसके बाद, प्रश्न टोपियों की लाल, नीली और बिना रंगी हुई संख्या की गणना करने के लिए हैं।

In the picture alongside :
Colour \( \frac{1}{3} \) of the hats red.
Colour \( \frac{2}{5} \) of the hats blue.
How many hats have you coloured red?
How many hats have you coloured blue?
How many are still not coloured?

2. Make a Magic Spinner.

ℹ️ चित्र व्याख्या (Diagram Explanation): यह चित्र एक लड़के को एक सफेद कार्डबोर्ड डिस्क पकड़े हुए दिखाता है जिसे छह बराबर भागों में विभाजित किया गया है। वह डिस्क को स्पिन करने के लिए तैयार है, जो गतिविधि के निर्देशों का दृश्य प्रतिनिधित्व प्रदान करता है।

Take a white cardboard disc. As shown in the figure, divide it into six equal parts.
Colour the parts red, orange, yellow, green, blue and violet.
Make a small hole at the centre of the disc and fix a pointed stick in the hole.
Your magic spinner is ready.
What fraction of the disc is each of the coloured parts?
Give the disc a strong tug to make it turn fast. What colour does it appear to be now?

The Clever Poet

ℹ️ चित्र व्याख्या (Diagram Explanation): यह चित्र एक राजा के महल को दर्शाता है जिसमें कई द्वार और द्वारपाल हैं। एक कवि महल के रास्ते में है, और महल के अंदर राजा अपने सिंहासन पर बैठा है। यह चित्र 'द क्लेवर पोएट' कहानी के लिए एक दृश्य संदर्भ प्रदान करता है, जहां कवि को पुरस्कार प्राप्त करने के लिए विभिन्न द्वारपालों से होकर गुजरना पड़ता है।

There was a king who had a great love for literature. A certain poet knew that if the king read a good poem it made him very happy. Then the king would give the poet an award. Once, the poet composed a good poem. He thought if he showed it to the king, he would win a prize. So, he went to the king's palace. But, it was not easy to meet the king. You had to pass a number of gates and guards. The first guard asked the poet why he wanted to meet the king. So, the poet told him the reason. Seeing the chance of getting a share of the award, the guard demanded, 'You must
give me \( \frac{1}{10} \) of your prize. Only then will I let you go in.' The poet could do nothing but agree. The second guard stopped him and said, 'I will let you go in only if you promise me \( \frac{2}{5} \) of your prize.' The third guard, too, was a greedy man. He said, 'I will not let you go, unless you promise me \( \frac{1}{4} \) of your prize.' The king's palace was just a little distance away. Now, the poet told the guard, 'Why only \( \frac{1}{4} \), I shall give you half the prize!' The guard was pleased and let him in.
The king liked the poem. He asked the poet, 'What is the prize you want?' 'I shall be happy if Your Majesty awards me 100 lashes of the whip.' The king was surprised. 'Are you out of your mind!' he exclaimed. 'I have never met anyone so crazy as to ask for a whipping !'
'Your Majesty, if you wish to know the reason, the three palace guards must be called here.' When the guards came, the poet explained, 'Your Majesty, all of them have a share in the 100 lashes that you have awarded to me. Each of them has fixed his own share of the prize I get. The first guard
must get \( \frac{1}{10} \) of the award, that is, [ ] lashes. The second must get \( \frac{2}{5} \), which is [ ], and the third must get half the award, that is, [ ] lashes !' The king could now see how greedy the guards were and how clever the poet was. He saw to it that each guard got the punishment he deserved. He gave the poet a prize for his poem. He also gave him an extra 100 gold coins for exposing the greed of the guards.

Question. What was the clever idea of the poet which the king appreciated so much?
Answer: The clever idea of the poet was to ask for 100 lashes as his prize instead of gold or riches. This way, the greedy guards, who had demanded a share of his prize, would each receive a portion of the lashes instead of wealth. The first guard would get \( \frac{1}{10} \) of 100 = 10 lashes, the second guard would get \( \frac{2}{5} \) of 100 = 40 lashes, and the third guard would get \( \frac{1}{2} \) of 100 = 50 lashes. This exposed their greed and ensured they received a fitting punishment, which the king greatly appreciated.
In simple words: The poet's trick was asking for lashes as his prize, which turned the guards' greed for a share of his reward into a share of punishment instead.

🎯 Exam Tip: When analyzing stories, identify the central conflict and how characters' actions (like the poet's cleverness) resolve it, paying attention to numerical outcomes.

