Download TN Board Solutions for Class 5 Maths Chapter 04 Measurements
Access comprehensive textbook solutions for Chapter 04 Measurements using the official curriculum guides for Class 5 Maths. Designed to align with the 2026-27 TN Board standards, these detailed answers help students reinforce core academic concepts.
Access TN Board Solutions and Answers
Access the complete solution PDF for Class 5 Maths below. Regular practice with these targeted textbook answers builds familiarity with standard question patterns and helps secure higher marks in final school evaluations.
Question 1. Fill in the blanks.
(i) 7 kg 400 g = _____ g
(ii) 5 g 50 mg = _____ mg
(iii) 9500 mg = _____ g _____ mg
(iv) 15 kg 350 g = _____ g
(v) 6250 g = _____ kg _____ g
Answer:
(i) 7 kg 400 g = 7400 g
(ii) 5 g 50 mg = 5050 mg
(iii) 9500 mg = 9 g 500 mg
(iv) 15 kg 350 g = 15350 g
(v) 6250 g = 6 kg 250 g
In simple words: To convert a larger unit to a smaller unit, you usually multiply. For example, 1 kg is 1000 g, and 1 g is 1000 mg. So, you add the parts together after converting to the smaller unit, or separate the parts for the larger and smaller units.
🎯 Exam Tip: Remember the basic conversion factors: 1 kg = 1000 g and 1 g = 1000 mg. This helps in quickly filling these types of blanks.
Question 2. Add the following:
(i) 4 kg 250 g + 3 kg 450 g
(ii) 75 g 430 mg + 750 g
(iii) 97 kg 45 g + 77 kg 450 g + 33 kg 250 g
(iv) 75 kg 400 g + 30 kg 250 g
Answer:
(i) 4 kg 250 g + 3 kg 450 g = 7 kg 700 g
| kg | g |
|---|---|
| 4 | 250 |
| + 3 | 450 |
| 7 | 700 |
| g | mg |
|---|---|
| 75 | 430 |
| + 750 | 000 |
| 825 | 430 |
| kg | g |
|---|---|
| 97 | 45 |
| 77 | 450 |
| + 33 | 250 |
| 207 | 745 |
| kg | g |
|---|---|
| 75 | 400 |
| + 30 | 250 |
| 105 | 650 |
🎯 Exam Tip: Always align numbers by their units (kg, g, mg) to avoid mistakes. Remember to carry over if the sum in a smaller unit exceeds its conversion value (e.g., 1000g = 1kg).
Question 3. Subtract the following:
(i) 40 kg 350 g – 25 kg 200 g
(ii) 35 kg 850 g – 18 kg 500 g
(iii) 985 kg 475 g – 275 kg 325 g
(iv) 700 kg – 300 kg 500 g
Answer:
(i) 40 kg 350 g – 25 kg 200 g = 15 kg 150 g
| kg | g |
|---|---|
| 40 | 350 |
| - 25 | 200 |
| 15 | 150 |
| kg | g |
|---|---|
| 35 | 850 |
| - 18 | 500 |
| 17 | 350 |
| kg | g |
|---|---|
| 985 | 475 |
| - 275 | 325 |
| 710 | 150 |
| kg | g |
|---|---|
| 700 | 000 |
| - 300 | 500 |
| 399 | 500 |
🎯 Exam Tip: Pay close attention when borrowing across units. If you borrow 1 kg, it becomes 1000 g in the grams column. If you borrow 1 g, it becomes 1000 mg.
Question 4. Multiply the following:
(i) 4 kg 300 g × 7
(ii) 17 kg 750 g × 8
(iii) 25 kg 550 g × 4
(iv) 72 g 350 mg × 5
Answer:
(i) 4 kg 300 g × 7 = 30 kg 100 g
| kg | g |
|---|---|
| 4 | 300 |
| \( \times 7 \) | |
| 30 | 100 |
| kg | g |
|---|---|
| 17 | 750 |
| \( \times 8 \) | |
| 142 | 000 |
| kg | g |
|---|---|
| 25 | 550 |
| \( \times 4 \) | |
| 102 | 200 |
| g | mg |
|---|---|
| 72 | 350 |
| \( \times 5 \) | |
| 361 | 750 |
🎯 Exam Tip: Always multiply the smaller unit first and carry over any excess to the larger unit before multiplying the larger unit. This ensures accuracy.
