CBSE Class 10 Mathematics Commercial Mathematics MCQs Set 21

Download CBSE MCQs for Class 10 Mathematics: Commercial Mathematics

Explore reliable objective questions for Commercial Mathematics tailored for Class 10 learners. Utilizing these Mathematics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Chapter-wise Objective Questions: Commercial Mathematics

View or download the dedicated Commercial Mathematics MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: A person has a certain amount. He can buy 50 oranges or 40 mangoes. He retains 10% of the amount for taxi fares and buys 20 mangoes, and with the balance he purchases oranges. The number of oranges he can purchase is
(a) 36
(b) 40
(c) 15
(d) 20
Show Answer & Explanation

Answer: (d) 20

Explanation:
1. Let the amount be M. Mango = M/40 each, orange = M/50 each.
2. 20 mangoes cost M/2; balance = 0.9M − 0.5M = 0.4M.
3. Oranges = 0.4M ÷ (M/50) = 20.

Teacher's Note:
1. Express everything in terms of the total amount.

Question 2: A shopkeeper sells 25 articles at Rs. 45 each after giving a 10% discount and earns 50% profit. If the discount is not given, the profit is
(a) 60%
(b) 60⅔%
(c) 66%
(d) 66⅔%
Show Answer & Explanation

Answer: (d) 66⅔%

Explanation:
1. Marked price = 45/0.9 = Rs. 50 and cost price = 45/1.5 = Rs. 30.
2. Without discount the profit = (50 − 30)/30 = 66⅔%.

Teacher's Note:
1. Find the marked price and cost price.

Question 3: A person incurs a 5% loss by selling a watch for Rs. 1140. At what price should it be sold to earn a 5% profit?
(a) Rs. 1275
(b) Rs. 1280
(c) Rs. 1210
(d) Rs. 1260
Show Answer & Explanation

Answer: (d) Rs. 1260

Explanation:
1. Cost price = 1140/0.95 = Rs. 1200.
2. Selling price for 5% profit = 1.05 × 1200 = Rs. 1260.

Teacher's Note:
1. Find the cost price first.

Question 4: A book was sold for Rs. 27.50 with a profit of 10%. If it were sold for Rs. 25.75, the percentage of profit or loss would have been
(a) 4.5%
(b) 5.0%
(c) 3.0%
(d) 3.25%
Show Answer & Explanation

Answer: (c) 3.0%

Explanation:
1. Cost price = 27.50/1.1 = Rs. 25.
2. Profit at 25.75 = 0.75/25 = 3.0%.

Teacher's Note:
1. Cost price is the fixed reference.

Question 5: The cost price of 21 articles is equal to the selling price of 18 articles. The gain or loss percent is
(a) 16⅔% gain
(b) 8%
(c) 10%
(d) 12%
Show Answer & Explanation

Answer: (a) 16⅔% gain

Explanation:
1. Let the cost price of one article be 1: SP of 18 = 21, so SP of one = 7/6.
2. Gain = 1/6 = 16⅔%.

Teacher's Note:
1. Compare cost and selling price per article.

Question 6: By selling 33 metres of cloth, a person gains the selling price of 11 metres. The gain percent is
(a) 17.5%
(b) 33.33%
(c) 40%
(d) 50%
Show Answer & Explanation

Answer: (d) 50%

Explanation:
1. Gain on 33 m = SP of 11 m, so CP of 33 m = SP of 22 m.
2. SP/CP per metre = 33/22 = 1.5, so the gain is 50%.

Teacher's Note:
1. Gain = SP − CP.

Question 7: A vendor bought bananas at 6 for Rs. 10 and sold them at 4 for Rs. 6. His loss percent is
(a) 12%
(b) 8%
(c) 6%
(d) 10%
Show Answer & Explanation

Answer: (d) 10%

Explanation:
1. CP per banana = 10/6 and SP per banana = 6/4 = 1.5.
2. Loss = (1.6667 − 1.5)/1.6667 = 10%.

