Revision Notes for Class 10 Mathematics: Chapter 12 Surface Areas and Volumes
Review targeted revision notes for Class 10 Mathematics with the CBSE Class 10 Mathematics Surface Areas and Volumes Notes Set 11. Built according to official educational guidelines for the 2026-27 academic year, these downloadable summaries for Chapter 12 Surface Areas and Volumes support daily study and last-minute exam readiness.
Review Chapter 12 Surface Areas and Volumes for Class 10 Mathematics
View or download the dedicated Chapter 12 Surface Areas and Volumes revision resource below. Engaging with these structured concept notes daily ensures continuous academic progress and mastery of the 2026-27 curriculum for Mathematics.
Cuboid and Cube
For a cuboid of length l, breadth b, height h: volume \( lbh \), total surface area \( 2(lb+bh+hl) \), lateral surface area \( 2h(l+b) \), diagonal \( \sqrt{l^2+b^2+h^2} \). A cube of edge a has volume \( a^3 \), total surface area \( 6a^2 \) and diagonal \( a\sqrt3 \).
Cylinder
Radius r and height h: curved surface area \( 2\pi rh \), total surface area \( 2\pi r(r+h) \), volume \( \pi r^2h \). A hollow cylinder of outer radius R and inner radius r has volume \( \pi h(R^2-r^2) \).
Cone and Frustum
Slant height \( l = \sqrt{r^2+h^2} \). Curved surface area \( \pi rl \), total surface area \( \pi r(r+l) \), volume \( \frac13\pi r^2h \). A frustum with radii R and r and height h has volume \( \frac13\pi h(R^2+r^2+Rr) \) and curved surface area \( \pi(R+r)l \) with \( l = \sqrt{h^2+(R-r)^2} \). A plane parallel to the base cuts a similar small cone; volumes of similar cones are in the cube of the ratio of their heights.
Sphere and Hemisphere
Sphere: surface area \( 4\pi r^2 \) and volume \( \frac43\pi r^3 \). Hemisphere: curved surface area \( 2\pi r^2 \), total surface area \( 3\pi r^2 \), volume \( \frac23\pi r^3 \).
Conversion of Solids
When one solid is melted and recast into another, the volume stays the same. Number of small solids = volume of the large solid ÷ volume of one small solid. 1 m³ = 1000 litres.
Solved Examples
Example 1. A cuboid is 12 cm × 9 cm × 8 cm. Find its total surface area and diagonal.
Answer:
TSA \( = 2(108+72+96) = 552 \) cm². Diagonal \( = \sqrt{144+81+64} = 17 \) cm.
552 cm² and 17 cm
Example 2. A cylinder has radius 7 cm and height 10 cm. Find its volume (use \( \pi = \frac{22}{7} \)).
Answer:
\( V = \frac{22}{7}\times49\times10 = 1540 \).
1540 cm³
Example 3. A cone has radius 6 cm and height 8 cm. Find its curved surface area and volume (use \( \pi = 3.14 \)).
Answer:
\( l = 10 \) cm. CSA \( = 3.14\times6\times10 = 188.4 \). Volume \( = \frac13\times3.14\times36\times8 = 301.44 \).
188.4 cm² and 301.44 cm³
Example 4. A metal sphere of radius 3 cm is melted and recast into a cylinder of radius 3 cm. Find the height of the cylinder.
Answer:
\( \frac43\pi(27) = \pi(9)h \Rightarrow h = 4 \).
4 cm
Example 5. Find the total surface area of a hemisphere of radius 7 cm (use \( \pi = \frac{22}{7} \)).
Answer:
\( 3\pi r^2 = 3\times\frac{22}{7}\times49 = 462 \).
462 cm²
Example 6. A frustum has radii 10 cm and 4 cm and height 8 cm. Find its slant height and volume (use \( \pi = 3.14 \)).
Answer:
\( l = \sqrt{64+36} = 10 \) cm. Volume \( = \frac13\times3.14\times8\times(100+16+40) = 1306.24 \).
10 cm and 1306.24 cm³
Example 7. How many cubes of edge 2 cm can be cut from a cuboid 10 cm × 8 cm × 6 cm?
Answer:
\( \frac{480}{8} = 60 \).
60 cubes
Example 8. A rectangular tank 6 m × 5 m × 4 m is filled with water. How many litres of water does it hold?
Answer:
Volume \( = 120 \) m³ \( = 120000 \) litres.
120000 litres
Free study material for Mathematics
Revision Notes and Key Concepts for Class 10 Mathematics Chapter 12 Surface Areas and Volumes
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FAQs
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