Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions

Get the most accurate TN Board Solutions for Class 5 Maths Chapter 04 Measurements here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 5 Maths. Our expert-created answers for Class 5 Maths are available for free download in PDF format.

Detailed Chapter 04 Measurements TN Board Solutions for Class 5 Maths

For Class 5 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 04 Measurements solutions will improve your exam performance.

Class 5 Maths Chapter 04 Measurements TN Board Solutions PDF

Let Us Recall (Text Book Page No.24)

 

Question 1. 10 milligram = ______ centigram
Answer: 10 milligrams is equal to 1 centigram. This conversion shows how smaller units of mass relate to slightly larger ones.
In simple words: Ten milligrams make up one centigram.

๐ŸŽฏ Exam Tip: Remember the prefixes: milli- means one-thousandth, and centi- means one-hundredth. This helps in understanding conversions.

 

Question 2. 10 centigram = ______ decigram
Answer: 10 centigrams is equivalent to 1 decigram. It takes ten centigrams to form one decigram.
In simple words: Ten centigrams are the same as one decigram.

๐ŸŽฏ Exam Tip: Practice writing out the full chain of metric prefixes (milli, centi, deci, base unit, deca, hecto, kilo) to recall the order and relationships.

 

Question 3. 10 decigram = ______ gram
Answer: 10 decigrams combine to make 1 gram. The gram is a fundamental unit for measuring mass in the metric system.
In simple words: One gram is made of ten decigrams.

๐ŸŽฏ Exam Tip: Base units like gram (g), meter (m), and liter (L) are important reference points in the metric system.

 

Question 4. 10 gram = ______ decagram
Answer: 10 grams equals 1 decagram. A decagram is a unit that is ten times larger than a gram.
In simple words: Ten grams form one decagram.

๐ŸŽฏ Exam Tip: Notice the pattern: multiplying by ten or dividing by ten is common for metric unit conversions.

 

Question 5. 10 decagram = ______ hectagram
Answer: 10 decagrams are equal to 1 hectagram. Hectagrams are larger units of mass, often used for slightly bigger measurements than decagrams.
In simple words: One hectagram is made from ten decagrams.

๐ŸŽฏ Exam Tip: Remember that "hecto-" means 100, so a hectagram is 100 grams, which is \( 10 \times 10 \) grams.

 

Question 6. 10 hectagram = ______ kilogram
Answer: 10 hectagrams make 1 kilogram. Kilograms are very common for weighing everyday objects. For instance, a bag of sugar might weigh a kilogram.
In simple words: Ten hectagrams are equal to one kilogram.

๐ŸŽฏ Exam Tip: The kilogram is the international base unit of mass and is often abbreviated as 'kg'.

Activity (TextBook Page No. 24 & 25)

 

Question. Tick the suitable unit to measure the following objects
Answer: Here are the suitable units for measuring the given objects:

  • Gold Earrings: milligrams (mg)
  • Okra: milligrams (mg)
  • Moringa Fruit: milligrams (mg)
  • Necklace: milligrams (mg)
  • Gold Rings: milligrams (mg)
  • Rice: kilograms (kg)
  • Green Gram (Moong Dal): kilograms (kg)
  • Spring Onion: kilograms (kg)
  • Grapes: kilograms (kg)
  • Red Beans: kilograms (kg)
These units are chosen based on the typical mass of each object, from very light (mg) to heavier (kg) items.
In simple words: Use milligrams for very light things like jewelry or single small vegetables. Use kilograms for heavier things like bags of rice or fruits.

๐ŸŽฏ Exam Tip: Always consider the actual size and weight of the object in real life when deciding which unit of measurement is most appropriate.

Try These (TextBook Page No. 24 & 25)

Convert into grams

 

Question 1. 2250 mg
Answer: To convert milligrams (mg) to grams (g), we divide by 1000, since 1 gram equals 1000 milligrams.
\( 2250 \text{ mg} = 2250 \div 1000 \text{ g} \)
\( 2250 \text{ mg} = 2 \text{ g } 250 \text{ mg} \) This means 2250 milligrams is 2 grams and 250 milligrams remaining.
In simple words: Since 1000 milligrams make 1 gram, 2250 milligrams is 2 grams and 250 milligrams left over.

