Multiple Choice Questions (MCQs) for Class 10 Mathematics: Chapter 01 Real Numbers
Access targeted multiple-choice questions for Chapter 01 Real Numbers designed to align with the latest CBSE academic syllabus for Class 10 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Practice Chapter 01 Real Numbers MCQs for Class 10 Mathematics
View or download the dedicated Chapter 01 Real Numbers MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.
Multiple Choice Questions
(a) 42 and 21
(b) 24 and 12
(c) 7 and 3
(d) 84 and 42
Show Answer & Explanation
Answer: (a) 42 and 21
Explanation:
1. The tree shows y = 3 × 7 = 21.
2. Then x = 2 × y = 2 × 21 = 42.
3. So x = 42 and y = 21: (a).
Teacher's Note:
1. Work from the bottom of the tree upwards.
2. Each box is the product of the two boxes below it.
(a) 3
(b) 4
(c) 5
(d) 2
Show Answer & Explanation
Answer: (b) 4
Explanation:
1. 196 = 2 × 2 × 7 × 7 = 2² × 7².
2. Sum of exponents = 2 + 2 = 4.
Teacher's Note:
1. Write 196 as a product of primes first.
2. Add only the exponents, not the primes.
(a) 1
(b) 0
(c) 2
(d) 3
Show Answer & Explanation
Answer: (c) 2
Explanation:
1. A prime number has exactly two factors, 1 and the number itself.
2. So the answer is 2.
Teacher's Note:
1. This is the definition of a prime number.
2. The number 1 has only one factor, so it is not prime.
(a) 3, 140
(b) 12, 420
(c) 3, 420
(d) 420, 3
Show Answer & Explanation
Answer: (c) 3, 420
Explanation:
1. 12 = 2² × 3, 21 = 3 × 7 and 15 = 3 × 5.
2. H.C.F. = lowest power of the common prime = 3.
3. L.C.M. = 2² × 3 × 5 × 7 = 420.
Teacher's Note:
1. H.C.F. uses common primes with the smallest powers.
2. L.C.M. uses every prime with the greatest power.
(a) 7911
(b) 7119
(c) 7791
(d) 7971
Show Answer & Explanation
Answer: (b) 7119
Explanation:
1. Product of the two numbers = H.C.F. × L.C.M.
2. 904 × other number = 113 × 56952.
3. Other number = (113 × 56952) ÷ 904 = 7119.
Teacher's Note:
1. Use H.C.F. × L.C.M. = product of the numbers.
2. Cancel 113 with 904 = 8 × 113 to make the division easy.
(a) 1
(b) −1
(c) 0
(d) none of these
Show Answer & Explanation
Answer: (a) 1
Explanation:
1. For n = 1, 24¹ = 24 and 24 = 8 × 3, which is divisible by 8.
2. n must be a natural number, so the least value is 1.
Teacher's Note:
1. Natural numbers start from 1.
2. Try the smallest value first.
(a) 15
(b) 16
(c) 17
(d) 18
Show Answer & Explanation
Answer: (d) 18
Explanation:
1. 306 = 2 × 3² × 17 and 1314 = 2 × 3² × 73.
2. H.C.F. = 2 × 3² = 18.
Teacher's Note:
1. Factorise both numbers into primes.
2. Multiply the common primes with the smallest powers.
(a) 44
(b) 54
(c) 56
(d) 68
Show Answer & Explanation
Answer: (c) 56
Explanation:
1. For two positive integers, H.C.F. × L.C.M. = a × b.
2. a × b = 2 × 28 = 56.
