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Detailed Chapter 04 Measurements TN Board Solutions for Class 5 Maths
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Class 5 Maths Chapter 04 Measurements TN Board Solutions PDF
Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 1 Chapter 4 Measurements Ex 4
Question 1. Fill in the blanks.
a. 7m 5cm = _______ cm
Answer:
\( 7m \, 5cm = 7 \times 100 \, cm + 5 \, cm = 700 \, cm + 5 \, cm = 705 \, cm \)
So, 7m 5cm = 705 cm.
In simple words: To change meters to centimeters, multiply the meter value by 100. Then, add any extra centimeters.
๐ฏ Exam Tip: Remember that 1 meter is equal to 100 centimeters, which is key for such conversions.
b. 505 mm = _______ cm _______ mm
Answer:
\( 505 \, mm = 505 \div 10 \, cm = 50 \, cm \, 5 \, mm \)
So, 505 mm = 50 cm 5 mm.
In simple words: To change millimeters to centimeters, divide the millimeter value by 10. The remainder will be in millimeters.
๐ฏ Exam Tip: Keep in mind that 1 centimeter is equal to 10 millimeters when converting units.
c. 326m = _______ cm
Answer:
\( 326 \, m = 326 \times 100 \, cm = 32600 \, cm \)
So, 326m = 32600 cm.
In simple words: When converting meters to centimeters, simply multiply the meter value by 100. Each meter has 100 centimeters.
๐ฏ Exam Tip: A quick way to convert meters to centimeters is to add two zeros to the meter value.
d. 5km 30m = _______ m
Answer:
\( 5 \, km \, 30 \, m = 5 \times 1000 \, m + 30 \, m = 5000 \, m + 30 \, m = 5030 \, m \)
So, 5km 30m = 5030 m.
In simple words: To convert kilometers to meters, multiply by 1000. Then, add any remaining meters to get the total in meters.
๐ฏ Exam Tip: Remember that 1 kilometer is equal to 1000 meters, which is essential for these conversions.
e. 650cm: _______ m _______ cm
Answer:
\( 650 \, cm = 650 \div 100 \, m = 6 \, m \, 50 \, cm \)
So, 650cm = 6 m 50 cm.
In simple words: To change centimeters to meters, divide by 100. The whole number part is meters, and the remainder is centimeters.
๐ฏ Exam Tip: Understanding that 100 centimeters make 1 meter helps in quickly converting between these units.
Question 2. True or false.
a) 600 m is 6mm.
Answer: False.
In simple words: 600 meters is a very long distance, much longer than 6 millimeters. One meter has 1000 millimeters, so 600 meters would be 600,000 millimeters.
๐ฏ Exam Tip: Always think about the size difference between units to catch false statements quickly.
b) 7000 m is 7 km.
Answer: True.
In simple words: Since 1000 meters make 1 kilometer, 7000 meters is exactly the same as 7 kilometers. This is a correct conversion.
๐ฏ Exam Tip: Knowing the basic conversion factors like 1 km = 1000 m is vital for true/false questions.
c) 400 cm is 4 km.
Answer: False.
In simple words: 400 centimeters is equal to 4 meters, not 4 kilometers. A kilometer is much, much longer than a meter.
๐ฏ Exam Tip: Be careful with conversions involving large differences in unit magnitude, like centimeters to kilometers.
d) 770 mm is 77 cm.
Answer: True.
In simple words: Because 10 millimeters make 1 centimeter, dividing 770 millimeters by 10 gives 77 centimeters. The statement is correct.
๐ฏ Exam Tip: Remember the relationship: to convert mm to cm, divide by 10; to convert cm to mm, multiply by 10.
e) 9000m is 90 mm.
Answer: False.
In simple words: 9000 meters is a very long distance. To convert meters to millimeters, you multiply by 1000, so 9000 meters is 9,000,000 millimeters, not 90 millimeters.
