GSEB Class 6 Maths Solutions Chapter 9 Data Handling Exercise 9.4

Get the most accurate GSEB Solutions for Class 6 Mathematics Chapter 09 Data Handling here. Updated for the 2026-27 academic session, these solutions are based on the latest GSEB textbooks for Class 6 Mathematics. Our expert-created answers for Class 6 Mathematics are available for free download in PDF format.

Detailed Chapter 09 Data Handling GSEB Solutions for Class 6 Mathematics

For Class 6 students, solving GSEB textbook questions is the most effective way to build a strong conceptual foundation. Our Class 6 Mathematics solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 09 Data Handling solutions will improve your exam performance.

Class 6 Mathematics Chapter 09 Data Handling GSEB Solutions PDF

 

Question 1. A survey of 120 school students was done to find which activity they prefer to do in their free time.

Preferred activityNumber of students
Playing45
Reading story books30
Watching TV20
Listening to music10
Painting15
Draw a bar graph to illustrate the above data taking the scale of 1 unit length = 5 students. Which activity is preferred by most of the students other than playing?

Answer:
Steps for drawing the bar graph:
(i) Draw two perpendicular lines, \( OX \) (horizontal) and \( OY \) (vertical).
(ii) Draw vertical bars (rectangles) of the same width, making sure to keep equal spacing between them.
(iii) Given the scale: \( 1 \) unit length \( = 5 \) students.
Therefore, the heights of the bars will be calculated as follows:
For playing: \( 45 \div 5 = 9 \) units
For reading story books: \( 30 \div 5 = 6 \) units
For watching TV: \( 20 \div 5 = 4 \) units
For listening to music: \( 10 \div 5 = 2 \) units
For painting: \( 15 \div 5 = 3 \) units

Number of students Preferred activity 0 5 10 15 20 25 30 35 40 45 Scale: 1 unit length = 5 students Playing Reading story books Watching TV Listening to music Painting

Answer: From the bar graph, playing is the most preferred activity with \( 45 \) students. Among other activities, 'Reading story books' is preferred by \( 30 \) students, which is the highest number after playing.
In simple words: First, we draw lines and mark out the scale, with each small block meaning 5 students. Then, we make bars for each activity as tall as the number of students who like it. Looking at the finished graph, after "playing", "reading story books" is the most popular activity.

Exam Tip: When drawing bar graphs, always label both axes clearly, choose an appropriate scale, and ensure the bars have uniform width and equal spacing for better visual representation.

 

Question 2. The number of Mathematics books sold by a shopkeeper on six consecutive days is shown below:

DaysNumber of books sold
Sunday65
Monday40
Tuesday30
Wednesday50
Thursday20
Friday70
Draw a bar graph to represent the above information choosing the scale of your choice.

Answer:
Steps for drawing the bar graph:
(i) Draw two perpendicular lines, \( OX \) (horizontal) and \( OY \) (vertical).
(ii) Draw bars (rectangles) of equal width on \( OX \), making sure they have the same spacing between them.
(iii) Taking an appropriate scale (here, \( 1 \) unit length \( = 10 \) books), we determine the heights of various bars as follows:
For Sunday: \( 65 \div 10 = 6.5 \) units
For Monday: \( 40 \div 10 = 4 \) units
For Tuesday: \( 30 \div 10 = 3 \) units
For Wednesday: \( 50 \div 10 = 5 \) units
For Thursday: \( 20 \div 10 = 2 \) units
For Friday: \( 70 \div 10 = 7 \) units

Number of books sold Days 0 10 20 30 40 50 60 70 80 90 Scale: 1 unit length = 10 books Sunday Monday Tuesday Wednesday Thursday Friday

Answer: The bar graph shows the number of Mathematics books sold over six days. The highest sales happened on Friday, with \( 70 \) books, and the lowest sales were on Thursday, with \( 20 \) books. The graph helps us easily compare daily book sales.
In simple words: We make a graph with bars to show how many math books were sold each day. Each bar's height shows the number of books, using a scale where 1 unit means 10 books.

Exam Tip: When choosing a scale for a bar graph, select one that allows the largest value to fit comfortably on the axis while still showing differences between bars clearly.

 

Question 3. The following table shows the number of bicycles manufactured in a factory during the years 1998-2002. Illustrate this data using a bar graph. Choose a scale of your choice.

YearsNumber of bicycles manufactured
1998800
1999600
2000900
20011100
20021200
(a) In which year was the maximum number of bicycles manufactured?
(b) In which year was the minimum number of bicycles manufactured?

