JEE Chemistry S Block Elements MCQs Set 25

Multiple Choice Questions (MCQs) for JEE Chemistry: S Block Elements

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Multiple Choice Questions

Question 1: The correct order of hydration enthalpies of alkali metal ions is:
(a) Li⁺ > Na⁺ > K⁺ > Cs⁺ > Rb⁺
(b) Na⁺ > Li⁺ > K⁺ > Rb⁺ > Cs⁺
(c) Na⁺ > Li⁺ > K⁺ > Cs⁺ > Rb⁺
(d) Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺
Show Answer & Explanation

Answer: (d) Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺

Explanation:
1. Hydration enthalpy depends on the charge density of the ion.
2. The ion size increases down the group, so the charge density and the hydration enthalpy fall steadily: Li⁺ > Na⁺ > K⁺ > Rb⁺ > Cs⁺.

Teacher's Note:
1. Smaller ions attract water molecules more strongly, so they have higher hydration enthalpy.

Question 2: Magnesium powder burns in air to give:
(a) MgO and Mg₃N₂
(b) Mg(NO₃)₂ and Mg₃N₂
(c) MgO only
(d) MgO and Mg(NO₃)₂
Show Answer & Explanation

Answer: (a) MgO and Mg₃N₂

Explanation:
1. Magnesium burns in oxygen to give MgO.
2. It also reacts with the nitrogen of air at high temperature to give magnesium nitride: 3Mg + N₂ → Mg₃N₂.

Teacher's Note:
1. Magnesium burning in air gives both the oxide and the nitride.

Question 3: The structures of beryllium chloride in the solid state and vapour phase, respectively, are:
(a) dimeric and dimeric
(b) chain and chain
(c) dimeric and chain
(d) chain and dimeric
Show Answer & Explanation

Answer: (d) chain and dimeric

Explanation:
1. In the solid state BeCl₂ has a polymeric chain structure with chlorine bridges.
2. In the vapour phase (below about 1200 K) it exists as a chlorine-bridged dimer, which dissociates to the linear monomer at higher temperature.

Teacher's Note:
1. BeCl₂ is electron-deficient and completes its octet through chlorine bridging.

Question 4: The correct sequence of thermal stability of the following carbonates is:
(a) BaCO₃ < CaCO₃ < SrCO₃ < MgCO₃
(b) MgCO₃ < CaCO₃ < SrCO₃ < BaCO₃
(c) MgCO₃ < SrCO₃ < CaCO₃ < BaCO₃
(d) BaCO₃ < SrCO₃ < CaCO₃ < MgCO₃
Show Answer & Explanation

Answer: (b) MgCO₃ < CaCO₃ < SrCO₃ < BaCO₃

Explanation:
1. The large carbonate ion is stabilised by large cations and polarised by small ones.
2. Down the group the cation size increases and the polarising power falls, so thermal stability increases: MgCO₃ < CaCO₃ < SrCO₃ < BaCO₃.

Teacher's Note:
1. Thermal stability of alkaline earth carbonates increases down the group.

Question 5: The incorrect statement is:
(a) lithium is the strongest reducing agent among the alkali metals
(b) lithium is least reactive with water among the alkali metals
(c) LiNO₃ decomposes on heating to give LiNO₂ and O₂
(d) LiCl crystallises from aqueous solution as LiCl·2H₂O
Show Answer & Explanation

Answer: (c) LiNO₃ decomposes on heating to give LiNO₂ and O₂

Explanation:
1. Li has the most negative E° (due to its very high hydration enthalpy), so it is the strongest reducing agent, yet it reacts the least vigorously with water.
2. LiCl is highly hydrated and crystallises as LiCl·2H₂O.
3. LiNO₃ decomposes to Li₂O, NO₂ and O₂ (4LiNO₃ → 2Li₂O + 4NO₂ + O₂), not to the nitrite, so statement (c) is incorrect.

Teacher's Note:
1. Lithium nitrate behaves like magnesium nitrate on heating, giving the oxide, not the nitrite.

Question 6: The metal that forms a nitride by reacting directly with N₂ of air is:
(a) Rb
(b) K
(c) Cs
(d) Li
Show Answer & Explanation

Answer: (d) Li

Explanation:
1. Among the alkali metals only lithium combines directly with nitrogen: 6Li + N₂ → 2Li₃N.
2. The small Li⁺ ion stabilises the large nitride ion through strong lattice energy.

Teacher's Note:
1. Lithium is the only alkali metal that forms a nitride directly.