๐ฏ Exam Tip: Always convert to the same base unit (like meters) before comparing or stating equivalences.
Question 3. Find the sum of the following
a. 17 m 45 cm + 52 m 30 cm
Answer:
First, add the centimeter parts: \( 45 \, cm + 30 \, cm = 75 \, cm \).
Next, add the meter parts: \( 17 \, m + 52 \, m = 69 \, m \).
So, the sum is 69 m 75 cm.
| m | cm |
|---|---|
| 17 | 45 |
| 52 | 30 |
| --- | --- |
| 69 | 75 |
In simple words: To add measurements with different units, add the same units separately. Meters with meters and centimeters with centimeters.
๐ฏ Exam Tip: When adding mixed units, always align the units properly and add them column by column, starting from the smallest unit.
b. 75 km 400 m + 37 km 300 m + 52 km 750 m
Answer:
First, add all the meter parts:
\( 400 \, m + 300 \, m + 750 \, m = 1450 \, m \).
We know that \( 1000 \, m = 1 \, km \), so \( 1450 \, m = 1 \, km \, 450 \, m \).
Carry over the 1 km to the kilometer column.
Next, add all the kilometer parts, including the carried over 1 km:
\( 75 \, km + 37 \, km + 52 \, km + 1 \, km = 165 \, km \).
So, the total sum is 165 km 450 m.
| km | m |
|---|---|
| 1 (carry) | |
| 75 | 400 |
| 37 | 300 |
| 52 | 750 |
| --- | --- |
| 165 | 450 |
In simple words: Add the meters first. If the sum is 1000 meters or more, convert it to kilometers and carry that over. Then add the kilometers, including any carried-over amounts.
๐ฏ Exam Tip: Always perform unit conversions (like m to km) before adding the larger units, carrying over any excess to the next column.
c. 4 cm 8 mm + 5 cm 9 mm
Answer:
First, add the millimeter parts: \( 8 \, mm + 9 \, mm = 17 \, mm \).
Since \( 10 \, mm = 1 \, cm \), \( 17 \, mm \) is \( 1 \, cm \, 7 \, mm \).
Carry over the 1 cm to the centimeter column.
Next, add the centimeter parts, including the carried over 1 cm:
\( 4 \, cm + 5 \, cm + 1 \, cm = 10 \, cm \).
So, the total sum is 10 cm 7 mm.
| cm | mm |
|---|---|
| 1 (carry) | |
| 4 | 8 |
| 5 | 9 |
| --- | --- |
| 10 | 7 |
In simple words: Add the millimeters first and convert any value over 10 mm into centimeters to carry over. Then add the centimeters, including the carry-over.
๐ฏ Exam Tip: When adding, always remember the conversion factor for the units (e.g., 10 mm = 1 cm) to correctly carry over values.
Question 4. Subtract the following
a. 15 km 450 m - 13 km 200 m.
Answer:
First, subtract the meter parts: \( 450 \, m - 200 \, m = 250 \, m \).
Next, subtract the kilometer parts: \( 15 \, km - 13 \, km = 2 \, km \).
So, the difference is 2 km 250 m.
| km | m |
|---|---|
| 15 | 450 |
| 13 | 200 |
| --- | --- |
| 2 | 250 |
In simple words: Subtract the smaller units first, then the larger units. Make sure to subtract from the corresponding unit.
๐ฏ Exam Tip: When subtracting mixed units, always start with the smallest unit column, borrowing from the larger unit if needed.
b. 750 m 840 mm โ 370m 480 mm.
Answer:
First, subtract the millimeter parts: \( 840 \, mm - 480 \, mm = 360 \, mm \).
Next, subtract the meter parts: \( 750 \, m - 370 \, m = 380 \, m \).
So, the difference is 380 m 360 mm.
| m | mm |
|---|---|
| 750 | 840 |
| 370 | 480 |
| --- | --- |
| 380 | 360 |
In simple words: Subtract the millimeters, then subtract the meters. Ensure you subtract numbers in the same unit column.