Answer:
Steps for drawing the bar graph:
(i) Draw two perpendicular lines, \( OX \) (horizontal) and \( OY \) (vertical).
(ii) Draw bars of equal width on \( OX \), ensuring they have the same spacing between them.
(iii) For determining the heights of various bars, we select an appropriate scale: \( 1 \) unit length \( = 200 \) bicycles.
Therefore, the heights of the bars will be:
For \( 1998 \): \( 800 \div 200 = 4 \) units
For \( 1999 \): \( 600 \div 200 = 3 \) units
For \( 2000 \): \( 900 \div 200 = 4.5 \) units
For \( 2001 \): \( 1100 \div 200 = 5.5 \) units
For \( 2002 \): \( 1200 \div 200 = 6 \) units

Number of bicycles Years 0 200 400 600 800 1000 1200 1400 1600 Scale: 1 unit length = 200 bicycles 1998 1999 2000 2001 2002

Answer: From the bar graph, we can observe the following:
(a) The maximum number of bicycles were produced in \( 2002 \), totaling \( 1200 \) bicycles.
(b) The minimum number of bicycles were produced in \( 1999 \), totaling \( 600 \) bicycles.
In simple words: The graph plainly shows that the factory made the most bikes in the year 2002, and they made the fewest bikes in 1999.

Exam Tip: When asked to identify maximum or minimum values from a bar graph, simply look for the tallest or shortest bar, respectively.

 

Question 4. The number of persons in various age groups in a town is given in the following table.

Age groupNumber of persons
1-142 lakhs
15-291 lakh 60 thousands
30-441 lakh 20 thousands
45-591 lakh 20 thousands
60-7480 thousands
75 and above40 thousands
Draw a bar graph to represent the above information and answer the following questions. (take 1 unit length = 20 thousand)
(a) Which two age groups have the same population?
(b) All persons in the age group of 60 and above are called senior citizens. How many senior citizens are there in the town?

Answer:
Steps for drawing the bar graph:
(i) Draw two perpendicular lines, \( OX \) (horizontal) and \( OY \) (vertical).
(ii) Draw bars of equal width on \( OX \), maintaining the same spacing between them.
(iii) Since the scale is given: \( 1 \) unit length \( = 20 \) thousand persons.
Therefore, the heights of various bars are given as:
For \( 1-14 \): \( 2,00,000 \div 20,000 = 10 \) units
For \( 15-29 \): \( 1,60,000 \div 20,000 = 8 \) units
For \( 30-44 \): \( 1,20,000 \div 20,000 = 6 \) units
For \( 45-59 \): \( 1,20,000 \div 20,000 = 6 \) units
For \( 60-74 \): \( 80,000 \div 20,000 = 4 \) units
For \( 75 \) and above: \( 40,000 \div 20,000 = 2 \) units

Number of persons Age group 0 20,000 40,000 60,000 80,000 1,00,000 1,20,000 1,40,000 1,60,000 1,80,000 2,00,000 Scale: 1 unit length = 20 thousand person 1-14 15-29 30-44 45-59 60-74 75 and above

Answer: From the bar graph, we can find the following information:
(a) The age groups \( 30-44 \) and \( 45-59 \) both have the same population, with \( 1 \) lakh \( 20 \) thousands each.
(b) The number of senior citizens (persons aged \( 60 \) and above) are found by adding the populations of the \( 60-74 \) and \( 75 \) and above age groups:
\( 80,000 + 40,000 = 1,20,000 \)
So, there are \( 1,20,000 \) senior citizens in the town.
In simple words: The bar graph visually presents the population of various age groups. We can clearly see that two groups, 30-44 and 45-59, have the same number of people. To find the total senior citizens, we add the numbers for those aged 60 and older.

Exam Tip: Always pay attention to the specific questions asked after the graph. Some questions may require calculations using the data, while others can be answered by direct observation from the graph.

Free study material for Mathematics

GSEB Solutions Class 6 Mathematics Chapter 09 Data Handling

Students can now access the GSEB Solutions for Chapter 09 Data Handling prepared by teachers on our website. These solutions cover all questions in exercise in your Class 6 Mathematics textbook. Each answer is updated based on the current academic session as per the latest GSEB syllabus.

Detailed Explanations for Chapter 09 Data Handling

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 6 Mathematics chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 6 students who want to understand both theoretical and practical questions. By studying these GSEB Questions and Answers your basic concepts will improve a lot.

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FAQs

Where can I find the latest GSEB Class 6 Maths Solutions Chapter 9 Data Handling Exercise 9.4 for the 2026-27 session?

The complete and updated GSEB Class 6 Maths Solutions Chapter 9 Data Handling Exercise 9.4 is available for free on StudiesToday.com. These solutions for Class 6 Mathematics are as per latest GSEB curriculum.

Are the Mathematics GSEB solutions for Class 6 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the GSEB Class 6 Maths Solutions Chapter 9 Data Handling Exercise 9.4 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Mathematics concepts are applied in case-study and assertion-reasoning questions.

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