CBSE Class 7 Science Advanced Physics Kinematics Very Short Answer Questions Set 02

Advanced Study Material for Class 7 Physics: Kinematics

Explore structured advanced study materials through the CBSE Class 7 Science Advanced Physics Kinematics Very Short Answer Questions Set 02. Tailored for Class 7 learners, utilizing these Physics resources ensures thorough preparation and strengthens foundational knowledge before final CBSE evaluations.

Practice Class 7 Physics Resources: Kinematics

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Very Short Answer Questions

Question 1. State whether true or false: One hour is equal to 360 second.
Answer:
False. One hour = 60 × 60 = 3600 seconds.
In simple words: An hour has 3600 seconds, not 360.

Teacher's Note:
1. Do not forget the second 60 when changing hours to seconds.
2. Minutes first (60), then seconds (60 again).

 

Question 2. State whether true or false: The motion of a simple pendulum is an example for oscillatory motion.
Answer:
True. The bob moves to and fro about its mean position.
In simple words: A swinging pendulum bob moves back and forth, so it is oscillatory.

Teacher's Note:
1. Any to-and-fro motion is oscillatory.
2. It is also periodic.

 

Question 3. State whether true or false: A nanosecond is one billionth of a second.
Answer:
True. 1 nanosecond = 10⁻⁹ s, which is one billionth of a second.
In simple words: Nano means one-billionth.

Teacher's Note:
1. Nano = 10⁻⁹.
2. Very small times are used in computers and lasers.

 

Question 4. State whether true or false: When an object is moving with a uniform speed, its average speed is equal to its velocity.
Answer:
False. When the speed is uniform, the average speed equals the (uniform) speed, not the velocity. Speed has no direction, but velocity has direction, so they are different quantities (their magnitudes are equal only for motion in a straight line).
In simple words: Speed and velocity are different things, since velocity needs a direction.

Teacher's Note:
1. Compare quantities of the same kind: average speed with speed.
2. Velocity must have both a magnitude and a direction.

 

Question 5. State whether true or false: We can use a simple pendulum to measure the time.
Answer:
True. Its motion is periodic, so the time taken for equal numbers of oscillations is the same. Old wall clocks used pendulums.
In simple words: A pendulum swings at a steady rhythm, so it can keep time.

Teacher's Note:
1. Periodic motion is the basis of all clocks.
2. Quartz clocks are now more accurate than pendulum clocks.

 

Question 6. State whether true or false: By using a distance-time graph we can find out the average speed of an object.
Answer:
True. From the graph, average speed = total distance ÷ total time, both of which can be read from the graph.
In simple words: The graph gives the distance and the time, so we can divide to get the speed.

Teacher's Note:
1. The slope of a distance-time graph gives the speed.
2. The graph also gives the distance at any instant.

 

Question 7. State whether true or false: Speedometer is used to measure the distance travelled by a vehicle.
Answer:
False. A speedometer measures the speed of a vehicle. The distance travelled is measured by an odometer.
In simple words: The speedometer shows speed, not distance.

Teacher's Note:
1. Speedo-meter: speed. Odo-meter: distance.
2. Both are fitted on the dashboard.

 

Question 8. State whether true or false: The distance-time graph of the motion of an object moving with a constant speed is a straight line.
Answer:
True. For constant speed the distance covered increases by equal amounts in equal times, so the graph is a straight line.
In simple words: Steady speed gives a straight sloping line on the distance-time graph.

Teacher's Note:
1. The steeper the line, the greater the speed.
2. A curved line means that the speed is changing.

 

Question 9. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Periodic motiona. Maximum displacement of vibrating particle from its mean position
B. Vibratory motionb. The piston of a motor car engine at uniform speed
C. Body at restc. Non-uniform motion
D. Amplituded. 18/5 km h⁻¹
E. Variable speede. Oscillating objects undergo change in shape or size
F. 1 m s⁻¹f. \( \frac{\text{Total displacement}}{\text{Total time}} \)
G. Average velocityg. Zero velocity

Answer:
A – b: the piston of a car engine repeats its motion after equal intervals of time.
B – e (the answer key also pairs B with b): a vibrating object changes slightly in shape or size.
C – g: a body at rest has zero velocity.
D – a: amplitude is the maximum displacement from the mean position.
E – c: variable speed is non-uniform motion.
F – d: 1 m s⁻¹ = 18/5 km h⁻¹ = 3.6 km h⁻¹.
G – f: average velocity = total displacement ÷ total time.
In simple words: Each term is paired with its meaning or an example.

Teacher's Note:
1. Do the sure matches first and leave the doubtful ones for the end.
2. Note that 1 m s⁻¹ = 18/5 km h⁻¹.

 

Question 10. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Curvilinear motiona. Motion that repeats itself at irregular intervals of time
B. Rectilinear motionb. Wings of a ceiling fan
C. Rotatory motionc. A shell fired from an artillery gun
D. Body moving with uniform velocityd. A stone dropped from a tower
E. Length of a pendulume. Point of suspension to the mid-point of the bob
F. Time period of a simple pendulumf. Square root of the length of the pendulum
G. Non-periodic motiong. Zero acceleration

Answer:
A – c: a shell follows a curved path.
B – d: a stone dropped from a tower falls along a straight line.
C – b: the wings of a ceiling fan rotate about an axis.
D – g: uniform velocity means no change in velocity, so acceleration is zero.
E – e: length is measured from the point of suspension to the middle of the bob.
F – f: T is proportional to the square root of the length.
G – a: non-periodic motion repeats at irregular intervals.
In simple words: Straight path, curved path, spinning and swinging are each linked to their typical example.

