Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1

Get the most accurate TN Board Solutions for Class 5 Maths Chapter 04 Measurements here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 5 Maths. Our expert-created answers for Class 5 Maths are available for free download in PDF format.

Detailed Chapter 04 Measurements TN Board Solutions for Class 5 Maths

For Class 5 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 04 Measurements solutions will improve your exam performance.

Class 5 Maths Chapter 04 Measurements TN Board Solutions PDF

 

Question 1. Fill in the blanks.
(i) 7 kg 400 g = _____ g
(ii) 5 g 50 mg = _____ mg
(iii) 9500 mg = _____ g _____ mg
(iv) 15 kg 350 g = _____ g
(v) 6250 g = _____ kg _____ g
Answer:
(i) 7 kg 400 g = 7400 g
(ii) 5 g 50 mg = 5050 mg
(iii) 9500 mg = 9 g 500 mg
(iv) 15 kg 350 g = 15350 g
(v) 6250 g = 6 kg 250 g
In simple words: To convert a larger unit to a smaller unit, you usually multiply. For example, 1 kg is 1000 g, and 1 g is 1000 mg. So, you add the parts together after converting to the smaller unit, or separate the parts for the larger and smaller units.

🎯 Exam Tip: Remember the basic conversion factors: 1 kg = 1000 g and 1 g = 1000 mg. This helps in quickly filling these types of blanks.

 

Question 2. Add the following:
(i) 4 kg 250 g + 3 kg 450 g
(ii) 75 g 430 mg + 750 g
(iii) 97 kg 45 g + 77 kg 450 g + 33 kg 250 g
(iv) 75 kg 400 g + 30 kg 250 g
Answer:
(i) 4 kg 250 g + 3 kg 450 g = 7 kg 700 g

kgg
4250
+ 3450
7700
(ii) 75 g 430 mg + 750 g = 825 g 430 mg
gmg
75430
+ 750000
825430
(iii) 97 kg 45 g + 77 kg 450 g + 33 kg 250 g = 207 kg 745 g
kgg
9745
77450
+ 33250
207745
(iv) 75 kg 400 g + 30 kg 250 g = 105 kg 650 g
kgg
75400
+ 30250
105650
In simple words: When you add measurements, line up the same units (like kg with kg and g with g). Add each unit column separately. If a sum in a smaller unit (like grams or milligrams) goes over its conversion limit (like 1000), carry over the extra amount to the next larger unit column.

🎯 Exam Tip: Always align numbers by their units (kg, g, mg) to avoid mistakes. Remember to carry over if the sum in a smaller unit exceeds its conversion value (e.g., 1000g = 1kg).

 

Question 3. Subtract the following:
(i) 40 kg 350 g – 25 kg 200 g
(ii) 35 kg 850 g – 18 kg 500 g
(iii) 985 kg 475 g – 275 kg 325 g
(iv) 700 kg – 300 kg 500 g
Answer:
(i) 40 kg 350 g – 25 kg 200 g = 15 kg 150 g

kgg
40350
- 25200
15150
(ii) 35 kg 850 g – 18 kg 500 g = 17 kg 350 g
kgg
35850
- 18500
17350
(iii) 985 kg 475 g – 275 kg 325 g = 710 kg 150 g
kgg
985475
- 275325
710150
(iv) 700 kg – 300 kg 500 g = 399 kg 500 g
kgg
700000
- 300500
399500
In simple words: When subtracting measurements, always put the larger number on top. If you need to subtract a bigger number from a smaller one in a unit column, borrow from the next larger unit. Remember that 1 kg equals 1000 g when borrowing.

🎯 Exam Tip: Pay close attention when borrowing across units. If you borrow 1 kg, it becomes 1000 g in the grams column. If you borrow 1 g, it becomes 1000 mg.

 

Question 4. Multiply the following:
(i) 4 kg 300 g × 7
(ii) 17 kg 750 g × 8
(iii) 25 kg 550 g × 4
(iv) 72 g 350 mg × 5
Answer:
(i) 4 kg 300 g × 7 = 30 kg 100 g

kgg
4300
\( \times 7 \)
30100
(ii) 17 kg 750 g × 8 = 142 kg 000 g
kgg
17750
\( \times 8 \)
142000
(iii) 25 kg 550 g × 4 = 102 kg 200 g
kgg
25550
\( \times 4 \)
102200
(iv) 72 g 350 mg × 5 = 361 g 750 mg
gmg
72350
\( \times 5 \)
361750
In simple words: When you multiply measurements, multiply each unit by the given number separately. If the product of the smaller unit (like grams or milligrams) goes over its conversion value (like 1000), convert the extra amount to the larger unit and carry it over to the next column.

🎯 Exam Tip: Always multiply the smaller unit first and carry over any excess to the larger unit before multiplying the larger unit. This ensures accuracy.