๐ฏ Exam Tip: If the smaller unit in the top number is less than the smaller unit in the bottom number, you'll need to borrow from the larger unit, remembering its conversion factor (e.g., 1 m = 1000 mm).
c. 5 km 400 m โ 3 km 350 m
Answer:
First, subtract the meter parts: \( 400 \, m - 350 \, m = 50 \, m \).
Next, subtract the kilometer parts: \( 5 \, km - 3 \, km = 2 \, km \).
So, the difference is 2 km 50 m.
| km | m |
|---|---|
| 5 | 400 |
| 3 | 350 |
| --- | --- |
| 2 | 50 |
In simple words: When subtracting, always handle the smaller unit (meters) first, then the larger unit (kilometers).
๐ฏ Exam Tip: Double-check your subtraction, especially when numbers are close, to avoid simple arithmetic errors.
Question 5. Multiply the following.
a. 350 m 45 cm ร 7
Answer:
First, multiply the centimeter part by 7:
\( 45 \, cm \times 7 = 315 \, cm \).
Convert 315 cm to meters and centimeters: \( 315 \, cm = 3 \, m \, 15 \, cm \).
Carry over the 3 m to the meter column.
Next, multiply the meter part by 7 and add the carried-over meters:
\( 350 \, m \times 7 = 2450 \, m \).
Add the carried over 3 m: \( 2450 \, m + 3 \, m = 2453 \, m \).
So, the total product is 2453 m 15 cm.
| m | cm |
|---|---|
| 350 | 45 |
| \( \times \) | 7 |
| --- | --- |
| 2453 | 15 |
In simple words: Multiply the smaller unit first. Convert any larger amount into the next unit and carry it over. Then multiply the larger unit and add what you carried over.
๐ฏ Exam Tip: When multiplying mixed units, carefully manage carry-overs from smaller units to larger units using the correct conversion factor.
b. 25 km 300 m ร 6
Answer:
First, multiply the meter part by 6:
\( 300 \, m \times 6 = 1800 \, m \).
Convert 1800 m to kilometers and meters: \( 1800 \, m = 1 \, km \, 800 \, m \).
Carry over the 1 km to the kilometer column.
Next, multiply the kilometer part by 6 and add the carried-over kilometers:
\( 25 \, km \times 6 = 150 \, km \).
Add the carried over 1 km: \( 150 \, km + 1 \, km = 151 \, km \).
So, the total product is 151 km 800 m.
| km | m |
|---|---|
| 25 | 300 |
| \( \times \) | 6 |
| --- | --- |
| 151 | 800 |
In simple words: Multiply the meters by the number, then convert any amount over 1000m to km and carry it. Then multiply the kilometers by the number and add the carried-over kilometers.
๐ฏ Exam Tip: Always remember that 1000 meters makes 1 kilometer when performing multiplication with carry-overs.
c. 37 m 350 mm ร 8
Answer:
First, multiply the millimeter part by 8:
\( 350 \, mm \times 8 = 2800 \, mm \).
Convert 2800 mm to meters and millimeters: \( 2800 \, mm = 2 \, m \, 800 \, mm \).
Carry over the 2 m to the meter column.
Next, multiply the meter part by 8 and add the carried-over meters:
\( 37 \, m \times 8 = 296 \, m \).
Add the carried over 2 m: \( 296 \, m + 2 \, m = 298 \, m \).
So, the total product is 298 m 800 mm.
| m | mm |
|---|---|
| 37 | 350 |
| \( \times \) | 8 |
| --- | --- |
| 298 | 800 |
In simple words: Multiply the millimeters first, converting any excess into meters and carrying it over. Then multiply the meters and add the carried-over meters.
๐ฏ Exam Tip: Remember that 1000 millimeters make 1 meter, which is vital for correctly managing carry-overs in multiplication.
Question 6. Divide the following
a. 950 km 800 m รท 5
Answer:
Divide the kilometer part by 5 first.
