Get the most accurate TN Board Solutions for Class 5 Maths Chapter 02 Numbers here. Updated for the 2026-27 academic session, these solutions are based on the latest TN Board textbooks for Class 5 Maths. Our expert-created answers for Class 5 Maths are available for free download in PDF format.
Detailed Chapter 02 Numbers TN Board Solutions for Class 5 Maths
For Class 5 students, solving TN Board textbook questions is the most effective way to build a strong conceptual foundation. Our Class 5 Maths solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 02 Numbers solutions will improve your exam performance.
Class 5 Maths Chapter 02 Numbers TN Board Solutions PDF
Question 1. Answer the following questions:
a. A cement factory produces 37500 bags of cements in a month (30 days). How many cement bags were produced in one day?
Answer: Total number of cement bags produced in a month = 37500
Number of days in a month = 30
To find out how many bags are produced in one day, we divide the total bags by the number of days.
Number of cement bags produced per day = \( 37500 \div 30 \)
\[
\begin{array}{r}
1250 \\
30\overline{)37500} \\
-30\downarrow \\
\hline
75 \\
-60\downarrow \\
\hline
150 \\
-150\downarrow \\
\hline
00 \\
-00 \\
\hline
0
\end{array}
\]
So, 1250 bags of cement were produced in one day.
In simple words: The factory makes 37500 cement bags in 30 days. To find out daily production, divide the total bags by the number of days. This shows the average number of bags made each day.
🎯 Exam Tip: When a question asks for a "per day" or "per unit" amount from a total, it usually means division. Clearly show your division steps to score full marks.
b. 8075 mangoes were harvested from a mango garden. 95 mangoes are packed in each package. How many packages will be there?
Answer: Total number of mangoes harvested = 8075
Number of mangoes packed in one package = 95
To find the total number of packages, we divide the total mangoes by the number of mangoes in each package.
Total number of packages = \( 8075 \div 95 \)
\[
\begin{array}{r}
85 \\
95\overline{)8075} \\
-760\downarrow \\
\hline
475 \\
-475 \\
\hline
0
\end{array}
\]
So, there will be 85 packages.
In simple words: There are 8075 mangoes, and each pack holds 95 mangoes. Divide the total mangoes by 95 to find out how many packs you can make. This tells you the total number of groups you can form.
🎯 Exam Tip: Pay attention to keywords like "each" or "per" to determine if you need to multiply or divide. If you're breaking a large total into equal smaller groups, division is the correct operation.
c. 25 families living in a street needed 1625 liters of water per day. How much of water is needed by one family?
Answer: Total number of families in the street = 25
Total liters of water needed per day = 1625
To find out how much water one family needs, we divide the total water by the number of families.
Water needed by one family = \( 1625 \div 25 \)
\[
\begin{array}{r}
65 \\
25\overline{)1625} \\
-150\downarrow \\
\hline
125 \\
-125 \\
\hline
0
\end{array}
\]
Therefore, 65 liters of water are needed by one family.
In simple words: 25 families use 1625 liters of water in a day. To find out how much water just one family uses, divide the total water by the number of families. This gives you the average water consumption per family.
🎯 Exam Tip: When distributing a total quantity equally among a certain number of units (like families, packets, or days), division is the correct method. Always include the unit in your final answer.
d. 6750 bananas have to be loaded in a tempo van. If 15 bananas are arranged in one basket, then how many baskets will be needed to arrange all the bananas?
Answer: Total number of bananas = 6750
Number of bananas arranged in one basket = 15
To find the total number of baskets needed, we divide the total bananas by the number of bananas per basket.
Number of baskets needed = \( 6750 \div 15 \)
\[
\begin{array}{r}
450 \\
15\overline{)6750} \\
-60\downarrow \\
\hline
75 \\
-75\downarrow \\
\hline
00 \\
-00 \\
\hline
0
\end{array}
\]
So, 450 baskets will be needed to arrange all the bananas.
In simple words: We have 6750 bananas, and each basket holds 15. Divide 6750 by 15 to find out the total number of baskets needed. This tells you how many containers are required for all the items.
🎯 Exam Tip: It is crucial to set up the division problem correctly, with the total quantity as the dividend and the quantity per group as the divisor. A clear understanding of the context will guide you in choosing the correct operation.