 

Question 5. Divide the following:
(i) 99 kg 990 g ÷ 3
(ii) 147 g 630 mg ÷ 7
(iii) 550 kg 220 g ÷ 11
(iv) 484 g 384 mg ÷ 4
Answer:
(i) 99 kg 990 g ÷ 3 = 33 kg 330 g

kgg
33330
399990
(-)9
09
(-)9
009
(-)9
09
(-)9
00
(ii) 147 g 630 mg ÷ 7 = 21 g 90 mg
gmg
2190
7147630
14
07
(-)7
063
(-)63
00
(iii) 550 kg 220 g ÷ 11 = 50 kg 20 g
kgg
5020
11550220
55
0022
(-)22
00
(iv) 484 g 384 mg ÷ 4 = 121 g 96 mg
gmg
12196
4484384
(-)4
08
8
04
(-)4
038
(-)36
24
(-)24
0
In simple words: To divide measurements, divide the larger unit first. If there's a remainder, convert it to the smaller unit (e.g., kg to g) and add it to the existing amount in the smaller unit. Then, divide the smaller unit. This way, the division is done step-by-step for each unit.

🎯 Exam Tip: When dividing measurements, always work from the largest unit to the smallest. If there's a remainder in the larger unit, convert it and add it to the next smaller unit before continuing the division.

 

Question 6. What is the total weight of 7 kg 500 g of cashew nut and 3 kg 350 g of pista?
Answer:
Weight of cashew nut = 7 kg 500 g
Weight of pista = 3 kg 350 g
Total weight = 7 kg 500 g + 3 kg 350 g
Total weight = 10 kg 850 g

kgg
7500
+ 3350
10850
In simple words: To find the total weight, you need to add the weight of the cashew nuts and the pista. We add the kilograms together and the grams together, then combine them for the final answer.

🎯 Exam Tip: For "total weight" questions, identify the individual weights and then perform addition, making sure to align units correctly.

 

Question 7. Vimal had a sack of cotton seeds weighing 50 kg 350 g. He used 7 kg 300 g cotton seeds to feed his cow. How much cotton seed will be remaining?
Answer:
Total weight of cotton seeds = 50 kg 350 g
Weight of cotton seeds used = 7 kg 300 g
Remaining cotton seeds = 50 kg 350 g - 7 kg 300 g
Remaining cotton seeds = 43 kg 50 g

kgg
50350
- 7300
43050
In simple words: To find out how much is left, we subtract the amount of cotton seeds used from the total amount Vimal had. We subtract kilograms from kilograms and grams from grams.

🎯 Exam Tip: When a problem asks "how much will be remaining," it always indicates a subtraction operation. Set up the larger quantity first.

 

Question 8. A glass bottle can contain 25 g 125 mg of medicine, how much medicine can 7 such bottles contain?
Answer:
Medicine in one bottle = 25 g 125 mg
Medicine in 7 bottles = (25 g 125 mg) \( \times \) 7
Medicine in 7 bottles = 175 g 875 mg

gmg
25125
\( \times 7 \)
175875
In simple words: To find the total amount of medicine in 7 bottles, we multiply the amount in one bottle by 7. We multiply the milligrams and grams separately and combine the results.

🎯 Exam Tip: For "how much in multiple items" questions, multiplication is usually the operation. Remember to convert and carry over any excess from smaller units to larger units during multiplication.

 

Question 9. 75 kg 750 g of groundnut seed is filled in five bags, how much groundnut seed can a bag contain?
Answer:
Total groundnut seed = 75 kg 750 g
Number of bags = 5
Groundnut seed per bag = 75 kg 750 g \( \div \) 5
Groundnut seed per bag = 15 kg 150 g

kgg
15150
575750
(-)5
25
(-)25
07
(-)5
25
(-)25
00
In simple words: To find out how much groundnut seed is in one bag when the total is shared among five bags, we need to divide the total by five. We divide the kilograms first, then carry any remainder to the grams and divide the grams.

🎯 Exam Tip: For "per item" or "shared equally" questions, division is the correct operation. Remember to convert any remainder from the larger unit to the smaller unit before continuing the division.

TN Board Solutions Class 5 Maths Chapter 04 Measurements

Students can now access the TN Board Solutions for Chapter 04 Measurements prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 04 Measurements

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Class 5 Solved Papers

Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 04 Measurements to get a complete preparation experience.

FAQs

Where can I find the latest Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.

Are the Maths TN Board solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

How do these Class 5 TN Board solutions help in scoring 90% plus marks?

Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 will help students to get full marks in the theory paper.

Do you offer Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 in multiple languages like Hindi and English?

Yes, we provide bilingual support for Class 5 Maths. You can access Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 in both English and Hindi medium.

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