CBSE Class 5 Mathematics Multiplication and Division of Large Numbers Worksheet Set 03

Answer: 4,236 × 10 = 42,360

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 563 × 100 = 56,300

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 725 × 1,000 = 7,25,000

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 2,345 × 60 = 1,40,700

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 468 × 700 = 3,27,600

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 1,234 × 23 = 28,382

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 5,347 × 486 = 25,98,642

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 2,468 × 305 = 7,52,740

Teacher's Note:
1. Multiply by each part of the multiplier and add the partial products.
2. Estimate by rounding to confirm the size of the answer.

Answer: 4 × 25 = 100, so 100 × 237 = 23,700.

Teacher's Note:
1. Pick the two numbers that make 100 when multiplied.
2. Multiplying by 100 only adds two zeros.

Answer: 5 × 20 = 100, so 100 × 1,986 = 1,98,600.

Teacher's Note:
1. Group the numbers whose product is easy first.
2. The grouping property lets us do this.

Answer: 2,346, by the order property of multiplication.

Teacher's Note:
1. The product does not change when the order of the numbers changes.
2. So the missing number is the other factor.

Answer: 35 × 100 = 3,500 and 35 × 37 = 1,295. Total = 4,795.

Teacher's Note:
1. Split 137 into 100 + 37 and multiply each part.
2. Add the two partial products at the end.

Answer: 903, by the grouping property.

Teacher's Note:
1. Only the grouping changes, the numbers stay the same.
2. So 903 must appear on the right.

Answer: Quotient = 555, remainder = 0. Check: 15 × 555 + 0 = 8,325.

Teacher's Note:
1. Divide one digit at a time and bring down the next digit.
2. The remainder must be smaller than the divisor.

Answer: Quotient = 1,521, remainder = 24. Check: 36 × 1,521 + 24 = 54,780.

Teacher's Note:
1. Divide one digit at a time and bring down the next digit.
2. The remainder must be smaller than the divisor.

Answer: Quotient = 346, remainder = 6. Check: 23 × 346 + 6 = 7,964.

Teacher's Note:
1. Divide one digit at a time and bring down the next digit.
2. The remainder must be smaller than the divisor.

Answer: Dividend = 187 × 3,078 + 96 = 5,75,586 + 96 = 5,75,682.

Teacher's Note:
1. Use Dividend = Divisor × Quotient + Remainder.
2. Multiply first and then add the remainder.

Answer: 256 × 176 = 45,056 km.

Teacher's Note:
1. Total distance is the distance per day times the number of days.
2. Multiply by 6, 70 and 100 separately and add.

Answer: 1,483 × 108 = 1,60,164 kg.

Teacher's Note:
1. Multiply the number of bags by the weight of one bag.
2. Multiplying by 108 means multiplying by 100 and by 8.

Answer: 23,040 ÷ 144 = 160 packets.

Teacher's Note:
1. Divide the total pens by the pens in each packet.
2. Check by multiplying 144 by the answer.

Answer: 17,766 ÷ 987 = 18.

Teacher's Note:
1. Divide the product by the known number to find the other.
2. Multiply back to check.