๐ŸŽฏ Exam Tip: When converting a smaller unit to a larger unit, you always divide. When converting a larger unit to a smaller unit, you multiply.

 

Question 2. 5 kg 400 g
Answer: To convert kilograms (kg) to grams (g), we multiply by 1000, since 1 kilogram equals 1000 grams.
\( 5 \text{ kg } 400 \text{ g} = (5 \times 1000) \text{ g} + 400 \text{ g} \)
\( = 5000 \text{ g} + 400 \text{ g} \)
\( = 5400 \text{ g} \) So, 5 kg 400 g is a total of 5400 grams. Knowing these conversions helps in cooking or scientific measurements.
In simple words: To change kilograms to grams, multiply the kilograms by 1000 and then add any extra grams. So, 5 kg 400 g becomes 5400 grams in total.

๐ŸŽฏ Exam Tip: Always remember that "kilo" means 1000, which simplifies many metric conversions.

Try These (TextBook Page No. 26)

Convert into kilogram

 

Question 1. 4000 gram
Answer: To convert grams (g) to kilograms (kg), we divide by 1000, because 1000 grams make 1 kilogram.
\( 4000 \text{ g} = 4000 \div 1000 \text{ kg} \)
\( = 4 \text{ kg} \) Thus, 4000 grams is exactly 4 kilograms. This is a straightforward conversion for a common household weight.
In simple words: Since 1000 grams is 1 kilogram, 4000 grams is simply 4 kilograms.

๐ŸŽฏ Exam Tip: Divisions by 10, 100, or 1000 can often be done quickly by shifting the decimal point to the left.

 

Question 2. 7350 gram
Answer: To change grams (g) into kilograms (kg), we divide the number of grams by 1000.
\( 7350 \text{ g} = 7350 \div 1000 \text{ kg} \)
\( = 7 \text{ kg } 350 \text{ g} \) This means 7350 grams is 7 kilograms and 350 grams. This conversion helps when expressing weights of items like groceries.
In simple words: Divide 7350 grams by 1000 to get kilograms. It is 7 kilograms and 350 grams left over.

๐ŸŽฏ Exam Tip: When dividing by 1000, the last three digits of the number represent the remaining grams, and the digits before them represent the kilograms.

 

Question 3. 4750 gram
Answer: To convert grams (g) to kilograms (kg), we need to divide the total grams by 1000.
\( 4750 \text{ g} = 4750 \div 1000 \text{ kg} \)
\( = 4 \text{ kg } 750 \text{ g} \) So, 4750 grams is equivalent to 4 kilograms and 750 grams. This is similar to thinking about currency, where 1000 cents make a dollar.
In simple words: Since 1000 grams makes 1 kilogram, 4750 grams is 4 kilograms and 750 grams remaining.

๐ŸŽฏ Exam Tip: A simple way to visualize this is that the number of thousands in grams becomes kilograms, and the rest are remaining grams.

Try These (TextBook Page No. 27)

Find the sum of the following

 

Question 1. 5 kg 300g + 19 kg 850 g
Answer: To find the sum, we add kilograms and grams separately, carrying over if necessary.

Kgg
\( (1) \)\( (1) \)
5300
\( (+) 19 \)850
25150
First, add the grams: \( 300 \text{ g} + 850 \text{ g} = 1150 \text{ g} \). Since 1000 g makes 1 kg, \( 1150 \text{ g} \) is \( 1 \text{ kg } 150 \text{ g} \). Carry over the 1 kg to the kilograms column. Next, add the kilograms, including the carried over 1 kg: \( 1 \text{ kg} + 5 \text{ kg} + 19 \text{ kg} = 25 \text{ kg} \). So, the total sum is 25 kg 150 g. This structured addition helps prevent errors when dealing with mixed units.
In simple words: Add grams first. If you get more than 1000 grams, turn 1000 grams into 1 kilogram and add it to the kilograms. Then add the kilograms. The total is 25 kg 150 g.