Question 7: The metal used for making the X-ray tube window is:
(a) Na
(b) Be
(c) Mg
(d) Ca
Show Answer & Explanation

Answer: (b) Be

Explanation:
1. Be has the highest ionisation enthalpy of these metals because of its very small size and 2s² configuration.
2. It has a very low atomic number and a low absorption of X-rays, so Be is used for the window.

Teacher's Note:
1. Beryllium is transparent to X-rays because of its low atomic number.

Question 8: Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of:
(a) sodium ammonia complex
(b) sodium ion-ammonia complex
(c) sodamide
(d) ammoniated electrons
Show Answer & Explanation

Answer: (d) ammoniated electrons

Explanation:
1. Na + (x + y)NH₃ → [Na(NH₃)ₓ]⁺ + [e(NH₃)ᵧ]⁻.
2. The ammoniated electrons absorb visible light and give the deep blue colour; they also make the solution paramagnetic, strongly reducing and conducting.

Teacher's Note:
1. The blue colour of alkali metals in liquid ammonia is due to solvated electrons.

Question 9: The amphoteric hydroxide is:
(a) Be(OH)₂
(b) Ca(OH)₂
(c) Sr(OH)₂
(d) Mg(OH)₂
Show Answer & Explanation

Answer: (a) Be(OH)₂

Explanation:
1. The basicity of group 2 hydroxides increases down the group.
2. Be(OH)₂ is amphoteric: Be(OH)₂ + 2HCl → BeCl₂ + 2H₂O and Be(OH)₂ + 2NaOH → Na₂[Be(OH)₄].

Teacher's Note:
1. Beryllium and its compounds are amphoteric because of the small size and high charge density of Be²⁺.

Question 10: A metal on combustion in excess air forms X. X upon hydrolysis with water yields H₂O₂ and O₂ along with another product. The metal is:
(a) Li
(b) Mg
(c) Rb
(d) Na
Show Answer & Explanation

Answer: (c) Rb

Explanation:
1. Rubidium forms the superoxide RbO₂ in excess air, because large cations stabilise the large O₂⁻ ion.
2. The superoxide hydrolyses as 2RbO₂ + 2H₂O → 2RbOH + H₂O₂ + O₂.

Teacher's Note:
1. K, Rb and Cs form superoxides; Na forms the peroxide and Li the oxide.

Question 11: The correct statement(s) among I to III with respect to potassium ions that are abundant within the cell fluids is/are: I. They activate many enzymes. II. They participate in the oxidation of glucose to produce ATP. III. Along with sodium ions, they are responsible for the transmission of nerve signals.
(a) I and III only
(b) I, II and III
(c) I and II only
(d) III only
Show Answer & Explanation

Answer: (b) I, II and III

Explanation:
1. K⁺ is the main intracellular cation and activates many enzymes.
2. It takes part in glycolysis and the Krebs cycle that produce ATP from glucose.
3. Together with Na⁺ (the sodium-potassium pump) it carries nerve signals, so all three statements are correct.

Teacher's Note:
1. Na⁺ and K⁺ are essential for nerve impulses and enzyme activity.

Question 12: The main oxides formed on combustion of Li, Na and K in excess of air, respectively, are:
(a) LiO₂, Na₂O₂ and K₂O
(b) Li₂O₂, Na₂O₂ and KO₂
(c) Li₂O, Na₂O₂ and KO₂
(d) Li₂O, Na₂O and KO₂
Show Answer & Explanation

Answer: (c) Li₂O, Na₂O₂ and KO₂

Explanation:
1. Li forms the normal oxide Li₂O, because the small Li⁺ stabilises the small O²⁻ ion.
2. Na forms the peroxide Na₂O₂, and K forms the superoxide KO₂, because larger cations stabilise larger anions.

Teacher's Note:
1. The oxygen-rich anion that forms grows with the cation size: oxide, peroxide, superoxide.

Question 13: Which one of the following alkaline earth metal sulphates has its hydration enthalpy greater than its lattice enthalpy?
(a) CaSO₄
(b) BeSO₄
(c) BaSO₄
(d) SrSO₄
Show Answer & Explanation

Answer: (b) BeSO₄

Explanation:
1. The small Be²⁺ ion has a very high hydration enthalpy, while the large sulphate ion keeps the lattice enthalpy relatively low.
2. For the other sulphates the larger cations give a high lattice enthalpy compared with the hydration enthalpy, so BeSO₄ is the one that dissolves readily.

Teacher's Note:
1. Solubility of the sulphates decreases down group 2 because hydration enthalpy falls faster than lattice enthalpy.