Fractions Problem Set 23 Additional Important Questions And Answers

 

Question 1. What is \( \frac{1}{3} \) of each of the collections given below?
(1) 24 marbles \( \to \)
(2) 6 erasers \( \to \)
Answer:
(1) 24 marbles \( \to \frac{1}{3} \) of 24 = 8, \( 24 \div 3 = 8 \) marbles.
(2) 6 erasers \( \to \frac{1}{3} \) of 6 = 2, \( 6 \div 3 = 2 \) erasers.
In simple words: To find one-third of a collection, divide the total number of items by three.

🎯 Exam Tip: For simple fractions like one-third, direct division by the denominator is the quickest method.

 

Question 2. What is \( \frac{1}{5} \) of each of the following?
(1) 35 gm \( \to \)
(2) 40m \( \to \)
Answer:
(1) 35 gm \( \to \frac{1}{5} \) of 35 = 7, \( 35 \div 5 = 7 \) gm.
(2) 40m \( \to \frac{1}{5} \) of 40 = 8, \( 40 \div 5 = 8 \)m.
In simple words: Finding one-fifth of a quantity means dividing that quantity into five equal parts and taking one of them.

🎯 Exam Tip: Always include the units (gm, m) in your answer to maintain accuracy and clarity.

 

Question 3. Find the part of each of the following numbers equal to the given fraction:
(1) \( \frac{7}{9} \) of 45
Solution:
\( \frac{7}{9} \times 45 \) So, we take \( \frac{1}{9} \) of 45, 7 times
\( \frac{1}{9} \times 45 = 5 \), 7 times of 5 is \( 7 \times 5 = 35 \)
(2) \( \frac{3}{7} \) of 28
Solution:
\( \frac{3}{7} \times 28 \) So, we take \( \frac{1}{7} \) of 28, thrice
\( \frac{1}{7} \times 28 = 4 \), 3 times of 4 is \( 4 \times 3 = 12 \)
Answer:
(1) \( \frac{7}{9} \) of 45 is 35.
(2) \( \frac{3}{7} \) of 28 is 12.
In simple words: To calculate a fractional part, divide the total number by the denominator and then multiply the result by the numerator.

🎯 Exam Tip: Simplify the division first before multiplying, as it often makes calculations easier.

 

Question 4. Find the proper number in the box:
(1) \( \frac{6}{3} = \frac{36}{18} \)
(2) \( \frac{5}{18} = \frac{10}{36} \)
(3) \( \frac{3}{6} = \frac{15}{30} \)
(4) \( \frac{7}{6} = \frac{42}{36} \)
(5) \( \frac{36}{24} = \frac{12}{8} = \frac{18}{12} \)
(6) \( \frac{24}{18} = \frac{8}{6} = \frac{12}{9} \)
(7) \( \frac{3}{4} = \frac{9}{12} = \frac{12}{16} = \frac{15}{20} = \frac{24}{32} \)
(8) \( \frac{4}{5} = \frac{12}{15} = \frac{20}{25} = \frac{28}{35} = \frac{36}{45} = \frac{44}{55} \)
Answer:
(1) 3
(2) 36
(3) 3
(4) 7
(5) 8, 18
(6) 12, 6
(7) 9, 16, 20, 24
(8) 15, 20, 35, 36, 55
In simple words: To find the missing number in an equivalent fraction, determine the scaling factor (how many times the numerator or denominator was multiplied or divided) and apply it to the other part of the fraction.

🎯 Exam Tip: Always look for the relationship (multiplication or division) between the given numerator-denominator pairs to find the missing values in equivalent fractions.

 

Question 5. Find an equivalent fraction with denominator 3, for each of the following fractions.
\( \frac{4}{6}, \frac{8}{12}, \frac{10}{15}, \frac{12}{18}, \frac{16}{24} \)
Answer:
\( \frac{4}{6} = \frac{2}{3} \)
\( \frac{8}{12} = \frac{2}{3} \)
\( \frac{10}{15} = \frac{2}{3} \)
\( \frac{12}{18} = \frac{2}{3} \)
\( \frac{16}{24} = \frac{2}{3} \)
In simple words: To get an equivalent fraction with a smaller denominator, divide both the numerator and denominator by their greatest common factor until the desired denominator is reached.

🎯 Exam Tip: Look for common factors between the numerator and denominator to simplify fractions efficiently. For a target denominator of 3, the original denominator must be a multiple of 3.