๐ŸŽฏ Exam Tip: Always add the smaller units (grams, milliliters) first. If their sum is greater than the conversion factor (e.g., 1000), carry over the appropriate whole number to the larger unit.

 

Question 2. 15 g 450 mg + 14 g 25 mg + 3 g 700 mg
Answer: We add milligrams and grams separately, carrying over from milligrams to grams when the sum exceeds 1000.

gmg
\( (1) \)\( (1) \)
15450
14025
\( (+) 3 \)700
33175
First, add the milligrams: \( 450 \text{ mg} + 25 \text{ mg} + 700 \text{ mg} = 1175 \text{ mg} \). Since 1000 mg makes 1 g, \( 1175 \text{ mg} \) is \( 1 \text{ g } 175 \text{ mg} \). Carry over the 1 g to the grams column. Next, add the grams, including the carried over 1 g: \( 1 \text{ g} + 15 \text{ g} + 14 \text{ g} + 3 \text{ g} = 33 \text{ g} \). Therefore, the total sum is 33 g 175 mg. This method keeps the calculation clear and accurate.
In simple words: Add all milligrams first. If the sum is more than 1000, carry 1 gram for every 1000 milligrams. Then add all the grams. The final answer is 33 g 175 mg.

๐ŸŽฏ Exam Tip: When writing sums, ensure milligrams (or any smaller unit) are aligned correctly, and use leading zeros (e.g., 025 mg) if necessary for consistency.

 

Question 3. 18 kg 750 g + 16 kg 400g + 3 kg 500g.
Answer: To find the sum, we add kilograms and grams separately.

kgg
\( (1) \)\( (1) \)
18750
16400
\( (+) 3 \)500
38650
First, add the grams: \( 750 \text{ g} + 400 \text{ g} + 500 \text{ g} = 1650 \text{ g} \). Since 1000 g makes 1 kg, \( 1650 \text{ g} \) is \( 1 \text{ kg } 650 \text{ g} \). Carry over the 1 kg to the kilograms column. Next, add the kilograms, including the carried over 1 kg: \( 1 \text{ kg} + 18 \text{ kg} + 16 \text{ kg} + 3 \text{ kg} = 38 \text{ kg} \). So, the total sum is 38 kg 650 g. This method is essential for keeping track of different units of measurement during addition.
In simple words: First, add all the grams. If the total grams are more than 1000, convert 1000 grams to 1 kilogram and carry it over. Then add all the kilograms, including any carried over ones. The answer is 38 kg 650 g.

๐ŸŽฏ Exam Tip: Always make sure to write down the carried-over values clearly above the next column to avoid calculation errors.

Try This (TextBook Page No. 28)

Subtract the following

 

Question a. 75 kg - 35 kg 400 g
Answer: To subtract, we arrange the numbers vertically and subtract grams from grams and kilograms from kilograms, borrowing when needed.

Kgg
\( (6)(14) \)\( (10) \)
75000
\( (-) 35 \)400
39600
We need to subtract 400 g from 0 g. So, we borrow 1 kg (which is 1000 g) from 75 kg, making it 74 kg. The grams become 1000 g. Now, subtract the grams: \( 1000 \text{ g} - 400 \text{ g} = 600 \text{ g} \). Then, subtract the kilograms: \( 74 \text{ kg} - 35 \text{ kg} = 39 \text{ kg} \). The difference is 39 kg 600 g. Borrowing from larger units is a key skill in these calculations.
In simple words: You cannot take 400 grams from 0 grams, so you borrow 1 kilogram (which is 1000 grams) from the 75 kilograms. Then you subtract the grams, and then subtract the kilograms. The answer is 39 kg 600 g.

