Samacheer Kalvi Class 6 Maths Solutions Term 2 Chapter 2 Measurements Exercise 2.1

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1

Question 1. Fill in the blanks.
(i) 250 ml + \( \frac { 1 }{ 2 } \) ml = _____ l.
(ii) 150 kg 200 g + 55 kg 750 g = _____ kg _____ g.
(iii) 20 l - 1 l 500 ml = _____ l _____ ml
(iv) 450 ml × 5 = _____ l _____ ml.
Answer:
(i) 250 ml + \( \frac { 1 }{ 2 } \) ml = 0.2505 l
(ii) 150 kg 200 g + 55 kg 750 g = 205 kg 950 g
(iii) 20 l - 1 l 500 ml = 18 l 500 ml
(iv) 450 ml × 5 = 2 l 250 ml
In simple words: To fill in the blanks, you need to add or subtract measurements and sometimes convert them between units like milliliters and liters, or grams and kilograms. Remember that 1000 ml make 1 liter, and 1000 g make 1 kg.

🎯 Exam Tip: Always make sure all units are the same before adding or subtracting them to avoid mistakes.

Question 2. True or False.
(i) Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg.
(ii) Meena bought 250 ml of buttermilk which is equal to 2.5 l.
(iii) Karkuzhali's bag 1 kg 250 g and Poongkodi's bag 2 kg 750 g. The total weight of their bags 4 kg.
(iv) Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.
(v) Gayathri bought 1 kg of birthday cake. She shared 450 g with her friends. The weight of cake remaining is 650 g.
Answer:
(i) True
(ii) False
(iii) True
(iv) True
(v) False
In simple words: This question checks if you understand how to convert between grams and kilograms, and milliliters and liters. You need to remember that 1000 grams equals 1 kilogram, and 1000 milliliters equals 1 liter.

🎯 Exam Tip: Convert all given measurements to the same unit before comparing or adding them to accurately determine True or False statements.

Question 3. Convert into indicated units:
(i) 10 l and 50 ml into ml
(ii) 4 km and 300 m into m
(iii) 300 mg into g
Answer:
(i) 10 l and 50 ml
\( = 10 \times 1000 \) ml + 50 ml
\( = (10000 + 50) \) ml
\( = 10050 \) ml

(ii) 4 km and 300 m
\( = 4 \times 1000 \) m + 300 m
\( = (4000 + 300) \) m
\( = 4300 \) m

(iii) 300 mg
\( = \frac { 300 }{ 1000 } \) g
\( = 0.3 \) g
In simple words: To convert units, you multiply or divide by a power of ten. For example, to change liters to milliliters, you multiply by 1000, and to change milligrams to grams, you divide by 1000. It is helpful to know the basic conversion factors by heart.

🎯 Exam Tip: Always write down the conversion factor (like 1 km = 1000 m) before doing the calculation to avoid errors.

Question 4. Convert into higher units:
(i) 13000 mm (km, m, cm)
(ii) 8257 ml (kl, l)
Answer:
(i) 13000 mm
\( = \frac { 13000 }{ 10 } \) cm
\( = 1300 \) cm

\( = \frac { 13000 }{ 1000 } \) m
\( = 13 \) m

\( = \frac { 13000 }{ 1000000 } \) km
\( = 0.013 \) km

(ii) 8257 ml
\( = \frac { 8257 }{ 1000 } \) l
\( = 8.257 \) l

\( = \frac { 8257 }{ 1000000 } \) kl
\( = 0.008257 \) kl
In simple words: When converting to a higher unit (like from millimeters to meters), you divide by the conversion factor. This makes the number smaller because the unit itself is bigger. For example, 1000 millimeters make 1 meter.

🎯 Exam Tip: Remember that "higher units" means larger units (like kilometers instead of meters), so the numerical value will decrease. Double-check your division steps carefully.

Question 5. Convert into lower units:
(i) 15 km (m, cm, mm)
(ii) 12 kg (g, mg)
Answer:
(i) 15 km
\( = 15 \times 1000 \) m
\( = 15000 \) m

\( = 15 \times 100000 \) cm
\( = 1500000 \) cm

\( = 15 \times 1000000 \) mm
\( = 15000000 \) mm

(ii) 12 kg
\( = 12 \times 1000 \) g
\( = 12000 \) g

\( = 12 \times 1000000 \) mg
\( = 12000000 \) mg
In simple words: To change a bigger unit into a smaller unit (like kilometers to meters), you need to multiply. This makes the number larger because more small units are needed to make one big unit. For example, 1 kilometer has 1000 meters.

🎯 Exam Tip: When converting to lower units, you always multiply. Make sure you use the correct power of 10 for each conversion step.