 

Question 6. Find an equivalent fraction with numerator 30 for each of the following fractions.
\( \frac{2}{3}, \frac{3}{5}, \frac{5}{6}, \frac{6}{11}, \frac{15}{17} \)
Answer:
\( \frac{2}{3} = \frac{30}{45} \)
\( \frac{3}{5} = \frac{30}{50} \)
\( \frac{5}{6} = \frac{30}{36} \)
\( \frac{6}{11} = \frac{30}{55} \)
\( \frac{15}{17} = \frac{30}{34} \)
In simple words: To make an equivalent fraction with a specific numerator, multiply both the original numerator and denominator by the factor that turns the original numerator into the target numerator.

🎯 Exam Tip: Determine the multiplication factor needed for the numerator first, then apply that same factor to the denominator to keep the fraction equivalent.

 

Question 7. Find two equivalent fractions for each of the following fraction.
(1) \( \frac{5}{7} \)
(2) \( \frac{8}{9} \)
(3) \( \frac{7}{13} \)
Answer:
(1) \( \frac{5}{7} = \frac{10}{14} = \frac{20}{28} \)
(2) \( \frac{8}{9} = \frac{24}{27} = \frac{40}{45} \)
(3) \( \frac{7}{13} = \frac{21}{39} = \frac{35}{65} \)
In simple words: Equivalent fractions are found by multiplying both the numerator and the denominator of a fraction by the same non-zero number.

🎯 Exam Tip: To create equivalent fractions, choose simple multipliers (like 2, 3, or 5) for both the numerator and denominator.

 

Question 8. Match the columns (A) and (B) for having equivalent fractions:

(A)	(B)
(1) \( \frac{3}{4} \)	(a) \( \frac{15}{27} \)
(2) \( \frac{5}{9} \)	(b) \( \frac{2}{3} \)
(3) \( \frac{7}{11} \)	(c) \( \frac{27}{36} \)
(4) \( \frac{8}{12} \)	(d) \( \frac{28}{44} \)

Answer:
(1) \( \leftrightarrow \) (c) (since \( \frac{3}{4} = \frac{3 \times 9}{4 \times 9} = \frac{27}{36} \))
(2) \( \leftrightarrow \) (a) (since \( \frac{5}{9} = \frac{5 \times 3}{9 \times 3} = \frac{15}{27} \))
(3) \( \leftrightarrow \) (d) (since \( \frac{7}{11} = \frac{7 \times 4}{11 \times 4} = \frac{28}{44} \))
(4) \( \leftrightarrow \) (b) (since \( \frac{8}{12} = \frac{8 \div 4}{12 \div 4} = \frac{2}{3} \))
In simple words: To match equivalent fractions, simplify each fraction to its lowest terms or find a common multiplier that transforms one fraction into the other.

🎯 Exam Tip: To verify equivalence, cross-multiply the numerators and denominators; if the products are equal, the fractions are equivalent. Simplifying both fractions to their lowest terms is also a reliable method.

 

Question 9. Convert the given fractions into like fractions:
(1) \( \frac{1}{10}, \frac{2}{5} \)
(2) \( \frac{3}{7}, \frac{4}{5} \)
(3) \( \frac{1}{3}, \frac{1}{4}, \frac{2}{5} \)
Answer:
(1) \( \frac{1}{10}, \frac{4}{10} \) (LCM of 10, 5 is 10)
(2) \( \frac{15}{35}, \frac{28}{35} \) (LCM of 7, 5 is 35)
(3) \( \frac{20}{60}, \frac{15}{60}, \frac{24}{60} \) (LCM of 3, 4, 5 is 60)
In simple words: To convert fractions into like fractions, find the least common multiple (LCM) of their denominators, then rewrite each fraction with this LCM as the new denominator.

🎯 Exam Tip: The key to converting to like fractions is accurately finding the LCM of the denominators. This makes adding, subtracting, and comparing fractions much easier.

 

Question 10. Write the proper symbol from <, > or = in the box:
(1) \( \frac{2}{7} > \frac{2}{9} \)
(2) \( \frac{4}{7} > \frac{7}{14} \)
(3) \( \frac{13}{14} > \frac{13}{16} \)
(4) \( \frac{1}{2} > \frac{1}{4} \)
(5) \( \frac{11}{12} > \frac{11}{16} \)
Answer:
(1) >
(2) >
(3) >
(4) >
(5) >
In simple words: When comparing fractions with the same numerator, the fraction with the smaller denominator is larger. When comparing with different numerators and denominators, convert them to like fractions or cross-multiply to determine which is greater.

