Maharashtra Board Class 5 Maths Chapter 4 Multiplication and Division Set 15 Solutions

Multiplication And Division Class 5 Problem Set 15 Question Answer Maharashtra Board

Std 5 Maths Chapter 4 Multiplication And Division

Question 1. Solve the following and write the quotient and remainder.
(1) 1284 ÷ 32
Answer:

		40
32	)	1284
	-	128
		---
		0004
		-0
		---
		4

Quotient = 40
Remainder = 4
In simple words: To solve this, we divide 1284 by 32. After performing the division, we find that 32 goes into 1284 exactly 40 times with a remainder of 4.

🎯 Exam Tip: Always show your long division steps clearly to earn full marks, ensuring proper alignment of numbers and subtractions.

Question 1. (2) 5586 ÷ 87
Answer:

		64
87	)	5586
	-	522
		----
		0366
	-	348
		----
		018

Quotient = 64
Remainder = 18
In simple words: When 5586 is divided by 87, the result is 64 with a remainder of 18. This means 87 fits into 5586 sixty-four times, and 18 is left over.

🎯 Exam Tip: Double-check your multiplication in each step of the division to avoid errors in the subtractions.

Question 1. (3) 1207 ÷ 27
Answer:

		44
27	)	1207
	-	108
		----
		127
	-	108
		----
		19

Quotient = 44
Remainder = 19
In simple words: Dividing 1207 by 27 gives a quotient of 44 and a remainder of 19. This means 27 goes into 1207 forty-four times, with 19 left as the remainder.

🎯 Exam Tip: Pay close attention to borrowing and subtracting accurately in each step of the long division process.

Question 1. (4) 8543 ÷ 41
Answer:

		208
41	)	8543
	-	82
		----
		034
	-	00
		----
		343
	-	328
		----
		15

Quotient = 208
Remainder = 15
In simple words: When 8543 is divided by 41, the quotient obtained is 208, and the remainder is 15. This signifies that 41 can be subtracted 208 times from 8543, with 15 remaining.

🎯 Exam Tip: Remember to place a zero in the quotient if the divisor does not go into the current part of the dividend, as seen in the '034' step.

Question 1. (5) 2304 ÷ 43
Answer:

		53
43	)	2304
	-	215
		----
		0154
	-	129
		----
		025

Quotient = 53
Remainder = 25
In simple words: Dividing 2304 by 43 yields a quotient of 53 and a remainder of 25. This means 43 can be fitted into 2304 fifty-three times, with 25 remaining at the end.

🎯 Exam Tip: Estimating the first digit of the quotient correctly can simplify the subsequent steps of the division.

Question 1. (6) 56,741 ÷ 26
Answer:

		2182
26	)	56741
	-	52
		-----
		047
	-	26
		-----
		214
	-	208
		-----
		0061
	-	52
		-----
		0009

Quotient = 2182
Remainder = 9
In simple words: When 56,741 is divided by 26, the quotient is 2182, and the remainder is 9. This means 26 goes into 56,741 two thousand one hundred eighty-two times, with 9 left over.

🎯 Exam Tip: Long division with larger numbers requires careful attention to place values and consistent application of the division steps.

Question 2. How many hours will it take to travel 336 km at a speed of 48 km per hour?
Answer:
Solution: Time = Distance ÷ Speed

		7
48	)	336
	-	336
		----
		000

It will take 7 hours.
In simple words: To find the time taken, we divide the total distance (336 km) by the speed (48 km/hour), which gives 7 hours.

🎯 Exam Tip: Remember the formula for speed, distance, and time (Distance = Speed × Time) and how to rearrange it for the required variable.

Question 3. Girija needed 35 cartons to pack 1400 books. There are an equal number of books in every carton. How many books did she pack into each carton?
Answer:
Solution: No. of cartons x No. of books in each carton = Total no. of books
35 x No. of books in each carton = 1400
No. of books in each carton = 1400 ÷ 35

		40
35	)	1400
	-	140
		----
		0000

She packs 40 books in each carton.
In simple words: To find the number of books in each carton, we divide the total number of books (1400) by the number of cartons (35), which results in 40 books per carton.

🎯 Exam Tip: Clearly state the formula or relationship between the given quantities before performing the calculation.

Question 4. The contribution for a picnic was 65 rupees each. Altogether, 2925 rupees were collected. How many had paid for the picnic?
Answer:
Solution:

		45
65	)	2925
	-	260
		----
		0325
	-	325
		----
		000

45 persons paid for the picnic.
In simple words: To find out how many people paid, we divide the total amount collected (2925 rupees) by the contribution per person (65 rupees), giving us 45 people.

🎯 Exam Tip: For word problems, ensure your final answer clearly states the units or what the number represents (e.g., "persons").