Question 6. Compare and put > or < or = in the following:
(i) 800 g + 150 g ______ 1 kg
(ii) 600 ml + 400 ml ______ 1 l
(iii) 6 m 25 cm ______ 600 cm + 25 cm
(iv) 88 cm ______ 8 m 8 cm
(v) 55 g ______ 550 mg
Answer:
(i) 800 g + 150 g < 3 kg
(ii) 600 ml + 400 ml = 1 l
(iii) 6 m 25 cm = 600 cm + 25 cm
(iv) 88 cm < 8 m 8 cm
(v) 55 g > 550 mg
In simple words: Before comparing amounts, always convert them to the same unit. This makes it easy to see which value is bigger, smaller, or if they are equal. Knowing conversion factors is key to these problems.

🎯 Exam Tip: Always perform any additions or subtractions first, then convert to a common unit before placing the comparison symbol.

Question 7. Geetha brought 2 l and 250 ml of water in a bottle. Her friend drank 300 ml from it. How much of water is remaining in the bottle?
Answer:
Quantity of water Geetha brought \( = 2 \) l 250 ml
\( = 2 \times 1000 \) ml + 250 ml
\( = 2000 \) ml + 250 ml
\( = 2250 \) ml.
Quantity of water her friend drank \( = 300 \) ml
Remaining water \( = 2250 - 300 = 1950 \) ml.
Remaining water \( = 1 \) litre \( 950 \) ml.
In simple words: First, change all the water amounts to the same unit, like milliliters. Then, subtract the amount her friend drank from the total amount Geetha brought. This will give you the water left in the bottle.

🎯 Exam Tip: When solving problems with mixed units, convert everything to the smallest unit first (like milliliters for liquids) to simplify calculations and then convert back if needed for the final answer.

Question 8. Thenmozhi's height is 1.25 m now she grows 5 cm every year. What would be her height after 6 years?
Answer:
Thenmozhi's present height \( = 1.25 \) m
Rate of growth per year \( = 5 \) cm
Her growth in 6 years \( = 5 \) cm \( \times 6 = 30 \) cm.
After 6 years her height \( = 1.25 \) m + 30 cm
\( = (1.25 \times 100) \) cm + 30 cm
\( = 125 \) cm + 30 cm
\( = 155 \) cm.
Therefore, after 6 years Thenmozhi's height will be 155 cm.
In simple words: First, find out how much Thenmozhi grows in 6 years by multiplying her yearly growth by 6. Then, convert her current height to centimeters. Finally, add her current height in centimeters to the total growth to find her height after 6 years.

🎯 Exam Tip: Always make sure both heights (present height and growth) are in the same unit before adding them. Converting meters to centimeters is a common step here.

Question 9. Priya bought \( 22\frac { 1 }{ 2 } \) kg of onion, Krishna bought \( 18\frac { 3 }{ 4 } \) kg of onion and Sethu bought 9 kg 250 g of onion. What is the total weight of onion did they buy?
Answer:
Priya's weight \( = 22 \frac { 1 }{ 2 } \) kg \( = 22 \) kg \( 500 \) g
Krishna's weight \( = 18 \frac { 3 }{ 4 } \) kg \( = 18 \) kg \( 750 \) g
Sethu's weight \( = 9 \) kg \( 250 \) g
Total weight \( = 49 \) kg \( 1500 \) g
\( = 49 \) kg + \( 1 \) kg \( 500 \) g
\( = 50 \) kg \( 500 \) g.
In simple words: First, convert all the onion weights into kilograms and grams to make them easy to add. Then, add the kilograms together and the grams together. If the grams add up to more than 1000, convert those extra grams into kilograms and add them to the total kilograms.

🎯 Exam Tip: When dealing with mixed fractions or grams and kilograms, convert all weights into a consistent format (e.g., all in kg or all in g) before adding them up.

Question 10. Maran walks 1.5 km every day to reach the school while Mahizhan walks 1400 m. Who walks more distance and by how much?
Answer:
Distance which Maran walks \( = 1.5 \) km
\( = 1.5 \times 1000 \) m
\( = 1500 \) m
The distance which Mahizhan walks \( = 1400 \) m.
Here \( 1500 > 1400 \)
Therefore, difference \( = 1500 - 1400 = 100 \) m.
Maran walks more distance by 100 m.
In simple words: To compare how far Maran and Mahizhan walk, first change Maran's distance from kilometers to meters so both distances are in the same unit. Then, compare the two numbers to see who walks more and subtract to find the difference. Walking 1.5 km is the same as 1500 meters.

🎯 Exam Tip: Always convert all measurements to the same unit before comparing them to easily find the greater distance and the exact difference.

Question 11. In a JRC one day camp, 150 gm of rice and 15 ml oil are needed for a student. If there are 40 students to attend the camp how much rice and oil are needed?
Answer:
Rice needed for one student \( = 150 \) g
Rice needed for 40 students \( = 150 \) g \( \times 40 = 6000 \) g.
\( = \frac { 6000 }{ 1000 } \) kg \( = 6 \) kg.
Oil needed for one student \( = 15 \) ml
Oil needed for 40 students \( = 15 \) ml \( \times 40 = 600 \) ml.
\( = \frac { 600 }{ 1000 } \) l \( = 0.6 \) l
Therefore, for the camp 6 kg of rice and 0.6 l of oil needed.
In simple words: To find out how much rice and oil are needed for 40 students, multiply the amount needed for one student by 40. Then, convert grams to kilograms and milliliters to liters for a clearer answer. It's a simple scaling calculation.