Teacher's Note:
1. Rectilinear means a straight path and curvilinear a curved path.
2. T ∝ √ℓ is the link between time period and length.

 

Question 11. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Circular motiona. Vehicle crossing over a fly-over bridge
B. Rectilinear motionb. One to-and-fro motion
C. Curvilinear motionc. Distance-time graph is a straight line
D. \( \frac{v - u}{a} \)d. 100 cm
E. Constant speede. Time (t)
F. Oscillationf. A spinning top
G. The length of a seconds pendulum (take g = 10 m s⁻²)g. Coin moving over a carrom board

Answer:
A – f: a spinning top moves in circles.
B – g: a coin sliding along a straight line on a carrom board.
C – a: a vehicle on a fly-over follows a curved path.
D – e: from v = u + at, t = (v − u)/a.
E – c: constant speed gives a straight-line distance-time graph.
F – b: one oscillation is one complete to-and-fro motion.
G – d: ℓ = gT²/4π² = 10 × 4/(4 × 10) = 1 m = 100 cm.
In simple words: Every term is linked with its meaning, formula or example.

Teacher's Note:
1. For the seconds pendulum use T = 2 s in ℓ = gT²/4π² with π² = 10.
2. D is a rearranged form of v = u + at.

 

Question 12. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Vibratory motiona. Distance-time graph is not a straight line
B. Rotatory motionb. Speed × time
C. Seconds pendulumc. Musical instruments
D. Distance travelledd. The rate of change of motion in a specific direction
E. Variable speede. Potter's wheel
F. Velocityf. 2 s

Answer:
A – c: strings of musical instruments vibrate.
B – e: a potter's wheel rotates.
C – f: a seconds pendulum has a time period of 2 s.
D – b: distance = speed × time.
E – a: with variable speed the distance-time graph is not a straight line.
F – d: velocity is the rate of motion in a particular direction.
In simple words: Each motion or quantity is matched with its example, value or relation.

Teacher's Note:
1. Learn the example of each kind of motion along with its definition.
2. Distance = speed × time is the most used relation in this chapter.

 

Question 13. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Speeda. Uniform motion
B. Timeb. Non-uniform motion
C. Average speedc. km h⁻¹
D. Uniform speed in a straight lined. second
E. Freely falling bodye. Change in time period
F. Change in length of a pendulumf. \( \frac{\text{Total distance}}{\text{Total time}} \)

Answer:
A – c: km h⁻¹ is a unit of speed.
B – d: the second is the unit of time.
C – f and c: average speed = total distance ÷ total time, and its unit may be km h⁻¹.
D – a: uniform speed in a straight line is uniform motion.
E – b: a freely falling body speeds up, so its motion is non-uniform.
F – e: changing the length changes the time period.
In simple words: Speed, time and the kinds of motion are matched with their units, formulae or results.

Teacher's Note:
1. Average speed can be matched with both its formula and its unit.
2. A falling body keeps gaining speed, so it is non-uniform.

 

Question 14. Match the entries given in Column A with the appropriate ones in Column B.
Column AColumn B
A. Non-uniform motiona. To measure the speed of the vehicle
B. Oscillatory motionb. Uniform motion
C. Mean positionc. A cricket ball that rolls over the ground
D. Speedometerd. The needle of a sewing machine that moves up and down
E. Constant speede. Freely suspended pendulum at rest
F. Accelerationf. \( \frac{\text{Total change in velocity}}{\text{Total time taken for change}} \)

Answer:
A – c: a rolling cricket ball slows down, so its motion is non-uniform.
B – d: the needle of a sewing machine moves to and fro.
C – e: the mean position is where a freely hanging pendulum rests.
D – a: a speedometer measures speed.
E – b: constant speed is uniform motion.
F – f: acceleration is change in velocity divided by time.
In simple words: Each term gets its example, device or formula.

Teacher's Note:
1. A ball rolling on the ground slows down, hence non-uniform.
2. Acceleration = change in velocity ÷ time.

 

Question 15. When can the speed and average speed of a vehicle be equal?
Answer:
They are equal when the vehicle moves with uniform (constant) speed.
If the speed does not change, total distance ÷ total time always gives that same constant speed.
In simple words: Steady speed means the average is the same as the speed at every moment.

Teacher's Note:
1. Average speed matters only when the speed keeps changing.
2. Check by taking any two stretches of the journey at the same speed.

 

Question 16. While determining the time period of a simple pendulum, why is the time for 20 or more oscillations found?
Answer:
One oscillation is over very quickly, and the small error in starting and stopping the stop watch would be a large part of a very short time. If the time for 20 or more oscillations is measured and divided by the number of oscillations, the error is divided too, so the time period is found more accurately.
In simple words: A longer time is easier to measure correctly, and dividing gives the time of one swing.

Teacher's Note:
1. The same stop watch error matters less in a long measurement.
2. Take an average of repeated readings for even better accuracy.

 

Question 17. Define amplitude and frequency. Write their SI units.
Answer:
Amplitude: the maximum displacement of the bob of a pendulum from its mean position. SI unit: metre (m).
Frequency: the number of oscillations made in one second. SI unit: hertz (Hz).
In simple words: Amplitude is how far it swings; frequency is how many swings in a second.

Teacher's Note:
1. Frequency n = 1/T.
2. Amplitude is a distance, so its unit is the unit of length.

Free CBSE Study Guides: Class 7 Physics Kinematics

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