GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1

Get the most accurate GSEB Solutions for Class 8 Mathematics Chapter 08 Comparing Quantities here. Updated for the 2026-27 academic session, these solutions are based on the latest GSEB textbooks for Class 8 Mathematics. Our expert-created answers for Class 8 Mathematics are available for free download in PDF format.

Detailed Chapter 08 Comparing Quantities GSEB Solutions for Class 8 Mathematics

For Class 8 students, solving GSEB textbook questions is the most effective way to build a strong conceptual foundation. Our Class 8 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 08 Comparing Quantities solutions will improve your exam performance.

Class 8 Mathematics Chapter 08 Comparing Quantities GSEB Solutions PDF

 

Question 1. Find the ratio of the following:
(a) Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.
(b) 5 m to 10 km
(c) 50 paise to Rs 5
Answer:
When working with ratios, the amounts must be in the same units. If they are not, we first change them to be identical.

(a) Speed of cycle = \( 15 \text{ km per hour} \)
Speed of scooter = \( 30 \text{ km per hour} \)
Ratio = \( \frac{\text{Speed of cycle}}{\text{Speed of scooter}} = \frac{15 \text{ km/hr}}{30 \text{ km/hr}} = \frac{15}{30} = \frac{1}{2} \) (or \( 1 : 2 \))

(b) Ratio = \( \frac{5 \text{m}}{10 \times 1000 \text{m}} \) (We change 10 km into meters)
\( = \frac{5}{10 \times 1000} = \frac{1}{2000} \) (or \( 1 : 2000 \))

(c) Ratio = \( \frac{50 \text{ paise}}{\text{Rs } 5} = \frac{50 \text{ paise}}{500 \text{ paise}} \) (We change Rs 5 to paise)
\( = \frac{50}{500} = \frac{1}{10} \) (or \( 1 : 10 \))
In simple words: To compare amounts using a ratio, always make sure their measurement units are the same. If they are different, change one to match the other before dividing.

Exam Tip: Remember to always express ratios in their simplest form. Also, verify that both quantities are in the same units before calculating the ratio.

 

Question 2. Convert the following ratios to percentages?
(a) 3:4
(b) 2:3
Answer:
(a) \( 3:4 = \frac{3}{4} \)
\( \implies \frac{3}{4} = \frac{3}{4} \times 100\% = (3 \times 25)\% = 75\% \)

(b) \( 2:3 = \frac{2}{3} \)
\( \implies \frac{2}{3} = \frac{2}{3} \times 100\% = \frac{200}{3}\% = 66\frac{2}{3}\% \)
In simple words: To change a ratio into a percentage, write it as a fraction and then multiply that fraction by 100%. Don't forget to add the percent symbol at the end.

Exam Tip: Ratios are often given in the format 'a:b'. Convert them into the fraction 'a/b' before multiplying by 100% to find the percentage equivalent.

 

Question 3. 72% of 25 students are good in Mathematics. How many are not good in Mathematics?
Answer:
72% of 25 students perform well in Mathematics.
\( \implies \) So, \( (100 - 72)\% \) of 25 students do not perform well in Mathematics.
\( \implies \) This means \( 28\% \) of 25 students are not good in Mathematics.
\( \implies \frac{28}{100} \times 25 = 7 \) students are not good in Mathematics.
In simple words: If most students are good at math, you can find the percentage of students who are not good by subtracting from 100%. Then, calculate that percentage of the total number of students.

Exam Tip: When dealing with percentages of a group, remember that "the remaining percentage" is found by subtracting the given percentage from 100%.

 

Question 4. A football team won 10 matches out of the total number of matches they played. If their win percentage was 40, then how many matches did they play in all?
Answer:
The team won 10 matches.
The team achieved victory in \( 40\% \) of the total number of matches played.
\( \implies 40\% \) of [Total number of matches] = 10
\( \implies \frac{40}{100} \times \) [Total number of matches] = 10
\( \implies \) Total number of matches = \( \frac{10 \times 100}{40} = 25 \)
Therefore, the team played a total of 25 matches.
In simple words: If you know how many games a team won and what percentage that represents of all their games, you can calculate the total number of games they played. Just set up an equation where the percentage of the total equals the number of games won.