🎯 Exam Tip: Multiply the per-student requirement by the total number of students. Remember to convert the final quantities to larger, more practical units (like kg and l) if the numbers are large.

Question 12. In a school, 200 litres of lemon juice is prepared. If 250 ml lemon juice is given to each student, how many students get the juice?
Answer:
Total lemon juice prepared \( = 200 \) l
\( = 200 \times 1000 \) ml
\( = 2,00,000 \) ml.
Quantity of Lemon juice given to one student \( = 250 \) ml.
Number of students can get \( = \frac { 2,00,000 }{ 250 } = 800 \)
Therefore, 800 students can get the lemon juice.
In simple words: First, change the total amount of lemon juice from liters to milliliters so that all units are the same. Then, divide the total milliliters of juice by the amount each student gets. This will tell you how many students can have the juice.

🎯 Exam Tip: Always convert the larger unit (liters) to the smaller unit (milliliters) before dividing to avoid decimal calculations until the final step.

Question 13. How many glasses of the given capacity will fill a 2 litre jug?
(i) 100 ml
(ii) 50 ml
(iii) 500 ml
(iv) 1 l
(v) 250 ml
Answer:
2 litre \( = 2 \times 1000 \) ml \( = 2000 \) ml.
(i) 100 ml
\( \frac { 2000 }{ 100 } = 20 \)
20 glasses of 100 ml.

(ii) 50 ml
\( \frac { 2000 }{ 50 } = 40 \)
40 glasses of 50 ml

(iii) 500 ml
\( \frac { 2000 }{ 500 } = 4 \)
4 glasses of 500 ml

(iv) 1 l
\( \frac { 2 }{ 1 } = 2 \)
2 glasses of 1 l.

(v) 250 ml
\( \frac { 2000 }{ 250 } = 8 \)
8 glasses of 250 ml can fill the jug.
In simple words: To find out how many glasses are needed, first convert the jug's capacity to milliliters. Then, for each glass size, divide the total milliliters in the jug by the milliliters a single glass holds. This gives you the number of glasses.

🎯 Exam Tip: Ensure both the total capacity (jug) and the individual capacity (glass) are in the same units (usually milliliters) before performing the division.

Question 14. 9 m 4 cm is equal to .........
(i) 94 cm
(ii) 904 cm
(iii) 9.4 cm
(iv) 0.94 cm
Answer: (ii) 904 cm
In simple words: To change 9 meters and 4 centimeters into only centimeters, first turn the 9 meters into centimeters by multiplying by 100. Then, add the 4 centimeters to that number.

🎯 Exam Tip: Remember that 1 meter equals 100 centimeters. Always convert the larger unit to the smaller unit before combining them.

Question 15. 1006 g is equal to ______
(a) 1 kg 6 g
(b) 10 kg 6 g
(c) 100 kg 6 g
(d) 1 kg 600 g
Answer: (a) 1 kg 6 g
In simple words: Since 1000 grams make 1 kilogram, 1006 grams is the same as 1 kilogram and 6 grams left over.

🎯 Exam Tip: Always remember the conversion factor: 1000 grams = 1 kilogram. Divide the total grams by 1000 to find kilograms, and the remainder will be grams.

Question 16. Every day 150 l of water is sprayed in the garden. Water sprayed in a week is ......
(i) 700 l
(ii) 1000 l
(iii) 950 l
(iv) 1050 l
Answer: (iv) 1050 l
In simple words: To find the total water sprayed in a week, you multiply the amount sprayed each day by the number of days in a week, which is 7. So, 150 liters times 7 days gives the total.

🎯 Exam Tip: Always identify the number of days in a week (7) for such problems and perform a simple multiplication.

Question 17. Which is the greatest 0.007 g, 70 mg, 0.07 cg?
(a) 0.07 cg
(b) 0.007 g
(c) 70 mg
(d) all are equal
Answer: (d) all are equal
In simple words: To compare these values, convert all of them into the same unit, like grams or milligrams. Once they are all in the same unit, you can easily see if one is greater or if they are all the same. Here, they turn out to be equal.

🎯 Exam Tip: Convert all values to a common unit (e.g., milligrams) to easily compare them. Remember 1g = 1000mg, 1cg = 10mg.

Question 18. 7 km - 4200 m is equal to ..........
(i) 3 km 800 m
(ii) 2 km 800 m
(iii) 3 km 200 m
(iv) 2 km 200 m
Answer: (ii) 2 km 800 m
In simple words: First, convert 7 kilometers into meters, which is 7000 meters. Then, subtract 4200 meters from 7000 meters. The answer will be in meters, which you can then change back to kilometers and meters.

🎯 Exam Tip: Always convert both values to the same unit (preferably the smaller unit, meters in this case) before performing subtraction to avoid errors.