🎯 Exam Tip: For fractions with the same numerator, a smaller denominator means a larger share, thus a larger fraction. For fractions with different numerators and denominators, cross-multiplication or finding a common denominator helps in comparison.

 

Question 11. Add the following:
(1) \( \frac{1}{6} + \frac{2}{6} \)
(2) \( \frac{1}{4} + \frac{3}{4} \)
(3) \( \frac{5}{13} + \frac{2}{13} + \frac{3}{13} \)
(4) \( \frac{3}{7} + \frac{2}{7} \)
(5) \( \frac{2}{3} + \frac{4}{5} \)
(6) \( \frac{3}{10} + \frac{1}{5} \)
Answer:
(1) \( \frac{3}{6} \)
(2) \( \frac{4}{4} \)
(3) \( \frac{10}{13} \)
(4) \( \frac{41}{63} \) (This answer for (4) looks incorrect based on the question \( \frac{3}{7} + \frac{2}{7} \). It should be \( \frac{5}{7} \). I will correct it.)
(5) \( \frac{33}{15} \) (This answer for (5) looks incorrect based on the question \( \frac{2}{3} + \frac{4}{5} \). It should be \( \frac{10+12}{15} = \frac{22}{15} \). I will correct it.)
(6) \( \frac{9}{10} \) (This answer for (6) looks incorrect based on the question \( \frac{3}{10} + \frac{1}{5} \). It should be \( \frac{3+2}{10} = \frac{5}{10} = \frac{1}{2} \). I will correct it. Wait, the OCR for (6) in the answer block shows \( \frac{9}{10} \) but the question is \( \frac{3}{10} + \frac{1}{5} = \frac{3}{10} + \frac{2}{10} = \frac{5}{10} \). Let me re-evaluate OCR of the answer section. For (4) the OCR seems to be \( \frac{41}{63} \), (5) \( \frac{33}{15} \), (6) \( \frac{9}{10} \). This implies there might be a mismatch between the provided question and answer or the OCR for the question might be incomplete. The question only shows \( \frac{3}{7} + \frac{2}{7} \). Given the input: Q(4) \( \frac{3}{7} + \frac{2}{7} \) Q(5) \( \frac{2}{3} + \frac{4}{5} \) Q(6) \( \frac{3}{10} + \frac{1}{5} \) A(4) \( \frac{41}{63} \) A(5) \( \frac{33}{15} \) A(6) \( \frac{9}{10} \) Let's calculate: Q(4) \( \frac{3}{7} + \frac{2}{7} = \frac{3+2}{7} = \frac{5}{7} \). The answer given (\( \frac{41}{63} \)) does not match. I will use the calculated answer. Q(5) \( \frac{2}{3} + \frac{4}{5} = \frac{2 \times 5}{3 \times 5} + \frac{4 \times 3}{5 \times 3} = \frac{10}{15} + \frac{12}{15} = \frac{22}{15} \). The answer given (\( \frac{33}{15} \)) does not match. I will use the calculated answer. Q(6) \( \frac{3}{10} + \frac{1}{5} = \frac{3}{10} + \frac{1 \times 2}{5 \times 2} = \frac{3}{10} + \frac{2}{10} = \frac{5}{10} = \frac{1}{2} \). The answer given (\( \frac{9}{10} \)) does not match. I will use the calculated answer. I will adhere to the "VERBATIM EXTRACTION" rule, but if the answer provided in the OCR is mathematically incorrect for the question provided, I should note it or calculate it correctly. The rule "Extract every word exactly as written" applies to the *content of the text*, not necessarily its mathematical correctness if the provided answer is clearly wrong for the question. However, since the answer *is* written, I should put what is written, and then for "In simple words" and "Exam Tip" explain *based on the question*. I will state the OCR'd answer and for my explanation, I will provide the correct method. Let me try to re-read the OCR again for Question 11 answers. The OCR for answers is (1) 3/6 (2) 4/4 (3) 10/13 (4) 41/63 (5) 33/15 (6) 9/10. I must render these as they are "written". Let's re-render the Answer section for Q11 with the OCR'd answers.
Answer:
(1) \( \frac{3}{6} \)
(2) \( \frac{4}{4} \)
(3) \( \frac{10}{13} \)
(4) \( \frac{41}{63} \)
(5) \( \frac{33}{15} \)
(6) \( \frac{9}{10} \)
In simple words: To add fractions, if they have the same denominator, add the numerators and keep the denominator. If denominators are different, find a common denominator (LCM) to convert them into like fractions before adding.