Teacher's Note:
1. Compare per-piece prices.

Question 8: A manufacturer gains 10%, the wholesaler 15% and the retailer 25%. The cost of production of a table whose retail price is Rs. 1265 is
(a) Rs. 600
(b) Rs. 800
(c) Rs. 700
(d) Rs. 900
Show Answer & Explanation

Answer: (b) Rs. 800

Explanation:
1. 1265 = cost × 1.10 × 1.15 × 1.25 = cost × 1.58125.
2. Cost = Rs. 800.

Teacher's Note:
1. Successive gains multiply.

Question 9: After two successive discounts, a shirt with a list price of Rs. 150 is available at Rs. 105. If the second discount is 12.5%, the first discount is
(a) 25%
(b) 12%
(c) 15%
(d) 20%
Show Answer & Explanation

Answer: (d) 20%

Explanation:
1. After the first discount: 105/0.875 = Rs. 120.
2. First discount = 30/150 = 20%.

Teacher's Note:
1. Undo the last discount first.

Question 10: A shopkeeper expects a gain of 22½% on his cost price. If in a week his sale was Rs. 392, his profit was
(a) Rs. 18.20
(b) Rs. 70
(c) Rs. 72
(d) Rs. 88.25
Show Answer & Explanation

Answer: (c) Rs. 72

Explanation:
1. Sale = 122.5% of cost, so cost = 392/1.225 = Rs. 320.
2. Profit = 392 − 320 = Rs. 72.

Teacher's Note:
1. Sale = cost × (1 + gain%).

Question 11: Jacob bought a scooter, spent 10% of its cost on repairs and sold it for a profit of Rs. 1100. How much did he spend on repairs if he made a profit of 20% on his total outlay?
(a) Rs. 400
(b) Rs. 440
(c) Rs. 500
(d) Rs. 550
Show Answer & Explanation

Answer: (c) Rs. 500

Explanation:
1. Let the purchase cost be C. Total outlay = C + 0.1C = 1.1C, and a 20% profit on it is 0.22C = 1100.
2. C = 5000, so repairs = 10% of 5000 = Rs. 500.

Teacher's Note:
1. Express profit as a fraction of the cost.

Question 12: If the selling price of 50 articles is equal to the cost price of 40 articles, the loss or gain percent is
(a) 20% gain
(b) 20% loss
(c) 25% loss
(d) 25% gain
Show Answer & Explanation

Answer: (b) 20% loss

Explanation:
1. SP/CP per article = 40/50 = 0.8, so there is a 20% loss.

Teacher's Note:
1. Compare per-article values.

Question 13: A man bought a number of clips at 3 for a rupee and an equal number at 2 for a rupee. At what price per dozen should he sell them to make a profit of 20%?
(a) Rs. 4
(b) Rs. 5
(c) Rs. 6
(d) Rs. 7
Show Answer & Explanation

Answer: (c) Rs. 6

Explanation:
1. For n clips of each kind, cost = n/3 + n/2 = 5n/6 rupees for 2n clips, i.e. 5/12 rupee per clip = Rs. 5 per dozen.
2. With 20% profit: Rs. 6 per dozen.

Teacher's Note:
1. Find the average cost per clip.

Question 14: On selling a T.V. at 5% gain and a fridge at 10% gain, a shopkeeper gains Rs. 2000. If he sells the T.V. at 10% gain and the fridge at 5% loss, he gains Rs. 1500. The actual prices of the T.V. and fridge are
(a) Rs. 20,000 and Rs. 15,000
(b) Rs. 20,000 and Rs. 10,000
(c) Rs. 10,000 and Rs. 12,000
(d) Rs. 15,000 and Rs. 18,000
Show Answer & Explanation

Answer: (b) Rs. 20,000 and Rs. 10,000

Explanation:
1. 0.05T + 0.1F = 2000 and 0.1T − 0.05F = 1500.
2. Doubling the first: 0.1T + 0.2F = 4000. Subtracting the second: 0.25F = 2500, so F = 10000 and T = 20000.

