NCERT Solutions for Class 5 Maths: Chapter 06 Fractions
Review structured textbook solutions for Class 5 Maths Chapter 06 Fractions. Built according to TN Board guidelines for the 2026-27 academic year, these downloadable answers support daily revision and problem-solving accuracy.
Practice Class 5 Maths Solutions: Chapter 06 Fractions
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Question 1. Write the proper symbol from <, >, or = in the box
(i) \( \frac{3}{5} \) ___ \( \frac{2}{5} \)
(ii) \( \frac{2}{8} \) ___ \( \frac{1}{8} \)
(iii) \( \frac{2}{11} \) ___ \( \frac{10}{11} \)
(iv) \( \frac{3}{15} \) ___ \( \frac{10}{30} \)
(v) \( \frac{3}{8} \) ___ \( \frac{3}{7} \)
(vi) \( \frac{4}{7} \) ___ \( \frac{4}{11} \)
(vii) \( \frac{5}{12} \) ___ \( \frac{1}{6} \)
(viii) \( \frac{4}{9} \) ___ \( \frac{4}{9} \)
(ix) \( \frac{3}{7} \) ___ \( \frac{5}{9} \)
(x) \( \frac{4}{11} \) ___ \( \frac{1}{5} \)
Answer:
(i) Since the denominators are the same, we compare the numerators: \( 3 > 2 \). So, \( \frac{3}{5} > \frac{2}{5} \). This is because a larger numerator with the same denominator means a bigger fraction.
(ii) Since the denominators are the same, we compare the numerators: \( 2 > 1 \). So, \( \frac{2}{8} > \frac{1}{8} \).
(iii) Since the denominators are the same, we compare the numerators: \( 2 < 10 \). So, \( \frac{2}{11} < \frac{10}{11} \).
(iv) To compare \( \frac{3}{15} \) and \( \frac{10}{30} \), we make their denominators the same.
Multiply the numerator and denominator of \( \frac{3}{15} \) by 2: \( \frac{3 \times 2}{15 \times 2} = \frac{6}{30} \).
Now compare \( \frac{6}{30} \) and \( \frac{10}{30} \). Since \( 6 < 10 \), we have \( \frac{6}{30} < \frac{10}{30} \).
Therefore, \( \frac{3}{15} < \frac{10}{30} \).
(v) To compare \( \frac{3}{8} \) and \( \frac{3}{7} \), we make their denominators the same by finding the least common multiple (LCM) of 8 and 7, which is 56.
For \( \frac{3}{8} \): multiply numerator and denominator by 7: \( \frac{3 \times 7}{8 \times 7} = \frac{21}{56} \).
For \( \frac{3}{7} \): multiply numerator and denominator by 8: \( \frac{3 \times 8}{7 \times 8} = \frac{24}{56} \).
Now compare \( \frac{21}{56} \) and \( \frac{24}{56} \). Since \( 21 < 24 \), we have \( \frac{21}{56} < \frac{24}{56} \).
Therefore, \( \frac{3}{8} < \frac{3}{7} \).
(vi) To compare \( \frac{4}{7} \) and \( \frac{4}{11} \), we make their denominators the same by finding the LCM of 7 and 11, which is 77.
For \( \frac{4}{7} \): multiply numerator and denominator by 11: \( \frac{4 \times 11}{7 \times 11} = \frac{44}{77} \).
For \( \frac{4}{11} \): multiply numerator and denominator by 7: \( \frac{4 \times 7}{11 \times 7} = \frac{28}{77} \).
Now compare \( \frac{44}{77} \) and \( \frac{28}{77} \). Since \( 44 > 28 \), we have \( \frac{44}{77} > \frac{28}{77} \).
Therefore, \( \frac{4}{7} > \frac{4}{11} \).
(vii) To compare \( \frac{5}{12} \) and \( \frac{1}{6} \), we make their denominators the same.
Multiply the numerator and denominator of \( \frac{1}{6} \) by 2: \( \frac{1 \times 2}{6 \times 2} = \frac{2}{12} \).
Now compare \( \frac{5}{12} \) and \( \frac{2}{12} \). Since \( 5 > 2 \), we have \( \frac{5}{12} > \frac{2}{12} \).
Therefore, \( \frac{5}{12} > \frac{1}{6} \).
(viii) Both fractions are exactly the same. So, \( \frac{4}{9} = \frac{4}{9} \). When the numerator and denominator are identical, the fractions are equal.
(ix) To compare \( \frac{3}{7} \) and \( \frac{5}{9} \), we make their denominators the same by finding the LCM of 7 and 9, which is 63.
For \( \frac{3}{7} \): multiply numerator and denominator by 9: \( \frac{3 \times 9}{7 \times 9} = \frac{27}{63} \).
For \( \frac{5}{9} \): multiply numerator and denominator by 7: \( \frac{5 \times 7}{9 \times 7} = \frac{35}{63} \).
Now compare \( \frac{27}{63} \) and \( \frac{35}{63} \). Since \( 27 < 35 \), we have \( \frac{27}{63} < \frac{35}{63} \).
Therefore, \( \frac{3}{7} < \frac{5}{9} \).
(x) To compare \( \frac{4}{11} \) and \( \frac{1}{5} \), we make their denominators the same by finding the LCM of 11 and 5, which is 55.
For \( \frac{4}{11} \): multiply numerator and denominator by 5: \( \frac{4 \times 5}{11 \times 5} = \frac{20}{55} \).
For \( \frac{1}{5} \): multiply numerator and denominator by 11: \( \frac{1 \times 11}{5 \times 11} = \frac{11}{55} \).
Now compare \( \frac{20}{55} \) and \( \frac{11}{55} \). Since \( 20 > 11 \), we have \( \frac{20}{55} > \frac{11}{55} \).
Therefore, \( \frac{4}{11} > \frac{1}{5} \).
In simple words: To compare fractions, make their bottom numbers (denominators) the same. Then, look at the top numbers (numerators). The fraction with the bigger top number is the larger one. If the denominators are already the same, just compare the numerators directly.
🎯 Exam Tip: When comparing fractions with different denominators, always find a common denominator first, usually the least common multiple (LCM), to avoid errors. Cross-multiplication is also a quick method for comparing two fractions.
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Free TN Board Textbook Explanations: Class 5 Maths Chapter 06 Fractions
Accessing Chapter 06 Fractions Solutions
Access structured TN Board textbook solutions for Chapter 06 Fractions. Designed in alignment with the latest academic curriculum for Class 5 Maths, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
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The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 3 Chapter 6 Fractions Exercise 6.4 is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.
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