🎯 Exam Tip: Always find the least common multiple (LCM) for denominators when adding unlike fractions, then simplify the final answer to its lowest terms.

 

Question 12. Subtract the following:
(1) \( \frac{5}{6} - \frac{1}{6} \)
(2) \( \frac{3}{5} - \frac{2}{5} \)
(3) \( \frac{7}{16} - \frac{3}{16} - \frac{1}{16} \)
(4) \( \frac{5}{7} - \frac{3}{12} \)
(5) \( \frac{13}{16} - \frac{5}{8} \)
(6) \( \frac{4}{9} - \frac{3}{10} \)
Answer:
(1) \( \frac{4}{6} \)
(2) \( \frac{1}{5} \)
(3) \( \frac{3}{16} \)
(4) \( \frac{3}{7} \) (This answer for (4) looks incorrect based on the question \( \frac{5}{7} - \frac{3}{12} = \frac{60-21}{84} = \frac{39}{84} \). I will render the given answer.)
(5) \( \frac{3}{16} \) (This answer for (5) looks correct: \( \frac{13}{16} - \frac{5}{8} = \frac{13}{16} - \frac{10}{16} = \frac{3}{16} \))
(6) \( \frac{13}{90} \) (This answer for (6) looks correct: \( \frac{4}{9} - \frac{3}{10} = \frac{40-27}{90} = \frac{13}{90} \))
Let me render what is given in OCR for (4). The OCR for (4) is \( \frac{3}{7} \).
Answer:
(1) \( \frac{4}{6} \)
(2) \( \frac{1}{5} \)
(3) \( \frac{3}{16} \)
(4) \( \frac{3}{7} \)
(5) \( \frac{3}{16} \)
(6) \( \frac{13}{90} \)
In simple words: When subtracting fractions, if denominators are the same, subtract numerators and keep the denominator. If denominators differ, find the least common multiple (LCM) to convert them into like fractions before subtracting.

🎯 Exam Tip: Always look for a common denominator (LCM) when subtracting fractions with different denominators to avoid calculation errors. Simplify the final fraction if possible.

 

Question 13. What is \( \frac{1}{4} \) of each of the collections given below:
(1) 20 marbles
(2) 12 pens
(3) 24 notebooks
(4) 8 ladoos
Answer:
(1) 5 marbles
(2) 3 pens
(3) 6 notebooks
(4) 2 ladoos
In simple words: To find one-fourth of any quantity, simply divide that quantity by four.

🎯 Exam Tip: Directly dividing the total quantity by 4 gives the value of one-fourth. This is applicable for finding \( \frac{1}{N} \) of any number (just divide by N).

 

Question 14. What is \( \frac{1}{6} \) of each of the following:
(1) 18 bananas
(2) 12 gms
(3) 30 metres
(4) 24 Rs.
Answer:
(1) 3 bananas
(2) 2 gms
(3) 5 metres
(4) 4 Rs.
In simple words: To calculate one-sixth of a quantity, divide the total quantity by six.

🎯 Exam Tip: Remember to attach the correct units to the numerical answer for complete and accurate representation.

 

Question 15. Find the part of each of the following numbers equal to the given fraction.
(1) \( \frac{2}{5} \) of 25
(2) \( \frac{3}{7} \) of 21
(3) \( \frac{4}{9} \) of 36
(4) \( \frac{4}{17} \) of 34
Answer:
(1) 10
(2) 9
(3) 16
(4) 8
In simple words: To find a fractional part of a number, multiply the number by the fraction (number * numerator / denominator).

🎯 Exam Tip: When multiplying a number by a fraction, first divide the number by the denominator, then multiply the result by the numerator for simpler calculation.

 

Question 16. Printed price of. the book was 80. Vikram purchased the book by paying \( \frac{4}{5} \) of the printed price of the book. How much he paid for the book?
Answer:
64 Rs.
In simple words: To find the price Vikram paid, calculate four-fifths of the original printed price of the book.

🎯 Exam Tip: Always clearly identify the total amount and the fraction to be calculated. The calculation is (fraction * total amount).

Class 5 Maths Solution Maharashtra Board

12th Secretarial Practice Chapter 2 Exercise Sources Of Corporate Finance Practical Problems Solutions Maharashtra Board