Exam Tip: When a percentage of a total is known, use the formula: Part = (Percentage/100) * Whole. Rearrange it to find the 'Whole' if the 'Part' and 'Percentage' are given.

 

Question 5. If Chameli had Rs 600 left after spending 75% of her money how much did she have in the beginning?
Answer:
Chameli used \( 75\% \) of her money for spending.
\( \implies \) So, she has \( (100 - 75)\% \) or \( 25\% \) of her money remaining.
She now possesses Rs 600.
\( \implies 25\% \) of her total money equals Rs 600.
\( \implies \) Total money = \( \frac{600 \times 100}{25} \)
\( = 600 \times 4 = \text{Rs } 2400 \)
Hence, she originally had Rs 2400.
In simple words: If a part of her money is left, first find what percentage that leftover part represents. Then, use that percentage and the amount of money to figure out how much money she had at the start.

Exam Tip: If a person spends a certain percentage, the remaining percentage is 100% minus the spent percentage. Use this remaining percentage to find the original amount.

 

Question 6. If 60% people in a city like cricket, 30% like football and the remaining like other games, then what per cent of the people like other games? If the total number of people are 50 lakh, find the exact number who like each type of game?
Answer:
Number of people who prefer cricket = \( 60\% \)
Number of people who prefer football = \( 30\% \)
\( \implies \) People who prefer other games = \( [100 - (60 + 30)]\% \)
\( = [100 - 90]\% = 10\% \)
Currently, the total population is 50,00,000.
\( \implies 60\% \) of 50,00,000 = \( \frac{60}{100} \times 5000000 \)
\( = 6 \times 5000000 = 30,00,000 \)
\( 30\% \) of 50,00,000 = \( \frac{30}{100} \times 5000000 \)
\( = 3 \times 5000000 = 15,00,000 \)
\( 10\% \) of 50,00,000 = \( \frac{10}{100} \times 5000000 \)
\( = 1 \times 5000000 = 5,00,000 \)
Thus, the numbers are:
Cricket = 30,00,000
Football = 15,00,000
Other games = 5,00,000
In simple words: First, add up the percentages for the known preferences and subtract from 100% to find the percentage for "other games." Then, calculate the actual number of people for each preference by finding that percentage of the city's total population.

Exam Tip: Always check that the sum of all percentages for different categories equals 100%. When calculating actual numbers from percentages, multiply the percentage (as a decimal or fraction) by the total quantity.

Free study material for Mathematics

GSEB Solutions Class 8 Mathematics Chapter 08 Comparing Quantities

Students can now access the GSEB Solutions for Chapter 08 Comparing Quantities prepared by teachers on our website. These solutions cover all questions in exercise in your Class 8 Mathematics textbook. Each answer is updated based on the current academic session as per the latest GSEB syllabus.

Detailed Explanations for Chapter 08 Comparing Quantities

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 8 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 8 students who want to understand both theoretical and practical questions. By studying these GSEB Questions and Answers your basic concepts will improve a lot.

Benefits of using Mathematics Class 8 Solved Papers

Using our Mathematics solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 8 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 08 Comparing Quantities to get a complete preparation experience.

FAQs

Where can I find the latest GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 for the 2026-27 session?

The complete and updated GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 is available for free on StudiesToday.com. These solutions for Class 8 Mathematics are as per latest GSEB curriculum.

Are the Mathematics GSEB solutions for Class 8 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

How do these Class 8 GSEB solutions help in scoring 90% plus marks?

Toppers recommend using GSEB language because GSEB marking schemes are strictly based on textbook definitions. Our GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 will help students to get full marks in the theory paper.

Do you offer GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 8 Mathematics. You can access GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 in both English and Hindi medium.

Is it possible to download the Mathematics GSEB solutions for Class 8 as a PDF?

Yes, you can download the entire GSEB Class 8 Maths Solutions Chapter 8 Comparing Quantities Exercise 8.1 in printable PDF format for offline study on any device.