๐ŸŽฏ Exam Tip: When borrowing from the larger unit, convert the borrowed unit into the equivalent amount of the smaller unit (e.g., 1 kg becomes 1000 g).

 

Question b. 57 kg 750 g - 23 kg 450 g
Answer: To find the difference, we subtract grams from grams and kilograms from kilograms.

Kgg
57750
\( (-) 23 \)450
34300
First, subtract the grams: \( 750 \text{ g} - 450 \text{ g} = 300 \text{ g} \). Next, subtract the kilograms: \( 57 \text{ kg} - 23 \text{ kg} = 34 \text{ kg} \). So, the difference is 34 kg 300 g. This subtraction is straightforward as no borrowing is required.
In simple words: Subtract the grams first, then subtract the kilograms. The result is 34 kg 300 g.

๐ŸŽฏ Exam Tip: Always align the units vertically when adding or subtracting to keep your calculations neat and accurate.

 

Question c. 975 kg 400 g - 755 kg 550 g
Answer: To subtract, we align the kilograms and grams. Since 400 g is smaller than 550 g, we need to borrow.

kgg
\( (6)(4) \)\( (13)(10) \)
975400
\( (-) 755 \)550
219850
First, we cannot subtract 550 g from 400 g. So, we borrow 1 kg (which is 1000 g) from 975 kg, making it 974 kg. The grams become \( 400 \text{ g} + 1000 \text{ g} = 1400 \text{ g} \). Now, subtract the grams: \( 1400 \text{ g} - 550 \text{ g} = 850 \text{ g} \). Next, subtract the kilograms: \( 974 \text{ kg} - 755 \text{ kg} = 219 \text{ kg} \). The final difference is 219 kg 850 g. Borrowing ensures the calculation stays correct even when the smaller unit in the top number is insufficient.
In simple words: Since you can't subtract 550 grams from 400 grams, borrow 1 kilogram (1000 grams) from the kilograms. Add the borrowed grams to the 400 grams. Then subtract the grams, and finally subtract the kilograms. The answer is 219 kg 850 g.

๐ŸŽฏ Exam Tip: Always double-check your borrowing and subtraction, especially when multiple units are involved, to ensure accuracy.

Try These (TextBook Page No. 29)

Multiply the following:

 

Question a. 7 kg 350 g ร— 7
Answer: We multiply grams and kilograms separately, then convert any excess grams into kilograms and add them to the kilogram column.

kgg
350
\( \times \)7
51450
First, multiply the grams: \( 350 \text{ g} \times 7 = 2450 \text{ g} \). Convert 2450 g to kilograms: \( 2450 \text{ g} = 2 \text{ kg } 450 \text{ g} \). Keep 450 g and carry over 2 kg. Next, multiply the kilograms: \( 7 \text{ kg} \times 7 = 49 \text{ kg} \). Add the carried over kilograms: \( 49 \text{ kg} + 2 \text{ kg} = 51 \text{ kg} \). So, the total is 51 kg 450 g. This method is effective for multiplying mixed units.
In simple words: Multiply grams by 7. Change any 1000 grams into 1 kilogram and carry it over. Then multiply kilograms by 7 and add any carried-over kilograms. The answer is 51 kg 450 g.

๐ŸŽฏ Exam Tip: Always convert the smaller unit (grams) to the larger unit (kilograms) *before* adding it to the kilogram column to avoid errors.

 

Question b. 9 kg 750 g ร— 3
Answer: We multiply grams and kilograms separately, making sure to carry over grams to kilograms as needed.

kgg
9750
\( \times \)3
29250
First, multiply the grams: \( 750 \text{ g} \times 3 = 2250 \text{ g} \). Convert 2250 g to kilograms: \( 2250 \text{ g} = 2 \text{ kg } 250 \text{ g} \). Keep 250 g and carry over 2 kg. Next, multiply the kilograms: \( 9 \text{ kg} \times 3 = 27 \text{ kg} \). Add the carried over kilograms: \( 27 \text{ kg} + 2 \text{ kg} = 29 \text{ kg} \). So, the final product is 29 kg 250 g. This multiplication shows how quantities increase while maintaining proper unit conversion.
In simple words: Multiply the grams by 3. If you get more than 1000 grams, change it to kilograms and add to the kilogram count. Then multiply the kilograms by 3 and add the carried-over kilograms. The answer is 29 kg 250 g.