\( 950 \, km \div 5 = 190 \, km \). There is no remainder in kilometers.
Next, divide the meter part by 5.
\( 800 \, m \div 5 = 160 \, m \).
So, the result is 190 km 160 m.
| km | m | |
|---|---|---|
| 190 | 160 | |
| 5 | \( \overline{950} \) | \( \overline{800} \) |
| -5 | ||
| 45 | ||
| -45 | ||
| 0 | 8 | |
| -5 | ||
| 30 | ||
| -30 | ||
| 0 |
In simple words: Divide the kilometers part first, then the meters part. If there is a remainder from the kilometers, convert it to meters and add it to the existing meters before dividing.
๐ฏ Exam Tip: When dividing mixed units, always divide the larger unit first. If there's a remainder, convert it to the smaller unit and add it before dividing the smaller unit.
b. 49 m 770 mm รท 7
Answer:
Divide the meter part by 7 first.
\( 49 \, m \div 7 = 7 \, m \). There is no remainder in meters.
Next, divide the millimeter part by 7.
\( 770 \, mm \div 7 = 110 \, mm \).
So, the result is 7 m 110 mm.
| m | mm | |
|---|---|---|
| 7 | 110 | |
| 7 | \( \overline{49} \) | \( \overline{770} \) |
| -49 | ||
| 0 | 7 | |
| -7 | ||
| 0 |
In simple words: Divide the meters by the number. Then divide the millimeters by the same number. Combine the results.
๐ฏ Exam Tip: Ensure that all steps of the division are shown clearly, especially if there are remainders that need to be converted.
c. 172 m 48 cm รท 4
Answer:
Divide the meter part by 4 first.
\( 172 \, m \div 4 = 43 \, m \). There is no remainder in meters.
Next, divide the centimeter part by 4.
\( 48 \, cm \div 4 = 12 \, cm \).
So, the result is 43 m 12 cm.
| m | cm | |
|---|---|---|
| 43 | 12 | |
| 4 | \( \overline{172} \) | \( \overline{48} \) |
| -16 | ||
| 12 | ||
| -12 | ||
| 0 | 4 | |
| -4 | ||
| 08 | ||
| -8 | ||
| 0 |
In simple words: First, divide the meters by the given number. Then, divide the centimeters by the same number. Put the results together.
๐ฏ Exam Tip: Pay attention to remainders; if a remainder exists from the larger unit, convert it to the smaller unit before continuing the division.
Life Related Problems
Question 7. Answer the following:
a. Saravanan had chosen to drive his vehicle from Puducherry to Chennai for a distance of 165 Km. While starting his vehicle, the odometer showed 000157 Km. Find the reading of the odometer, when he reached Chennai?
Answer:
Distance from Puducherry to Chennai = 165 km
Odometer reading at the start = 000157 km
To find the reading upon reaching Chennai, we add the distance traveled to the starting reading:
Reading of odometer after reaching Chennai = Starting reading + Distance traveled
\( = 157 \, km + 165 \, km = 322 \, km \)
So, the odometer will show 000322 km when he reaches Chennai.
In simple words: To find the new odometer reading, add the distance traveled to the starting odometer reading.
๐ฏ Exam Tip: For odometer problems, remember to add the new distance to the previous reading to find the final reading.
b. Karthik Raja decided to travel from A. He moves 1 Km in east to reach B. Then he goes 2 Km towards north and reaches C. Then he goes 1 Km towards west and reaches D. If he goes 2 Km towards South, Where would he reach? Draw a suitable diagram and calculate the total distance travelled by him.
Answer:
Starting from A, Karthik travels:
1. A to B: 1 km (East)
2. B to C: 2 km (North)
3. C to D: 1 km (West)
4. D to A: 2 km (South)
After traveling 2 Km towards South from D, he would reach point A again.