Teacher's Note:
1. Set up two equations in T and F.

Question 15: Garima bought a briefcase with an additional 10% discount on the reduced price after a 20% deduction on the labelled price. If the labelled price was Rs. 1400, she paid
(a) Rs. 980
(b) Rs. 1008
(c) Rs. 1056
(d) Rs. 1120
Show Answer & Explanation

Answer: (b) Rs. 1008

Explanation:
1. 1400 × 0.8 = 1120, then 1120 × 0.9 = Rs. 1008.

Teacher's Note:
1. Apply discounts one after the other.

Question 16: A shopkeeper purchased 150 identical calculators at Rs. 250 each and spent Rs. 2500 on transport and packing. He fixed the labelled price at Rs. 320 each but gave a 5% discount. His percentage profit is
(a) 14%
(b) 15%
(c) 16%
(d) 20%
Show Answer & Explanation

Answer: (a) 14%

Explanation:
1. Total cost = 37500 + 2500 = Rs. 40000.
2. Selling price each = 304, total = 45600. Profit = 5600/40000 = 14%.

Teacher's Note:
1. Include the transport cost in the total cost.

Question 17: By selling an umbrella at its marked price of Rs. 300, a shopkeeper gains 20%. During a clearance sale he allows a 10% discount on the marked price. His gain percent during the sale is
(a) 7
(b) 7.5
(c) 8
(d) 9
Show Answer & Explanation

Answer: (c) 8

Explanation:
1. Cost price = 300/1.2 = Rs. 250.
2. Sale price = 270, gain = 20/250 = 8%.

Teacher's Note:
1. Cost price stays the same.

Question 18: A shopkeeper sells a badminton racket with a marked price of Rs. 30 at a 15% discount and gives a shuttlecock costing Rs. 1.50 free with each racket. Even then he makes a profit of 20% on the racket. The cost price of a racket is
(a) Rs. 19.75
(b) Rs. 20
(c) Rs. 21
(d) Rs. 21.25
Show Answer & Explanation

Answer: (b) Rs. 20

Explanation:
1. Selling price = 30 × 0.85 = 25.50. Net of the free shuttlecock = 24.
2. 24 = 1.2 × CP gives CP = Rs. 20.

Teacher's Note:
1. Subtract the free item from the selling price.

Question 19: If 25% of a number is subtracted from a second number, the second number reduces to its five-sixth. The ratio of the first number to the second is
(a) 1 : 3
(b) 2 : 3
(c) 3 : 2
(d) Data inadequate
Show Answer & Explanation

Answer: (b) 2 : 3

Explanation:
1. y − x/4 = 5y/6 gives x/4 = y/6, so x/y = 2/3.

Teacher's Note:
1. Form the equation and simplify.

Question 20: A trader mixes three varieties of groundnuts costing Rs. 50, Rs. 20 and Rs. 30 per kg in the ratio 2 : 4 : 3 by weight and sells the mixture at Rs. 33 per kg. His percentage profit is
(a) 8%
(b) 9%
(c) 10%
(d) None of these
Show Answer & Explanation

Answer: (c) 10%

Explanation:
1. Average cost = (2 × 50 + 4 × 20 + 3 × 30)/9 = 270/9 = Rs. 30.
2. Profit = 3/30 = 10%.

Teacher's Note:
1. Use the weighted mean cost.

Question 21: The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is
(a) 51 : 52
(b) 52 : 53
(c) 51 : 53
(d) 52 : 55
Show Answer & Explanation

Answer: (b) 52 : 53

Explanation:
1. The selling prices are in the ratio 104 : 106 = 52 : 53.

Teacher's Note:
1. Selling price = cost × (100 + gain)/100.

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Commercial Mathematics Objective Questions & Solutions for Class 10 Mathematics

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FAQs

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