Question 14: The products obtained on heating LiNO₃ will be:
(a) LiNO₂ + O₂
(b) Li₂O + NO₂ + O₂
(c) Li₃N + O₂
(d) Li₂O + NO + O₂
Show Answer & Explanation

Answer: (b) Li₂O + NO₂ + O₂

Explanation:
1. Lithium nitrate behaves differently from the other alkali metal nitrates.
2. It decomposes like the nitrates of group 2: 4LiNO₃ → 2Li₂O + 4NO₂ + O₂.

Teacher's Note:
1. Other alkali metal nitrates give the nitrite and O₂, but LiNO₃ gives the oxide, NO₂ and O₂.

Question 15: What is the best description of the change that occurs when Na₂O(s) is dissolved in water?
(a) Oxidation number of sodium decreases
(b) Oxide ion accepts a shared pair of electrons
(c) Oxide ion donates a pair of electrons
(d) Oxidation number of oxygen increases
Show Answer & Explanation

Answer: (c) Oxide ion donates a pair of electrons

Explanation:
1. Na₂O + H₂O → 2NaOH is not a redox reaction, so the oxidation numbers of Na and O do not change.
2. The oxide ion O²⁻ donates a pair of electrons to H⁺ of water and is converted into OH⁻ (it acts as a base).

Teacher's Note:
1. Na₂O is a basic oxide; the oxide ion takes a proton from water.

Question 16: One mole of magnesium nitride on reaction with an excess of water gives:
(a) one mole of ammonia
(b) one mole of nitric acid
(c) two moles of ammonia
(d) two moles of nitric acid
Show Answer & Explanation

Answer: (c) two moles of ammonia

Explanation:
1. Mg₃N₂ + 6H₂O → 3Mg(OH)₂ + 2NH₃.
2. So 1 mol of Mg₃N₂ gives 2 mol of NH₃.

Teacher's Note:
1. Metal nitrides hydrolyse to the metal hydroxide and ammonia.

Question 17: Beryllium and aluminium exhibit many properties which are similar. But the two elements differ in:
(a) exhibiting maximum covalency in compounds
(b) forming polymeric hydrides
(c) forming covalent halides
(d) exhibiting amphoteric nature in their oxides
Show Answer & Explanation

Answer: (a) exhibiting maximum covalency in compounds

Explanation:
1. Be and Al both form polymeric hydrides, covalent halides and amphoteric oxides.
2. Be (Z = 4) has no d orbitals and has a maximum covalency of 4, while Al can reach a covalency of 6, as in [AlF₆]³⁻.

Teacher's Note:
1. The second period element cannot expand its octet beyond four.

Question 18: The substance not likely to contain CaCO₃ is:
(a) a marble statue
(b) calcined gypsum
(c) sea shells
(d) dolomite
Show Answer & Explanation

Answer: (b) calcined gypsum

Explanation:
1. Marble, sea shells and dolomite (CaCO₃·MgCO₃) all contain calcium carbonate.
2. Calcined gypsum is plaster of Paris, CaSO₄·½H₂O, a sulphate.

Teacher's Note:
1. Gypsum and its derivatives are sulphates, not carbonates.

Question 19: The substance used in Holmes signals of the ship is a mixture of:
(a) CaC₂ + Ca₃P₂
(b) Ca₃(PO₄)₂ + Pb₃O₄
(c) H₃PO₄ + CaCl₂
(d) NH₃ + HOCl
Show Answer & Explanation

Answer: (a) CaC₂ + Ca₃P₂

Explanation:
1. Holmes signals use calcium carbide and calcium phosphide put in a perforated pipe and floated on water.
2. Water produces acetylene and phosphine; phosphine ignites spontaneously and lights the acetylene.

Teacher's Note:
1. CaC₂ gives C₂H₂ and Ca₃P₂ gives spontaneously inflammable PH₃ with water.

Question 20: A metal M forms a water soluble MSO₄ and an inert MO. MO in aqueous solution forms insoluble M(OH)₂, which is soluble in NaOH. The metal M is:
(a) Be
(b) Mg
(c) Ca
(d) Sr
Show Answer & Explanation

Answer: (a) Be

Explanation:
1. Be forms soluble BeSO₄, and BeO is very inert.
2. Be(OH)₂ is amphoteric and dissolves in NaOH to give [Be(OH)₄]²⁻, whereas Mg(OH)₂, Ca(OH)₂ and Sr(OH)₂ do not dissolve in alkali (Ca(OH)₂ and Sr(OH)₂ are also fairly soluble in water).

Teacher's Note:
1. Only beryllium hydroxide is amphoteric among the group 2 hydroxides.

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