Total Distance = Distance A-B + Distance B-C + Distance C-D + Distance D-A
Total Distance = \( 1 \, km + 2 \, km + 1 \, km + 2 \, km = 6 \, km \)
So, he would reach point A, and the total distance traveled is 6 km.
In simple words: Karthik travels in a square shape, returning to his starting point. To find the total distance, add up the length of each part of his journey.
๐ฏ Exam Tip: For directional travel problems, drawing a simple diagram helps visualize the path and calculate the total distance and final position accurately.
c. Sangeetha has just finished building a new house with garden area. She measured the garden area and found it to be 6m x 6m. Suppose she has to put a pole every 1m, how many poles are required? What should be the total length of the fencing material to fence the garden?
Answer:
The garden is a square with a side length of 6m.
The perimeter of the garden = \( 4 \times \text{Side} = 4 \times 6 \, m = 24 \, m \).
If a pole is required every 1m, then the number of poles needed is equal to the perimeter.
Number of poles required = \( 24 \div 1 = 24 \) poles.
The total length of the fencing material to fence the garden is given by multiplying the perimeter by a factor (likely height of the fence, in this case, 1.5):
Length of fencing material = Perimeter \( \times \) 1.5
\( = 24 \, m \times 1.5 = 36 \, m \)
So, 24 poles are required, and the total length of fencing material is 36 m.
In simple words: First, find the total length around the garden. This is how many poles are needed if they are 1 meter apart. Then, multiply this length by 1.5 to find the total fencing material needed.
๐ฏ Exam Tip: When calculating fencing, remember to find the perimeter first. If a height or multiple layers are implied, factor that into the total material needed.
d. One student needs 1 m 25 cm cloth to stitch a shirt. What is the total length of clothes need to stitch a class of 22 students?
Answer:
Cloth needed for one student = 1 m 25 cm
To find the total cloth needed for 22 students, we multiply the cloth per student by 22:
Total cloth needed for 22 students = \( 1 \, m \, 25 \, cm \times 22 \).
Convert 1 m 25 cm to centimeters: \( 1 \, m = 100 \, cm \), so \( 100 \, cm + 25 \, cm = 125 \, cm \).
Multiply 125 cm by 22:
\( 125 \, cm \times 22 = 2750 \, cm \).
Convert 2750 cm back to meters and centimeters:
\( 2750 \, cm = 27 \, m \, 50 \, cm \).
So, 27 m 50 cm of cloth is needed for 22 students.
In simple words: First, change the cloth needed for one student into only centimeters. Then multiply this total by the number of students. Finally, change the answer back to meters and centimeters.
๐ฏ Exam Tip: For multiplication with mixed units, convert everything to the smallest unit first, multiply, and then convert the result back to mixed units.
e. The distance from village A to village B is 3 km 450 m. The distance from village B to village C is 5 km 350 m. What will be the total length of the road, if the road is laid from village A to village C?
Answer:
Distance from village A to Village B = 3 km 450 m
Distance from village B to village C = 5 km 350 m
To find the total length of the road from A to C, we add these two distances:
Total distance from A to C = \( (3 \, km \, 450 \, m) + (5 \, km \, 350 \, m) \).
First, add the meter parts: \( 450 \, m + 350 \, m = 800 \, m \).
Next, add the kilometer parts: \( 3 \, km + 5 \, km = 8 \, km \).
So, the total length of the road from A to C is 8 km 800 m.
| km | m |
|---|---|
| 3 | 450 |
| 5 | 350 |
| --- | --- |
| 8 | 800 |
In simple words: To find the total length of the road, add the kilometer parts together and the meter parts together separately.
๐ฏ Exam Tip: For distance problems involving segments, simply add the lengths of each segment to find the total distance, ensuring units are aligned.
Free study material for Maths
TN Board Solutions Class 5 Maths Chapter 04 Measurements
Students can now access the TN Board Solutions for Chapter 04 Measurements prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.
Detailed Explanations for Chapter 04 Measurements
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