Teacher's Note:
1. Use the product rule for H.C.F. and L.C.M.
2. The H.C.F. must always divide the L.C.M.
(a) 135
(b) 15
(c) 225
(d) 45
Show Answer & Explanation
Answer: (d) 45
Explanation:
1. Common primes are 3 and 5.
2. Smallest powers: 3² and 5¹.
3. H.C.F. = 3² × 5 = 9 × 5 = 45.
Teacher's Note:
1. Take the smaller exponent of each common prime.
2. Do not multiply the larger powers; that gives the L.C.M.
(a) composite numbers
(b) twin primes
(c) co-primes
(d) none of these
Show Answer & Explanation
Answer: (c) co-primes
Explanation:
1. Two numbers whose only common factor is 1 are called co-primes.
2. So the answer is co-primes.
Teacher's Note:
1. Co-prime numbers need not be prime themselves, for example 8 and 9.
2. Twin primes are primes differing by 2.
(a) an integer
(b) an irrational number
(c) a rational number
(d) none of the above
Show Answer & Explanation
Answer: (b) an irrational number
Explanation:
1. π = 3.14159... is a non-terminating, non-repeating decimal.
2. So π is irrational.
Teacher's Note:
1. The values 22/7 and 3.14 are only approximations of π.
2. A rational number has a terminating or repeating decimal.
(a) 3
(b) 4
(c) 2
(d) 1
Show Answer & Explanation
Answer: (b) 4
Explanation:
1. A composite number has more than two factors.
2. 2 and 3 are prime and 1 is neither prime nor composite.
3. The factors of 4 are 1, 2 and 4, so the smallest composite number is 4.
Teacher's Note:
1. Check the numbers in order, starting from 1.
2. 1 is neither prime nor composite.
(a) 1
(b) 2
(c) 4
(d) none of these
Show Answer & Explanation
Answer: (b) 2
Explanation:
1. Smallest prime = 2 and smallest composite = 4.
2. H.C.F. (2, 4) = 2.
Teacher's Note:
1. Identify the two numbers first.
2. 2 divides 4, so the H.C.F. is the smaller number.
(a) m
(b) m + 1
(c) 2m
(d) 2m + 1
Show Answer & Explanation
Answer: (c) 2m
Explanation:
1. Even integers are …, −2, 0, 2, 4, 6, …
2. Each is 2 times an integer, so every even integer has the form 2m.
Teacher's Note:
1. An even number is divisible by 2.
2. 2m + 1 gives the odd integers.
(a) an integer
(b) a natural number
(c) an odd integer
(d) an even integer
Show Answer & Explanation
Answer: (c) an odd integer
Explanation:
1. Let n = 2k + 1 (odd). Then n² − 1 = 4k² + 4k = 4k(k + 1).
2. k(k + 1) is a product of two consecutive integers, so it is even, and 4k(k + 1) is divisible by 8.
3. For an even n, n² − 1 is odd. Answer: an odd integer.
Teacher's Note:
1. Test n = 3: 3² − 1 = 8, and n = 2: 2² − 1 = 3.
2. Odd n gives n² − 1 = 4k(k + 1).
Assertion–Reason Questions
Assertion (A): \( \frac{123}{6250} \) is a terminating decimal.
Reason (R): The rational number \( \frac{p}{q} \) is a terminating decimal if q = 2ᵐ × 5ⁿ for some whole numbers m and n.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. 6250 = 2 × 5⁵, which has the form 2ᵐ × 5ⁿ with m = 1 and n = 5.
2. So the Reason holds and the fraction 123/6250 terminates, so the Assertion is true.
3. The Reason is the rule that proves the Assertion: option (a).
Teacher's Note:
1. Only the primes 2 and 5 may appear in the denominator.
2. Factorise the denominator before deciding.
Assertion (A): −1, 0, 2 and \( \frac{-4}{3} \) are all examples of rational numbers.
Reason (R): All integers and all fractions of the form \( \frac{p}{q} \) (q ≠ 0) are rational numbers.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. −1 = −1/1, 0 = 0/1 and 2 = 2/1 are in the form p/q, and −4/3 is already in that form, so the Assertion is true.
2. The Reason is true.
3. The Reason is the definition that makes each listed number rational: option (a).
Teacher's Note:
1. A rational number is any number that can be written as p/q with q ≠ 0.
2. Every integer n can be written as n/1.
Free study material for Mathematics
Multiple Choice Questions (MCQs) for Class 10 Mathematics Chapter 01 Real Numbers
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FAQs
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