๐ŸŽฏ Exam Tip: Performing the multiplication of the smaller unit first helps manage any carry-overs into the larger unit efficiently.

 

Question c. 45 kg 800 g ร— 6
Answer: We multiply the grams and kilograms separately, carrying over as required.

kgg
45800
\( \times \)6
274800
First, multiply the grams: \( 800 \text{ g} \times 6 = 4800 \text{ g} \). Convert 4800 g to kilograms: \( 4800 \text{ g} = 4 \text{ kg } 800 \text{ g} \). Keep 800 g and carry over 4 kg. Next, multiply the kilograms: \( 45 \text{ kg} \times 6 = 270 \text{ kg} \). Add the carried over kilograms: \( 270 \text{ kg} + 4 \text{ kg} = 274 \text{ kg} \). So, the total product is 274 kg 800 g. Understanding these multi-unit operations is crucial for real-world applications.
In simple words: Multiply grams by 6. Convert any 1000 grams into 1 kilogram and add to the kilogram total. Then multiply kilograms by 6 and add any carried-over kilograms. The answer is 274 kg 800 g.

๐ŸŽฏ Exam Tip: Always write down the steps of multiplication clearly to minimize arithmetic errors and make the process easy to follow.

Try This (TextBook Page No. 29)

Divide the following:

 

Question a. 7 kg 490 g รท 7
Answer: To divide mixed units, we divide the larger unit first, then convert any remainder to the smaller unit and add it to the existing smaller unit, then divide.
Divide kilograms: \( 7 \text{ kg} \div 7 = 1 \text{ kg} \).
The remainder for kg is 0. So, we have 0 kg to carry over to grams.
Now, divide grams: \( 490 \text{ g} \div 7 = 70 \text{ g} \).
Therefore, \( 7 \text{ kg } 490 \text{ g} \div 7 = 1 \text{ kg } 70 \text{ g} \). This calculation is common when sharing items equally.
In simple words: First, divide the kilograms by 7. Then divide the grams by 7. Put them together for the final answer, which is 1 kg 70 g.

๐ŸŽฏ Exam Tip: When dividing mixed units, if the larger unit has a remainder, convert it into the smaller unit and add it to the smaller unit amount before dividing the smaller unit.

 

Question b. 35 kg 650 g รท 5
Answer: We divide the kilograms first. Any remainder from the kilograms is converted to grams and added to the existing grams before dividing that total.
Divide kilograms: \( 35 \text{ kg} \div 5 = 7 \text{ kg} \).
The remainder for kg is 0. So, we have 0 kg to carry over to grams.
Now, divide grams: \( 650 \text{ g} \div 5 \).
\( 6 \div 5 = 1 \) remainder \( 1 \). Bring down 5, making it 15.
\( 15 \div 5 = 3 \). Bring down 0, making it 0.
\( 0 \div 5 = 0 \).
So, \( 650 \text{ g} \div 5 = 130 \text{ g} \).
Therefore, \( 35 \text{ kg } 650 \text{ g} \div 5 = 7 \text{ kg } 130 \text{ g} \). This process ensures all parts of the measurement are divided correctly.
In simple words: Divide the kilograms by 5 first. Then divide the grams by 5. Combine these results to get 7 kg 130 g.

๐ŸŽฏ Exam Tip: Always perform division systematically, starting from the largest unit and moving to the smallest, handling remainders carefully.

