Get the most accurate TN Board Solutions for Class 6 Maths Chapter 04 Geometry here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 6 Maths. Our expert-created answers for Class 6 Maths are available for free download in PDF format.
Detailed Chapter 04 Geometry TN Board Solutions for Class 6 Maths
For Class 6 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 6 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 04 Geometry solutions will improve your exam performance.
Class 6 Maths Chapter 04 Geometry TN Board Solutions PDF
Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Ex 4.3
Question 1. Observe the diagram and fill in the blanks.
(i) 'A', 'O' and 'B' are ......... points.
(ii) 'A', 'O' and 'C' are ......... points.
(iii) 'A','B' and 'C'are ......... points.
(iv) ......... is the point of concurrency.
Answer:
(i) 'A', 'O' and 'B' are **collinear** points. These three points lie on the same straight line, forming the diameter of the circle.
(ii) 'A', 'O' and 'C' are **non-collinear** points. These points do not lie on a single straight line, forming a triangle instead.
(iii) 'A','B' and 'C' are **endpoints/non-collinear** points. While A and B are endpoints of a diameter, adding C makes the set of three points non-collinear.
(iv) **O** is the point of concurrency. This is because all diameters and chords passing through the center meet at point O.
In simple words: Collinear points are all in a straight line, like A, O, B. Non-collinear points are not in a straight line, like A, O, C. Point O is where lines meet if they pass through the center of the circle.
🎯 Exam Tip: Remember that "collinear" means "lying on the same line" and "concurrent" means "passing through the same point".
Question 2. Draw any line and mark any 3 points that are collinear.
Answer:
The image shows a straight line 'l' with three points P, Q, and R. Since all three points lie on the same line, they are collinear.
In simple words: Draw a straight line. Put three dots on that line and label them P, Q, and R. These dots are collinear because they are all on the same straight path.
🎯 Exam Tip: Use a ruler to ensure your line is perfectly straight when drawing collinear points.
Question 3. Draw any line and mark any 4 points that are not collinear.
Answer:
The diagram shows three points A, B, and C that lie on a straight line. A fourth point, D, is marked in a different position so it does not lie on the same line as A, B, and C. This way, all four points A, B, C, and D are not collinear when considered together.
In simple words: Draw a line and put three dots (A, B, C) on it. Then, put one more dot (D) somewhere else, not on that line. These four dots together are not in a straight line.
🎯 Exam Tip: To show non-collinear points, ensure at least one point is clearly off the line formed by the others.
Question 4. Draw any 3 lines to have a point of concurrency.
Answer:
The diagram shows three lines \( l_1 \), \( l_2 \), and \( l_3 \) that all pass through the exact same central point. This point where they all meet is called the point of concurrency.
In simple words: Draw three lines so they all cross over at one single point, like spokes on a wheel. That point is where they are concurrent.
🎯 Exam Tip: When drawing concurrent lines, make sure all lines visibly pass through the exact same single point, not just close to it.
Question 5. Draw any 3 lines that are not concurrent. Find the number of points of intersection.
Answer:
The diagram shows three lines, \( l_1 \), \( l_2 \), and \( l_3 \), which do not all pass through the same single point. When three lines are not concurrent, they will typically intersect at three different points, forming a triangle. In this figure, there are **3** points of intersection where each pair of lines crosses.
In simple words: Draw three lines that do not all meet at one place. Each pair of lines will cross, making three separate crossing points in total.
🎯 Exam Tip: If three lines are drawn randomly, they will usually form a triangle and have three intersection points unless they are parallel or concurrent.
Objective Type Questions
Observe the Diagram and give answers
Question 6. A set of collinear points in the figure are
(a) A, B, C
(b) A, F, C
(c) B, C, D
(d) A, C, D
Answer: (b) A, F, C
In simple words: Collinear points are those that lie on the same straight line. In the given figure, points A, F, and C are all on the diagonal line that runs from the bottom-left to the top-right corner.
🎯 Exam Tip: To identify collinear points, mentally trace a straight line through the points. If all points fall on that single line, they are collinear.
Question 7. A set of non-collinear points in the figure are .........
(a) A, F, C
(b) B, F, D
(c) E, F, G
(d)A,D,C
Answer: (d) A, D, C
In simple words: Non-collinear points are points that do not lie on a single straight line. In the diagram, if you try to draw a straight line through A, D, and C, you will find it's not possible; A, D form a side, but C is at another corner, so they create a bent path.
🎯 Exam Tip: For non-collinear points, ensure that even if two points are on a line, the third point is distinctly off that line.
Question 8. A point of concurrency in the figure is
(a) E
(b) F
(c) G
(d) H
Answer: (b) F
In simple words: The point of concurrency is where several lines meet or cross. In the figure, point F is the central point where all the main lines like diagonals and mid-lines intersect.
🎯 Exam Tip: Look for the central point where three or more lines visibly cross each other; this is usually the point of concurrency.
Free study material for Maths
TN Board Solutions Class 6 Maths Chapter 04 Geometry
Students can now access the TN Board Solutions for Chapter 04 Geometry prepared by teachers on our website. These solutions cover all questions in exercise in your Class 6 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.
Detailed Explanations for Chapter 04 Geometry
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 6 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 6 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.
Benefits of using Maths Class 6 Solved Papers
Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 6 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 04 Geometry to get a complete preparation experience.
FAQs
The complete and updated Samacheer Kalvi Class 6 Maths Solutions Term 1 Chapter 4 Geometry Exercise 4.3 is available for free on StudiesToday.com. These solutions for Class 6 Maths are as per latest TN Board curriculum.
Yes, our experts have revised the Samacheer Kalvi Class 6 Maths Solutions Term 1 Chapter 4 Geometry Exercise 4.3 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 6 Maths Solutions Term 1 Chapter 4 Geometry Exercise 4.3 will help students to get full marks in the theory paper.
Yes, we provide bilingual support for Class 6 Maths. You can access Samacheer Kalvi Class 6 Maths Solutions Term 1 Chapter 4 Geometry Exercise 4.3 in both English and Hindi medium.
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