Question 5. Divide the following:
(i) 99 kg 990 g ÷ 3
(ii) 147 g 630 mg ÷ 7
(iii) 550 kg 220 g ÷ 11
(iv) 484 g 384 mg ÷ 4
Answer:
(i) 99 kg 990 g ÷ 3 = 33 kg 330 g
| kg | g | |
|---|---|---|
| 33 | 330 | |
| 3 | 99 | 990 |
| (-)9 | ||
| 09 | ||
| (-)9 | ||
| 00 | 9 | |
| (-)9 | ||
| 09 | ||
| (-)9 | ||
| 00 |
| g | mg | |
|---|---|---|
| 21 | 90 | |
| 7 | 147 | 630 |
| 14 | ||
| 07 | ||
| (-)7 | ||
| 0 | 63 | |
| (-)63 | ||
| 00 |
| kg | g | |
|---|---|---|
| 50 | 20 | |
| 11 | 550 | 220 |
| 55 | ||
| 00 | 22 | |
| (-)22 | ||
| 00 |
| g | mg | |
|---|---|---|
| 121 | 96 | |
| 4 | 484 | 384 |
| (-)4 | ||
| 08 | ||
| 8 | ||
| 04 | ||
| (-)4 | ||
| 0 | 38 | |
| (-)36 | ||
| 24 | ||
| (-)24 | ||
| 0 |
🎯 Exam Tip: When dividing measurements, always work from the largest unit to the smallest. If there's a remainder in the larger unit, convert it and add it to the next smaller unit before continuing the division.
Question 6. What is the total weight of 7 kg 500 g of cashew nut and 3 kg 350 g of pista?
Answer:
Weight of cashew nut = 7 kg 500 g
Weight of pista = 3 kg 350 g
Total weight = 7 kg 500 g + 3 kg 350 g
Total weight = 10 kg 850 g
| kg | g |
|---|---|
| 7 | 500 |
| + 3 | 350 |
| 10 | 850 |
🎯 Exam Tip: For "total weight" questions, identify the individual weights and then perform addition, making sure to align units correctly.
Question 7. Vimal had a sack of cotton seeds weighing 50 kg 350 g. He used 7 kg 300 g cotton seeds to feed his cow. How much cotton seed will be remaining?
Answer:
Total weight of cotton seeds = 50 kg 350 g
Weight of cotton seeds used = 7 kg 300 g
Remaining cotton seeds = 50 kg 350 g - 7 kg 300 g
Remaining cotton seeds = 43 kg 50 g
| kg | g |
|---|---|
| 50 | 350 |
| - 7 | 300 |
| 43 | 050 |
🎯 Exam Tip: When a problem asks "how much will be remaining," it always indicates a subtraction operation. Set up the larger quantity first.
Question 8. A glass bottle can contain 25 g 125 mg of medicine, how much medicine can 7 such bottles contain?
Answer:
Medicine in one bottle = 25 g 125 mg
Medicine in 7 bottles = (25 g 125 mg) \( \times \) 7
Medicine in 7 bottles = 175 g 875 mg
| g | mg |
|---|---|
| 25 | 125 |
| \( \times 7 \) | |
| 175 | 875 |
🎯 Exam Tip: For "how much in multiple items" questions, multiplication is usually the operation. Remember to convert and carry over any excess from smaller units to larger units during multiplication.
Question 9. 75 kg 750 g of groundnut seed is filled in five bags, how much groundnut seed can a bag contain?
Answer:
Total groundnut seed = 75 kg 750 g
Number of bags = 5
Groundnut seed per bag = 75 kg 750 g \( \div \) 5
Groundnut seed per bag = 15 kg 150 g
| kg | g | |
|---|---|---|
| 15 | 150 | |
| 5 | 75 | 750 |
| (-)5 | ||
| 25 | ||
| (-)25 | ||
| 0 | 7 | |
| (-)5 | ||
| 25 | ||
| (-)25 | ||
| 00 |
🎯 Exam Tip: For "per item" or "shared equally" questions, division is the correct operation. Remember to convert any remainder from the larger unit to the smaller unit before continuing the division.
Free study material for Maths
TN Board Solutions for Class 5 Maths Chapter 04 Measurements
Official TN Board Solutions for Chapter 04 Measurements
Access structured TN Board textbook solutions for Chapter 04 Measurements. Designed in alignment with the latest academic curriculum for Class 5 Maths, these answers cover all end-of-chapter exercises to support daily learning and homework completion.
Step-by-Step Explanations for Chapter 04 Measurements
Clear, methodical explanations accompany every challenging problem within the Class 5 Maths text. Engaging with these detailed answers lays a solid foundation for advanced learning and improves foundational clarity for upcoming assessments.
Next Steps in Your Maths Revision
Frequent review of these structured answers builds strong analytical capabilities and response efficiency. Maximize your academic readiness by combining these textbook solutions with our curated study materials and mock evaluations for Class 5 Maths.
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The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.
Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements Exercise 4.1 will help students to get full marks in the theory paper.
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