 

Question c. 6 g 240 mg รท 4
Answer: We divide grams by 4. If there's a remainder, we convert it to milligrams and add it to the existing milligrams before dividing.
Divide grams: \( 6 \text{ g} \div 4 = 1 \text{ g} \) with a remainder of 2 g.
Convert the remainder 2 g to milligrams: \( 2 \text{ g} = 2 \times 1000 \text{ mg} = 2000 \text{ mg} \).
Add this to the existing milligrams: \( 2000 \text{ mg} + 240 \text{ mg} = 2240 \text{ mg} \).
Now, divide the total milligrams: \( 2240 \text{ mg} \div 4 \).
\( 22 \div 4 = 5 \) remainder 2. Bring down 4, making it 24.
\( 24 \div 4 = 6 \). Bring down 0, making it 0.
\( 0 \div 4 = 0 \).
So, \( 2240 \text{ mg} \div 4 = 560 \text{ mg} \).
Therefore, \( 6 \text{ g } 240 \text{ mg} \div 4 = 1 \text{ g } 560 \text{ mg} \). This detailed approach is necessary for accurate calculations.
In simple words: Divide 6 grams by 4, which is 1 gram with 2 grams left. Change these 2 grams to 2000 milligrams. Add them to 240 milligrams, making 2240 milligrams. Divide 2240 milligrams by 4, which is 560 milligrams. So the answer is 1 g 560 mg.

๐ŸŽฏ Exam Tip: When dividing, if the remainder from the larger unit is not zero, always convert it to the smaller unit and combine it before the next division step.

 

Question d. 150 g 750 mg รท 15
Answer: We divide grams by 15. If there's a remainder, we convert it to milligrams and add to the existing milligrams, then divide that sum.
Divide grams: \( 150 \text{ g} \div 15 = 10 \text{ g} \).
The remainder for grams is 0. So, we have 0 g to carry over to milligrams.
Now, divide milligrams: \( 750 \text{ mg} \div 15 \).
\( 75 \div 15 = 5 \). Bring down 0, making it 0.
\( 0 \div 15 = 0 \).
So, \( 750 \text{ mg} \div 15 = 50 \text{ mg} \).
Therefore, \( 150 \text{ g } 750 \text{ mg} \div 15 = 10 \text{ g } 50 \text{ mg} \). This type of division is useful in chemistry or pharmacy when precise measurements are needed.
In simple words: First, divide the grams (150 g) by 15, which is 10 grams. Then, divide the milligrams (750 mg) by 15, which is 50 milligrams. Put these together to get 10 g 50 mg.

๐ŸŽฏ Exam Tip: For divisions with no remainder in the larger unit, the process is simpler, as you just divide each unit separately.

Try This (TextBook Page No. 34)

Convert into millilitre:

 

Question a. 5 l 500 ml
Answer: To convert liters (l) to milliliters (ml), we multiply by 1000, since 1 liter equals 1000 milliliters.
\( 5 \text{ l } 500 \text{ ml} = (5 \times 1000) \text{ ml} + 500 \text{ ml} \)
\( = 5000 \text{ ml} + 500 \text{ ml} \)
\( = 5500 \text{ ml} \) So, 5 liters and 500 milliliters is a total of 5500 milliliters. This conversion is often used in recipes or medical dosages.
In simple words: To change liters to milliliters, multiply liters by 1000 and add the extra milliliters. So, 5 liters 500 ml becomes 5500 ml.

๐ŸŽฏ Exam Tip: Remember that "milli" always means one-thousandth, so 1 liter is 1000 milliliters, and 1 meter is 1000 millimeters.

 

Question b. 9 l 200 ml
Answer: To convert liters (l) to milliliters (ml), we multiply the number of liters by 1000 and then add any extra milliliters.
\( 9 \text{ l } 200 \text{ ml} = (9 \times 1000) \text{ ml} + 200 \text{ ml} \)
\( = 9000 \text{ ml} + 200 \text{ ml} \)
\( = 9200 \text{ ml} \) Therefore, 9 liters and 200 milliliters is equivalent to 9200 milliliters. This method ensures accuracy when converting between units.
In simple words: To convert to milliliters, multiply the liters by 1000, then add the existing milliliters. So, 9 liters 200 ml becomes 9200 ml.

