Mathematics Objective Questions and Answers: Chapter 08 Introduction to Trigonometry
Access targeted multiple-choice questions for Chapter 08 Introduction to Trigonometry designed to align with the latest CBSE academic syllabus for Class 10 Mathematics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Download Chapter 08 Introduction to Trigonometry MCQs with Answers
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Multiple Choice Questions
(a) \(1 - \frac{1}{m}\)
(b) \(m^2 - 1\)
(c) \(\frac{1}{m}\)
(d) \(-m\)
Show Answer & Explanation
Answer: (c) \(\frac{1}{m}\)
Explanation:
1. \((\sec\theta - \tan\theta)(\sec\theta + \tan\theta) = \sec^2\theta - \tan^2\theta = 1\).
2. So \(\sec\theta + \tan\theta = \frac{1}{m}\).
(a) \(\sin\theta \cot\theta = \cos\theta\)
(b) \(\cos\theta \tan\theta = \sin\theta\)
(c) \(\csc^2\theta - \cot^2\theta = 1\)
(d) \(\tan^2\theta - \sec^2\theta = 1\)
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Answer: (d) \(\tan^2\theta - \sec^2\theta = 1\)
Explanation:
1. \(\sec^2\theta - \tan^2\theta = 1\), so \(\tan^2\theta - \sec^2\theta = -1\), not \(1\).
2. The other three are true.
(a) \(\tan^2\theta\)
(b) \(\sec^2\theta\)
(c) 1
(d) -1
Show Answer & Explanation
Answer: (d) -1
Explanation:
1. \(\cos^2\theta - 1 = -\sin^2\theta\), so the expression is \(-1\).
(a) 1
(b) \(\frac{3}{4}\)
(c) \(\frac{1}{2}\)
(d) \(\frac{1}{4}\)
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Answer: (c) \(\frac{1}{2}\)
Explanation:
1. \(\sin\theta = \cos\theta\) gives \(\theta = 45^\circ\).
2. \(\sin^4 45^\circ + \cos^4 45^\circ = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}\).
(a) \(\frac{b}{\sqrt{b^2 - a^2}}\)
(b) \(\frac{b}{a}\)
(c) \(\frac{\sqrt{b^2 - a^2}}{b}\)
(d) \(\frac{a}{\sqrt{b^2 - a^2}}\)
Show Answer & Explanation
Answer: (c) \(\frac{\sqrt{b^2 - a^2}}{b}\)
Explanation:
1. Base \(= \sqrt{b^2 - a^2}\), so \(\cos\theta = \frac{\sqrt{b^2 - a^2}}{b}\).
Teacher's Note:
1. The square roots in options (a) and (d) are reconstructed from the source's layout.
(a) \(\cos b\)
(b) \(\cos 2b\)
(c) \(\sin a\)
(d) \(\sin 2a\)
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Answer: (b) \(\cos 2b\)
Explanation:
1. \(\cos(a + b) = 0\) gives \(a + b = 90^\circ\), so \(a = 90^\circ - b\).
2. \(\sin(a - b) = \sin(90^\circ - 2b) = \cos 2b\).
(a) \(\frac{1}{\sqrt{3}}\)
(b) \(\sqrt{3}\)
(c) 1
(d) 0
Show Answer & Explanation
Answer: (c) 1
Explanation:
1. \(\cos 9a = \sin(90^\circ - 9a) = \sin a\), so \(90^\circ - 9a = a\), giving \(a = 9^\circ\).
2. \(\tan 5a = \tan 45^\circ = 1\).
Teacher's Note:
1. Option (a) and (b) square roots are reconstructed from the extraction.
(a) 0
(b) 1
(c) \(\frac{1}{2}\)
(d) \(\frac{\sqrt{3}}{2}\)
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Answer: (a) 0
Explanation:
1. \(\angle A + \angle B + 90^\circ = 180^\circ\), so \(A + B = 90^\circ\).
2. \(\cos 90^\circ = 0\).
Teacher's Note:
1. Options (c) and (d) are reconstructed from the extraction. Please check against the printed book.
(a) \(0^\circ\)
(b) \(30^\circ\)
(c) \(60^\circ\)
(d) \(90^\circ\)
Show Answer & Explanation
Answer: (d) \(90^\circ\)
Explanation:
1. \(\alpha = 30^\circ\) and \(\beta = 60^\circ\), so \(\alpha + \beta = 90^\circ\).
(a) \(\frac{2}{3}\)
(b) \(\frac{1}{3}\)
(c) \(\frac{1}{2}\)
(d) \(\frac{3}{4}\)
Show Answer & Explanation
Answer: (c) \(\frac{1}{2}\)
Explanation:
1. Divide numerator and denominator by \(\cos\theta\): \(\frac{4\tan\theta - 1}{4\tan\theta + 1} = \frac{3 - 1}{3 + 1} = \frac{1}{2}\).
Assertion (A): The value of \(\sec^2 10^\circ - \cot^2 80^\circ\) is 1.
Reason (R): The value of \(\sin 30^\circ = \frac{1}{2}\).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. \(\cot 80^\circ = \tan 10^\circ\), so \(\sec^2 10^\circ - \tan^2 10^\circ = 1\). The assertion is true.
2. \(\sin 30^\circ = \frac{1}{2}\) is true, but it does not explain the assertion.
Assertion (A): The value of \(\sin\theta = \frac{4}{3}\) is not possible.
Reason (R): Hypotenuse is the largest side in any right angled triangle.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. \(\sin\theta = \frac{P}{H}\) cannot exceed 1, so \(\frac{4}{3}\) is impossible.
2. The reason, that the hypotenuse is the largest side, explains why.
Assertion (A): \(\sin^2 67^\circ + \cos^2 67^\circ = 1\).
Reason (R): For any value of \(\theta\), \(\sin^2\theta + \cos^2\theta = 1\).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Substituting \(\theta = 67^\circ\) in the identity gives the assertion. The reason is the identity itself.
Assertion (A): For \(0 < \theta \le 90^\circ\), \(\csc\theta - \cot\theta\) and \(\csc\theta + \cot\theta\) are reciprocals of each other.
Reason (R): \(\csc^2\theta - \cot^2\theta = 1\).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. \((\csc\theta + \cot\theta)(\csc\theta - \cot\theta) = 1\), so the two are reciprocals.
2. The identity used in the assertion is the reason.
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FAQs
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