Practice MCQs for JEE Chemistry S Block Elements
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Multiple Choice Questions
(a) Blue and non-conducting
(b) Blue and conducting
(c) Colourless and non-conducting
(d) Colourless and conducting
Show Answer & Explanation
Answer: (b) Blue and conducting
Explanation:
1. The metal dissolves to give ammoniated cations and ammoniated electrons: M + (x+y)NH3 → [M(NH3)x]+ + [e(NH3)y]-.
2. The ammoniated electrons absorb red light, giving a blue colour, and the free ions make the solution conducting.
3. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) A suspension of Mg(OH)2 in water
(b) A colloid of Mg(OH)2 in water
(c) A true solution of Mg(OH)2 in water
(d) Pure Mg(OH)2
Show Answer & Explanation
Answer: (a) A suspension of Mg(OH)2 in water
Explanation:
1. Mg(OH)2 is only sparingly soluble, so in milk of magnesia its solid particles are suspended in water.
2. It is used as an antacid.
3. Answer: (a)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Limestone
(b) Dicalcium silicate
(c) Gypsum
(d) Tricalcium aluminate
Show Answer & Explanation
Answer: (c) Gypsum
Explanation:
1. About 2 to 3% gypsum (CaSO4·2H2O) is added to cement clinker.
2. It retards the rapid setting caused by tricalcium aluminate and so increases the setting time.
3. Answer: (c)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Cs+ > Rb+ > K+ > Na+ > Li+
(b) Li+ > Na+ > K+ > Rb+ > Cs+
(c) Na+ > K+ > Rb+ > Cs+ > Li+
(d) Cs+ > Na+ > Rb+ > Li+ > K+
Show Answer & Explanation
Answer: (b) Li+ > Na+ > K+ > Rb+ > Cs+
Explanation:
1. The smaller the ion, the higher its charge density and the greater its hydration.
2. Li+ is the most hydrated and Cs+ the least.
3. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Its hydroxide is the most soluble in its group
(b) It forms a peroxide
(c) Its sulphate is the most soluble among the sulphates of its group
(d) Its carbonate is the most stable in its group
Show Answer & Explanation
Answer: (c) Its sulphate is the most soluble among the sulphates of its group
Explanation:
1. The amphoteric oxide of the group 2 elements is BeO, so the element is beryllium.
2. BeSO4 is the most soluble sulphate of the group; Be(OH)2 is the least soluble hydroxide, Be forms no peroxide and BeCO3 is the least stable carbonate.
3. Answer: (c)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) B, BF3, H3BO3
(b) B2H6, BF3, H3BO3
(c) B2H6, H3BO3, BF3
(d) Na2B4O7, B2H6, BF3
Show Answer & Explanation
Answer: (c) B2H6, H3BO3, BF3
Explanation:
1. Diborane is made by 4BF3 + 3LiAlH4 → 2B2H6 + 3LiF + 3AlF3, so Z is BF3 and X is B2H6.
2. B2H6 + 6H2O → 2H3BO3 + 6H2 (Y = H3BO3), and B2H6 burns to B2O3 and water.
3. Answer: (c)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) NaCl + NH4HCO3 → NaHCO3 + NH4Cl
(b) 2NaOH + CO2 → Na2CO3 + H2O
(c) 2NaHCO3 → Na2CO3 + H2O + CO2 (on heating)
(d) NH3 + H2CO3 → NH4HCO3
Show Answer & Explanation
Answer: (b) 2NaOH + CO2 → Na2CO3 + H2O
Explanation:
1. In the Solvay process ammoniated brine is carbonated to NH4HCO3, which gives NaHCO3 with NaCl; heating then gives Na2CO3.
2. Reaction of NaOH with CO2 is not a step in it.
3. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) NaCl
(b) LiCl
(c) BaCl2
(d) CaCl2
Show Answer & Explanation
Answer: (b) LiCl
Explanation:
1. LiCl is largely covalent, because the small Li+ polarises Cl-, so it dissolves in organic solvents like ether.
2. The other chlorides are ionic.
3. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Na2SO5
(b) Na2S2O8
(c) Na2S2O6
(d) Na2S2O3
Show Answer & Explanation
Answer: (d) Na2S2O3
Explanation:
1. Sodium thiosulphate (hypo) dissolves unexposed silver halide by forming a soluble silver thiosulphate complex.
2. Answer: (d)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Be
(b) Mg
(c) Cs
(d) Ba
Show Answer & Explanation
Answer: (d) Ba
Explanation:
1. Cs is an alkali metal, so it is not an alkaline earth metal.
2. Among the alkaline earth metals Be, Mg and Ba, Ba has the lowest ionisation enthalpy and is the most electropositive.
3. Answer: (d)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) Potassium (K)
(b) Bromine (Br)
(c) Sodium (Na)
(d) Magnesium (Mg)
Show Answer & Explanation
Answer: (c) Sodium (Na)
Explanation:
1. Chile saltpetre is sodium nitrate, NaNO3.
2. Answer: (c)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) H2O2
(b) Na2O
(c) Na2O and O3
(d) NaOH and Na2CO3
Show Answer & Explanation
Answer: (d) NaOH and Na2CO3
Explanation:
1. Na2O2 absorbs moisture and CO2 from air.
2. It forms white NaOH and Na2CO3.
3. Answer: (d)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) KO2
(b) K2O2
(c) KOH
(d) LiOH
Show Answer & Explanation
Answer: (a) KO2
Explanation:
1. 4KO2 + 2CO2 → 2K2CO3 + 3O2.
2. KO2 absorbs CO2 and releases O2 at the same time; KOH and LiOH only absorb CO2.
3. Answer: (a)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) The setting time of cement becomes less
(b) The setting time of cement increases
(c) The colour of cement becomes light
(d) A shining surface is obtained
Show Answer & Explanation
Answer: (b) The setting time of cement increases
Explanation:
1. Gypsum controls the rate of hydration of tricalcium aluminate.
2. Without it, the cement would set too quickly.
3. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) CaO
(b) Ca(OH)2
(c) Ca(OCl)2
(d) Ca(ClO3)2
Show Answer & Explanation
Answer: (b) Ca(OH)2
Explanation:
1. Slaked lime reacts with chlorine: Ca(OH)2 + Cl2 → CaOCl2 + H2O.
2. Answer: (b)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) (I) only
(b) (III) only
(c) (II) and (III)
(d) (I), (II) and (III)
Show Answer & Explanation
Answer: (d) (I), (II) and (III)
Explanation:
1. Boron dissolves in hot concentrated alkali to give a borate and H2.
2. White phosphorus disproportionates to hypophosphite and phosphine, and sulphur disproportionates to thiosulphate and sulphide, so all three are correct (balanced forms are not needed).
3. Answer: (d)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
(a) NiO < MgO < SrO < K2O < Cs2O
(b) NiO < MgO < K2O < SrO < Cs2O
(c) MgO < NiO < SrO < K2O < Cs2O
(d) SrO < NiO < MgO < K2O < Cs2O
Show Answer & Explanation
Answer: (a) NiO < MgO < SrO < K2O < Cs2O
Explanation:
1. Basic character rises with the electropositivity of the metal, which increases down a group and from group 2 to group 1.
2. Hence NiO (weakly basic) < MgO < SrO < K2O < Cs2O.
3. Answer: (a)
Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.
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S Block Elements Objective Questions & Solutions for JEE Chemistry
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FAQs
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