๐ŸŽฏ Exam Tip: Clearly show the multiplication and addition steps for full marks, even if you can do mental math.

 

Question c. 2 l 300 ml
Answer: To convert liters (l) to milliliters (ml), we multiply the liters by 1000 and add the given milliliters.
\( 2 \text{ l } 300 \text{ ml} = (2 \times 1000) \text{ ml} + 300 \text{ ml} \)
\( = 2000 \text{ ml} + 300 \text{ ml} \)
\( = 2300 \text{ ml} \) Thus, 2 liters and 300 milliliters equals 2300 milliliters. Knowing these conversions is practical for daily life.
In simple words: Multiply 2 liters by 1000 to get 2000 milliliters, then add 300 milliliters. The total is 2300 milliliters.

๐ŸŽฏ Exam Tip: Always pay attention to the base unit (e.g., liter) and the prefix (e.g., milli-) to ensure you are multiplying or dividing by the correct factor.

Activity (TextBook Page No. 34)

 

Question. Complete the following table by converting Litre to Millilitre.
Answer: Here is the completed table showing the conversion from Litre to Millilitre:

LitreMillilitre
1 l1000 ml
2 l2000 ml
3 l3000 ml
4 l4000 ml
5 l 300 ml5300 ml
6 l6000 ml
7 l7000 ml
8 l 400 ml8400 ml
9 l9000 ml
10 l 200 ml10200 ml
To convert liters to milliliters, multiply the number of liters by 1000. If there are additional milliliters, add them to the result. This table illustrates the direct relationship between liters and milliliters, a common conversion in volume measurements.
In simple words: To fill in the table, multiply the liters by 1000 to get milliliters. If there are extra milliliters, add them. For example, 1 liter is 1000 ml, and 5 liters 300 ml is 5300 ml.

๐ŸŽฏ Exam Tip: Memorizing that 1 liter = 1000 milliliters is fundamental for all liquid volume conversions.

Try These (TextBook Page No. 35)

 

Question 1. 4 l 300 ml + 6 l 700 ml
Answer: We add milliliters and liters separately, carrying over any excess milliliters to the liters column.

lml
\( (1) \)
4300
\( (+) 6 \)700
11000
First, add the milliliters: \( 300 \text{ ml} + 700 \text{ ml} = 1000 \text{ ml} \). Since 1000 ml makes 1 l, \( 1000 \text{ ml} \) is \( 1 \text{ l } 0 \text{ ml} \). Carry over the 1 l to the liters column. Next, add the liters, including the carried over 1 l: \( 1 \text{ l} + 4 \text{ l} + 6 \text{ l} = 11 \text{ l} \). So, the total sum is 11 l 0 ml, which is simply 11 liters. This calculation is straightforward when the milliliters sum up to a whole liter.
In simple words: Add the milliliters first. 300 ml plus 700 ml is 1000 ml, which is 1 liter. Carry this 1 liter. Then add 4 liters plus 6 liters plus the carried 1 liter, which makes 11 liters. The total is 11 liters.

๐ŸŽฏ Exam Tip: When milliliters add up to exactly 1000, remember to carry over 1 liter and record 000 ml in the milliliters column.

 

Question 2. 7 l 250 ml + 2 l 300 ml
Answer: We add the milliliters and liters separately.

lml
7250
\( (+) 2 \)300
9550
First, add the milliliters: \( 250 \text{ ml} + 300 \text{ ml} = 550 \text{ ml} \). Since 550 ml is less than 1000 ml, there is no carry-over to the liters. Next, add the liters: \( 7 \text{ l} + 2 \text{ l} = 9 \text{ l} \). So, the total sum is 9 l 550 ml. This is a simple addition problem where no borrowing or carrying over is needed.
In simple words: Add the milliliters (250 + 300 = 550 ml). Then add the liters (7 + 2 = 9 l). The answer is 9 l 550 ml.