Question 5. Which number, on being multiplied by 56, gives a product of 9688?
Answer:
Solution:

		173
56	)	9688
	-	56
		----
		408
	-	392
		----
		168
	-	168
		----
		000

173
In simple words: To find the unknown number, we perform the inverse operation of multiplication, which is division. We divide the product (9688) by the known multiplier (56), resulting in 173.

🎯 Exam Tip: Remember that if \(A \times B = C\), then \(B = C \div A\), which is a crucial concept for solving such problems.

Question 6. If 48 sheets are required for making one notebook, how many notebooks at the most will 5880 sheets make and how many sheets will be left over?
Answer:
Solution:

		122
48	)	5880
	-	48
		----
		108
	-	96
		----
		0120
	-	96
		----
		024

122 notebooks can be made and 24 sheets left over.
In simple words: To find the number of notebooks, we divide the total sheets (5880) by the sheets per notebook (48). The quotient (122) is the number of notebooks, and the remainder (24) is the sheets left over.

🎯 Exam Tip: In problems asking "how many...and how many left over," the quotient is the main answer, and the remainder is the "left over" part.

Question 7. What will the quotient be when the smallest five-digit number is divided by the smallest four-digit number?
Answer:
Solution:
Smallest five-digit number is 10,000 and smallest four-digit number is 1,000.
So, 10000 ÷ 1000 = 10

		10
1000	)	10000
	-	1000
		------
		00000

Quotient = 10
In simple words: The smallest five-digit number is 10,000 and the smallest four-digit number is 1,000. Dividing 10,000 by 1,000 gives a quotient of 10.

🎯 Exam Tip: Know the definition of smallest/largest numbers for a given number of digits (e.g., smallest 3-digit is 100, largest 3-digit is 999).

Mixed Examples

Question. A farmer brought 140 trays of chilli seedlings. Each tray had 24 seedlings. He planted all the seedlings in his field, putting 32 in a row. How many rows of chillies did he plant?
Answer:
Let us find out the total number of seedlings when there were 24 seedlings in each of the 140 trays. We shall multiply 140 and 24.

		140
	x	24
-----
		560
+		2800
-----
		3360

Total number of seedlings 3,360.
To find out how many rows were planted with 32 seedlings in each row, we shall divide 3,360 by 32.
The quotient is 105.
Therefore, the number of rows is 105.
Carry out the multiplication of 105 × 32 and verify your answer.

		105
32	)	3360
	-	32
		----
		016
	-	00
		----
		160
	-	160
		----
		000

In simple words: First, calculate the total seedlings by multiplying trays (140) by seedlings per tray (24), which is 3360. Then, divide the total seedlings (3360) by the number of seedlings per row (32) to get 105 rows.

🎯 Exam Tip: Break down multi-step word problems into smaller, manageable calculations (e.g., first find total, then divide) and show each step clearly.

Multiplication And Division Problem Set 15 Additional Important Questions And Answers

Solve The Following And Write The Quotient And Remainder.

Question. (1) 9148 ÷ 37
Answer:

		247
37	)	9148
	-	74
		----
		174
	-	148
		----
		0268
	-	259
		----
		009

Quotient = 247
Remainder = 9
In simple words: When 9148 is divided by 37, the division process yields a quotient of 247 and a remainder of 9.

🎯 Exam Tip: Practice mental multiplication of smaller numbers with the divisor to speed up the long division process.

Question. (2) 1175 ÷ 15
Answer:

		78
15	)	1175
	-	105
		----
		0125
	-	120
		----
		005

Quotient = 78
Remainder = 5
In simple words: Dividing 1175 by 15 results in a quotient of 78, meaning 15 goes into 1175 seventy-eight times, with a remainder of 5.

🎯 Exam Tip: Always clearly state both the quotient and the remainder when asked, as both are part of the complete answer for division problems.

Solve The Following Word Problems:

Question. (1) If 45 kg of sugar cost 1305 Rs., what is the rate of sugar per kg?
Answer:
Solution:

		29
45	)	1305
	-	90
		----
		0405
	-	405
		----
		000

The rate per kg of sugar is 29 Rs..
In simple words: To find the cost per kg, we divide the total cost (1305 Rs.) by the total quantity of sugar (45 kg), which gives us 29 Rs. per kg.

🎯 Exam Tip: Ensure that the currency abbreviation (Rs. in this case) is correctly appended to the final answer for financial problems.

Question. (2) 17 people spent Rs. 83,475. How much did each person spend and what is the amount left?
Answer:
Solution:

		4910
17	)	83475
	-	68
		-----
		154
	-	153
		-----
		0017
	-	17
		-----
		0005
	-	0
		-----
		5

Each person spent 4,910 Rs. and the amount left is 5 Rs.
In simple words: To find individual spending, divide the total amount (Rs. 83,475) by the number of people (17). Each person spent Rs. 4910, and Rs. 5 was left over as a remainder.

🎯 Exam Tip: When dealing with money, clearly state both the amount spent per person and any remaining amount, ensuring correct currency notation.

Class 5 Maths Solution Maharashtra Board