Question 2. Divide the following.
a. \( 4525 \div 15 \)
Answer: We need to divide 4525 by 15.
\[
\begin{array}{r}
301 \\
15\overline{)4525} \\
-45\downarrow \\
\hline
02 \\
-00\downarrow \\
\hline
25 \\
-15 \\
\hline
10
\end{array}
\]
The quotient is 301 and the remainder is 10. This means that 15 goes into 4525 three hundred and one times, with ten left over.
In simple words: When you divide 4525 by 15, you get 301. There will be 10 left over because 15 cannot divide into 10 evenly.
🎯 Exam Tip: When performing division, remember to bring down one digit at a time and place a zero in the quotient if the divisor cannot go into the new number. Always state both the quotient and the remainder clearly.
b. \( 3448 \div 24 \)
Answer: We need to divide 3448 by 24.
\[
\begin{array}{r}
143 \\
24\overline{)3448} \\
-24\downarrow \\
\hline
104 \\
-96\downarrow \\
\hline
88 \\
-72 \\
\hline
16
\end{array}
\]
The quotient is 143 and the remainder is 16. This calculation shows how many full groups of 24 can be made from 3448 items, with some items remaining.
In simple words: When you divide 3448 by 24, you get 143. There will be 16 left over because 24 cannot divide into 16 evenly.
🎯 Exam Tip: Estimating the first digit of the quotient can help simplify the division process. Always check your work by multiplying the quotient by the divisor and adding the remainder to see if you get the original dividend.
c. \( 7342 \div 18 \)
Answer: We need to divide 7342 by 18.
\[
\begin{array}{r}
407 \\
18\overline{)7342} \\
-72\downarrow \\
\hline
14 \\
-00\downarrow \\
\hline
142 \\
-126 \\
\hline
16
\end{array}
\]
The quotient is 407 and the remainder is 16. The remainder is always smaller than the divisor.
In simple words: When you divide 7342 by 18, you get 407. You will have 16 left over because 18 cannot divide into 16 completely.
🎯 Exam Tip: Remember to place a zero in the quotient if the divisor is larger than the number you've brought down. This ensures correct place value in your answer.
d. \( 3626 \div 37 \)
Answer: We need to divide 3626 by 37.
\[
\begin{array}{r}
98 \\
37\overline{)3626} \\
-333\downarrow \\
\hline
296 \\
-296 \\
\hline
0
\end{array}
\]
The quotient is 98 and the remainder is 0. This means 3626 is perfectly divisible by 37.
In simple words: When you divide 3626 by 37, you get exactly 98. There is nothing left over.
🎯 Exam Tip: Sometimes, the remainder is zero, meaning the division is exact. Practice your multiplication tables for the divisor to make the division process smoother.
e. \( 4872 \div 56 \)
Answer: We need to divide 4872 by 56.
\[
\begin{array}{r}
87 \\
56\overline{)4872} \\
-448\downarrow \\
\hline
392 \\
-392 \\
\hline
0
\end{array}
\]
The quotient is 87 and the remainder is 0. This shows that 4872 is exactly divisible by 56.
In simple words: When you divide 4872 by 56, you get exactly 87. There is nothing left over at the end.
🎯 Exam Tip: Long division requires careful attention to subtraction and multiplication at each step. Double-check your calculations to avoid small errors that can change the final quotient and remainder.
Free study material for Maths
TN Board Solutions Class 5 Maths Chapter 02 Numbers
Students can now access the TN Board Solutions for Chapter 02 Numbers prepared by teachers on our website. These solutions cover all questions in exercise in your Class 5 Maths textbook. Each answer is updated based on the current academic session as per the latest TN Board syllabus.
Detailed Explanations for Chapter 02 Numbers
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 5 Maths chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 5 students who want to understand both theoretical and practical questions. By studying these TN Board Questions and Answers your basic concepts will improve a lot.
Benefits of using Maths Class 5 Solved Papers
Using our Maths solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 5 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 02 Numbers to get a complete preparation experience.
FAQs
The complete and updated Samacheer Kalvi Class 5 Maths Solutions Term 1 Chapter 2 Numbers Exercise 2.9 is available for free on StudiesToday.com. These solutions for Class 5 Maths are as per latest TN Board curriculum.
Yes, our experts have revised the Samacheer Kalvi Class 5 Maths Solutions Term 1 Chapter 2 Numbers Exercise 2.9 as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths concepts are applied in case-study and assertion-reasoning questions.
Toppers recommend using TN Board language because TN Board marking schemes are strictly based on textbook definitions. Our Samacheer Kalvi Class 5 Maths Solutions Term 1 Chapter 2 Numbers Exercise 2.9 will help students to get full marks in the theory paper.
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