๐ŸŽฏ Exam Tip: For simple additions like this, you can directly add the units if there are no carry-overs to manage.

 

Question 3. 5 l 500 ml - 4 l 450 ml
Answer: We subtract milliliters from milliliters and liters from liters.
First, subtract the milliliters: \( 500 \text{ ml} - 450 \text{ ml} = 50 \text{ ml} \).
Next, subtract the liters: \( 5 \text{ l} - 4 \text{ l} = 1 \text{ l} \).
So, the difference is 1 l 50 ml. This is a straightforward subtraction since 500 ml is greater than 450 ml, avoiding the need for borrowing.
In simple words: Subtract 450 ml from 500 ml to get 50 ml. Then subtract 4 liters from 5 liters to get 1 liter. The answer is 1 l 50 ml.

๐ŸŽฏ Exam Tip: Always subtract the smaller units first. If the top number's smaller unit is less than the bottom number's, you'll need to borrow from the larger unit.

 

Question 4. 46 l 300 ml - 12 l 550 ml
Answer: To subtract these mixed units, we need to borrow from liters because 300 ml is less than 550 ml.

lml
\( (5) \)\( (12)(10) \)
46300
\( (-)12 \)550
33750
First, since 300 ml is smaller than 550 ml, we borrow 1 liter (which is 1000 ml) from 46 liters, making it 45 liters. The milliliters become \( 300 \text{ ml} + 1000 \text{ ml} = 1300 \text{ ml} \). Now, subtract the milliliters: \( 1300 \text{ ml} - 550 \text{ ml} = 750 \text{ ml} \). Next, subtract the liters: \( 45 \text{ l} - 12 \text{ l} = 33 \text{ l} \). The final difference is 33 l 750 ml. This shows how borrowing works with liquid measurements.
In simple words: You can't take 550 ml from 300 ml, so you borrow 1 liter (1000 ml) from the 46 liters, making it 45 liters. Add the borrowed 1000 ml to 300 ml to get 1300 ml. Subtract the milliliters, then subtract the liters. The answer is 33 l 750 ml.

๐ŸŽฏ Exam Tip: Clearly cross out the original numbers and write the new borrowed values above them to keep track during subtraction.

Try These (TextBook Page No. 37)

Multiply the following:

 

Question 1. 2 l 250 ml x 2
Answer: We multiply the milliliters and liters separately, handling any carry-overs from milliliters to liters.

lml
2250
\( \times \)2
4500
First, multiply the milliliters: \( 250 \text{ ml} \times 2 = 500 \text{ ml} \). Since 500 ml is less than 1000 ml, there is no carry-over to the liters. Next, multiply the liters: \( 2 \text{ l} \times 2 = 4 \text{ l} \). So, the final product is 4 l 500 ml. This simple multiplication demonstrates how quantities of liquid are doubled.
In simple words: Multiply 250 ml by 2 to get 500 ml. Then multiply 2 liters by 2 to get 4 liters. The total is 4 l 500 ml.

๐ŸŽฏ Exam Tip: When multiplying mixed units, ensure you multiply each unit separately and convert any overflow from the smaller unit to the larger unit before combining.

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TN Board Solutions Class 5 Maths Chapter 04 Measurements

Students can now access the TN Board Solutions for Chapter 04 Measurements prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.

Detailed Explanations for Chapter 04 Measurements

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.

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Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 04 Measurements to get a complete preparation experience.

FAQs

Where can I find the latest Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions for the 2026-27 session?

The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.

Are the Maths TN Board solutions for Class 5 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.

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Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions will help students to get full marks in the theory paper.

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Yes, we provide bilingual support for Class 5 Maths. You can access Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions in both English and Hindi medium.

Is it possible to download the Maths TN Board solutions for Class 5 as a PDF?

Yes, you can download the entire Samacheer Kalvi Class 5 Maths Solutions Term 2 Chapter 4 Measurements InText Questions in printable PDF format for offline study on any device.